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Zorluk: OrtaAngles, Parallel Lines, and Polygons

In a regular polygon, the measure of each interior angle is 132132^\circ greater than the measure of each exterior angle. How many sides does this polygon have?

Cevap: 15 sides

Cevap

The polygon has 15 sides.
Since the interior angle II and exterior angle EE of a regular polygon sum to 180180^\circ (I+E=180I + E = 180^\circ) and their given difference is IE=132I - E = 132^\circ, subtracting the difference equation from the sum equation gives 2E=482E = 48^\circ, which simplifies to E=24E = 24^\circ. The number of sides is n=360E=36024=15n = \frac{360^\circ}{E} = \frac{360^\circ}{24^\circ} = 15.

Adım Adım Çözüm

1
Set up the linear pair equation for interior and exterior angles
I+E=180I + E = 180^\circ
An interior angle and its adjacent exterior angle at any vertex of a polygon lie on a straight line and sum to 180180^\circ.
2
Set up the given condition equation
IE=132I - E = 132^\circ
The question states that each interior angle is 132132^\circ greater than each exterior angle.
3
Solve for the exterior angle EE
E=24E = 24^\circ
Subtracting IE=132I - E = 132^\circ from I+E=180I + E = 180^\circ yields 2E=482E = 48^\circ, giving E=24E = 24^\circ.
4
Calculate the number of sides nn
n=15n = 15
The sum of all exterior angles of any convex polygon is 360360^\circ, so n=360E=36024=15n = \frac{360^\circ}{E} = \frac{360^\circ}{24^\circ} = 15.

Anahtar Kavram

Interior and Exterior Angle Properties of Regular Polygons
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