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Zorluk: OrtaAngles, Parallel Lines, and Polygons

The measures of the exterior angles of an convex hexagon are given as xx^\circ, (x+10)(x + 10)^\circ, (2x5)(2x - 5)^\circ, (x+25)(x + 25)^\circ, (2x+15)(2x + 15)^\circ, and (x5)(x - 5)^\circ. What is the measure of the largest interior angle of the hexagon?

  1. A
    9595^\circ
  2. B
    8585^\circ
  3. 145145^\circCevap
  4. D
    135135^\circ

Cevap

145145^\circ
The sum of all exterior angles of a convex polygon is 360360^\circ. Summing the given expressions yields 8x+40=3608x + 40 = 360^\circ, which gives x=40x = 40^\circ. Evaluating each exterior angle shows that the smallest exterior angle is (405)=35(40 - 5)^\circ = 35^\circ. Since interior and exterior angles on a straight line are supplementary, the largest interior angle is 18035=145180^\circ - 35^\circ = 145^\circ.

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1
Set up equation using the sum of exterior angles
x+(x+10)+(2x5)+(x+25)+(2x+15)+(x5)=360x + (x + 10) + (2x - 5) + (x + 25) + (2x + 15) + (x - 5) = 360^\circ
The sum of the exterior angles of any convex polygon is always 360360^\circ.
2
Simplify and solve for xx
8x+40=360    8x=320    x=408x + 40 = 360 \implies 8x = 320 \implies x = 40^\circ
Combining like terms gives 8x+40=3608x + 40 = 360.
3
Find the smallest exterior angle
x5=405=35x - 5 = 40 - 5 = 35^\circ
The largest interior angle corresponds to the smallest exterior angle because an interior angle and its adjacent exterior angle add up to 180180^\circ.
4
Calculate the largest interior angle
18035=145180^\circ - 35^\circ = 145^\circ
Subtracting the smallest exterior angle from 180180^\circ yields the largest interior angle.

Anahtar Kavram

Exterior and Interior Angle Relationship in Polygons
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