Tüm alıştırma soruları

2131 soru

Soru 41Soru

A vertical flagpole stands on flat, horizontal ground. An observer at point SS on the ground measures the angle of elevation to the top of the flagpole to be 6060^\circ. A second observer at point PP on the ground, located 3030 feet further from the base of the flagpole along the same line extending from the base through SS, measures the angle of elevation to the top of the flagpole to be 3030^\circ. What is the height of the flagpole, in feet?

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Cevap: 15315\sqrt{3}

Cevap

The height of the flagpole is 15315\sqrt{3} feet.
Let BB be the base and TT be the top of the flagpole. The right triangle TBSTBS has angles 3030^\circ, 6060^\circ, and 9090^\circ at BB. If BS=xBS = x, then the height TB=x3TB = x\sqrt{3}. In right triangle TBPTBP, the angle at PP is 3030^\circ, so the base BP=TB3=(x3)3=3xBP = TB\sqrt{3} = (x\sqrt{3})\sqrt{3} = 3x. Since BP=BS+30BP = BS + 30, we set up 3x=x+303x = x + 30, yielding x=15x = 15. Therefore, the height TB=153TB = 15\sqrt{3} feet.

Adım Adım Çözüm

1
Model the scenario using right triangles.
Let BB be the base of the flagpole and TT be the top. Triangle TBSTBS is a 30609030^\circ-60^\circ-90^\circ right triangle at BB, and triangle TBPTBP is also a 30609030^\circ-60^\circ-90^\circ right triangle at BB.
The flagpole is perpendicular to the horizontal ground.
2
Express side lengths in terms of base distance x=BSx = BS.
In 30609030^\circ-60^\circ-90^\circ triangle TBSTBS, TB=x3TB = x\sqrt{3} and ST=2xST = 2x.
The side opposite the 6060^\circ angle is 3\sqrt{3} times the side opposite the 3030^\circ angle.
3
Set up the equation for triangle TBPTBP.
In 30609030^\circ-60^\circ-90^\circ triangle TBPTBP, the side opposite the 3030^\circ angle is TB=x3TB = x\sqrt{3}, so the adjacent side BP=(x3)3=3xBP = (x\sqrt{3})\sqrt{3} = 3x.
The side opposite the 6060^\circ angle (BPBP) is 3\sqrt{3} times the side opposite the 3030^\circ angle (TBTB).
4
Solve for xx using the given distance SP=30SP = 30.
Since BP=BS+SPBP = BS + SP, we have 3x=x+303x = x + 30, which simplifies to 2x=302x = 30, so x=15x = 15.
The total horizontal distance BPBP is the sum of segments BSBS and SPSP.
5
Calculate the height TBTB.
TB=153TB = 15\sqrt{3}.
Substitute x=15x = 15 into TB=x3TB = x\sqrt{3}.

Anahtar Kavram

Special Right Triangle Ratios (30609030^\circ-60^\circ-90^\circ)
Tahmini Süre:1m 30s
Soru 42Soru

Read the sentence below concerning astrobiological research. Based on the explicit continuation structural signal in the sentence, enter a word or phrase that logically completes the blank.

Aşağıdaki boşlukları doldurun

The discovery of intact organic molecules within subterranean basalt deposits did not merely suggest the possibility of microbial life in extreme environments; , by confirming active metabolic pathways miles beneath the seafloor, the study forced astrobiologists to broaden their criteria for planetary habitability.
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Cevap

indeed (or an equivalent intensifying continuation transition such as 'in fact', 'furthermore', or 'moreover')
The sentence follows an escalating continuation pattern initiated by 'did not merely'. The second independent clause enhances the scope of the discovery from a mere possibility to a confirmed finding that alters scientific criteria. An intensifying continuation word such as 'indeed' or 'furthermore' correctly bridges the two clauses while maintaining logical coherence.

Adım Adım Çözüm

1
Analyze the structural construction of the sentence.
Identified the correlative escalating framework 'did not merely [X]; [blank], [Y]'.
The phrase 'did not merely suggest' sets up an intensifying continuation where the second clause provides stronger evidence or a more conclusive assertion.
2
Determine the required directional signal for the blank.
The blank requires a continuation/intensification transition.
The second clause reinforces and expands upon the first clause rather than contrasting with it or expressing concession.
3
Select a fitting transition word.
Words such as 'indeed', 'in fact', 'furthermore', or 'moreover' logically complete the causal continuation.
These terms correctly signal that the second statement builds upon and confirms the claim made in the first statement.

Anahtar Kavram

Interpreting Continuation and Causal Structural Signals
Tahmini Süre:1m 0s
Soru 43Soru

A beverage mixture is prepared by combining apple juice, orange juice, and grape juice in a ratio of 3:4:53 : 4 : 5 by volume. If a pitcher contains a total of 4848 fluid ounces of this mixture, how many fluid ounces of orange juice are in the pitcher?

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Cevap: 1616 fluid ounces

Cevap

1616 fluid ounces
The ratio 3:4:53 : 4 : 5 indicates that the total mixture is divided into 3+4+5=123 + 4 + 5 = 12 equal parts. Orange juice accounts for 44 of these 1212 parts, representing 412=13\frac{4}{12} = \frac{1}{3} of the total volume. Taking 13\frac{1}{3} of 4848 fluid ounces gives 1616 fluid ounces.

Adım Adım Çözüm

1
Calculate the total number of ratio parts.
Total parts = 3+4+5=123 + 4 + 5 = 12.
To find the fraction of each ingredient in the mixture, we must sum all parts of the ratio.
2
Determine the fraction of the total volume that represents orange juice.
Orange juice fraction = 412=13\frac{4}{12} = \frac{1}{3}.
Orange juice corresponds to 44 parts out of the 1212 total parts.
3
Multiply the orange juice fraction by the total volume.
13×48=16\frac{1}{3} \times 48 = 16 fluid ounces.
Multiplying the part-to-whole fraction by the total volume yields the exact volume of orange juice.

Anahtar Kavram

Part-to-Whole Ratio Relationships
Tahmini Süre:45s
Soru 44Soru

If xx and yy are real numbers such that 2x59|2x - 5| \le 9 and y+34|y + 3| \le 4, what is the maximum possible value of x2y+1|x - 2y + 1|?

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Cevap: 2222

Cevap

The maximum possible value of x2y+1|x - 2y + 1| is 22.
The correct answer is 22 because solving the absolute value inequalities gives 2x7-2 \le x \le 7 and 7y1-7 \le y \le 1. To maximize x2y+1x - 2y + 1, we take the largest possible value of xx (77), the smallest possible value of yy (7-7, making 2y=14-2y = 14), and add 11, obtaining 7+14+1=227 + 14 + 1 = 22. Since the lower bound of x2y+1x - 2y + 1 is 3-3, the maximum absolute value is 22=22|22| = 22.

Adım Adım Çözüm

1
Find the range of possible values for xx from the inequality 2x59|2x - 5| \le 9.
92x59    42x14    2x7-9 \le 2x - 5 \le 9 \implies -4 \le 2x \le 14 \implies -2 \le x \le 7.
An absolute value inequality AB|A| \le B unwraps to BAB-B \le A \le B.
2
Find the range of possible values for yy from the inequality y+34|y + 3| \le 4.
4y+34    7y1-4 \le y + 3 \le 4 \implies -7 \le y \le 1.
Unwrapping the absolute value inequality gives the upper and lower bounds for yy on the real number line.
3
Determine the range of possible values for 2y-2y.
Multiplying 7y1-7 \le y \le 1 by 2-2 and reversing the inequality signs yields 2(1)2y2(7)    22y14-2(1) \le -2y \le -2(-7) \implies -2 \le -2y \le 14.
Multiplying an inequality by a negative number reverses the direction of the inequality signs.
4
Combine the ranges to find the minimum and maximum bounds for z=x2y+1z = x - 2y + 1.
Minimum z=(2)+(2)+1=3z = (-2) + (-2) + 1 = -3; Maximum z=7+14+1=22z = 7 + 14 + 1 = 22. Thus, 3x2y+122-3 \le x - 2y + 1 \le 22.
Adding the individual minimums gives the absolute minimum, and adding the individual maximums gives the absolute maximum.
5
Calculate the maximum value of the absolute value x2y+1|x - 2y + 1|.
max(x2y+1)=max(3,22)=22\\max(|x - 2y + 1|) = \\max(|-3|, |22|) = 22.
The absolute value of a quantity ranging from 3-3 to 2222 reaches its maximum distance from zero at 2222.

Anahtar Kavram

Properties of Real Numbers, Number Line Inequalities, and Absolute Value Operations
Tahmini Süre:2m 30s
Soru 45Soru

In analyzing the ecological impact of rapid industrial development, environmental scientists note that expanding infrastructure continues to exact a heavy toll on local biodiversity, demanding sacrifices from surrounding ecosystems that cannot easily be recovered.

Which of the following words is closest in meaning to the word 'exact' as it is used in the passage above?

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Cevap: impose

Cevap

impose
In the context of the passage, 'exact' is used as a verb meaning to demand, inflict, or levy (e.g., 'to exact a toll'). Substituting 'impose' preserves the intended meaning that infrastructure expansion forces or inflicts a severe cost on biodiversity.

Adım Adım Çözüm

1
Identify the target word and its grammatical role in the sentence
The word 'exact' follows the infinitive marker 'to' ('to exact a heavy toll'), indicating it functions as a verb, not an adjective.
Determining the part of speech filters out primary adjective definitions that do not fit the syntactical structure.
2
Analyze surrounding contextual clues
The clause 'demanding sacrifices from surrounding ecosystems' directly clarifies what 'exact a heavy toll' means.
The surrounding text provides an explicit restatement of the secondary verb meaning.
3
Substitute options to find the semantic match
Replacing 'exact' with 'impose' yields 'continues to impose a heavy toll', maintaining the exact meaning of demanding or inflicting a cost.
'Impose' correctly captures the secondary verb definition of requiring or inflicting something burdensome.

Anahtar Kavram

Secondary verb meanings of polysemous words in academic contexts
Soru 46Soru

Although early biographers depicted the diplomat’s private journal as a purely (i)________ account designed to settle old scores, subsequent historical analysis reveals that the entries were surprisingly (ii)________, offering an extraordinarily balanced and objective record of the negotiations.

Which of the following pairs of terms best completes the passage in a logically coherent manner?

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Cevap: (i) rancorous, (ii) dispassionate

Cevap

The pair '(i) rancorous, (ii) dispassionate' correctly completes the text by establishing the required contrast between a bitter early portrayal and a balanced historical reality.
The sentence relies on a concessive transition ('Although') paired with internal elaboration clues. The descriptive phrase 'designed to settle old scores' points to Blank (i) needing a word meaning resentful or bitter ('rancorous'). In contrast, the second clause describes the entries as an 'extraordinarily balanced and objective record', requiring Blank (ii) to mean impartial or unbiased ('dispassionate'). Only the pair featuring 'rancorous' for Blank (i) and 'dispassionate' for Blank (ii) satisfies both semantic requirements concurrently.

Adım Adım Çözüm

1
Analyze the clue for Blank (ii)
The phrase 'offering an extraordinarily balanced and objective record' directly describes the second blank.
Blank (ii) must be a synonym or positive attribute corresponding to 'balanced' and 'objective', pointing to 'dispassionate'.
2
Identify structural transition and clue for Blank (i)
The initial contrast word 'Although' indicates that early biographers held a view opposite to the 'balanced and objective' reality, while 'designed to settle old scores' provides a specific negative clue for Blank (i).
Blank (i) requires a term indicating bitterness or hostility, pointing to 'rancorous'.
3
Verify inter-blank dependency and overall sentence coherence
Combining 'rancorous' and 'dispassionate' completes the contrast smoothly: early biographers saw it as a bitter account, but later analysis revealed it to be surprisingly objective.
Both blanks must work simultaneously to satisfy both the internal clause clues and the overarching concession structure ('Although...').

Anahtar Kavram

Multi-Blank Dependency Tracking
Soru 47Soru

A laboratory mixture is created by combining two solutions containing a specific tracer compound. Solution X has a volume of 2.5×1032.5 \times 10^3 milliliters and a tracer concentration of 4.8×1074.8 \times 10^{-7} grams per milliliter. Solution Y has a volume of 7.5×1037.5 \times 10^3 milliliters and a tracer concentration of 1.6×1061.6 \times 10^{-6} grams per milliliter. What is the total mass, in grams, of the tracer compound present in the combined mixture?

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Cevap: 1.32×1021.32 \times 10^{-2}

Cevap

1.32×1021.32 \times 10^{-2} grams
The mass in Solution X is (2.5×103)×(4.8×107)=1.2×103(2.5 \times 10^3) \times (4.8 \times 10^{-7}) = 1.2 \times 10^{-3} grams, and the mass in Solution Y is (7.5×103)×(1.6×106)=1.2×102(7.5 \times 10^3) \times (1.6 \times 10^{-6}) = 1.2 \times 10^{-2} grams. Rewriting 1.2×1031.2 \times 10^{-3} as 0.12×1020.12 \times 10^{-2} allows direct addition: (0.12+1.2)×102=1.32×102(0.12 + 1.2) \times 10^{-2} = 1.32 \times 10^{-2} grams.

Adım Adım Çözüm

1
Calculate the mass of the tracer in Solution X
MX=(2.5×103)×(4.8×107)=12.0×104=1.2×103M_X = (2.5 \times 10^3) \times (4.8 \times 10^{-7}) = 12.0 \times 10^{-4} = 1.2 \times 10^{-3} grams
Mass equals volume multiplied by concentration.
2
Calculate the mass of the tracer in Solution Y
MY=(7.5×103)×(1.6×106)=12.0×103=1.2×102M_Y = (7.5 \times 10^3) \times (1.6 \times 10^{-6}) = 12.0 \times 10^{-3} = 1.2 \times 10^{-2} grams
Mass equals volume multiplied by concentration.
3
Sum the tracer masses and adjust to scientific notation
Mtotal=1.2×103+1.2×102=0.12×102+1.2×102=1.32×102M_{\text{total}} = 1.2 \times 10^{-3} + 1.2 \times 10^{-2} = 0.12 \times 10^{-2} + 1.2 \times 10^{-2} = 1.32 \times 10^{-2} grams
To add terms in scientific notation, convert them to have matching exponents before adding coefficients.

Anahtar Kavram

Arithmetic operations with Scientific Notation and Decimals
Tahmini Süre:1m 30s
Soru 48Soru

If x+y=8x + y = 8 and 2xy=72x - y = 7, what is the value of xx?

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Cevap: 5

Cevap

5
Adding the two equations yields (x+y)+(2xy)=8+7(x + y) + (2x - y) = 8 + 7, which simplifies to 3x=153x = 15. Dividing both sides by 3 gives the correct value, x=5x = 5.

Adım Adım Çözüm

1
Add the two equations together to eliminate the variable yy.
(x+y)+(2xy)=8+7    3x=15(x + y) + (2x - y) = 8 + 7 \implies 3x = 15
Since the coefficients of yy are +1+1 and 1-1, adding the equations eliminates yy directly.
2
Solve for xx by dividing both sides of the equation by 3.
x=153=5x = \frac{15}{3} = 5
Isolating xx gives the required solution.

Anahtar Kavram

Elimination Method in Systems of Linear Equations
Soru 49Soru

If 2x34x53=x+1512\frac{2x - 3}{4} - \frac{x - 5}{3} = \frac{x + 15}{12}, what is the value of 3x23x - 2?

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Cevap: 10

Cevap

The value of 3x23x - 2 is 1010.
Multiplying the given linear equation by the least common denominator 12 yields 3(2x3)4(x5)=x+153(2x - 3) - 4(x - 5) = x + 15. Expanding both sides gives 6x94x+20=x+156x - 9 - 4x + 20 = x + 15, which simplifies to 2x+11=x+152x + 11 = x + 15, leading to x=4x = 4. Substituting x=4x = 4 into 3x23x - 2 gives 3(4)2=103(4) - 2 = 10.

Adım Adım Çözüm

1
Clear the denominators by multiplying both sides of the equation by the least common multiple of 4, 3, and 12, which is 12.
12(2x34)12(x53)=12(x+1512)    3(2x3)4(x5)=x+1512 \cdot \left(\frac{2x - 3}{4}\right) - 12 \cdot \left(\frac{x - 5}{3}\right) = 12 \cdot \left(\frac{x + 15}{12}\right) \implies 3(2x - 3) - 4(x - 5) = x + 15
Eliminating fractions simplifies the algebraic manipulation.
2
Distribute the coefficients through the terms in parentheses, paying careful attention to the negative sign on the second term.
6x94x+20=x+156x - 9 - 4x + 20 = x + 15
Distributing 4-4 across (x5)(x - 5) yields 4x+20-4x + 20.
3
Combine like terms on the left side of the equation.
2x+11=x+152x + 11 = x + 15
Grouping variable terms (6x4x=2x)(6x - 4x = 2x) and constant terms (9+20=11)(-9 + 20 = 11).
4
Isolate the variable xx by subtracting xx and 1111 from both sides.
x=4x = 4
Solves the linear equation for xx.
5
Substitute x=4x = 4 into the target expression 3x23x - 2.
3(4)2=122=103(4) - 2 = 12 - 2 = 10
Calculates the final answer requested in the stem.

Anahtar Kavram

Linear Equations with Fractional Coefficients
Soru 50Soru

The processing times for a specific type of database query on a server cluster are normally distributed with a mean of 180180 milliseconds and a standard deviation of 2525 milliseconds. Which of the following statements must be true? Indicate all such statements.

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Cevap: Approximately 68%68\% of the query processing times are between 155155 milliseconds and 205205 milliseconds.; A query processing time of 230230 milliseconds corresponds to a zz-score of +2.0+2.0.; A query processing time of 205205 milliseconds corresponds to approximately the 84th84\text{th} percentile rank.

Cevap

The correct statements are those asserting that approximately 68% of processing times lie between 155 ms and 205 ms, that a processing time of 230 ms corresponds to a z-score of +2.0, and that 205 ms corresponds to approximately the 84th percentile rank.
For a normal distribution with mean μ=180\mu = 180 and standard deviation σ=25\sigma = 25: (1) The interval μ±1σ=[155,205]\mu \pm 1\sigma = [155, 205] contains approximately 68%68\% of all observations. (2) A score of 230230 ms has a zz-score of 23018025=+2.0\frac{230-180}{25} = +2.0. (3) A score of 205205 ms corresponds to z=+1.0z = +1.0, which accumulates 50%50\% (area below mean) +34%+ 34\% (area between mean and +1σ+1\sigma) = 84%84\% percentile rank.

Adım Adım Çözüm

1
Evaluate the 1 standard deviation interval
μ±1σ=180±25=[155,205]\mu \pm 1\sigma = 180 \pm 25 = [155, 205] ms
The 68-95-99.7 empirical rule states that approximately 68% of observations in a normal distribution fall within 1 standard deviation of the mean.
2
Calculate the z-score for a query processing time of 230 ms
z=23018025=5025=+2.0z = \frac{230 - 180}{25} = \frac{50}{25} = +2.0
The standard score formula z=xμσz = \frac{x - \mu}{\sigma} measures how many standard deviations an observation is above or below the mean.
3
Determine the percentile rank for 205 ms and 155 ms
For 205 ms (z=+1z = +1), percentile = 50%+34%=84%50\% + 34\% = 84\%. For 155 ms (z=1z = -1), percentile = 50%34%=16%50\% - 34\% = 16\%.
50% of the distribution lies below the mean. For z=+1z = +1, add the 34% between mean and z=+1z = +1. For z=1z = -1, subtract the 34% from 50%.
4
Evaluate relative percentage change versus standard deviation
A 1 standard deviation increase (2525 ms) above the mean (180180 ms) equals an increase of 2518013.89%\frac{25}{180} \approx 13.89\%.
Standard deviation measures absolute dispersion in the units of the variable, not a percentage of the mean.

Anahtar Kavram

Empirical Rule, z-Score Calculation, and Percentile Ranks in Normal Distributions
Soru 51Soru

A sequence a1,a2,a3,a_1, a_2, a_3, \dots is defined by an=1n+n+2a_n = \frac{1}{\sqrt{n} + \sqrt{n+2}} for all positive integers nn. If S=n=198anS = \sum_{n=1}^{98} a_n, which of the following is closest to the value of SS when rounded to the nearest tenth?

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Cevap: 8.8

Cevap

The value of SS rounded to the nearest tenth is 8.8.
The term ana_n simplifies to n+2n2\frac{\sqrt{n+2} - \sqrt{n}}{2} upon rationalizing the denominator. Summing from n=1n=1 to 9898 causes all middle terms to cancel out, leaving 99+100122\frac{\sqrt{99} + \sqrt{100} - \sqrt{1} - \sqrt{2}}{2}. Substituting 100=10\sqrt{100} = 10, 1=1\sqrt{1} = 1, 999.95\sqrt{99} \approx 9.95, and 21.41\sqrt{2} \approx 1.41 gives approximately 8.778.77, which rounds to 8.8.

Adım Adım Çözüm

1
Rationalize the general term ana_n
an=1n+n+2n+2nn+2n=n+2n(n+2)n=n+2n2a_n = \frac{1}{\sqrt{n} + \sqrt{n+2}} \cdot \frac{\sqrt{n+2} - \sqrt{n}}{\sqrt{n+2} - \sqrt{n}} = \frac{\sqrt{n+2} - \sqrt{n}}{(n+2) - n} = \frac{\sqrt{n+2} - \sqrt{n}}{2}
Eliminating radicals from the denominator reveals the underlying telescoping structure of the sequence.
2
Expand the summation S=n=198anS = \sum_{n=1}^{98} a_n
S=12[(31)+(42)+(53)++(9997)+(10098)]S = \frac{1}{2} \left[ (\sqrt{3} - \sqrt{1}) + (\sqrt{4} - \sqrt{2}) + (\sqrt{5} - \sqrt{3}) + \dots + (\sqrt{99} - \sqrt{97}) + (\sqrt{100} - \sqrt{98}) \right]
Writing out initial and final terms demonstrates which terms cancel.
3
Simplify the telescoping sum
S=99+100122=99+10122=9+9922S = \frac{\sqrt{99} + \sqrt{100} - \sqrt{1} - \sqrt{2}}{2} = \frac{\sqrt{99} + 10 - 1 - \sqrt{2}}{2} = \frac{9 + \sqrt{99} - \sqrt{2}}{2}
All intermediate terms cancel out, leaving two positive boundary terms and two negative boundary terms.
4
Estimate square root values and perform rounding
Since 999.94987\sqrt{99} \approx 9.94987 and 21.41421\sqrt{2} \approx 1.41421, S9+9.949871.414212=17.535662=8.767838.8S \approx \frac{9 + 9.94987 - 1.41421}{2} = \frac{17.53566}{2} = 8.76783 \approx 8.8
Evaluating the radicals to two decimal places allows accurate rounding to the nearest tenth.

Anahtar Kavram

Telescoping Series Summation and Square Root Estimation
Soru 52Soru

If x>1x > 1 and xx=x2\sqrt{x^{\sqrt{x}}} = x^2, what is the value of xx?

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Cevap: 1616

Cevap

16
By rewriting the square root as an exponent of 1/21/2, the left side becomes xx2x^{\frac{\sqrt{x}}{2}}. Since the base xx is greater than 1, set the exponents equal to each other: x2=2\frac{\sqrt{x}}{2} = 2, which gives x=4\sqrt{x} = 4. Squaring both sides yields x=16x = 16.

Adım Adım Çözüm

1
Express the radical on the left side of the equation as a fractional exponent.
xx=(xx)12=xx2\sqrt{x^{\sqrt{x}}} = (x^{\sqrt{x}})^{\frac{1}{2}} = x^{\frac{\sqrt{x}}{2}}
The square root rule states that ak=a1k\sqrt[k]{a} = a^{\frac{1}{k}}.
2
Set the exponent of the left side equal to the exponent of the right side.
x2=2\frac{\sqrt{x}}{2} = 2
Since the bases are equal (x>1x > 1), their corresponding exponents must be equal.
3
Solve for x\sqrt{x} by multiplying both sides by 2.
x=4\sqrt{x} = 4
Isolating the radical term allows determination of the root value.
4
Square both sides to solve for xx.
x=42=16x = 4^2 = 16
Squaring a principal square root yields the underlying radicand.

Anahtar Kavram

Combining Fractional Exponents and Radical Expressions
Soru 53Soru

A renewable energy facility distributes stored electricity among three battery banks: Bank 1, Bank 2, and Bank 3. Initially, the ratio of the energy stored in Bank 1 to Bank 2 to Bank 3 is 3:4:53 : 4 : 5.

To balance the system, two sequential transfers of energy are performed without any energy loss:
1. Energy is transferred from Bank 3 to Bank 1 such that the ratio of the energy in Bank 1 to Bank 2 becomes 5:45 : 4.
2. Energy is then transferred from Bank 2 to Bank 3 such that the ratio of the energy in Bank 2 to Bank 3 becomes 1:41 : 4.

If Bank 3 contains 60 MWh60\text{ MWh} more energy after the second transfer than it did initially, what was the total amount of energy, in MWh, stored across all three battery banks?

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Cevap: 1,200 MWh1,200\text{ MWh}

Cevap

The total energy stored across all three battery banks is 1,200 MWh1,200\text{ MWh}.
The correct answer is 1,200 MWh1,200\text{ MWh}. By setting up algebraic expressions for the energy in each bank relative to total energy TT, we track how each transfer modifies individual bank totals while conserving total energy. The intermediate transfer reduces Bank 3 from 2560T\frac{25}{60}T to 1560T\frac{15}{60}T, and the subsequent transfer increases it to 2860T\frac{28}{60}T. The resulting difference of 360T=120T\frac{3}{60}T = \frac{1}{20}T equals 60 MWh60\text{ MWh}, solving directly to T=1,200 MWhT = 1,200\text{ MWh}.

Adım Adım Çözüm

1
Express initial energy quantities in terms of total energy TT
Bank 1 = 312T\frac{3}{12}T, Bank 2 = 412T\frac{4}{12}T, Bank 3 = 512T=2560T\frac{5}{12}T = \frac{25}{60}T
The ratio 3:4:53 : 4 : 5 sums to 1212 total parts.
2
Calculate energy amounts after the first transfer (Bank 3 to Bank 1)
Bank 2 remains 412T\frac{4}{12}T; Bank 1 becomes 512T\frac{5}{12}T; Bank 3 becomes T512T412T=312TT - \frac{5}{12}T - \frac{4}{12}T = \frac{3}{12}T
The new ratio of Bank 1 to Bank 2 is 5:45 : 4, and Bank 2's energy did not change.
3
Calculate energy amounts after the second transfer (Bank 2 to Bank 3)
Combined energy in Banks 2 and 3 = 412T+312T=712T\frac{4}{12}T + \frac{3}{12}T = \frac{7}{12}T. Final Bank 3 = 45×712T=2860T\frac{4}{5} \times \frac{7}{12}T = \frac{28}{60}T
Bank 1 remains unchanged at 512T\frac{5}{12}T. The remaining energy is divided between Bank 2 and Bank 3 in a 1:41 : 4 ratio.
4
Determine the net change in Bank 3 and solve for total energy TT
Net change = 2860T2560T=360T=120T\frac{28}{60}T - \frac{25}{60}T = \frac{3}{60}T = \frac{1}{20}T. Since 120T=60 MWh\frac{1}{20}T = 60\text{ MWh}, T=1,200 MWhT = 1,200\text{ MWh}
Bank 3 ended with 60 MWh60\text{ MWh} more than its initial amount.

Anahtar Kavram

Multi-stage ratio rebalancing and conservation of total quantity
Soru 54Soru
For all real numbers xx such that x3x \neq 3 and x5x \neq -5, the algebraic expression
(x29)24(x3)2(x3)(x+5)\frac{(x^2 - 9)^2 - 4(x - 3)^2}{(x - 3)(x + 5)}
can be simplified to the equivalent polynomial expression x2+ax+bx^2 + ax + b, where aa and bb are constants. What is the value of a+ba + b?
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Cevap: -5

Cevap

The value of a+ba + b is 5-5.
Factoring the numerator yields (x3)2(x+1)(x+5)(x - 3)^2(x + 1)(x + 5). Canceling the common factors (x3)(x - 3) and (x+5)(x + 5) with the denominator simplifies the expression to (x3)(x+1)=x22x3(x - 3)(x + 1) = x^2 - 2x - 3. Comparing this to x2+ax+bx^2 + ax + b identifies a=2a = -2 and b=3b = -3, giving a sum of a+b=5a + b = -5.

Adım Adım Çözüm

1
Factor the numerator by recognizing (x29)=(x3)(x+3)(x^2 - 9) = (x - 3)(x + 3)
(x29)24(x3)2=[(x3)(x+3)]24(x3)2=(x3)2(x+3)24(x3)2(x^2 - 9)^2 - 4(x - 3)^2 = [(x - 3)(x + 3)]^2 - 4(x - 3)^2 = (x - 3)^2 (x + 3)^2 - 4(x - 3)^2
Applying the difference of squares identity inside the squared term allows factoring out common factors.
2
Factor out (x3)2(x - 3)^2 from the numerator
(x3)2[(x+3)24](x - 3)^2 \left[ (x + 3)^2 - 4 \right]
Extracting the greatest common algebraic factor simplifies the remaining expression.
3
Apply difference of squares to (x+3)24(x + 3)^2 - 4
(x+3)222=((x+3)2)((x+3)+2)=(x+1)(x+5)(x + 3)^2 - 2^2 = ((x + 3) - 2)((x + 3) + 2) = (x + 1)(x + 5)
Recognizing (x+3)222(x + 3)^2 - 2^2 as A2B2A^2 - B^2 yields factored linear terms directly.
4
Substitute the fully factored numerator back into the rational expression and simplify
\frac{(x - 3)^2 (x + 1)(x + 5)}{(x - 3)(x + 5)} = (x - 3)(x + 1)
Canceling non-zero common factors (x3)(x - 3) and (x+5)(x + 5) simplifies the rational function.
5
Expand (x3)(x+1)(x - 3)(x + 1) and determine a+ba + b
(x3)(x+1)=x22x3(x - 3)(x + 1) = x^2 - 2x - 3, so a=2a = -2 and b=3b = -3. Therefore, a+b=2+(3)=5a + b = -2 + (-3) = -5.
Matching coefficients with x2+ax+bx^2 + ax + b gives a=2a = -2 and b=3b = -3.

Anahtar Kavram

Simplifying complex rational expressions through nested difference of squares factoring.
Soru 55Soru

Let pp and qq be integers such that p<0<qp < 0 < q, (1)p+(1)q=0(-1)^p + (-1)^q = 0, and p2q+pp^2 q + p is an even integer. Which of the following expressions must be negative?

Cevabı ve açıklamayı göster

Cevap: pqp^q

Cevap

pqp^q
From (1)p+(1)q=0(-1)^p + (-1)^q = 0, pp and qq must have opposite parities. Factoring p2q+pp^2 q + p into p(pq+1)p(pq + 1) shows that if pp were odd, qq would be even, leading to an odd product odd×odd=odd\text{odd} \times \text{odd} = \text{odd}. Because p2q+pp^2 q + p is given as even, pp must be an even integer and qq must be an odd integer. Given p<0p < 0, pp is a negative even integer, and qq is a positive odd integer. The expression pqp^q represents a negative base raised to an odd exponent, which is guaranteed to be negative.

Adım Adım Çözüm

1
Determine the parities of pp and qq using the equation (1)p+(1)q=0(-1)^p + (-1)^q = 0.
One of pp or qq is even and the other is odd.
For the sum (1)p+(1)q(-1)^p + (-1)^q to equal 00, one term must equal 11 and the other must equal 1-1, meaning pp and qq have opposite parities.
2
Analyze the parity of p2q+p=p(pq+1)p^2 q + p = p(pq + 1) to determine which variable is even.
pp must be even, and qq must be odd.
If pp were odd, qq would be even, making pqpq even, pq+1pq+1 odd, and p(pq+1)p(pq+1) odd. Since p2q+pp^2 q + p is even, pp must be even and qq must be odd.
3
Evaluate the sign of pqp^q using sign rules for exponents.
pq<0p^q < 0
pp is negative (p<0p < 0) and qq is a positive odd integer. A negative number raised to an odd power is always negative.

Anahtar Kavram

Parity and sign rules for negative bases and integer exponents
Soru 56Soru
Consider the system of linear equations in two variables xx and yy:
2x3y=a4x6y=b\begin{aligned} 2x - 3y &= a \\ 4x - 6y &= b \end{aligned}
where aa and bb are real constants. Which of the following statements MUST be true? Select all that apply.

Geçerli olan tümünü seçin

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Cevap: If b=2ab = 2a, the system has infinitely many solutions.; If b2ab \neq 2a, the system has no solution.; If b=2a+1b = 2a + 1, the lines represented by the equations in the xyxy-plane are parallel and distinct.

Cevap

The correct statements are: 'If b=2ab = 2a, the system has infinitely many solutions.', 'If b2ab \neq 2a, the system has no solution.', and 'If b=2a+1b = 2a + 1, the lines represented by the equations in the xyxy-plane are parallel and distinct.'
Statements asserting that the system has infinitely many solutions when b=2ab = 2a, no solution when b2ab \neq 2a, and parallel distinct lines when b=2a+1b = 2a + 1 are all mathematically sound. Multiplying the first equation by 2 reveals that the left sides are identical (4x6y4x - 6y). Equality of the right sides (b=2ab = 2a) makes the lines identical, whereas inequality (b2ab \neq 2a) makes them parallel and distinct.

Adım Adım Çözüm

1
Analyze the coefficients of the system of equations.
The coefficients of xx and yy in the second equation (44 and 6-6) are exactly twice the coefficients of xx and yy in the first equation (22 and 3-3).
Comparing coefficient ratios determines line relationships (slopes).
2
Multiply the first equation by 2.
2(2x3y)=2(a)    4x6y=2a2(2x - 3y) = 2(a) \implies 4x - 6y = 2a.
This puts the left side of the first equation in exact alignment with the second equation (4x6y=b4x - 6y = b).
3
Evaluate the condition for infinitely many solutions.
If b=2ab = 2a, the two equations become 4x6y=2a4x - 6y = 2a and 4x6y=2a4x - 6y = 2a, which describe the exact same line, giving infinitely many solutions.
Coincident lines intersect at every point along the line.
4
Evaluate the condition for no solution.
If b2ab \neq 2a, subtracting the equations gives 0=b2a00 = b - 2a \neq 0, a contradiction. Hence, the lines are parallel and distinct, meaning no solution exists.
Distinct parallel lines never intersect.
5
Examine specific cases such as b=2a+1b = 2a + 1 and a=0,b=0a=0, b=0.
For b=2a+1b = 2a + 1, since 2a+12a2a + 1 \neq 2a, b2ab \neq 2a, confirming parallel distinct lines. For a=0,b=0a=0, b=0, b=2(0)=0b = 2(0) = 0, which yields infinitely many solutions rather than a unique solution.
Verifies specific option claims.

Anahtar Kavram

Systems of Linear Equations (Solvability and Geometric Interpretation)
Soru 57Soru

If xx is a real number such that 16x+34=8x1\sqrt[4]{16^{x+3}} = 8^{x-1}, what is the value of xx?

Cevabı ve açıklamayı göster

Cevap: 3

Cevap

The value of xx is 33.
To solve 16x+34=8x1\sqrt[4]{16^{x+3}} = 8^{x-1}, express both sides with the base 2. The left side simplifies to (24)x+34=24(x+3)4=2x+3\sqrt[4]{(2^4)^{x+3}} = 2^{\frac{4(x+3)}{4}} = 2^{x+3}. The right side simplifies to (23)x1=23(x1)=23x3(2^3)^{x-1} = 2^{3(x-1)} = 2^{3x-3}. Equating the exponents yields x+3=3x3x + 3 = 3x - 3, which solves to 2x=62x = 6, giving x=3x = 3.

Adım Adım Çözüm

1
Rewrite 16 and 8 using prime base 2
16=2416 = 2^4 and 8=238 = 2^3
Converting terms to a common base allows direct comparison of exponents.
2
Simplify the left-hand side radical expression
16x+34=(24)x+34=24(x+3)4=2x+3\sqrt[4]{16^{x+3}} = \sqrt[4]{(2^4)^{x+3}} = 2^{\frac{4(x+3)}{4}} = 2^{x+3}
The nn-th root amn\sqrt[n]{a^m} is equivalent to am/na^{m/n}.
3
Simplify the right-hand side exponential expression
8x1=(23)x1=23(x1)=23x38^{x-1} = (2^3)^{x-1} = 2^{3(x-1)} = 2^{3x-3}
Applying the exponent power rule (am)n=amn(a^m)^n = a^{m \cdot n} requires multiplying 33 by (x1)(x - 1).
4
Equate the exponents and solve for xx
x+3=3x3    2x=6    x=3x + 3 = 3x - 3 \implies 2x = 6 \implies x = 3
When au=ava^u = a^v for a>0a > 0 and a1a \neq 1, it follows that u=vu = v.

Anahtar Kavram

Solving exponential equations using prime base factorization and radical conversion rules
Soru 58Soru

If the pair (x,y)(x, y) satisfies the system of linear equations below, what is the value of xyx - y?

3x5y=142x+7y=1\begin{aligned} 3x - 5y &= 14 \\ 2x + 7y &= -1 \end{aligned}
Cevabı ve açıklamayı göster

Cevap: 4

Cevap

The value of xyx - y is 44.
Solving the system of linear equations by elimination gives x=3x = 3 and y=1y = -1. Substituting these values into the target expression xyx - y yields 3(1)=3+1=43 - (-1) = 3 + 1 = 4.

Adım Adım Çözüm

1
Eliminate one variable using the elimination method.
Multiply the first equation by 22 and the second equation by 33:
6x10y=286x - 10y = 28
6x+21y=36x + 21y = -3
Creating matching coefficients for xx allows elimination of xx by subtraction.
2
Subtract the first modified equation from the second modified equation to solve for yy.
(6x+21y)(6x10y)=328(6x + 21y) - (6x - 10y) = -3 - 28
31y=31    y=131y = -31 \implies y = -1
Subtracting eliminates xx, isolating yy.
3
Substitute y=1y = -1 back into one of the original equations to solve for xx.
3x5(1)=14    3x+5=14    3x=9    x=33x - 5(-1) = 14 \implies 3x + 5 = 14 \implies 3x = 9 \implies x = 3
Plugging in yy allows direct solution for xx.
4
Evaluate the requested expression xyx - y.
xy=3(1)=3+1=4x - y = 3 - (-1) = 3 + 1 = 4
Subtracting a negative value is equivalent to adding its positive value.

Anahtar Kavram

Solving systems of linear equations using elimination and evaluating algebraic expressions.
Tahmini Süre:1m 30s
Soru 59Soru

The quadratic equation x2kx+36=0x^2 - kx + 36 = 0, where kk is a positive constant, has two distinct real roots r1r_1 and r2r_2 such that r2r1=5r_2 - r_1 = 5. What is the value of kk?

Cevabı ve açıklamayı göster

Cevap: 13

Cevap

The value of kk is 13.
According to Vieta's formulas, for the quadratic equation x2kx+36=0x^2 - kx + 36 = 0, the sum of the roots is r1+r2=kr_1 + r_2 = k and the product of the roots is r1r2=36r_1 r_2 = 36. Using the identity (r2r1)2=(r1+r2)24r1r2(r_2 - r_1)^2 = (r_1 + r_2)^2 - 4r_1 r_2, we substitute the known values r2r1=5r_2 - r_1 = 5, r1+r2=kr_1 + r_2 = k, and r1r2=36r_1 r_2 = 36. This gives 52=k24(36)5^2 = k^2 - 4(36), which simplifies to 25=k214425 = k^2 - 144. Solving for k2k^2 gives k2=169k^2 = 169. Since kk is specified as a positive constant, k=13k = 13.

Adım Adım Çözüm

1
Apply Vieta's formulas to the given quadratic equation
The sum of the roots is r1+r2=kr_1 + r_2 = k and the product of the roots is r1r2=36r_1 r_2 = 36.
For any quadratic equation ax2+bx+c=0ax^2 + bx + c = 0, the sum of roots is b/a-b/a and the product of roots is c/ac/a.
2
Relate the difference of the roots to their sum and product
(r2r1)2=(r1+r2)24r1r2(r_2 - r_1)^2 = (r_1 + r_2)^2 - 4r_1 r_2
Expanding both sides shows that r222r1r2+r12=r12+2r1r2+r224r1r2r_2^2 - 2r_1 r_2 + r_1^2 = r_1^2 + 2r_1 r_2 + r_2^2 - 4r_1 r_2, which is an algebraic identity.
3
Substitute the known values into the identity
52=k24(36)    25=k21445^2 = k^2 - 4(36) \implies 25 = k^2 - 144
We are given that r2r1=5r_2 - r_1 = 5, r1r2=36r_1 r_2 = 36, and r1+r2=kr_1 + r_2 = k.
4
Solve for the positive constant kk
k2=169    k=13k^2 = 169 \implies k = 13
Adding 144 to both sides gives k2=169k^2 = 169. Taking the positive square root because k>0k > 0 yields k=13k = 13.

Anahtar Kavram

Vieta's Formulas and Root Difference Identity
Soru 60Soru

Read the passage below:

While early twentieth-century art conservators viewed the micro-cracking in Renaissance oil paintings as an alarming sign of (i)________, subsequent micro-analytical studies revealed that these fissures actually release internal structural tension. Far from presaging imminent structural failure, the phenomenon is largely (ii)________, serving to stabilize the paint layers against environmental fluctuations over centuries. Consequently, aggressive interventionist attempts to artificially seal these micro-cracks often prove not merely redundant but outright (iii)________, inducing synthetic stresses that accelerate physical flaking.

Which of the following combinations of words best completes the blanks in the passage to maintain logical and contextual coherence?

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Cevap: (i) degradation, (ii) benign, (iii) deleterious

Cevap

(i) degradation, (ii) benign, (iii) deleterious
The combination of 'degradation', 'benign', and 'deleterious' satisfies all local syntax requirements and maintains overall thematic coherence across the three sentences. 'Degradation' fits the alarm of conservators, 'benign' reflects the harmless nature demonstrated by scientific analysis, and 'deleterious' matches the destructive consequences of intervention.

Adım Adım Çözüm

1
Analyze Blank (i) using sentence clues.
Blank (i) describes what early conservators feared micro-cracking represented. The phrase 'alarming sign of' points to a negative physical process, making 'degradation' the logical choice.
The sentence sets up an initial misconception of damage before the second clause introduces micro-analytical evidence.
2
Analyze Blank (ii) using cross-sentence structural signals.
The phrase 'Far from presaging imminent structural failure' establishes a contrast. Since it is not indicative of failure and actually serves to 'stabilize', the phenomenon is 'benign'.
The contrast signal 'Far from...' requires a term that opposes 'imminent structural failure'.
3
Analyze Blank (iii) based on consequence and degree.
The sentence begins with 'Consequently' and uses the intensifying frame 'not merely redundant but outright...'. Because interventions 'induce synthetic stresses' and 'accelerate physical flaking', the outcome is harmful, fitting 'deleterious'.
The discourse marker 'not merely X but outright Y' requires Y to be a stronger, more severe escalation of negative impact than simple redundancy.

Anahtar Kavram

Cross-Sentence Contextual Coherence in Multi-Blank Text Completion
Tahmini Süre:1m 30s
ÖncekiSayfa 3 / 107Sonraki
Tüm alıştırma soruları — GRE General Test | Examkin