Soru

Zorluk: OrtaMolecular Shapes, VSEPR Theory, and Hybridization

Match each chemical species to its correct molecular geometry and central atom hybridization state.

  • BeCl2BeCl_2Linear shape, spsp hybridization
  • BF3BF_3Trigonal planar shape, sp2sp^2 hybridization
  • CH4CH_4Tetrahedral shape, sp3sp^3 hybridization
  • SF6SF_6Octahedral shape, sp3d2sp^3d^2 hybridization

Cevap

BeCl2BeCl_2 matches Linear shape, spsp hybridization; BF3BF_3 matches Trigonal planar shape, sp2sp^2 hybridization; CH4CH_4 matches Tetrahedral shape, sp3sp^3 hybridization; SF6SF_6 matches Octahedral shape, sp3d2sp^3d^2 hybridization.
Each chemical species is matched to its corresponding molecular geometry and central atom hybridization based on the number of sigma bonds and lone pairs present on the central atom.

Adım Adım Çözüm

1
Determine steric number for BeCl2BeCl_2
BeBe forms 2 single bonds with 0 lone pairs, giving a steric number of 2 (spsp hybridization, linear shape).
Two electron domains arrange at 180° to minimize electron pair repulsion.
2
Determine steric number for BF3BF_3
BB forms 3 single bonds with 0 lone pairs, giving a steric number of 3 (sp2sp^2 hybridization, trigonal planar shape).
Three electron domains arrange at 120° in a single plane.
3
Determine steric number for CH4CH_4
CC forms 4 single bonds with 0 lone pairs, giving a steric number of 4 (sp3sp^3 hybridization, tetrahedral shape).
Four electron domains arrange symmetrically in three-dimensional space at 109.5°.
4
Determine steric number for SF6SF_6
SS forms 6 single bonds with 0 lone pairs, giving a steric number of 6 (sp3d2sp^3d^2 hybridization, octahedral shape).
Six electron domains arrange symmetrically at 90° axial/equatorial positions.

Anahtar Kavram

Valence Shell Electron Pair Repulsion (VSEPR) Theory and Orbital Hybridization
Tahmini Süre:1m 0s
Bu soruyu puanla