Tüm alıştırma soruları

2195 soru

Soru 741Soru

An artisan chocolate factory produces a signature dark chocolate blend using cocoa mass, cocoa butter, and cane sugar in the initial ratio of 2:3:42 : 3 : 4 by weight, respectively. To modify the flavor profile for a new batch, the master chocolatier adds 1010 kilograms of cocoa mass and 2020 kilograms of cocoa butter to the mix, while removing 55 kilograms of cane sugar. As a result, the ratio of cocoa mass to cocoa butter in the modified mixture becomes 4:74 : 7. What was the total weight, in kilograms, of the initial dark chocolate blend?

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Cevap: 4545

Cevap

The total weight of the initial dark chocolate blend was 4545 kilograms.
By setting the initial weights of cocoa mass, cocoa butter, and cane sugar as 2x2x, 3x3x, and 4x4x, the initial total weight is 9x9x. The modified weights for cocoa mass and cocoa butter are 2x+102x + 10 and 3x+203x + 20, respectively. Equating their ratio to 47\frac{4}{7} gives 2x+103x+20=47\frac{2x + 10}{3x + 20} = \frac{4}{7}, which simplifies to 14x+70=12x+8014x + 70 = 12x + 80, so 2x=102x = 10 and x=5x = 5. Substituting x=5x = 5 into the total weight expression 9x9x yields 9(5)=459(5) = 45 kilograms.

Adım Adım Çözüm

1
Define initial ingredient weights using a multiplier variable.
Cocoa mass = 2x2x, Cocoa butter = 3x3x, Cane sugar = 4x4x. Total initial weight = 2x+3x+4x=9x2x + 3x + 4x = 9x.
Expressing quantities in terms of a common ratio multiplier xx enables setting up algebraic equations after alterations.
2
Express the modified weights of cocoa mass and cocoa butter.
New cocoa mass = 2x+102x + 10; New cocoa butter = 3x+203x + 20.
The problem states 1010 kg of cocoa mass and 2020 kg of cocoa butter were added.
3
Set up the proportion equation using the new ratio of cocoa mass to cocoa butter.
2x+103x+20=47\frac{2x + 10}{3x + 20} = \frac{4}{7}
The modified ratio of cocoa mass to cocoa butter is given as 4:74 : 7.
4
Cross-multiply and solve for xx.
7(2x+10)=4(3x+20)    14x+70=12x+80    2x=10    x=57(2x + 10) = 4(3x + 20) \implies 14x + 70 = 12x + 80 \implies 2x = 10 \implies x = 5.
Solving the linear equation determines the common ratio multiplier value.
5
Calculate the initial total weight of the blend.
Initial total weight = 9x=9(5)=459x = 9(5) = 45 kg.
Multiplying the sum of all initial ratio parts by the multiplier gives the requested initial total weight.

Anahtar Kavram

Ratio setup and algebraic scaling in multi-part word problems with changing quantities
Tahmini Süre:2m 0s
Soru 742Soru

A specialty coffee shop sells two types of coffee beans: Type A for $8\$8 per pound and Type B for $12\$12 per pound. A customer buys a total of xx pounds of coffee, consisting of aa pounds of Type A and bb pounds of Type B, for a total cost of CC dollars. Which of the following equations correctly model the relationship between these quantities? Select all that apply.

Geçerli olan tümünü seçin

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Cevap: a=xba = x - b; C=12x4aC = 12x - 4a; b=C8a12b = \frac{C - 8a}{12}

Cevap

The correct formulations are a=xba = x - b, C=12x4aC = 12x - 4a, and b=C8a12b = \frac{C - 8a}{12}.
The system is defined by two fundamental linear relationships: weight total a+b=xa + b = x and cost total 8a+12b=C8a + 12b = C. Isolating aa from the weight total gives a=xba = x - b. Substituting b=xab = x - a into the cost equation yields C=8a+12(xa)=12x4aC = 8a + 12(x - a) = 12x - 4a. Isolating bb from the cost equation gives 12b=C8a    b=C8a1212b = C - 8a \implies b = \frac{C - 8a}{12}. All three expressions are mathematically equivalent and correct.

Adım Adım Çözüm

1
Set up the basic linear system from the word problem.
Total weight equation: a+b=xa + b = x; Total cost equation: 8a+12b=C8a + 12b = C.
Word problems with total quantity and total monetary value translate into two distinct linear equations.
2
Rearrange the total weight equation to express aa in terms of xx and bb.
a=xba = x - b.
Subtracting bb from both sides isolates aa.
3
Substitute b=xab = x - a into the total cost equation.
C=8a+12(xa)=8a+12x12a=12x4aC = 8a + 12(x - a) = 8a + 12x - 12a = 12x - 4a.
Expressing cost in terms of a single variable aa and total weight xx simplifies multi-variable models.
4
Isolate bb in the total cost equation.
12b=C8a    b=C8a1212b = C - 8a \implies b = \frac{C - 8a}{12}.
Subtracting the cost contribution of Type A (8a8a) and dividing by the unit cost of Type B (1212) isolates bb.

Anahtar Kavram

Linear Equation Modeling in Word Problems
Soru 743Soru

A market research firm surveyed 300300 consumers regarding their subscriptions to three streaming services: Service X, Service Y, and Service Z.

- 4040 consumers subscribed to none of the three services.
- 160160 consumers subscribed to Service X.
- 140140 consumers subscribed to Service Y.
- 130130 consumers subscribed to Service Z.
- Exactly 6060 consumers subscribed to exactly two of the services.

How many consumers subscribed to all three services?

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Cevap: 55

Cevap

55 consumers subscribed to all three services.
The total number of consumers subscribing to at least one service is 30040=260300 - 40 = 260. Expressing the total union in terms of non-overlapping region counts gives e1+e2+e3=260e_1 + e_2 + e_3 = 260, where e1e_1 is the number subscribing to exactly one service, e2=60e_2 = 60 is the number subscribing to exactly two, and e3e_3 is the number subscribing to all three. Thus, e1+e3=200e_1 + e_3 = 200. Summing the individual totals gives X+Y+Z=e1+2e2+3e3=430|X| + |Y| + |Z| = e_1 + 2e_2 + 3e_3 = 430, which simplifies to e1+3e3=310e_1 + 3e_3 = 310. Subtracting e1+e3=200e_1 + e_3 = 200 from e1+3e3=310e_1 + 3e_3 = 310 yields 2e3=1102e_3 = 110, so e3=55e_3 = 55.

Adım Adım Çözüm

1
Calculate the total number of consumers who subscribed to at least one streaming service.
Total in union XYZ=30040=260|X \cup Y \cup Z| = 300 - 40 = 260.
Consumers subscribing to at least one service represent the total sample minus those subscribing to none.
2
Set up the region equations for 3-set inclusion-exclusion in terms of elements in exactly 1 set (e1e_1), exactly 2 sets (e2e_2), and all 3 sets (e3e_3).
Equation 1: e1+e2+e3=260e_1 + e_2 + e_3 = 260; Equation 2: X+Y+Z=e1+2e2+3e3=160+140+130=430|X| + |Y| + |Z| = e_1 + 2e_2 + 3e_3 = 160 + 140 + 130 = 430.
Summing individual set sizes counts elements in exactly one set once, elements in exactly two sets twice, and elements in all three sets three times.
3
Substitute e2=60e_2 = 60 into both equations.
Equation 1: e1+60+e3=260    e1+e3=200e_1 + 60 + e_3 = 260 \implies e_1 + e_3 = 200; Equation 2: e1+2(60)+3e3=430    e1+3e3=310e_1 + 2(60) + 3e_3 = 430 \implies e_1 + 3e_3 = 310.
Simplifying both equations yields a system of two linear equations in terms of e1e_1 and e3e_3.
4
Subtract the simplified Equation 1 from Equation 2 to solve for e3e_3.
(e1+3e3)(e1+e3)=310200    2e3=110    e3=55(e_1 + 3e_3) - (e_1 + e_3) = 310 - 200 \implies 2e_3 = 110 \implies e_3 = 55.
Subtracting eliminates e1e_1, directly yielding the number of consumers subscribing to all three services.

Anahtar Kavram

3-Set Inclusion-Exclusion Principle using Exact Region Counts
Soru 744Soru

If x2(2x3)=9(2x3)x^2(2x - 3) = 9(2x - 3), what is the sum of all distinct real solutions for xx?

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Cevap: 1.51.5

Cevap

The sum of all distinct real solutions for xx is 1.51.5.
To find all solutions without losing roots, set the equation to zero: x2(2x3)9(2x3)=0x^2(2x - 3) - 9(2x - 3) = 0. Factoring out (2x3)(2x - 3) gives (x29)(2x3)=0(x^2 - 9)(2x - 3) = 0, which fully factors into (x3)(x+3)(2x3)=0(x - 3)(x + 3)(2x - 3) = 0. The distinct real roots are 33, 3-3, and 1.51.5. Adding these values together yields 3+(3)+1.5=1.53 + (-3) + 1.5 = 1.5.

Adım Adım Çözüm

1
Move all terms to one side of the equation to avoid losing solutions by dividing by a variable expression.
x2(2x3)9(2x3)=0x^2(2x - 3) - 9(2x - 3) = 0
Dividing by an expression containing variables can eliminate valid roots.
2
Factor out the common term (2x3)(2x - 3).
(x29)(2x3)=0(x^2 - 9)(2x - 3) = 0
Factoring allows application of the zero-product property.
3
Factor the quadratic term x29x^2 - 9 as a difference of squares.
(x3)(x+3)(2x3)=0(x - 3)(x + 3)(2x - 3) = 0
a2b2=(ab)(a+b)a^2 - b^2 = (a - b)(a + b).
4
Set each factor to zero to find all real solutions.
x3=0    x=3x - 3 = 0 \implies x = 3, x+3=0    x=3x + 3 = 0 \implies x = -3, and 2x3=0    x=1.52x - 3 = 0 \implies x = 1.5.
If the product of factors is zero, at least one factor must equal zero.
5
Sum all distinct real solutions.
3+(3)+1.5=1.53 + (-3) + 1.5 = 1.5
The question asks for the sum of all distinct real solutions.

Anahtar Kavram

Factoring Polynomial Equations and Avoiding Variable Cancellation
Tahmini Süre:1m 30s
Soru 745Soru

A specialized express freight facility uses three automated sorting systems—System 1, System 2, and System 3—to process incoming shipments. Operating continuously at their respective constant rates, System 1 and System 2 working together can process 1 full shipment in 6 hours; System 2 and System 3 working together can process the same shipment in 10 hours; and System 1 and System 3 working together can process the shipment in 7.5 hours. Processing begins with System 1 and System 2 working together. After 3 hours, System 1 breaks down and stops operating, at which point System 3 is immediately activated to work alongside System 2 until the entire shipment is completed. How many total hours does it take, from the start of processing, to complete the entire shipment?

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Cevap: 8

Cevap

The total time required from start to completion is 8 hours.
Converting completion times to work rates per hour gives paired rates of 1/6, 1/10, and 2/15. Summing these and dividing by 2 yields a combined three-system rate of 1/5 shipment per hour. In the first 3 hours, System 1 and System 2 complete 3 * (1/6) = 1/2 of the shipment. System 2 and System 3 then finish the remaining 1/2 at their combined rate of 1/10 per hour, requiring (1/2) / (1/10) = 5 hours. Total elapsed time is 3 + 5 = 8 hours.

Adım Adım Çözüm

1
Set up equations for the rate of work done per hour by each pair of systems
Let r1,r2,r3r_1, r_2, r_3 be the individual work rates in shipments per hour. Then r1+r2=16r_1 + r_2 = \frac{1}{6}, r2+r3=110r_2 + r_3 = \frac{1}{10}, and r1+r3=17.5=215r_1 + r_3 = \frac{1}{7.5} = \frac{2}{15}.
Work rate is inversely proportional to completion time (Rate=WorkTimeRate = \frac{Work}{Time}).
2
Calculate the combined processing rate of all three systems
2(r1+r2+r3)=16+110+215=5+3+430=1230=252(r_1 + r_2 + r_3) = \frac{1}{6} + \frac{1}{10} + \frac{2}{15} = \frac{5 + 3 + 4}{30} = \frac{12}{30} = \frac{2}{5}, which simplifies to r1+r2+r3=15r_1 + r_2 + r_3 = \frac{1}{5} shipment per hour.
Adding the three paired rates accounts for each individual system's rate exactly twice.
3
Determine the amount of work completed during the initial 3-hour period
Work completed = 3 hours×(r1+r2)=3×16=123 \text{ hours} \times (r_1 + r_2) = 3 \times \frac{1}{6} = \frac{1}{2} of the total shipment.
System 1 and System 2 operate together at a combined rate of 16\frac{1}{6} shipment per hour for 3 hours.
4
Calculate the time needed for System 2 and System 3 to complete the remaining shipment
Remaining work = 112=121 - \frac{1}{2} = \frac{1}{2}. Time required = 1/2r2+r3=1/21/10=5\frac{1/2}{r_2 + r_3} = \frac{1/2}{1/10} = 5 hours.
System 2 and System 3 work together at a combined rate of 110\frac{1}{10} shipment per hour to finish the remaining half of the job.
5
Calculate the total time elapsed from start to finish
Total time = 3 hours+5 hours=8 hours3 \text{ hours} + 5 \text{ hours} = 8 \text{ hours}.
The question asks for the total duration of the process from the beginning.

Anahtar Kavram

Solving systems of simultaneous work rate equations and analyzing multi-stage combined work.
Soru 746Soru

A jar contains 33 green marbles and 22 red marbles. If two marbles are selected at random one after another without replacement, what is the probability that both selected marbles are green?

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Cevap: 0.3

Cevap

The probability that both selected marbles are green is 0.30.3.
Because selection is done without replacement, the outcome of the first draw changes the composition of the jar for the second draw. The probability of selecting a green marble first is 3/53/5. With one green marble removed, 22 green marbles remain among 44 total marbles, so the probability of selecting green on the second draw is 2/42/4. Multiplying these sequential probabilities gives (3/5)×(2/4)=6/20=0.3(3/5) \times (2/4) = 6/20 = 0.3.

Adım Adım Çözüm

1
Calculate the probability of drawing a green marble on the first selection.
P(First Green)=35P(\text{First Green}) = \frac{3}{5}
There are 33 green marbles out of 55 total marbles in the jar.
2
Calculate the conditional probability of drawing a green marble on the second selection.
P(Second GreenFirst Green)=24=12P(\text{Second Green} \mid \text{First Green}) = \frac{2}{4} = \frac{1}{2}
Because the first marble was not replaced, 22 green marbles remain out of a total of 44 remaining marbles.
3
Multiply the probabilities of the dependent sequential events.
P(Both Green)=35×12=310=0.3P(\text{Both Green}) = \frac{3}{5} \times \frac{1}{2} = \frac{3}{10} = 0.3
The probability of both dependent events occurring is the product of the first event's probability and the conditional probability of the second event.

Anahtar Kavram

Probability of Dependent Events Without Replacement
Soru 747Soru

An industrial semiconductor fabrication facility operates three specialized chemical vapor deposition (CVD) chambers—Chamber 1, Chamber 2, and Chamber 3—to process a large batch of silicon wafers.

When Chamber 1 and Chamber 2 operate together at their respective constant rates, they can complete the entire batch in 1212 hours. When Chamber 2 and Chamber 3 operate together at their respective constant rates, they can complete the entire batch in 2020 hours.

To process a new batch, Chamber 1 operates alone for 44 hours. Next, Chamber 2 is turned on to assist Chamber 1, and both chambers operate together for an additional 66 hours. Finally, Chambers 1 and 2 are shut down, and Chamber 3 operates alone for 1818 hours to finish the remaining portion of the batch.

How many hours would it take Chamber 3 to process the entire batch working alone at its constant rate?

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Cevap: 60 hours

Cevap

60 hours
The correct answer is 60 hours. By subtracting the combined rate of Chambers 2 and 3 (120\frac{1}{20}) from the combined rate of Chambers 1 and 2 (112\frac{1}{12}), we find that Chamber 1's rate exceeds Chamber 3's rate by 130\frac{1}{30} batch per hour. Substituting r1=r3+130r_1 = r_3 + \frac{1}{30} into the total work equation for the three stages (4r1+6(r1+r2)+18r3=14 r_1 + 6(r_1 + r_2) + 18 r_3 = 1) yields 22r3+215=1222 r_3 + \frac{2}{15} = \frac{1}{2}, giving r3=160r_3 = \frac{1}{60}. Therefore, Chamber 3 requires 60 hours alone.

Adım Adım Çözüm

1
Define rate variables and establish equations for the combined pairs.
Let r1,r2,r3r_1, r_2, r_3 represent the work rates of Chambers 1, 2, and 3 in fraction of batch per hour. We are given r1+r2=112r_1 + r_2 = \frac{1}{12} and r2+r3=120r_2 + r_3 = \frac{1}{20}.
Work rate is the reciprocal of completion time for a full job.
2
Find the difference between the rates of Chamber 1 and Chamber 3.
(r1+r2)(r2+r3)=112120    r1r3=560360=260=130(r_1 + r_2) - (r_2 + r_3) = \frac{1}{12} - \frac{1}{20} \implies r_1 - r_3 = \frac{5}{60} - \frac{3}{60} = \frac{2}{60} = \frac{1}{30}. Thus, r1=r3+130r_1 = r_3 + \frac{1}{30}.
Eliminating r2r_2 allows us to express r1r_1 strictly in terms of r3r_3.
3
Calculate the work completed in each stage of the multi-stage schedule.
Stage 1 work = 4r14 r_1. Stage 2 work = 6(r1+r2)=6(112)=126(r_1 + r_2) = 6 \left(\frac{1}{12}\right) = \frac{1}{2}. Stage 3 work = 18r318 r_3.
Work completed equals rate multiplied by time operating.
4
Set up the total work equation and solve for Chamber 3's rate r3r_3.
4r1+12+18r3=1    4(r3+130)+18r3=12    22r3+215=12    22r3=15430=1130    r3=1130×22=1604 r_1 + \frac{1}{2} + 18 r_3 = 1 \implies 4 \left(r_3 + \frac{1}{30}\right) + 18 r_3 = \frac{1}{2} \implies 22 r_3 + \frac{2}{15} = \frac{1}{2} \implies 22 r_3 = \frac{15 - 4}{30} = \frac{11}{30} \implies r_3 = \frac{11}{30 \times 22} = \frac{1}{60}.
Sum of work across all stages equals 11 complete batch.
5
Determine the time required for Chamber 3 to complete the entire batch alone.
Time =1r3=60= \frac{1}{r_3} = 60 hours.
Total time for a single entity is the reciprocal of its individual work rate.

Anahtar Kavram

Multi-stage work rate modeling with system of linear equations
Tahmini Süre:2m 30s
Soru 748Soru

In a market research study of 100100 consumers, 6565 consumers stated that they regularly purchase Brand A, and 4545 consumers stated that they regularly purchase Brand B. If 2020 consumers purchase neither Brand A nor Brand B, how many consumers regularly purchase both Brand A and Brand B?

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Cevap: 30

Cevap

The number of consumers who regularly purchase both Brand A and Brand B is 3030.
According to the principle of inclusion-exclusion for two sets, Total=Brand A+Brand BBoth+Neither\text{Total} = \text{Brand A} + \text{Brand B} - \text{Both} + \text{Neither}. Substituting the given numbers into this relationship gives 100=65+45Both+20100 = 65 + 45 - \text{Both} + 20, which simplifies to 100=130Both100 = 130 - \text{Both}. Subtracting 100100 from 130130 yields Both=30\text{Both} = 30.

Adım Adım Çözüm

1
Identify the given values from the problem statement.
Total=100\text{Total} = 100, Brand A=65\text{Brand A} = 65, Brand B=45\text{Brand B} = 45, Neither=20\text{Neither} = 20.
Extracting all known set quantities to set up the overlapping sets equation.
2
Apply the inclusion-exclusion formula for two overlapping sets.
Total=Brand A+Brand BBoth+Neither\text{Total} = \text{Brand A} + \text{Brand B} - \text{Both} + \text{Neither}.
Subtracting the overlap prevents double-counting elements belonging to both groups.
3
Substitute the values and solve for the unknown overlap.
100=65+45Both+20    100=130Both    Both=30100 = 65 + 45 - \text{Both} + 20 \implies 100 = 130 - \text{Both} \implies \text{Both} = 30.
Algebraically determining the number of consumers in the intersection.

Anahtar Kavram

Two-Set Inclusion-Exclusion Principle
Soru 749Soru

A commercial coffee roasting facility operates two industrial roasters, Roaster XX and Roaster YY. Working alone at its constant rate, Roaster XX can process a standard batch of coffee beans in 1212 hours. Working alone at its constant rate, Roaster YY can process the exact same batch in 88 hours.

Roaster XX begins processing a standard batch alone. After 33 hours, Roaster YY is turned on, and both roasters work together at their respective constant rates until the batch is completely processed. What is the total time, in hours, required to process the entire batch of coffee beans?

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Cevap: 6.66.6 hours

Cevap

6.6 hours
In the first 33 hours, Roaster XX completes 3×112=143 \times \frac{1}{12} = \frac{1}{4} of the total batch, leaving 34\frac{3}{4} of the batch remaining. When both roasters work together, their combined rate is 112+18=524\frac{1}{12} + \frac{1}{8} = \frac{5}{24} batch per hour. The time required for both roasters to finish the remaining 34\frac{3}{4} batch is 3/45/24=3.6\frac{3/4}{5/24} = 3.6 hours. Adding the initial 33 hours yields a total elapsed time of 6.66.6 hours.

Adım Adım Çözüm

1
Calculate individual work rates per hour.
Roaster XX rate = 112\frac{1}{12} batch/hr; Roaster YY rate = 18\frac{1}{8} batch/hr.
Work rate is the reciprocal of the time required to complete one full job.
2
Determine the amount of work completed by Roaster XX in the first 33 hours and the remaining work.
Work done = 3×112=143 \times \frac{1}{12} = \frac{1}{4} batch. Remaining work = 114=341 - \frac{1}{4} = \frac{3}{4} batch.
Roaster XX worked alone for the first 33 hours.
3
Calculate the combined work rate of both roasters working together.
Combined rate = 112+18=224+324=524\frac{1}{12} + \frac{1}{8} = \frac{2}{24} + \frac{3}{24} = \frac{5}{24} batch/hr.
Simultaneous work rates are additive.
4
Find the time taken to complete the remaining work together.
Combined time = 3/45/24=34×245=185=3.6\frac{3/4}{5/24} = \frac{3}{4} \times \frac{24}{5} = \frac{18}{5} = 3.6 hours.
Time equals remaining work divided by the combined work rate.
5
Add the initial single-roaster phase to the combined work phase to find total time.
Total time = 3+3.6=6.63 + 3.6 = 6.6 hours.
The question asks for the total time to process the entire batch.

Anahtar Kavram

Work Rate and Combined Work
Soru 750Soru

If xx is a real number such that 92x+127x13x+23=243\sqrt[3]{\frac{9^{2x+1} \cdot 27^{x-1}}{3^{x+2}}} = 243, what is the value of xx?

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Cevap: 3

Cevap

The value of xx is 3.
Converting all terms inside the radical to powers of 3 yields 34x+233x33x+23=36x33=32x1\sqrt[3]{\frac{3^{4x+2} \cdot 3^{3x-3}}{3^{x+2}}} = \sqrt[3]{3^{6x-3}} = 3^{2x-1}. Setting 32x1=243=353^{2x-1} = 243 = 3^5 gives 2x1=52x - 1 = 5, which solves to x=3x = 3.

Adım Adım Çözüm

1
Express all exponential terms inside the radical using a common base of 3.
92x+1=34x+29^{2x+1} = 3^{4x+2} and 27x1=33x327^{x-1} = 3^{3x-3}.
Unifying bases allows the application of exponent multiplication and division rules.
2
Simplify the algebraic expression inside the cube root.
34x+233x33x+2=3(4x+2)+(3x3)(x+2)=36x3\frac{3^{4x+2} \cdot 3^{3x-3}}{3^{x+2}} = 3^{(4x+2) + (3x-3) - (x+2)} = 3^{6x-3}.
Adding exponents for multiplication of like bases and subtracting for division.
3
Simplify the radical expression using fractional exponent rules.
36x33=(36x3)1/3=32x1\sqrt[3]{3^{6x-3}} = (3^{6x-3})^{1/3} = 3^{2x-1}.
Taking the nn-th root of a power corresponds to dividing the exponent by nn.
4
Solve for xx by equating the exponent to the prime factorized form of 243.
32x1=35    2x1=5    x=33^{2x-1} = 3^5 \implies 2x - 1 = 5 \implies x = 3.
Since the bases are identical and non-zero, the exponents must be equal.

Anahtar Kavram

Exponent and radical rules with common base conversion
Soru 751Soru

A merchant combines 1010 kilograms of Brand A tea costing $20\$20 per kilogram with 3030 kilograms of Brand B tea costing $40\$40 per kilogram. What is the average cost per kilogram of the combined mixture?

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Cevap: $35\$35

Cevap

The average cost per kilogram of the combined tea mixture is $35\$35.
The correct option of $35\$35 properly weights each unit price by its respective quantity. Brand A contributes 10×20=$20010 \times 20 = \$200 and Brand B contributes 30×40=$120030 \times 40 = \$1200, giving a combined total cost of $1400\$1400 for 4040 kg. Dividing $1400\$1400 by 4040 yields $35\$35 per kilogram.

Adım Adım Çözüm

1
Calculate the total cost of Brand A tea
10 kg×$20/kg=$20010 \text{ kg} \times \$20/\text{kg} = \$200
To find the overall weighted cost, we first determine the total dollar amount spent on Brand A.
2
Calculate the total cost of Brand B tea
30 kg×$40/kg=$120030 \text{ kg} \times \$40/\text{kg} = \$1200
Next, we calculate the total dollar amount spent on Brand B.
3
Find total combined cost and total combined weight
\text{Total cost} = \$200 + \$1200 = \$1400; \text{Total weight} = 10 + 30 = 40 \text{ kg}
Sum the total cost of both components and their combined weights.
4
Divide total combined cost by total combined weight
\text{Weighted Average Cost} = \frac{\$1400}{40 \text{ kg}} = \$35/\text{kg}
The weighted average formula is Total Cost divided by Total Quantity.

Anahtar Kavram

Weighted Average in Applied Contexts
Tahmini Süre:1m 0s
Soru 752Soru

For all non-zero real numbers aa and bb, the custom binary operator \star is defined by ab=a2b2aba \star b = \frac{a^2 - b^2}{ab}. A function ff is defined for all positive numbers xx by f(x)=(x+1)xf(x) = (x + 1) \star x. What is the value of f(3)f(2)f(3) \star f(2)?

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Cevap: 5170-\frac{51}{70}

Cevap

5170-\frac{51}{70}
First, evaluate the inner function values: f(3)=43=423243=712f(3) = 4 \star 3 = \frac{4^2 - 3^2}{4 \cdot 3} = \frac{7}{12} and f(2)=32=322232=56=1012f(2) = 3 \star 2 = \frac{3^2 - 2^2}{3 \cdot 2} = \frac{5}{6} = \frac{10}{12}. Next, evaluate the outer operation (712)(1012)=(7/12)2(10/12)2(7/12)(10/12)=4910070=5170\left(\frac{7}{12}\right) \star \left(\frac{10}{12}\right) = \frac{(7/12)^2 - (10/12)^2}{(7/12)(10/12)} = \frac{49 - 100}{70} = -\frac{51}{70}. Hence, the correct response is 5170-\frac{51}{70}.

Adım Adım Çözüm

1
Evaluate f(3)f(3) using the definition of f(x)f(x) and the custom operator \star.
f(3)=(3+1)3=43=42324×3=16912=712f(3) = (3 + 1) \star 3 = 4 \star 3 = \frac{4^2 - 3^2}{4 \times 3} = \frac{16 - 9}{12} = \frac{7}{12}
By definition, f(x)=(x+1)xf(x) = (x+1) \star x. Setting x=3x=3 yields 434 \star 3.
2
Evaluate f(2)f(2) using the definition of f(x)f(x) and the custom operator \star.
f(2)=(2+1)2=32=32223×2=946=56f(2) = (2 + 1) \star 2 = 3 \star 2 = \frac{3^2 - 2^2}{3 \times 2} = \frac{9 - 4}{6} = \frac{5}{6}
Setting x=2x=2 in f(x)f(x) yields 323 \star 2.
3
Evaluate f(3)f(2)=(712)(56)f(3) \star f(2) = \left(\frac{7}{12}\right) \star \left(\frac{5}{6}\right).
(712)(1012)=(712)2(1012)2(712)(1012)=4910014470144=5170\left(\frac{7}{12}\right) \star \left(\frac{10}{12}\right) = \frac{\left(\frac{7}{12}\right)^2 - \left(\frac{10}{12}\right)^2}{\left(\frac{7}{12}\right)\left(\frac{10}{12}\right)} = \frac{\frac{49 - 100}{144}}{\frac{70}{144}} = -\frac{51}{70}
Apply the rule uv=u2v2uvu \star v = \frac{u^2 - v^2}{uv} with u=712u = \frac{7}{12} and v=1012v = \frac{10}{12}.

Anahtar Kavram

Custom non-commutative binary operators and function evaluation
Tahmini Süre:2m 0s
Soru 753Soru

Working together at their respective constant rates, Machine X and Machine Y can complete a specialized production order in 1212 hours. If Machine X works alone for 44 hours and Machine Y works alone for 99 hours, they complete 712\frac{7}{12} of the total order. Machine Z operates at a constant rate that is 50%50\% greater than the rate of Machine X. How many hours would it take Machine Y and Machine Z working together to complete the entire order?

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Cevap: 1010

Cevap

1010 hours
The correct answer is 1010 hours. Solving the system of equations yields individual rates of 130\frac{1}{30} order/hour for Machine X and 120\frac{1}{20} order/hour for Machine Y. A 50%50\% rate increase gives Machine Z a rate of 120\frac{1}{20} order/hour. Adding the rates of Machine Y and Machine Z yields a combined rate of 110\frac{1}{10} order/hour, which requires 1010 hours to complete one job.

Adım Adım Çözüm

1
Define variables and model the joint rate equation.
Let xx be the rate of Machine X (order/hour) and yy be the rate of Machine Y (order/hour). Their combined rate equation is x+y=112x + y = \frac{1}{12}.
Working together for 1212 hours completes 11 full order.
2
Set up the second equation based on the partial work completed.
4x+9y=7124x + 9y = \frac{7}{12}.
Machine X works for 44 hours and Machine Y works for 99 hours to complete 712\frac{7}{12} of the order.
3
Solve the system of linear equations for xx and yy.
Express 4x+9y4x + 9y as 4(x+y)+5y=7124(x + y) + 5y = \frac{7}{12}. Substituting x+y=112x + y = \frac{1}{12} gives 4(112)+5y=712    412+5y=712    5y=312=14    y=1204\left(\frac{1}{12}\right) + 5y = \frac{7}{12} \implies \frac{4}{12} + 5y = \frac{7}{12} \implies 5y = \frac{3}{12} = \frac{1}{4} \implies y = \frac{1}{20}. Subsequently, x=112120=5360=260=130x = \frac{1}{12} - \frac{1}{20} = \frac{5 - 3}{60} = \frac{2}{60} = \frac{1}{30}.
Determines the individual work rates of Machine X and Machine Y.
4
Calculate the work rate of Machine Z.
Rate of Machine Z = 1.5×x=1.5×130=32×130=1201.5 \times x = 1.5 \times \frac{1}{30} = \frac{3}{2} \times \frac{1}{30} = \frac{1}{20}.
Machine Z is 50%50\% faster than Machine X.
5
Calculate the combined rate and total time for Machine Y and Machine Z.
Combined rate = y+z=120+120=220=110y + z = \frac{1}{20} + \frac{1}{20} = \frac{2}{20} = \frac{1}{10}. Total time = 1110=10\frac{1}{\frac{1}{10}} = 10 hours.
The inverse of the combined rate gives the total time required to finish one job.

Anahtar Kavram

Work Rates and Simultaneous Linear Modeling
Tahmini Süre:2m 30s
Soru 754Soru

For all real numbers aa and bb, the custom binary operation \star is defined by ab=a22b2+aba \star b = a^2 - 2b^2 + ab. The function gg is defined by g(x)=x3g(x) = x \star 3. What is the positive value of xx for which g(x)=10g(x) = 10?

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Cevap: 4

Cevap

The positive value of xx for which g(x)=10g(x) = 10 is 44.
Evaluating g(x)=x3g(x) = x \star 3 gives x22(3)2+x(3)=x2+3x18x^2 - 2(3)^2 + x(3) = x^2 + 3x - 18. Setting this expression equal to 1010 produces the quadratic equation x2+3x28=0x^2 + 3x - 28 = 0. Factoring yields (x+7)(x4)=0(x + 7)(x - 4) = 0, giving solutions x=7x = -7 and x=4x = 4. Since xx must be positive, the correct value is 44.

Adım Adım Çözüm

1
Apply the definition of the custom binary operator \star to find g(x)g(x).
g(x)=x3=x22(3)2+x(3)=x218+3x=x2+3x18g(x) = x \star 3 = x^2 - 2(3)^2 + x(3) = x^2 - 18 + 3x = x^2 + 3x - 18
Substitute a=xa = x and b=3b = 3 into the given formula ab=a22b2+aba \star b = a^2 - 2b^2 + ab.
2
Set the function expression equal to 1010 and rearrange into standard quadratic form.
x2+3x18=10    x2+3x28=0x^2 + 3x - 18 = 10 \implies x^2 + 3x - 28 = 0
Subtract 1010 from both sides to form a quadratic equation equal to zero.
3
Factor the quadratic equation to find the values of xx.
(x+7)(x4)=0    x=7 or x=4(x + 7)(x - 4) = 0 \implies x = -7 \text{ or } x = 4
Find two numbers that multiply to 28-28 and add to 33, which are 77 and 4-4.
4
Select the positive value of xx as specified in the stem.
x=4x = 4
The question asks specifically for the positive value of xx.

Anahtar Kavram

Evaluating non-commutative custom operators and solving polynomial equations resulting from function evaluations.
Tahmini Süre:2m 0s
Soru 755Soru

A local theater sold a total of 120120 tickets for a weekend performance, consisting only of adult tickets and student tickets. Adult tickets were sold for $15\$15 each, and student tickets were sold for $10\$10 each. If the total revenue from the ticket sales was $1500\$1{}500, how many adult tickets were sold?

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Cevap: 60

Cevap

The correct answer is 60 adult tickets.
By setting up the total ticket equation a+s=120a + s = 120 and total revenue equation 15a+10s=150015a + 10s = 1500, substituting s=120as = 120 - a gives 15a+10(120a)=150015a + 10(120 - a) = 1500. Simplifying yields 5a=3005a = 300, so a=60a = 60. Thus, 60 adult tickets were sold.

Adım Adım Çözüm

1
Set up the linear equation in one variable.
15a+10(120a)=150015a + 10(120 - a) = 1500
Express the number of student tickets as (120a)(120 - a) so the revenue equation relies on a single variable.
2
Expand and combine like terms.
5a+1200=15005a + 1200 = 1500
Distribute 1010 across (120a)(120 - a) to simplify the equation.
3
Isolate the variable aa.
a=60a = 60
Subtract 12001200 from both sides and divide by 55 to find the number of adult tickets.

Anahtar Kavram

Algebraic Modeling of Linear Systems in Two Variables
Tahmini Süre:1m 0s
Soru 756Soru

How many integer values of xx satisfy the inequality x34|x - 3| \leq 4?

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Cevap: 9

Cevap

There are 9 integer values of xx that satisfy the inequality.
Unfolding x34|x - 3| \leq 4 yields 4x34-4 \leq x - 3 \leq 4. Adding 3 across all terms gives 1x7-1 \leq x \leq 7. The integer values satisfying this range are 1,0,1,2,3,4,5,6,7-1, 0, 1, 2, 3, 4, 5, 6, 7, which totals 9 values.

Adım Adım Çözüm

1
Convert the absolute value inequality into a compound linear inequality.
4x34-4 \leq x - 3 \leq 4
The absolute value inequality kc|k| \leq c (for c0c \geq 0) is equivalent to ckc-c \leq k \leq c.
2
Isolate xx by adding 3 across all parts of the inequality.
1x7-1 \leq x \leq 7
Adding the same constant to all parts of an inequality maintains the inequality relationships.
3
Count the total number of integer values within the inclusive range [1,7][-1, 7].
9
The number of integers in an inclusive range [a,b][a, b] is calculated as ba+1b - a + 1, which gives 7(1)+1=97 - (-1) + 1 = 9.

Anahtar Kavram

Solving absolute value inequalities and counting integer solutions within a bounded interval
Soru 757Soru

For all real numbers aa and bb, the custom binary operator \star is defined by ab=2aba \star b = 2a - b. The function ff is defined for all real numbers by f(x)=x21f(x) = x^2 - 1. If (x3)f(3)=6(x \star 3) \star f(3) = 6, what is the value of xx?

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Cevap: 5

Cevap

5
First, evaluate the function f(3)=321=8f(3) = 3^2 - 1 = 8. Next, evaluate the first custom operation x3=2x3x \star 3 = 2x - 3. Substituting these into the overall expression yields (2x3)8=2(2x3)8=4x14(2x - 3) \star 8 = 2(2x - 3) - 8 = 4x - 14. Setting this equal to 6 gives 4x14=64x - 14 = 6, which simplifies to 4x=204x = 20, so x=5x = 5.

Adım Adım Çözüm

1
Evaluate the inner function f(3)f(3)
f(3)=321=91=8f(3) = 3^2 - 1 = 9 - 1 = 8
Substitute x=3x = 3 into the given definition f(x)=x21f(x) = x^2 - 1.
2
Evaluate the inner custom operation x3x \star 3
x3=2x3x \star 3 = 2x - 3
Apply the custom operator rule ab=2aba \star b = 2a - b with a=xa = x and b=3b = 3.
3
Evaluate the outer custom operation (x3)f(3)(x \star 3) \star f(3)
(2x3)8=2(2x3)8=4x68=4x14(2x - 3) \star 8 = 2(2x - 3) - 8 = 4x - 6 - 8 = 4x - 14
Substitute the results from Step 1 and Step 2 into the custom operator definition.
4
Solve the algebraic equation for xx
4x14=6    4x=20    x=54x - 14 = 6 \implies 4x = 20 \implies x = 5
Set the simplified expression equal to 6 as given in the problem stem and isolate xx.

Anahtar Kavram

Custom Operator Evaluation and Nested Functions
Tahmini Süre:1m 30s
Soru 758Soru

A commercial bakery prepares a specialty grain blend using Organic Wheat, Spelt, and Rye flour. Initially, the ratio of Organic Wheat to Spelt to Rye flour in the batch is 4:3:24 : 3 : 2 by weight. To meet specific recipe requirements, 3030 kilograms of Organic Wheat and 1515 kilograms of Spelt are added to the batch, while 1010 kilograms of Rye are removed. After these adjustments, the ratio of Organic Wheat to Rye flour in the batch becomes 3:13 : 1. What was the total weight, in kilograms, of the initial batch of flour before any adjustments were made?

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Cevap: 270

Cevap

270 kilograms
By representing the initial amounts of Organic Wheat, Spelt, and Rye as 4x4x, 3x3x, and 2x2x kilograms respectively, the initial total weight is 9x9x kilograms. Following the adjustments, the new amount of Wheat is 4x+304x + 30 kg and the new amount of Rye is 2x102x - 10 kg. Equating their ratio to 3:13 : 1 gives 4x+302x10=31\frac{4x + 30}{2x - 10} = \frac{3}{1}. Solving for xx gives 4x+30=6x304x + 30 = 6x - 30, leading to 2x=602x = 60 or x=30x = 30. Therefore, the initial total weight of the flour batch was 9×30=2709 \times 30 = 270 kilograms.

Adım Adım Çözüm

1
Define initial quantities using a common multiplier xx.
Organic Wheat =4x= 4x, Spelt =3x= 3x, Rye =2x= 2x. Initial total weight =4x+3x+2x=9x= 4x + 3x + 2x = 9x.
The initial ratio 4:3:24 : 3 : 2 specifies the relative proportions of the three components in the batch.
2
Express the updated amounts after additions and removals.
New Organic Wheat =4x+30= 4x + 30, New Spelt =3x+15= 3x + 15, New Rye =2x10= 2x - 10.
Incorporating the specified additions (+30+30 kg Wheat, +15+15 kg Spelt) and removal (10-10 kg Rye).
3
Set up an equation using the new ratio of Organic Wheat to Rye (3:13 : 1).
4x+302x10=31\frac{4x + 30}{2x - 10} = \frac{3}{1}
The problem states that the updated ratio of Wheat to Rye is 3:13 : 1.
4
Solve for the multiplier xx.
4x+30=3(2x10)    4x+30=6x30    2x=60    x=304x + 30 = 3(2x - 10) \implies 4x + 30 = 6x - 30 \implies 2x = 60 \implies x = 30.
Cross-multiplying and solving the linear equation yields x=30x = 30.
5
Calculate the total weight of the initial batch.
Initial total =9x=9×30=270= 9x = 9 \times 30 = 270 kilograms.
Substituting x=30x = 30 back into the initial total expression 9x9x gives the required initial batch mass.

Anahtar Kavram

Ratio Modification and Multi-Part Proportions
Tahmini Süre:2m 0s
Soru 759Soru

Worker A can complete a specific publishing task alone in 44 hours, while Worker B can complete the exact same task alone in 66 hours. Working together continuously at their respective constant individual rates, how many hours will it take both workers to complete one such task?

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Cevap: 2.42.4

Cevap

The combined time required to complete the task is 2.42.4 hours.
The correct response calculates each worker's hourly rate of completion (one-fourth and one-sixth of the job per hour), sums them to find a combined rate of five-twelfths of the job per hour, and takes the reciprocal to find that the total time required is 2.42.4 hours.

Adım Adım Çözüm

1
Determine individual work rates per hour.
Worker A's rate is 14\frac{1}{4} of the task per hour; Worker B's rate is 16\frac{1}{6} of the task per hour.
Work rate is defined as the reciprocal of total time required to complete one unit of work.
2
Sum the individual rates to find the combined work rate.
Combined Rate = 14+16=312+212=512\frac{1}{4} + \frac{1}{6} = \frac{3}{12} + \frac{2}{12} = \frac{5}{12} task per hour.
When working together, rates add together linearly.
3
Calculate total time by taking the reciprocal of the combined rate.
Time = 1Combined Rate=125=2.4\frac{1}{\text{Combined Rate}} = \frac{12}{5} = 2.4 hours.
Time equals total work (1 unit) divided by the combined rate.

Anahtar Kavram

Combined Work Rates
Tahmini Süre:1m 0s
Soru 760Soru

At a technology company, a team of 6060 software engineers works on product development. Of these engineers, 3535 work on the mobile application, 2828 work on the web platform, and 1010 work on neither project. How many engineers work on both the mobile application and the web platform?

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Cevap: 1313

Cevap

13 engineers work on both the mobile application and the web platform.
According to the fundamental principle of overlapping sets for two groups, the total number of individuals in the universe is equal to the number of individuals in Group A plus the number in Group B, minus those counted in both groups (to prevent double counting), plus those in neither group: Total=Set A+Set BBoth+Neither\text{Total} = \text{Set A} + \text{Set B} - \text{Both} + \text{Neither}. Substituting the given values gives 60=35+28Both+1060 = 35 + 28 - \text{Both} + 10. Simplifying the right side yields 60=73Both60 = 73 - \text{Both}, so Both=13\text{Both} = 13. Thus, the value 1313 is correct.

Adım Adım Çözüm

1
Identify the given set values and formula
Total=60\text{Total} = 60, Mobile=35\text{Mobile} = 35, Web=28\text{Web} = 28, Neither=10\text{Neither} = 10
Define all components of the standard two-set overlapping formula: Total=Set A+Set BBoth+Neither\text{Total} = \text{Set A} + \text{Set B} - \text{Both} + \text{Neither}.
2
Substitute the values into the overlapping sets formula
60=35+28Both+1060 = 35 + 28 - \text{Both} + 10
Set up the linear equation to solve for the unknown intersection (Both).
3
Simplify and solve for Both
60=73Both    Both=7360=1360 = 73 - \text{Both} \implies \text{Both} = 73 - 60 = 13
Combine like terms (35+28+10=7335 + 28 + 10 = 73) and isolate the variable to find the number of engineers in both groups.

Anahtar Kavram

Two-Set Overlapping Venn Diagram Principle
Tahmini Süre:1m 0s
ÖncekiSayfa 38 / 110Sonraki
Tüm alıştırma soruları — GMAT | Examkin