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Zorluk: ZorAngles, Parallel Lines, and Polygons

Three of the interior angles of a convex polygon are each 120120^\circ, while the remaining interior angles are each 160160^\circ. How many sides does the polygon have?

Cevap: 12 sides

Cevap

The polygon has 12 sides.
The sum of the interior angles of an nn-sided polygon is (n2)×180(n - 2) \times 180^\circ. From the problem, the sum of the angles is 3×120+(n3)×160=160n1203 \times 120^\circ + (n - 3) \times 160^\circ = 160^\circ n - 120^\circ. Equating 180(n2)180^\circ(n - 2) to 160n120160^\circ n - 120^\circ gives 180n360=160n120180^\circ n - 360^\circ = 160^\circ n - 120^\circ, which simplifies to 20n=24020^\circ n = 240^\circ, yielding n=12n = 12.

Adım Adım Çözüm

1
Write down the standard formula for the sum of interior angles of an nn-sided convex polygon.
Sum of interior angles = (n2)×180(n - 2) \times 180^\circ.
Any nn-sided convex polygon can be split into (n2)(n-2) triangles, each having an interior angle sum of 180180^\circ.
2
Express the total sum of interior angles using the given values.
Sum = 3(120)+(n3)(160)=360+160n480=160n1203(120^\circ) + (n - 3)(160^\circ) = 360^\circ + 160^\circ n - 480^\circ = 160^\circ n - 120^\circ.
Three angles are 120120^\circ, so the remaining (n3)(n - 3) angles must each equal 160160^\circ.
3
Equate the theoretical sum to the calculated sum.
180(n2)=160n120    180n360=160n120180^\circ(n - 2) = 160^\circ n - 120^\circ \implies 180^\circ n - 360^\circ = 160^\circ n - 120^\circ.
Both expressions represent the total interior angle sum of the same polygon.
4
Solve the equation for the number of sides nn.
20n=240    n=1220^\circ n = 240^\circ \implies n = 12.
Subtracting 160n160^\circ n from both sides and adding 360360^\circ yields 20n=24020^\circ n = 240^\circ.

Anahtar Kavram

Sum of Interior Angles of a Polygon
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