Tüm alıştırma soruları

13931 soru

Soru 4001Soru

A cocoa processing firm in Nigeria faces various market developments and regulatory shifts. Match each economic scenario on the left with its corresponding impact on the supply of processed cocoa on the right.

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Öğeler

Introduction of advanced automated processing technology that increases output efficiency per worker.
A sharp rise in the market selling price of processed cocoa flour.
An increase in the import duty levied on essential processing chemicals.
Provision of a direct per-unit financial grant by the government to local cocoa processors.

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Cevap

Advanced automated processing technology matches with a rightward shift of the supply curve driven by technological advancement. A sharp rise in market selling price matches with an upward movement along the existing supply curve indicating an increase in quantity supplied. An increase in import duty on processing chemicals matches with a leftward shift of the supply curve caused by higher input costs. Provision of a direct per-unit financial grant matches with a rightward shift resulting from reduced unit costs via state intervention.
Each scenario correctly applies the economic principles of supply determinants: price variations of the product itself produce movements along the curve, while non-price parameters like technological innovation, input taxation, and government subsidies shift the supply curve in directions dictated by their net effect on production costs.

Adım Adım Çözüm

1
Differentiate between factors that shift the supply curve and factors that cause movement along the supply curve.
Identified that own-price changes alter quantity supplied (movement along the curve), while non-price determinants (technology, input prices, government taxes/subsidies) alter supply (shift of the curve).
The law of supply establishes price-quantity relationships along a given schedule, whereas external non-price factors re-establish a completely new supply schedule.
2
Evaluate the effect of technological innovation.
Technological progress increases output per unit of input, lowering marginal cost and shifting the supply curve rightward.
Firms can produce more efficiently at existing market prices.
3
Evaluate the effect of a change in own-price.
An increase in the commodity's selling price leads to an upward movement along the current curve.
Producers expand output along their existing production frontier to capitalize on higher profit margins per unit.
4
Analyze government policies and input price changes.
Increased duties on inputs raise costs (shifting supply leftward), while subsidies reduce costs (shifting supply rightward).
Taxes act as cost additions whereas subsidies act as cost reductions.

Anahtar Kavram

Distinction between Shifts in Supply and Movements along the Supply Curve
Soru 4002Soru

Chlorofluorocarbons (CFCs) released into the atmosphere diffuse into the stratosphere, where they are decomposed by intense solar ultraviolet radiation. Which active reactive species generated during this photolysis process directly catalyzes the catalytic breakdown of ozone (O3\text{O}_3) molecules?

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Cevap: Chlorine free radical (Cl\text{Cl}^\bullet)

Cevap

The chlorine free radical (Cl\text{Cl}^\bullet) released from the photolysis of chlorofluorocarbons directly catalyzes the depletion of stratospheric ozone molecules.
Under stratospheric ultraviolet (UV) irradiation, chlorofluorocarbon (CFC) molecules undergo homolytic cleavage to produce reactive chlorine free radicals (Cl\text{Cl}^\bullet). A chlorine radical attacks an ozone molecule (O3\text{O}_3) to form a chlorine monoxide radical (ClO\text{ClO}^\bullet) and a diatomic oxygen molecule (O2\text{O}_2). The chlorine monoxide radical subsequently reacts with atomic oxygen to regenerate the free chlorine radical (Cl\text{Cl}^\bullet). Because the radical is regenerated, it acts as a catalyst in the continuous breakdown of the protective ozone layer.

Adım Adım Çözüm

1
Identify the photolysis reaction of CFCs in the stratosphere.
Ultraviolet radiation breaks a C-Cl\text{C-Cl} bond in CFCs (e.g., CF2Cl2+hνCF2Cl+Cl\text{CF}_2\text{Cl}_2 + h\nu \rightarrow \text{CF}_2\text{Cl}^\bullet + \text{Cl}^\bullet), releasing reactive chlorine free radicals.
High-energy UV photons possess sufficient energy to cleave the chemical bond in the tropospheric-stable CFC molecules upon reaching the stratosphere.
2
Analyze the catalytic cycle of ozone destruction.
Cl+O3ClO+O2\text{Cl}^\bullet + \text{O}_3 \rightarrow \text{ClO}^\bullet + \text{O}_2 followed by ClO+OCl+O2\text{ClO}^\bullet + \text{O} \rightarrow \text{Cl}^\bullet + \text{O}_2.
The chlorine free radical acts as a true catalyst because it is regenerated at the end of the reaction cycle, allowing a single radical to destroy up to 100,000100,000 ozone molecules.
3
Distinguish between greenhouse gases and ozone-depleting catalysts.
CO2\text{CO}_2 and CH4\text{CH}_4 trap infrared heat (greenhouse effect), whereas Cl\text{Cl}^\bullet radicals chemically decompose ozone (ozone layer depletion).
Conflating global warming mechanisms with ozone depletion mechanisms is a common conceptual error.

Anahtar Kavram

Photolysis of CFCs and Catalytic Cycle of Ozone Layer Depletion
Soru 4003Soru

Match each of the following Balance of Payments transaction items with its correct account classification.

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Öğeler

Export of crude oil
Payment for international freight services
Foreign direct investment into domestic real estate

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Cevap

Export of crude oil matches Visible Trade Account; Payment for international freight services matches Invisible Trade Account; Foreign direct investment into domestic real estate matches Capital and Financial Account.
Tangible merchandise like crude oil is recorded in the visible trade section of the current account. Services such as shipping and freight are intangibles recorded in the invisible trade section of the current account. Financial movements such as foreign direct investments involve capital asset creation and belong to the capital and financial account.

Adım Adım Çözüm

1
Identify the nature of the transaction for Export of crude oil.
Crude oil is a physical, tangible commodity (merchandise).
Tangible exports and imports are classified as visible trade in the Current Account.
2
Identify the nature of the transaction for Freight services payment.
Shipping/freight is a service (intangible item).
Intangible service transactions are classified as invisible trade in the Current Account.
3
Identify the nature of Foreign direct investment.
FDI involves international capital movement and ownership of physical assets/capital.
Long-term investment flows and ownership of foreign assets belong to the Capital and Financial Account.

Anahtar Kavram

Structure of the Balance of Payments
Soru 4004Soru

A dominant firm operating in a non-collusive oligopoly currently sells its product at a prevailing market price of P0=N4,000P_0 = \text{N}4,000. The price elasticity of demand for its product is Ed=2.8|E_d| = 2.8 for prices above P0P_0, and Ed=0.35|E_d| = 0.35 for prices below P0P_0. If an automated production process reduces the firm's marginal cost from MC1=N2,500MC_1 = \text{N}2,500 to MC2=N2,100MC_2 = \text{N}2,100, and this new marginal cost line continues to intersect the vertical gap in the marginal revenue curve, how will the firm adjust its price and output to maximize profits?

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Cevap: Maintain both the current price at N4,000\text{N}4,000 and the existing output level, because the marginal cost shift remains within the discontinuous segment of the marginal revenue curve.

Cevap

The firm will maintain both its current price at N4,000\text{N}4,000 and its existing output level because the marginal cost reduction occurs entirely within the vertical discontinuity of its marginal revenue curve.
Under Paul Sweezy's kinked demand curve model, non-collusive oligopolists assume rivals will match price cuts but ignore price increases. This asymmetry creates a kink in the demand curve at the prevailing price and a corresponding vertical gap in the marginal revenue curve. Any change in marginal cost that stays within this gap leaves the profit-maximizing output and price unchanged, accounting for rigid prices in oligopolistic markets.

Adım Adım Çözüm

1
Analyze the demand curve structure based on rival behavior assumptions.
Above P0=N4,000P_0 = \text{N}4,000, demand is elastic (Ed=2.8|E_d| = 2.8) because rivals do not follow price increases. Below P0P_0, demand is inelastic (Ed=0.35|E_d| = 0.35) because rivals match price cuts.
Asymmetric rival responses create a kinked demand curve at the prevailing price P0P_0.
2
Determine the impact of the kinked demand curve on the Marginal Revenue (MRMR) curve.
The abrupt drop in price elasticity at P0P_0 creates a vertical gap (discontinuity) in the MRMR curve directly below the kink point.
MRMR is derived from demand elasticity; a sudden drop in elasticity causes a step down in MRMR values at that specific quantity.
3
Evaluate the effect of the reduction in Marginal Cost (MCMC).
The shift from MC1=N2,500MC_1 = \text{N}2,500 to MC2=N2,100MC_2 = \text{N}2,100 occurs within the vertical boundaries of the MRMR gap.
Since the MCMC curve still passes through the vertical MRMR gap, the condition MR=MCMR = MC remains fulfilled at the same output and price level, demonstrating organizational price rigidity.

Anahtar Kavram

Price Rigidity and Discontinuous Marginal Revenue in Oligopoly
Tahmini Süre:2m 0s
Soru 4005Soru

Match each organ of the Economic Community of West African States (ECOWAS) with its correct principal function.

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Öğeler

Authority of Heads of State and Government
Council of Ministers
ECOWAS Commission

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Cevap

Authority of Heads of State and Government matches the supreme decision-making organ determining general policy direction; Council of Ministers matches the body preparing meetings and making recommendations to the summit; ECOWAS Commission matches the permanent executive arm handling day-to-day administrative implementation.
The institutional framework of ECOWAS assigns distinct responsibilities: the Authority of Heads of State and Government is the supreme policy-making body, the Council of Ministers prepares proposals and oversees operational matters, and the ECOWAS Commission handles administrative execution.

Adım Adım Çözüm

1
Identify the highest political authority in ECOWAS.
The Authority of Heads of State and Government holds supreme decision-making authority.
It brings together national leaders to set high-level community policies.
2
Identify the ministerial advisory organ.
The Council of Ministers reviews policies and prepares agenda recommendations.
It acts as a preparatory body composed of member state ministers.
3
Identify the administrative organ.
The ECOWAS Commission carries out day-to-day administrative functions.
It operates as the civil service and executive secretariat of the organisation.

Anahtar Kavram

Institutional structure and organ functions of ECOWAS
Soru 4006Soru

Chidubem Ventures PLC has an authorized capital of ₦500,000 divided into 1,000,000 ordinary shares of 50k each. Out of these, 600,000 shares have been issued and fully paid-up. If the directors declare a dividend of 8% on ordinary share capital, what is the total dividend amount to be debited to the Profit and Loss Appropriation Account?

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Cevap: ₦24,000

Cevap

₦24,000
Dividends must be calculated strictly on the paid-up capital. The paid-up capital is 600,000 shares multiplied by ₦0.50 (50k), yielding ₦300,000. Computing 8% of ₦300,000 gives ₦24,000, which is the total dividend amount transferred from the Profit and Loss Appropriation Account.

Adım Adım Çözüm

1
Calculate total paid-up share capital
600,000 shares × ₦0.50 = ₦300,000
Dividends are paid only on shares actually issued and paid for, converted from kobo to Naira (50k = ₦0.50).
2
Calculate the total dividend declared
8% × ₦300,000 = ₦24,000
The declared dividend percentage is applied directly to the total paid-up ordinary share capital.

Anahtar Kavram

Dividend Calculation on Paid-Up Capital
Tahmini Süre:45s
Soru 4007Soru

An electronics wholesaler delivers 50 television sets to a retailer under an agreement stating that ownership remains with the wholesaler until the full price is paid in three monthly installments. Before making the first payment, the retailer sells 10 sets in the ordinary course of business to retail customers who buy them in good faith without knowledge of the retention-of-title clause. The retailer subsequently defaults on payment and becomes insolvent. Which of the following best explains the legal position regarding title to the 10 sets and the remedies available under the Sale of Goods Act?

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Cevap: The retail customers obtain valid title under the 'buyer in possession' exception to nemo dat, leaving the wholesaler with a personal remedy to sue the retailer for the contract price.

Cevap

The retail customers acquire valid title under the buyer in possession exception to the nemo dat rule, leaving the wholesaler with a personal remedy against the retailer for the contract price.
Under Section 25 of the Sale of Goods Act, when a buyer who has bought or agreed to buy goods obtains possession of them with the seller's consent, delivering those goods under a sale to an innocent third party acting in good faith confers valid legal title on that third party. Consequently, the original seller loses the right to repossess those goods and must rely on a personal remedy (suing the defaulting buyer for the contract price).

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1
Analyze the general rule of title transfer (Nemo Dat Quod Non Habet).
Normally, a seller cannot transfer a better title than they possess, so a buyer under a retention-of-title agreement lacks full legal title until payment.
Establishing the baseline statutory rule under the Sale of Goods Act.
2
Identify statutory exceptions to the Nemo Dat rule.
Where a buyer has obtained possession of goods with the consent of the seller ('buyer in possession'), any sale by that buyer to an innocent third party acting in good faith without notice delivers valid title.
Determining whether third-party buyers are protected under commercial law.
3
Evaluate the seller's available remedies under the circumstances.
Because title has validly passed to the third-party retail customers, the original unpaid seller loses real rights over those 10 sets (right of lien or repossession) and is limited to personal remedies against the defaulting buyer for the price of the goods.
Matching statutory buyer/seller remedies to the specific factual outcome.

Anahtar Kavram

Nemo Dat Quod Non Habet Exceptions and Remedies of the Unpaid Seller
Soru 4008Soru

A metal plate is initially in the form of a rectangle ABCDABCD measuring 14 cm14\text{ cm} by 10 cm10\text{ cm}, where AB=14 cmAB = 14\text{ cm}. A semicircular piece with diameter ABAB is cut out from side ABAB. On the opposite side CDCD, an isosceles triangular plate with base CDCD and height 24 cm24\text{ cm} is attached externally. Taking π=227\pi = \frac{22}{7}, what is the total area of the resulting plate in cm2\text{cm}^2?

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Cevap: 231

Cevap

The total area of the resulting plate is 231 cm2231\text{ cm}^2.
The net area of the plate is found by starting with the area of the rectangle (140 cm2140\text{ cm}^2), subtracting the area of the semicircular cutout (77 cm277\text{ cm}^2), and adding the area of the attached isosceles triangle (168 cm2168\text{ cm}^2), resulting in 14077+168=231 cm2140 - 77 + 168 = 231\text{ cm}^2.

Adım Adım Çözüm

1
Calculate the area of the original rectangle ABCD
140 cm²
The area of a rectangle is calculated as length×width=14 cm×10 cm=140 cm2\text{length} \times \text{width} = 14\text{ cm} \times 10\text{ cm} = 140\text{ cm}^2.
2
Calculate the area of the removed semicircular section
77 cm²
The radius of the semicircle is r=142=7 cmr = \frac{14}{2} = 7\text{ cm}. The area of a semicircle is 12πr2=12×227×72=77 cm2\frac{1}{2}\pi r^2 = \frac{1}{2} \times \frac{22}{7} \times 7^2 = 77\text{ cm}^2.
3
Calculate the area of the attached triangular section
168 cm²
The area of a triangle is 12×base×height=12×14 cm×24 cm=168 cm2\frac{1}{2} \times \text{base} \times \text{height} = \frac{1}{2} \times 14\text{ cm} \times 24\text{ cm} = 168\text{ cm}^2.
4
Combine the area components to determine the final net area
231 cm²
Subtract the removed semicircular area from the rectangle's area and add the attached triangle's area: 14077+168=231 cm2140 - 77 + 168 = 231\text{ cm}^2.

Anahtar Kavram

Perimeter and Area of Composite Plane Figures
Soru 4009Soru

What is the equation of the normal to the curve y=2x23x+1y = 2x^2 - 3x + 1 at the point where x=2x = 2?

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Cevap: x+5y17=0x + 5y - 17 = 0

Cevap

x+5y17=0x + 5y - 17 = 0
Evaluating y=2x23x+1y = 2x^2 - 3x + 1 at x=2x = 2 gives the point (2,3)(2, 3). Differentiating gives dydx=4x3\frac{dy}{dx} = 4x - 3, which evaluates to 55 at x=2x = 2. The normal line gradient is therefore 15-\frac{1}{5}. Using the point-slope formula y3=15(x2)y - 3 = -\frac{1}{5}(x - 2) and rearranging to standard linear form results in x+5y17=0x + 5y - 17 = 0.

Adım Adım Çözüm

1
Find the yy-coordinate of the point of contact on the curve when x=2x = 2.
Substitute x=2x = 2 into y=2x23x+1y = 2x^2 - 3x + 1: y=2(2)23(2)+1=86+1=3y = 2(2)^2 - 3(2) + 1 = 8 - 6 + 1 = 3. The point is (2,3)(2, 3).
The line of normal passes through the point of tangency on the curve.
2
Differentiate y=2x23x+1y = 2x^2 - 3x + 1 with respect to xx to find the gradient of the tangent.
dydx=4x3\frac{dy}{dx} = 4x - 3. At x=2x = 2, mt=4(2)3=5m_t = 4(2) - 3 = 5.
The derivative of a curve evaluated at a point yields the gradient of the tangent line at that point.
3
Determine the gradient of the normal line.
Since the normal is perpendicular to the tangent, mn=1mt=15m_n = -\frac{1}{m_t} = -\frac{1}{5}.
Perpendicular lines have gradients whose product is 1-1 (mtmn=1m_t \cdot m_n = -1).
4
Form the equation of the normal line passing through (2,3)(2, 3) with gradient mn=15m_n = -\frac{1}{5}.
y3=15(x2)    5(y3)=(x2)    5y15=x+2    x+5y17=0y - 3 = -\frac{1}{5}(x - 2) \implies 5(y - 3) = -(x - 2) \implies 5y - 15 = -x + 2 \implies x + 5y - 17 = 0.
Applying the point-slope form yy1=m(xx1)y - y_1 = m(x - x_1) establishes the linear equation.

Anahtar Kavram

Tangents and Normals to Curves
Soru 4010Soru

A commercial bank receives a new cash deposit of N250,000\text{N}250,000. Following multiple rounds of lending across the banking system, the total credit created in the economy expands to N1,250,000\text{N}1,250,000. What is the Cash Reserve Ratio enforced by the monetary authority?

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Cevap: 20%20\%

Cevap

The Cash Reserve Ratio enforced by the monetary authority is 20%20\%.
The relationship between initial cash deposits, total credit expanded, and the reserve ratio is given by Total Credit Created=Initial DepositCash Reserve Ratio\text{Total Credit Created} = \frac{\text{Initial Deposit}}{\text{Cash Reserve Ratio}}. Substituting N1,250,000=N250,000Cash Reserve Ratio\text{N}1,250,000 = \frac{\text{N}250,000}{\text{Cash Reserve Ratio}} and solving for the ratio gives N250,000N1,250,000=0.20\frac{\text{N}250,000}{\text{N}1,250,000} = 0.20, or 20%20\%.

Adım Adım Çözüm

1
Recall the credit creation formula linking initial deposit, total credit created, and the cash reserve ratio.
Total Credit Created=Initial DepositCash Reserve Ratio\text{Total Credit Created} = \frac{\text{Initial Deposit}}{\text{Cash Reserve Ratio}}
The total volume of credit created by commercial banks depends inversely on the stipulated reserve percentage.
2
Rearrange the formula to isolate the Cash Reserve Ratio.
Cash Reserve Ratio=Initial DepositTotal Credit Created\text{Cash Reserve Ratio} = \frac{\text{Initial Deposit}}{\text{Total Credit Created}}
Dividing initial deposit by total credit expanded gives the reserve ratio directly.
3
Substitute the given numerical values into the equation and calculate.
Cash Reserve Ratio=N250,000N1,250,000=0.20=20%\text{Cash Reserve Ratio} = \frac{\text{N}250,000}{\text{N}1,250,000} = 0.20 = 20\%
Executing the division yields 0.200.20, which converts to 20%20\%.

Anahtar Kavram

Credit Multiplier and Reserve Requirements in Commercial Banking
Soru 4011Soru

The length of the mercury column in an uncalibrated liquid-in-glass thermometer is 2.0cm2.0\,\text{cm} at the ice point (0C0^\circ\text{C}) and 18.0cm18.0\,\text{cm} at the steam point (100C100^\circ\text{C}). What is the temperature when the length of the mercury column is 9.2cm9.2\,\text{cm}?

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Cevap: 45C45^\circ\text{C}

Cevap

The temperature corresponding to a mercury column length of 9.2cm9.2\,\text{cm} is 45C45^\circ\text{C}.
The temperature on the Celsius scale is given by the formula θ=LθL0L100L0×100C\theta = \frac{L_\theta - L_0}{L_{100} - L_0} \times 100^\circ\text{C}. Substituting L0=2.0cmL_0 = 2.0\,\text{cm}, L100=18.0cmL_{100} = 18.0\,\text{cm}, and Lθ=9.2cmL_\theta = 9.2\,\text{cm} yields θ=7.216.0×100C=45C\theta = \frac{7.2}{16.0} \times 100^\circ\text{C} = 45^\circ\text{C}.

Adım Adım Çözüm

1
Identify the fixed points and the thermometric property values.
Ice point length L0=2.0cmL_0 = 2.0\,\text{cm}, steam point length L100=18.0cmL_{100} = 18.0\,\text{cm}, and observed length Lθ=9.2cmL_\theta = 9.2\,\text{cm}.
The linear scale equation requires establishing the reference points on the Celsius scale.
2
Calculate the fundamental interval length (L100L0L_{100} - L_0).
L100L0=18.0cm2.0cm=16.0cmL_{100} - L_0 = 18.0\,\text{cm} - 2.0\,\text{cm} = 16.0\,\text{cm}.
The fundamental interval represents the total change in length corresponding to 100C100^\circ\text{C}.
3
Apply the linear interpolation formula θ=LθL0L100L0×100C\theta = \frac{L_\theta - L_0}{L_{100} - L_0} \times 100^\circ\text{C}.
θ=9.22.016.0×100C=7.216.0×100C=45C\theta = \frac{9.2 - 2.0}{16.0} \times 100^\circ\text{C} = \frac{7.2}{16.0} \times 100^\circ\text{C} = 45^\circ\text{C}.
This scales the fractional change in thermometric property above the ice point to degrees Celsius.

Anahtar Kavram

Linear interpolation on empirical temperature scales
Tahmini Süre:1m 30s
Soru 4012Soru

Nigeria's thermal electricity generation relies predominantly on domestic fossil fuel deposits. Which of the following thermal power stations was historically built to utilize coal extracted from the Anambra Basin rather than natural gas from the Niger Delta?

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Cevap: Oji River Power Station

Cevap

Oji River Power Station
Oji River Power Station in Enugu State is historically renowned as Nigeria's key coal-fired thermal power installation, established to leverage the sub-bituminous coal deposits of the Enugu coalfields within the Anambra Basin. By contrast, facilities like Egbin, Afam, and Sapele are gas-fired thermal stations linked directly to petroleum and natural gas fields in the Niger Delta region.

Adım Adım Çözüm

1
Identify the geographical distribution of fossil fuel resources in Nigeria
Coal deposits are concentrated in the sub-bituminous coal belt of the Anambra Basin (Enugu/Kogi/Benue region), whereas natural gas is abundant in the southern Niger Delta sedimentary basin.
Understanding resource geography helps correlate raw fuel locations with power infrastructure.
2
Match the specified thermal power station to its original primary fuel supply
Oji River Power Station was established in Enugu State specifically to harness coal from the local coalfield for thermal power generation.
Oji River is Nigeria's prime historical example of a coal-fired power plant built near coal mines.

Anahtar Kavram

Spatial distribution and utilization of coal versus natural gas for thermal power generation in Nigeria
Tahmini Süre:1m 15s
Soru 4013Soru

Mr. Adebayo employs a personal chauffeur for his family, a private cook for his household, an insurance agent to manage his company's risk policies, and a housemaid for domestic chores. Which of these individuals is engaged in a commercial occupation?

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Cevap: The insurance agent

Cevap

The insurance agent is engaged in a commercial occupation.
Insurance is an auxiliary to trade. Individuals working in insurance provide essential services that facilitate trade and business risk management, making the role a commercial occupation.

Adım Adım Çözüm

1
Define commercial and direct service occupations.
Commercial occupations involve trading activities and auxiliaries to trade (such as banking, insurance, warehousing, and commercial transport), whereas direct service occupations involve personal services rendered directly to individuals for non-commercial personal satisfaction.
Classification depends on whether the occupation facilitates commercial trade or directly satisfies personal individual needs.
2
Classify each profession mentioned in the stem.
The personal chauffeur, private cook, and housemaid render personal domestic services directly to the employer's family. The insurance agent provides risk management, which is an auxiliary to trade.
Insurance directly assists commercial enterprises and trade activities, establishing it as a commercial occupation.

Anahtar Kavram

Distinction Between Commercial and Direct Service Occupations
Soru 4014Soru

Which credit instrument is issued by an importer's bank to guarantee payment to an exporter upon the presentation of specified shipping documents?

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Cevap: Letter of Credit

Cevap

Letter of Credit
A Letter of Credit is an undertaking by a buyer's bank assuring the seller that payment will be made provided the required shipping documents are presented in compliance with the agreement.

Adım Adım Çözüm

1
Identify the primary function described in the scenario.
The instrument serves as a bank-backed payment guarantee in foreign trade.
Exporters require assurance that they will receive payment before shipping goods overseas.
2
Match the function to the correct credit instrument.
A Letter of Credit is the standard financial instrument used by commercial banks to guarantee foreign trade payments.
It substitutes the creditworthiness of the bank for that of the importer.

Anahtar Kavram

Forms and Instruments of Credit - Letter of Credit
Tahmini Süre:45s
Soru 4015Soru

Post-independence Nigerian political history witnessed a series of military interventions and regime changes. Arrange the following military coups and regime transitions in the correct chronological order from earliest to latest.

Öğeleri doğru sıraya koymak için sürükleyin

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Cevap

The correct chronological sequence of military interventions from earliest to latest is: Major Chukwuma Nzeogwu leading the first military coup (January 1966), followed by Lieutenant Colonel Yakubu Gowon assuming power after the counter-coup (July 1966), followed by General Murtala Muhammed overthrowing General Yakubu Gowon (July 1975), and finally Major-General Ibrahim Babangida ousting Major-General Muhammadu Buhari (August 1985).
The correct sequence begins with the inaugural coup of January 1966 led by Major Nzeogwu, followed by the July 1966 counter-coup establishing Yakubu Gowon's military leadership, followed by the July 1975 coup that brought Murtala Muhammed to power, and concludes with the August 1985 palace coup led by Ibrahim Babangida.

Adım Adım Çözüm

1
Identify the date of the first military coup d'état led by Major Chukwuma Nzeogwu.
Establishes January 15, 1966 as the starting event of military rule in Nigeria.
This marked the initial collapse of civilian democratic rule in the First Republic.
2
Identify the date of the counter-coup that brought Lieutenant Colonel Yakubu Gowon to head the Federal Military Government.
Establishes July 29, 1966 as the second chronological event.
The July counter-coup directly followed the political fallout of the January coup and the promulgation of Decree No. 34.
3
Identify the date of General Murtala Muhammed's takeover from General Yakubu Gowon.
Establishes July 29, 1975 as the third chronological event.
Murtala Muhammed removed Gowon after nine years in power due to delays in executing a democratic transition program.
4
Identify the date of Major-General Ibrahim Babangida's palace coup against Major-General Muhammadu Buhari.
Establishes August 27, 1985 as the fourth chronological event.
Babangida ousted Buhari following disagreements over economic policies and military governance strategies.

Anahtar Kavram

Chronological timeline of military interventions and regime changes in post-independence Nigeria
Soru 4016Soru

What is the pH of an aqueous solution containing 0.365 g dm30.365\text{ g dm}^{-3} of hydrochloric acid (HCl\text{HCl})? [Molar mass of HCl=36.5 g mol1\text{HCl} = 36.5\text{ g mol}^{-1}]

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Cevap: 2.02.0

Cevap

The pH of the solution is 2.0.
The solution has a molar concentration of 0.01 mol dm30.01\text{ mol dm}^{-3} (0.365 g dm3/36.5 g mol10.365\text{ g dm}^{-3} / 36.5\text{ g mol}^{-1}). Taking the negative base-10 logarithm of 1.0×102 mol dm31.0 \times 10^{-2}\text{ mol dm}^{-3} yields a pH of 2.0.

Adım Adım Çözüm

1
Convert mass concentration to molar concentration (molarity)
[HCl]=0.365 g dm336.5 g mol1=0.01 mol dm3=1.0×102 mol dm3[\text{HCl}] = \frac{0.365\text{ g dm}^{-3}}{36.5\text{ g mol}^{-1}} = 0.01\text{ mol dm}^{-3} = 1.0 \times 10^{-2}\text{ mol dm}^{-3}
pH calculations require concentration in units of mol dm3\text{mol dm}^{-3}.
2
Determine the hydrogen ion concentration [H+][\text{H}^+]
[H+]=1.0×102 mol dm3[\text{H}^+] = 1.0 \times 10^{-2}\text{ mol dm}^{-3}
Hydrochloric acid is a strong monoprotic acid that fully dissociates in water.
3
Calculate the pH using the pH formula
pH=log10[H+]=log10(1.0×102)=2.0\text{pH} = -\log_{10}[\text{H}^+] = -\log_{10}(1.0 \times 10^{-2}) = 2.0
pH is defined as the negative logarithm to base 10 of the hydrogen ion concentration.

Anahtar Kavram

Calculating pH from mass concentration of a strong acid
Tahmini Süre:1m 0s
Soru 4017Soru

A bullet of mass 20 g20\text{ g} is moving horizontally at a speed of 400 m s1400\text{ m s}^{-1}. It strikes a stationary block of wood and emerges from the opposite side with a speed of 100 m s1100\text{ m s}^{-1}. What is the magnitude of the work done by the bullet against the resistance of the block, in Joules?

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Cevap: 1500

Cevap

The magnitude of the work done by the bullet in penetrating the block is 1500 J1500\text{ J}.
According to the Work-Energy Theorem, the net work done on an object equals the change in its kinetic energy. The reduction in kinetic energy as the bullet slows from 400 m s1400\text{ m s}^{-1} to 100 m s1100\text{ m s}^{-1} equals the work done against the resistive force of the wooden block.

Adım Adım Çözüm

1
Convert the mass of the bullet into standard SI units (kilograms)
m=201000=0.02 kgm = \frac{20}{1000} = 0.02\text{ kg}
The standard SI unit for mass in energy equations is the kilogram.
2
Determine the initial kinetic energy of the bullet before entering the block
Eki=12×0.02 kg×(400 m s1)2=1600 JE_{ki} = \frac{1}{2} \times 0.02\text{ kg} \times (400\text{ m s}^{-1})^2 = 1600\text{ J}
Kinetic energy is defined as Ek=12mv2E_k = \frac{1}{2} m v^2.
3
Determine the final kinetic energy of the bullet as it emerges from the block
Ekf=12×0.02 kg×(100 m s1)2=100 JE_{kf} = \frac{1}{2} \times 0.02\text{ kg} \times (100\text{ m s}^{-1})^2 = 100\text{ J}
The bullet loses speed upon passing through the block, reducing its kinetic energy.
4
Apply the Work-Energy Theorem to find the work done against resistive forces
W=ΔEk=1600 J100 J=1500 JW = \Delta E_k = 1600\text{ J} - 100\text{ J} = 1500\text{ J}
The net work done on the bullet equals its change in kinetic energy.

Anahtar Kavram

Work-Energy Theorem
Soru 4018Soru

A boat sails 10 km10\text{ km} from a port PP on a bearing of 040040^\circ to a point QQ. From QQ, it changes direction and sails 103 km10\sqrt{3}\text{ km} on a bearing of 130130^\circ to reach a point RR. What is the bearing of port PP from point RR?

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Cevap: 280280^\circ

Cevap

The bearing of port P from point R is 280280^\circ.
By drawing North reference lines at P, Q, and R, the back bearing of P from Q is 040+180=220040^\circ + 180^\circ = 220^\circ. The bearing of R from Q is 130130^\circ, creating an interior right angle of 220130=90220^\circ - 130^\circ = 90^\circ at Q. Using right-triangle trigonometry, tan(QPR)=10310=3\tan(\angle QPR) = \frac{10\sqrt{3}}{10} = \sqrt{3}, giving QPR=60\angle QPR = 60^\circ. Adding this to the initial bearing of 040040^\circ gives the bearing of R from P as 100100^\circ. Finally, adding 180180^\circ gives the reverse bearing of P from R as 280280^\circ.

Adım Adım Çözüm

1
Determine the interior angle PQR\angle PQR at vertex QQ
PQR=90\angle PQR = 90^\circ
The back bearing of P from Q is 040+180=220040^\circ + 180^\circ = 220^\circ. The bearing of R from Q is 130130^\circ. The interior angle between QP and QR is 220130=90220^\circ - 130^\circ = 90^\circ.
2
Calculate the angle QPR\angle QPR inside right-angled triangle PQRPQR
QPR=60\angle QPR = 60^\circ
Since triangle PQRPQR is right-angled at QQ, tan(QPR)=oppositeadjacent=QRPQ=10310=3\tan(\angle QPR) = \frac{\text{opposite}}{\text{adjacent}} = \frac{QR}{PQ} = \frac{10\sqrt{3}}{10} = \sqrt{3}. Therefore, QPR=arctan(3)=60\angle QPR = \arctan(\sqrt{3}) = 60^\circ.
3
Find the forward bearing of point RR from port PP
Bearing of RR from P=100P = 100^\circ
The bearing of Q from P is 040040^\circ. Since R lies to the right (clockwise) of segment PQ, add QPR=60\angle QPR = 60^\circ to 040040^\circ: 040+60=100040^\circ + 60^\circ = 100^\circ.
4
Compute the back bearing of port PP from point RR
Bearing of PP from R=280R = 280^\circ
The back bearing is obtained by adding 180180^\circ to the forward bearing from P to R: 100+180=280100^\circ + 180^\circ = 280^\circ.

Anahtar Kavram

Three-point bearing calculations using right-triangle trigonometry and back bearings
Tahmini Süre:2m 30s
Soru 4019Soru

A line L1L_1 is given by the equation 3x+4y24=03x + 4y - 24 = 0, intersecting the x-axis at point AA and the y-axis at point BB. A second line L2L_2 has the equation 4x3y+k=04x - 3y + k = 0, where k>0k > 0. If the perpendicular distance from the midpoint of the line segment ABAB to L2L_2 is 55 units, what is the value of kk?

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Cevap: 18

Cevap

The value of kk is 1818.
To find kk, first determine the intercepts of L1L_1: setting y=0y=0 gives A(8,0)A(8, 0) and setting x=0x=0 gives B(0,6)B(0, 6). The midpoint MM of segment ABAB is (8+02,0+62)=(4,3)\left(\frac{8+0}{2}, \frac{0+6}{2}\right) = (4, 3). Using the perpendicular distance formula d=Ax0+By0+CA2+B2d = \frac{|Ax_0 + By_0 + C|}{\sqrt{A^2 + B^2}} for point M(4,3)M(4,3) and line 4x3y+k=04x - 3y + k = 0, we get d=4(4)3(3)+k42+(3)2=7+k5d = \frac{|4(4) - 3(3) + k|}{\sqrt{4^2 + (-3)^2}} = \frac{|7 + k|}{5}. Setting d=5d = 5 gives 7+k=25|7 + k| = 25. Since k>0k > 0, solving 7+k=257 + k = 25 gives the correct value k=18k = 18.

Adım Adım Çözüm

1
Determine the coordinates of points A and B
A=(8,0)A = (8, 0) and B=(0,6)B = (0, 6)
Setting y=0y = 0 in 3x+4y24=03x + 4y - 24 = 0 yields 3x=24    x=83x = 24 \implies x = 8. Setting x=0x = 0 yields 4y=24    y=64y = 24 \implies y = 6.
2
Calculate the midpoint M of segment AB
M=(4,3)M = (4, 3)
Using the midpoint formula M=(x1+x22,y1+y22)=(8+02,0+62)=(4,3)M = \left(\frac{x_1 + x_2}{2}, \frac{y_1 + y_2}{2}\right) = \left(\frac{8 + 0}{2}, \frac{0 + 6}{2}\right) = (4, 3).
3
Set up the perpendicular distance equation from M(4,3) to line L₂
d=7+k5d = \frac{|7 + k|}{5}
Applying the distance formula d=Ax0+By0+CA2+B2d = \frac{|Ax_0 + By_0 + C|}{\sqrt{A^2 + B^2}} gives d=4(4)3(3)+k42+(3)2=169+k25=7+k5d = \frac{|4(4) - 3(3) + k|}{\sqrt{4^2 + (-3)^2}} = \frac{|16 - 9 + k|}{\sqrt{25}} = \frac{|7 + k|}{5}.
4
Solve for k given d = 5 and k > 0
k=18k = 18
Equating distance to 55 gives 7+k5=5    7+k=25\frac{|7 + k|}{5} = 5 \implies |7 + k| = 25. Since k>0k > 0, 7+k=257 + k = 25, which yields k=18k = 18.

Anahtar Kavram

Perpendicular Distance from a Point to a Straight Line
Tahmini Süre:2m 30s
Soru 4020Soru

If 214x=3125214_x = 312_5, where xx represents a positive integer base, find the value of xx.

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Cevap: 6

Cevap

The value of the base xx is 6.
Expanding 3125312_5 to base 10 gives 3(25)+1(5)+2(1)=823(25) + 1(5) + 2(1) = 82. Expanding 214x214_x gives 2x2+x+42x^2 + x + 4. Equating both expressions yields 2x2+x78=02x^2 + x - 78 = 0. Factoring as (2x+13)(x6)=0(2x + 13)(x - 6) = 0 gives the positive integer root x=6x = 6.

Adım Adım Çözüm

1
Convert the right side of the equation from base 5 to base 10
3125=3×52+1×51+2×50=75+5+2=8210312_5 = 3 \times 5^2 + 1 \times 5^1 + 2 \times 5^0 = 75 + 5 + 2 = 82_{10}
Converting known non-decimal bases to base 10 provides a standard baseline for algebraic manipulation.
2
Expand the left side expression in terms of powers of xx
214x=2x2+x+4214_x = 2x^2 + x + 4
Positional values in base xx correspond to powers of xx (x2,x1,x0x^2, x^1, x^0).
3
Formulate and rearrange the resulting quadratic equation in standard form
2x2+x+4=82    2x2+x78=02x^2 + x + 4 = 82 \implies 2x^2 + x - 78 = 0
Setting the base 10 expansions equal forms a quadratic equation.
4
Solve the quadratic equation for positive integer values of xx
x=6x = 6
Factoring (2x+13)(x6)=0(2x + 13)(x - 6) = 0 gives x=6x = 6 or x=6.5x = -6.5. A base must be a positive integer larger than all individual digits appearing in the number (digits are 2, 1, 4, so x>4x > 4).

Anahtar Kavram

Converting non-decimal numbers to base 10 using positional expansion to solve polynomial equations involving unknown bases.
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