Tüm alıştırma soruları

612 soru

Soru 361Soru

For the quadratic function ff, the table below shows three points that lie on its graph in the xyxy-plane, where kk is a constant.

xxf(x)f(x)
2200
6600
1115-15

If the vertex of the graph of y=f(x)y = f(x) is (4,k)(4, k), what is the value of kk?

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Cevap: 12

Cevap

The value of kk is 1212.
The table indicates that the function has xx-intercepts at x=2x = 2 and x=6x = 6 because f(2)=0f(2) = 0 and f(6)=0f(6) = 0. Consequently, the quadratic function can be written in factored form as f(x)=a(x2)(x6)f(x) = a(x - 2)(x - 6) for some constant aa. Using the point (1,15)(1, -15) to find aa, we substitute x=1x = 1 and f(1)=15f(1) = -15, which yields 15=a(12)(16)-15 = a(1 - 2)(1 - 6), or 15=5a-15 = 5a, so a=3a = -3. Since the vertex of the graph is (4,k)(4, k), the value of kk is the function value at the vertex's xx-coordinate, which is f(4)f(4). Evaluating the function gives k=3(42)(46)=3(2)(2)=12k = -3(4 - 2)(4 - 6) = -3(2)(-2) = 12.

Adım Adım Çözüm

1
Write the quadratic function in factored form using the given xx-intercepts.
f(x)=a(x2)(x6)f(x) = a(x - 2)(x - 6)
The table shows that f(2)=0f(2) = 0 and f(6)=0f(6) = 0, meaning the graph has xx-intercepts at x=2x = 2 and x=6x = 6.
2
Substitute the point (1,15)(1, -15) into the factored equation to find the value of the constant aa.
a=3a = -3
Substituting x=1x = 1 and f(x)=15f(x) = -15 gives 15=a(12)(16)    15=5a    a=3-15 = a(1 - 2)(1 - 6) \implies -15 = 5a \implies a = -3.
3
Calculate the value of kk by finding the function value at the vertex x=4x = 4.
k=12k = 12
Since the vertex is (4,k)(4, k), the value of kk is f(4)f(4). Substituting x=4x = 4 into f(x)=3(x2)(x6)f(x) = -3(x - 2)(x - 6) yields k=3(42)(46)=3(2)(2)=12k = -3(4 - 2)(4 - 6) = -3(2)(-2) = 12.

Anahtar Kavram

Using intercepts and an additional point to determine the equation of a quadratic function, and evaluating it at the vertex.
Soru 362Soru

A specialized cooling system is used to lower the temperature of a chemical solution in a laboratory. The temperature of the solution, TT, in degrees Celsius, can be modeled by the linear equation T=85.41.25mT = 85.4 - 1.25m, where mm is the number of minutes since the cooling process began. According to the model, how many minutes does it take for the temperature of the solution to decrease by 1515 degrees Celsius?

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Cevap: 12

Cevap

12 minutes
The correct answer is 12. In the equation T=85.41.25mT = 85.4 - 1.25m, the coefficient of mm is 1.25-1.25, which indicates that the temperature decreases by 1.251.25 degrees Celsius for each minute that passes. To find how many minutes it takes for the temperature to decrease by 1515 degrees Celsius, divide the total decrease by the rate of decrease: 151.25=12\frac{15}{1.25} = 12.

Adım Adım Çözüm

1
Identify the rate of change from the linear equation.
The rate of decrease is 1.251.25 degrees Celsius per minute.
The slope of the linear equation T=85.41.25mT = 85.4 - 1.25m is 1.25-1.25, representing the change in temperature per minute.
2
Divide the target temperature change by the rate of change to find the time.
12 minutes
To find the number of minutes for a 1515-degree decrease at a rate of 1.251.25 degrees per minute, calculate 151.25\frac{15}{1.25}.

Anahtar Kavram

Interpreting the slope of a linear relationship in context
Soru 363Soru

A projectile is launched from the ground. Its height, in feet, tt seconds after launch is modeled by the function h(t)=16t2+v0th(t) = -16t^2 + v_0 t, where v0v_0 is the initial upward velocity in feet per second. If the projectile reaches its maximum height of 144144 feet, what is the value of v0v_0?

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Cevap: 96

Cevap

The correct answer is 96. The initial velocity of the projectile must be 96 feet per second to reach a maximum height of 144 feet.
The maximum height of a projectile modeled by a quadratic function is the yy-value of its vertex. For h(t)=16t2+v0th(t) = -16t^2 + v_0 t, the time tt at the vertex is given by t=b2a=v02(16)=v032t = -\frac{b}{2a} = -\frac{v_0}{2(-16)} = \frac{v_0}{32}. Substituting this value of tt back into the height equation yields the maximum height: h(v032)=16(v032)2+v0(v032)=16(v021024)+v0232=v0264+v0232=v0264h\left(\frac{v_0}{32}\right) = -16\left(\frac{v_0}{32}\right)^2 + v_0\left(\frac{v_0}{32}\right) = -16\left(\frac{v_0^2}{1024}\right) + \frac{v_0^2}{32} = -\frac{v_0^2}{64} + \frac{v_0^2}{32} = \frac{v_0^2}{64}. Given that the maximum height is 144144 feet, we set v0264=144\frac{v_0^2}{64} = 144, which simplifies to v02=144×64v_0^2 = 144 \times 64. Taking the square root of both sides gives v0=12×8=96v_0 = 12 \times 8 = 96.

Adım Adım Çözüm

1
Find the time tt at which the maximum height occurs using the vertex formula.
t=v032t = \frac{v_0}{32}
For a quadratic function of the form f(x)=ax2+bx+cf(x) = ax^2 + bx + c, the vertex occurs at x=b2ax = -\frac{b}{2a}. Here, a=16a = -16 and b=v0b = v_0, so the vertex is at t=v02(16)=v032t = -\frac{v_0}{2(-16)} = \frac{v_0}{32}.
2
Substitute the time t=v032t = \frac{v_0}{32} into the height function to express the maximum height in terms of v0v_0.
h(v032)=v0264h\left(\frac{v_0}{32}\right) = \frac{v_0^2}{64}
Evaluating h(v032)h\left(\frac{v_0}{32}\right) gives 16(v032)2+v0(v032)=16(v021024)+v0232=v0264+v0232=v0264-16\left(\frac{v_0}{32}\right)^2 + v_0\left(\frac{v_0}{32}\right) = -16\left(\frac{v_0^2}{1024}\right) + \frac{v_0^2}{32} = -\frac{v_0^2}{64} + \frac{v_0^2}{32} = \frac{v_0^2}{64}.
3
Set the maximum height expression equal to the given maximum height of 144144 feet and solve for v0v_0.
v0=96v_0 = 96
Setting v0264=144\frac{v_0^2}{64} = 144 yields v02=144×64=9216v_0^2 = 144 \times 64 = 9216. Taking the positive square root (since v0v_0 represents a positive initial upward velocity) gives v0=144×64=12×8=96v_0 = \sqrt{144} \times \sqrt{64} = 12 \times 8 = 96.

Anahtar Kavram

Determining the vertex coordinates of a quadratic function to find maximum value in context.
Soru 364Soru

If 272x2=(13)x827^{2x - 2} = \left(\frac{1}{3}\right)^{x - 8}, what is the value of xx?

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Cevap: 2

Cevap

The value of xx is 22.
To solve the equation 272x2=(13)x827^{2x - 2} = \left(\frac{1}{3}\right)^{x - 8}, express both sides with the base 33. Since 27=3327 = 3^3 and 13=31\frac{1}{3} = 3^{-1}, the equation becomes (33)2x2=(31)x8(3^3)^{2x - 2} = (3^{-1})^{x - 8}. Applying the exponent rule (am)n=amn(a^m)^n = a^{mn} yields 36x6=38x3^{6x - 6} = 3^{8 - x}. Since the bases are now the same, set the exponents equal to each other: 6x6=8x6x - 6 = 8 - x. Adding xx to both sides gives 7x6=87x - 6 = 8, and adding 66 to both sides gives 7x=147x = 14. Dividing by 77 results in x=2x = 2.

Adım Adım Çözüm

1
Rewrite 2727 and 13\frac{1}{3} as powers of 33.
27=3327 = 3^3 and 13=31\frac{1}{3} = 3^{-1}
This allows both sides of the equation to be expressed with a common base of 33 so their exponents can be equated.
2
Substitute these bases back into the equation and apply exponent rules.
(33)2x2=(31)x8    33(2x2)=3(x8)    36x6=38x(3^3)^{2x - 2} = (3^{-1})^{x - 8} \implies 3^{3(2x - 2)} = 3^{-(x - 8)} \implies 3^{6x - 6} = 3^{8 - x}
Using the power rule (am)n=amn(a^m)^n = a^{mn}, multiply the outer exponent by the power of the base.
3
Equate the exponents and solve for xx.
6x6=8x    7x=14    x=26x - 6 = 8 - x \implies 7x = 14 \implies x = 2
Since the bases are equal, their exponents must be equal for the equation to hold true.

Anahtar Kavram

Solving exponential equations by finding a common base and applying exponent rules.
Soru 365Soru

A bakery recipe requires 1212 ounces of butter to make one batch of bread. How many pounds of butter are needed to make 88 batches of bread? (Given that 1 pound=16 ounces1\text{ pound} = 16\text{ ounces})

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Cevap: 6

Cevap

The bakery needs 66 pounds of butter.
The total amount of butter needed for 88 batches is calculated by multiplying the butter required for one batch by the number of batches: 8×12=968 \times 12 = 96 ounces. Given that 1 pound=16 ounces1\text{ pound} = 16\text{ ounces}, we convert ounces to pounds by dividing the total ounces by 1616. Therefore, 96÷16=696 \div 16 = 6 pounds of butter are needed.

Adım Adım Çözüm

1
Calculate the total ounces of butter needed.
9696 ounces
Since each batch requires 1212 ounces, 88 batches require 8×12=968 \times 12 = 96 ounces.
2
Convert the total ounces to pounds.
66 pounds
Divide the total number of ounces by the conversion factor (1616 ounces per pound): 9616=6\frac{96}{16} = 6.

Anahtar Kavram

To convert a quantity from a smaller unit to a larger unit, multiply the initial quantity by the number of groups to find the total in the smaller unit, and then divide by the conversion factor that relates the two units.
Soru 366Soru

A rideshare driver has a daily goal of earning at least 150.Sofartoday,thedriverhasearned150. So far today, the driver has earned 45. The driver earns 12perrideplusanaveragetipof12 per ride plus an average tip of 3 per ride. If the driver must pay a daily vehicle fee of $15, what is the minimum number of additional rides the driver must complete today to meet or exceed the daily earnings goal?

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Cevap: 8

Cevap

The minimum number of additional rides the driver must complete today is 8.
The driver earns 12plusa12 plus a 3 tip per ride, which is 15perride.Startingwith15 per ride. Starting with 45 and subtracting the 15feeleavesthedriverwith15 fee leaves the driver with 30 before completing any new rides. To reach at least 150,thedriverneedstoearnatleast150, the driver needs to earn at least 120 more. Dividing 120bythe120 by the 15 rate per ride gives a minimum of 8 rides.

Adım Adım Çözüm

1
Define the variable xx for the number of additional rides and write an inequality representing the total net earnings.
45+12x+3x1515045 + 12x + 3x - 15 \geq 150
To represent the condition that the driver's total earnings, including initial earnings and new rides, minus the fee, must be at least $150.
2
Simplify the left side of the inequality by combining the constants and the xx terms.
30+15x15030 + 15x \geq 150
To group like terms and simplify the expression before solving.
3
Subtract 30 from both sides of the inequality to isolate the variable term.
15x12015x \geq 120
To isolate the term with the variable on one side of the inequality.
4
Divide both sides of the inequality by 15 to solve for xx.
x8x \geq 8
To find the minimum value of xx that satisfies the inequality.

Anahtar Kavram

Solving linear inequalities in one variable to find a minimum threshold value in a real-world scenario.
Soru 367Soru

A map has a scale where 22 centimeters represents 1515 kilometers. If the distance between two cities on the map is 88 centimeters, what is the actual distance between the two cities, in kilometers?

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Cevap: 60

Cevap

The actual distance between the two cities is 6060 kilometers.
The correct answer is 6060. The map scale is 22 centimeters to 1515 kilometers. The map distance between the cities is 88 centimeters, which is 44 times the scale distance of 22 centimeters (since 8÷2=48 \div 2 = 4). Therefore, the actual distance between the cities is 44 times the scale distance of 1515 kilometers, which is 15×4=6015 \times 4 = 60 kilometers.

Adım Adım Çözüm

1
Set up a proportion using the map scale ratio of centimeters to kilometers.
215=8x\frac{2}{15} = \frac{8}{x}
This establishes that the ratio of map distance to actual distance remains constant.
2
Solve for the unknown actual distance, xx, by cross-multiplying.
2x=1202x = 120
Multiplying the numerator of each fraction by the denominator of the other solves the proportion.
3
Divide by the coefficient of xx to find the final actual distance.
x=60x = 60
Dividing 120120 by 22 isolates xx and gives the actual distance in kilometers.

Anahtar Kavram

Setting up and solving proportions using scale factors.
Soru 368Soru

At the beginning of the year, a library had 800800 history books. In the first half of the year, the number of history books increased by 15%15\%. In the second half of the year, the library acquired more history books, representing a percent increase of x%x\% over the number of history books at the midyear point. If the library had a total of 10121{}012 history books at the end of the year, what is the value of xx?

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Cevap: 10

Cevap

The value of xx is 1010.
To find the second percent increase, we must first calculate the intermediate midyear value. A 15%15\% increase on 800800 is 800×1.15=920800 \times 1.15 = 920. The subsequent increase of x%x\% is based on this midyear value of 920920. Setting up the equation 920×(1+x100)=1012920 \times (1 + \frac{x}{100}) = 1{}012 and solving for xx yields 1+x100=1.101 + \frac{x}{100} = 1.10, which gives x=10x = 10.

Adım Adım Çözüm

1
Calculate the number of history books at the midyear point after the first increase of 15%15\%
920920 books
An increase of 15%15\% on the initial 800800 books is calculated as 800×(1+0.15)=920800 \times (1 + 0.15) = 920.
2
Set up an equation for the second percent increase of x%x\% from the midyear value to the final value of 10121{}012
920×(1+x100)=1012920 \times (1 + \frac{x}{100}) = 1{}012
The second increase is x%x\% of the midyear value of 920920, resulting in the final value of 10121{}012.
3
Solve the equation for xx
x=10x = 10
Divide both sides of the equation by 920920 to get 1+x100=1.101 + \frac{x}{100} = 1.10, subtract 11 to get x100=0.10\frac{x}{100} = 0.10, and multiply by 100100 to find x=10x = 10.

Anahtar Kavram

Calculating successive percent increases by applying the percent change to the intermediate base value.

Alternatif Yöntem

Instead of calculating the intermediate number of books, we can express the final number of books as 800×1.15×(1+x100)=1012800 \times 1.15 \times (1 + \frac{x}{100}) = 1{}012. Simplifying 800×1.15800 \times 1.15 gives 920920, so 920×(1+x100)=1012920 \times (1 + \frac{x}{100}) = 1{}012, leading to the same result of x=10x = 10.
Tahmini Süre:1m 30s
Soru 369Soru

A survey of 80 commuters asked about their primary method of transportation to work and their commute distance. The results are summarized in the table below.

Commute DistanceBicycleWalkTotal
Under 1 mile152540
1 mile or more35540
Total503080

Based on the table, what fraction of the commuters who commute a distance of under 1 mile choose walking as their primary transportation method?

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Cevap: 0.625

Cevap

5/8 or 0.625
To find the fraction of commuters who commute a distance of under 1 mile that choose walking, limit the sample space to the row representing 'Under 1 mile', which has a subtotal of 40 commuters. Within this row, 25 commuters walk. Thus, the fraction is 25/40, which simplifies to 5/8 (or 0.625).

Adım Adım Çözüm

1
Identify the conditional group (denominator).
The row 'Under 1 mile' has a total of 40 commuters.
The phrase 'of the commuters who commute a distance of under 1 mile' restricts the group of interest to only those in this row.
2
Identify the target group within the restricted group (numerator).
25 commuters choose walking.
Within the 'Under 1 mile' row, we look at the 'Walk' column.
3
Calculate the conditional fraction.
25/40 = 5/8 (or 0.625).
Divide the target count by the conditional group total to find the fraction.

Anahtar Kavram

Conditional Probability from a Two-Way Table
Soru 370Soru

In the xyxy-plane, a line is represented by the equation aybx=24ay - bx = 24, where aa and bb are constants. If the line has a yy-intercept of (0,3)(0, -3) and passes through the point (4,5)(4, 5), what is the slope of the line?

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Cevap: 2

Cevap

The slope of the line is 2.
Substituting the y-intercept (0,3)(0, -3) into the equation aybx=24ay - bx = 24 yields 3a=24-3a = 24, which gives a=8a = -8. Substituting the point (4,5)(4, 5) and a=8a = -8 into the equation yields 8(5)4b=24-8(5) - 4b = 24, which simplifies to 404b=24-40 - 4b = 24, giving b=16b = -16. Re-assembling the equation gives 8y+16x=24-8y + 16x = 24. Solving for yy in terms of xx yields y=2x3y = 2x - 3, where the coefficient of xx is the slope, 2.

Adım Adım Çözüm

1
Substitute the y-intercept (0,3)(0, -3) into the given equation aybx=24ay - bx = 24 to find the value of aa.
a=8a = -8
Since the y-intercept lies on the line, its coordinates satisfy the line's equation.
2
Substitute the point (4,5)(4, 5) and the value of a=8a = -8 into the equation to find the value of bb.
b=16b = -16
Since the point (4,5)(4, 5) lies on the line, its coordinates must satisfy the equation.
3
Write the resulting equation 8y+16x=24-8y + 16x = 24 in slope-intercept form (y=mx+cy = mx + c) to identify the slope.
y=2x3y = 2x - 3, which gives a slope of 22.
The slope of a line in the form y=mx+cy = mx + c is represented by the coefficient mm of xx.

Anahtar Kavram

Finding the slope of a line from a given equation by determining its constant coefficients using known points.
Tahmini Süre:1m 30s
Soru 371Soru

For the quadratic function f(x)=x2+bx+cf(x) = -x^2 + bx + c, where bb and cc are positive constants, the maximum value of f(x)f(x) is kk. The distance between the two xx-intercepts of the graph of y=f(x)y = f(x) in the xyxy-plane is equal to 23k\frac{2}{3}k. If the graph of y=f(x)y = f(x) passes through the point (1,8)(1, 8), what is the value of bb?

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Cevap: 4

Cevap

The correct answer is 4.
The correct answer is 4. By expressing the maximum value kk and the distance between the xx-intercepts dd in terms of the constants bb and cc, we set up the equation d=23kd = \frac{2}{3}k. This simplifies to b2+4c=36b^2 + 4c = 36. Using the point (1,8)(1, 8), we establish c=9bc = 9 - b. Substituting this into the first equation yields b24b=0b^2 - 4b = 0, giving b=4b = 4 as the only positive solution.

Adım Adım Çözüm

1
Find the maximum value kk of the function f(x)=x2+bx+cf(x) = -x^2 + bx + c in terms of bb and cc.
k=b24+ck = \frac{b^2}{4} + c
The maximum value of a quadratic function with a negative leading coefficient occurs at its vertex, where x=b2a=b2x = -\frac{b}{2a} = \frac{b}{2}.
2
Find the distance dd between the xx-intercepts of the graph in terms of bb and cc.
d=b2+4cd = \sqrt{b^2 + 4c}
The xx-intercepts are the roots of x2+bx+c=0-x^2 + bx + c = 0, which are x=b±b2+4c2x = \frac{b \pm \sqrt{b^2 + 4c}}{2}. The distance between them is the difference of these roots.
3
Use the relation d=23kd = \frac{2}{3}k to find the value of the expression b2+4cb^2 + 4c.
b2+4c=36b^2 + 4c = 36
Substituting the expressions for dd and kk gives b2+4c=16(b2+4c)\sqrt{b^2 + 4c} = \frac{1}{6}(b^2 + 4c). Solving this radical equation yields b2+4c=36b^2 + 4c = 36.
4
Use the point (1,8)(1, 8) to express cc in terms of bb.
c=9bc = 9 - b
Since the graph passes through (1,8)(1, 8), substituting x=1x = 1 and y=8y = 8 into y=x2+bx+cy = -x^2 + bx + c yields 8=1+b+c8 = -1 + b + c, which simplifies to c=9bc = 9 - b.
5
Substitute c=9bc = 9 - b into b2+4c=36b^2 + 4c = 36 and solve for bb.
b=4b = 4
Substituting yields b2+4(9b)=36    b24b=0b^2 + 4(9 - b) = 36 \implies b^2 - 4b = 0. Solving for bb gives b=0b = 0 or b=4b = 4. Since bb is a positive constant, we have b=4b = 4.

Anahtar Kavram

Quadratic Functions and Graphs
Soru 372Soru

A solar panel generates 120120 watt-hours of electricity every 33 hours. At this rate, how many watt-hours of electricity will the solar panel generate in 88 hours?

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Cevap: 320

Cevap

The solar panel will generate 320320 watt-hours of electricity in 88 hours.
To find the total electricity generated, we determine the unit rate of energy generation: 120 watt-hours3 hours=40\frac{120 \text{ watt-hours}}{3 \text{ hours}} = 40 watt-hours per hour. Multiplying this rate by the new duration of 88 hours gives 40×8=32040 \times 8 = 320 watt-hours. Proportional reasoning also works: 1203=x8\frac{120}{3} = \frac{x}{8}, which yields x=320x = 320.

Adım Adım Çözüm

1
Calculate the hourly rate of electricity generation.
The rate is 4040 watt-hours per hour.
Dividing the energy produced (120120 watt-hours) by the elapsed time (33 hours) gives the unit rate.
2
Calculate the total energy generated over the new duration of 88 hours.
The total energy is 320320 watt-hours.
Multiplying the unit rate (4040 watt-hours per hour) by the target duration (88 hours) gives the total energy generated.

Anahtar Kavram

Calculating and applying unit rates to solve proportional relationships.

Alternatif Yöntem

Set up a proportion where the ratio of energy to time remains constant: 1203=x8\frac{120}{3} = \frac{x}{8}. Cross-multiply to solve for xx: 3x=120×83x = 120 \times 8, which simplifies to 3x=9603x = 960. Divide by 33 to find x=320x = 320.
Tahmini Süre:45s
Soru 373Soru

A technician at a chemistry lab prepares a solution by mixing 33 milliliters of acid with every 77 milliliters of distilled water. If the technician uses 3535 milliliters of distilled water to prepare the solution, how many milliliters of acid are needed?

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Cevap: 15

Cevap

The correct answer is 15.
To maintain the ratio of 33 milliliters of acid for every 77 milliliters of distilled water, the proportion acidwater=37=x35\frac{\text{acid}}{\text{water}} = \frac{3}{7} = \frac{x}{35} is established. Multiplying both sides by 3535 gives x=35×37=15x = 35 \times \frac{3}{7} = 15 milliliters of acid.

Adım Adım Çözüm

1
Set up the proportion relating acid to distilled water.
37=x35\frac{3}{7} = \frac{x}{35}, where xx is the required amount of acid in milliliters.
The ratio of acid to distilled water must remain constant.
2
Solve the proportion for xx.
x=15x = 15
Multiply both sides of the equation by 35 to isolate xx.

Anahtar Kavram

Solving proportions to find an unknown quantity when the ratio is constant.

Alternatif Yöntem

Find the scale factor: 3535 divided by 77 is 55. Multiply the acid amount (33) by this scale factor of 55 to get 1515.
Tahmini Süre:45s
Soru 374Soru

A catering company charges a flat setup fee of 500plus500 plus 35 per guest. A company has budgeted at most 2,400forabanquet.Ifthecompanyalsowantstopurchaseacelebrationcakefor2,400 for a banquet. If the company also wants to purchase a celebration cake for 150, what is the maximum number of guests they can invite to the banquet without exceeding their budget?

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Cevap: 50

Cevap

The maximum number of guests the company can invite without exceeding their budget is 50.
The total cost of the banquet consists of a flat setup fee (500),acelebrationcake(500), a celebration cake ( 150), and a variable cost of 35perguest(35 per guest ( 35g ,where, where g representsthenumberofguests).Sincethecompanyhasbudgetedatmost represents the number of guests). Since the company has budgeted at most 2,400, the sum of these expenses must be less than or equal to 2,400.Thisisrepresentedbytheinequality2,400. This is represented by the inequality 35g + 500 + 150 \le 2400 .Combiningtheconstantsyields. Combining the constants yields 35g + 650 \le 2400 .Subtracting650frombothsidesgives. Subtracting 650 from both sides gives 35g \le 1750 .Dividingbothsidesby35resultsin. Dividing both sides by 35 results in g \le 50$. Therefore, the maximum number of guests they can invite without exceeding their budget is 50.

Adım Adım Çözüm

1
Set up the inequality representing the total expenses.
35g+500+150240035g + 500 + 150 \le 2400
The sum of the fixed setup fee, the cake cost, and the variable per-guest cost must not exceed the maximum budget of $2,400.
2
Simplify the inequality by combining the constants.
35g+650240035g + 650 \le 2400
Combining the fixed expenses (500setupfeeand500 setup fee and 150 cake) simplifies the calculation.
3
Isolate the variable term by subtracting the fixed cost from both sides.
35g175035g \le 1750
This determines the portion of the budget that can be allocated specifically to guests.
4
Solve for the variable by dividing both sides by the cost per guest.
g50g \le 50
Dividing the remaining guest budget by the rate per guest gives the maximum number of guests allowed.

Anahtar Kavram

Formulating and solving multi-step linear inequalities in one variable to determine a maximum value in context.
Soru 375Soru

A polynomial function P(x)P(x) of degree 4 with real coefficients is symmetric about the line x=2x = 2 in the xyxy-plane. If P(x)P(x) is divisible by x24x+3x^2 - 4x + 3, the remainder when P(x)P(x) is divided by x4x - 4 is 3636, and P(2)=8P(2) = -8, what is the value of P(5)P(5)?

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Cevap: 136

Cevap

The value of P(5)P(5) is 136.
The correct answer of 136 is found by representing the symmetric fourth-degree polynomial as P(x)=a(x2)4+b(x2)2+cP(x) = a(x - 2)^4 + b(x - 2)^2 + c, solving for the coefficients using the roots at x=3x=3, the point (2,8)(2, -8), and the remainder point (4,36)(4, 36), and then evaluating the resulting expression (x2)4+7(x2)28(x-2)^4 + 7(x-2)^2 - 8 at x=5x=5.

Adım Adım Çözüm

1
Express the fourth-degree polynomial in a form that reflects its symmetry.
P(x)=a(x2)4+b(x2)2+cP(x) = a(x - 2)^4 + b(x - 2)^2 + c
Since the graph of P(x)P(x) is symmetric about the line x=2x = 2, the polynomial expression in terms of (x2)(x - 2) must contain only even powers.
2
Use the divisibility condition to establish an equation for the coefficients.
P(3)=a(32)4+b(32)2+c=a+b+c=0P(3) = a(3-2)^4 + b(3-2)^2 + c = a + b + c = 0
The divisor x24x+3x^2 - 4x + 3 factors into (x1)(x3)(x-1)(x-3). By the Factor Theorem, P(3)=0P(3) = 0 and P(1)=0P(1) = 0.
3
Use the given value P(2)=8P(2) = -8 to find the constant term cc.
c=8c = -8
Substituting x=2x = 2 into P(x)=a(x2)4+b(x2)2+cP(x) = a(x - 2)^4 + b(x - 2)^2 + c makes the terms with (x2)(x-2) equal to zero, leaving P(2)=cP(2) = c.
4
Formulate a system of linear equations for aa and bb.
a+b=8a + b = 8 and 4a+b=114a + b = 11
Substituting c=8c = -8 into a+b+c=0a + b + c = 0 gives a+b=8a + b = 8. By the Remainder Theorem, P(4)=36P(4) = 36, which gives a(42)4+b(42)28=36    16a+4b=44    4a+b=11a(4-2)^4 + b(4-2)^2 - 8 = 36 \implies 16a + 4b = 44 \implies 4a + b = 11.
5
Solve the system of equations for aa and bb.
a=1a = 1 and b=7b = 7
Subtracting a+b=8a + b = 8 from 4a+b=114a + b = 11 yields 3a=3    a=13a = 3 \implies a = 1, which then gives b=7b = 7.
6
Evaluate the polynomial at x=5x = 5.
P(5)=136P(5) = 136
Substitute a=1a = 1, b=7b = 7, c=8c = -8, and x=5x = 5 into the symmetric polynomial form: P(5)=(52)4+7(52)28=34+7(32)8=81+638=136P(5) = (5-2)^4 + 7(5-2)^2 - 8 = 3^4 + 7(3^2) - 8 = 81 + 63 - 8 = 136.

Anahtar Kavram

Polynomial Factors and Graphs
Soru 376Soru

At a certain car dealership, the number of hybrid vehicles sold in 2024 was 40%40\% of the number of gasoline vehicles sold in 2024. In 2025, the number of hybrid vehicles sold increased by 35%35\% compared to 2024, and the number of gasoline vehicles sold decreased by 10%10\% compared to 2024. If the dealership only sold hybrid and gasoline vehicles in both years, what percent of the total vehicles sold in 2025 were hybrid vehicles?

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Cevap: 37.5

Cevap

37.5
To find the percentage of hybrid vehicles sold in 2025, we first express the number of vehicles sold in 2024 in terms of a single variable. Let the number of gasoline vehicles sold in 2024 be gg. Since the hybrid sales were 40%40\% of the gasoline sales, the number of hybrid vehicles sold in 2024 is 0.40g0.40g. In 2025, hybrid sales increased by 35%35\%, resulting in 0.40g×1.35=0.54g0.40g \times 1.35 = 0.54g hybrid vehicles sold. Gasoline sales decreased by 10%10\%, resulting in g×0.90=0.90gg \times 0.90 = 0.90g gasoline vehicles sold. The total number of vehicles sold in 2025 is the sum of these two quantities: 0.54g+0.90g=1.44g0.54g + 0.90g = 1.44g. The percentage of hybrid vehicles sold in 2025 is the ratio of hybrid sales to total sales: 0.54g1.44g×100=37.5%\frac{0.54g}{1.44g} \times 100 = 37.5\%.

Adım Adım Çözüm

1
Define variables for the number of vehicles sold in 2024.
Let the number of gasoline vehicles sold in 2024 be gg. The number of hybrid vehicles sold in 2024 is 0.40g0.40g.
Establishing initial values in terms of a single variable allows for comparison after percentage changes are applied.
2
Determine the number of hybrid and gasoline vehicles sold in 2025 after their respective percentage changes.
Hybrid vehicles sold in 2025: 0.40g×(1+0.35)=0.54g0.40g \times (1 + 0.35) = 0.54g. Gasoline vehicles sold in 2025: g×(10.10)=0.90gg \times (1 - 0.10) = 0.90g.
Applying the percent increase of 35%35\% to the 2024 hybrid vehicles and the percent decrease of 10%10\% to the 2024 gasoline vehicles.
3
Calculate the total number of vehicles sold in 2025.
Total vehicles sold in 2025: 0.54g+0.90g=1.44g0.54g + 0.90g = 1.44g.
Summing the two types of vehicles sold in 2025 to find the new total.
4
Compute the percentage of hybrid vehicles out of the total vehicles sold in 2025.
0.54g1.44g×100=37.5%\frac{0.54g}{1.44g} \times 100 = 37.5\%.
Dividing the 2025 hybrid sales by the total 2025 sales and multiplying by 100 to convert to a percentage.

Anahtar Kavram

Calculating percent change and conditional percentages from initial relative ratios.
Soru 377Soru
If xx is a real number that satisfies the equation below, what is the value of xx?
x+2x43x=12x24x\frac{x + 2}{x - 4} - \frac{3}{x} = \frac{12}{x^2 - 4x}
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Cevap: 1

Cevap

The only valid real solution to the equation is 11.
Multiplying the equation by the common denominator x(x4)x(x - 4) simplifies the equation to x2x=0x^2 - x = 0. Solving this quadratic equation yields x=0x = 0 and x=1x = 1. Because x=0x = 0 leads to a division by zero in the original equation, it is extraneous. Therefore, the only valid real solution is 11.

Adım Adım Çözüm

1
Determine the common denominator and restrictions for the rational equation.
The common denominator is x(x4)=x24xx(x - 4) = x^2 - 4x. The restrictions are x0x \neq 0 and x4x \neq 4.
Finding the common denominator allows us to eliminate fractions, while the restrictions help us identify potential extraneous solutions.
2
Multiply the entire equation by the common denominator x(x4)x(x - 4).
x(x+2)3(x4)=12x(x + 2) - 3(x - 4) = 12
This step clears the rational expressions, leaving a polynomial equation.
3
Expand and simplify the polynomial equation.
x2+2x3x+12=12x^2 + 2x - 3x + 12 = 12, which simplifies to x2x=0x^2 - x = 0.
Expanding the terms allows us to combine like terms and set the quadratic equation to zero.
4
Factor the quadratic equation to solve for xx.
x(x1)=0x(x - 1) = 0, giving candidate solutions x=0x = 0 or x=1x = 1.
Applying the zero-product property identifies the roots of the quadratic equation.
5
Verify the candidate solutions against the initial restrictions.
Since x=0x = 0 makes the denominators in the original equation equal to zero, it is extraneous. The candidate solution x=1x = 1 is valid.
We must verify solutions because multiplying by a variable expression can introduce extraneous roots that make the original expressions undefined.

Anahtar Kavram

Solving rational equations by clearing denominators and checking for extraneous solutions.
Tahmini Süre:1m 30s
Soru 378Soru

During a science experiment, a liquid is cooled at a constant rate of 0.50.5 degrees Celsius per minute. What is the cooling rate of the liquid, in degrees Celsius per hour?

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Cevap: 30

Cevap

The cooling rate of the liquid is 3030 degrees Celsius per hour.
To find the cooling rate in degrees Celsius per hour, we multiply the rate per minute by the conversion factor. There are 6060 minutes in 11 hour. Multiplying 0.50.5 degrees Celsius per minute by 6060 minutes per hour yields 3030 degrees Celsius per hour.

Adım Adım Çözüm

1
Identify the initial cooling rate per minute.
0.50.5 degrees Celsius per minute
This is the rate given in the problem statement.
2
Convert minutes to hours by multiplying the rate by 6060.
3030 degrees Celsius per hour
An hour contains 6060 minutes, so the total temperature decrease in one hour will be 6060 times the decrease in one minute.

Anahtar Kavram

Unit conversions involving rates
Soru 379Soru

In the quadratic equation 2x212x+k=02x^2 - 12x + k = 0, kk is a constant. If the sum of the squares of the solutions to the equation is 2626, what is the value of kk?

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Cevap: 10

Cevap

The value of kk is 1010.
The correct answer is 1010. By expressing the sum of the squares of the solutions as x12+x22=(x1+x2)22x1x2x_1^2 + x_2^2 = (x_1 + x_2)^2 - 2x_1 x_2, we can substitute the sum of the solutions (122=6-\frac{-12}{2} = 6) and the product of the solutions (k2\frac{k}{2}) directly into the expression. This gives 26=36k26 = 36 - k. Solving for kk yields k=10k = 10. Alternatively, solving the quadratic equation using the quadratic formula yields solutions 3+1448k43 + \frac{\sqrt{144-8k}}{4} and 31448k43 - \frac{\sqrt{144-8k}}{4}. Squaring these solutions and setting their sum equal to 2626 simplifies to 18+2(1448k16)=2618 + 2\left(\frac{144-8k}{16}\right) = 26, which also solves to k=10k = 10.

Adım Adım Çözüm

1
Find the sum and product of the solutions using the coefficients of the quadratic equation.
The sum of the solutions is 66 and the product of the solutions is k2\frac{k}{2}.
By Vieta's formulas, for any quadratic equation ax2+bx+c=0ax^2 + bx + c = 0 with solutions x1x_1 and x2x_2, the sum of the solutions is x1+x2=bax_1 + x_2 = -\frac{b}{a} and the product of the solutions is x1x2=cax_1 x_2 = \frac{c}{a}.
2
Apply the algebraic identity to express the sum of the squares of the solutions in terms of their sum and product.
x12+x22=(x1+x2)22x1x2x_1^2 + x_2^2 = (x_1 + x_2)^2 - 2x_1 x_2
This identity allows us to substitute the sum and product of the solutions directly without solving for the individual solutions first.
3
Substitute the values and solve for kk.
26=622(k2)    26=36k    k=1026 = 6^2 - 2\left(\frac{k}{2}\right) \implies 26 = 36 - k \implies k = 10
Substituting the given sum of squares (2626), the sum of solutions (66), and the product of solutions (k2\frac{k}{2}) allows us to solve for the unknown constant kk directly.

Anahtar Kavram

Using the relationship between the roots and coefficients of a quadratic equation (Vieta's formulas) in combination with algebraic identities to solve for unknown constants.
Soru 380Soru

A commercial bakery uses an automated flour silo. The mass of the flour in the silo, FF, in kilograms, is modeled as a linear function of the time tt, in hours, after the bakery opens. The table below shows the mass of the flour remaining in the silo at two different times during the day:

Time (hours), ttMass of flour (kilograms), FF
331,8501,850
771,4901,490

If the mass of the flour in the silo decreases at a constant rate of rr kilograms per hour, what is the value of rr?

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Cevap: 90

Cevap

90
The rate of decrease of the flour is represented by the magnitude of the slope of the linear relationship. Using the points (3,1850)(3, 1850) and (7,1490)(7, 1490) from the table, the slope is calculated as 1490185073=3604=90\frac{1490 - 1850}{7 - 3} = \frac{-360}{4} = -90. This indicates that the mass of the flour decreases by 9090 kilograms per hour. Therefore, the value of rr is 9090.

Adım Adım Çözüm

1
Identify the data points representing time and mass from the table.
(t1,F1)=(3,1850)(t_1, F_1) = (3, 1850) and (t2,F2)=(7,1490)(t_2, F_2) = (7, 1490)
We need two coordinates to find the slope of the linear relationship.
2
Calculate the slope (rate of change) of the linear function.
Slope = 1490185073=90\frac{1490 - 1850}{7 - 3} = -90
The slope formula y2y1x2x1\frac{y_2 - y_1}{x_2 - x_1} gives the rate of change of the mass of the flour per hour.
3
Determine the value of rr based on the rate of decrease.
r=90r = 90
The rate of decrease is the positive magnitude of the rate of change.

Anahtar Kavram

Interpreting rate of change (slope) from tabular data in a linear context
Tahmini Süre:1m 30s
ÖncekiSayfa 19 / 31Sonraki
Tüm alıştırma soruları — SAT | Examkin