Tüm alıştırma soruları

612 soru

Soru 121Soru

In the xyxy-plane, the graph of the linear equation y=mx+by = mx + b, where mm and bb are constants, passes through the point (2,7)(2, 7). If this graph is translated 33 units to the right and 44 units down, the resulting graph passes through the point (4,2)(4, 2). What is the value of bb?

Cevabı ve açıklamayı göster

Cevap: 5

Cevap

5
The correct answer is 55. Since the original graph passes through (2,7)(2, 7) and undergoes a translation of 33 units to the right and 44 units down, the point (2,7)(2, 7) is translated to (2+3,74)=(5,3)(2 + 3, 7 - 4) = (5, 3) on the new graph. The translated graph also passes through (4,2)(4, 2). Using the slope formula on the two points (5,3)(5, 3) and (4,2)(4, 2) of the translated line gives a slope of 11. Since a translation preserves the slope, the original line also has a slope of 11. Substituting m=1m = 1 and (2,7)(2, 7) into the original equation y=mx+by = mx + b yields 7=1(2)+b7 = 1(2) + b, which simplifies to b=5b = 5.

Adım Adım Çözüm

1
Determine a point on the translated graph by translating the given point (2,7)(2, 7) on the original graph.
The point (5,3)(5, 3) is on the translated graph.
Since the entire graph is translated 33 units to the right and 44 units down, every point on the original graph is translated by the same vector (+3,4)(+3, -4).
2
Calculate the slope of the translated graph using the points (5,3)(5, 3) and (4,2)(4, 2).
The slope m=1m = 1.
The slope of a line passing through (x1,y1)(x_1, y_1) and (x2,y2)(x_2, y_2) is given by the change in y divided by the change in x.
3
Find the slope of the original graph.
The slope of the original graph is also 11.
Translating a line horizontally and vertically shifts its position but does not alter its slope.
4
Substitute the slope m=1m = 1 and the point (2,7)(2, 7) into the slope-intercept form of the original line, y=mx+by = mx + b, to solve for bb.
b=5b = 5.
This determines the value of the y-intercept of the original line.

Anahtar Kavram

Linear Equations in Two Variables
Soru 122Soru

An online store sells small gift boxes for 1010 dollars each and large gift boxes for 1515 dollars each. A customer wants to buy a total of at most 1010 boxes. If the customer must spend at least 120120 dollars on the boxes, what is the minimum number of large gift boxes the customer must buy?

Cevabı ve açıklamayı göster

Cevap: 4

Cevap

The minimum number of large gift boxes the customer must buy is 4.
Using the constraints from the problem, we set up the system of inequalities: x+y10x + y \leq 10 and 10x+15y12010x + 15y \geq 120. Expressing the first inequality as x10yx \leq 10 - y and substituting it into the second gives 10(10y)+15y12010(10 - y) + 15y \geq 120. Simplifying this results in 100+5y120100 + 5y \geq 120, which simplifies to 5y205y \geq 20, or y4y \geq 4. Therefore, the minimum number of large gift boxes the customer must buy is 44.

Adım Adım Çözüm

1
Define variables for the quantities of each box.
Let xx be the number of small boxes and yy be the number of large boxes.
Establishing variables is necessary to translate the word problem into algebraic inequalities.
2
Write the system of inequalities representing the constraints.
x+y10x + y \leq 10 and 10x+15y12010x + 15y \geq 120
The total number of boxes is at most 1010, and the total cost must be at least 120120 dollars.
3
Express xx in terms of yy using the first inequality.
x10yx \leq 10 - y
This allows substitution into the second inequality to solve for the target variable yy.
4
Substitute x10yx \leq 10 - y into the second inequality and simplify.
100+5y120100 + 5y \geq 120
Solving the resulting single-variable inequality will determine the possible values of yy.
5
Solve the inequality for yy.
y4y \geq 4
Subtracting 100100 and dividing by 55 isolates yy to show its minimum possible value is 44.

Anahtar Kavram

Systems of Linear Inequalities in Two Variables
Soru 123Soru

A sports store orders standard helmets for 2020 dollars each and premium helmets for 5050 dollars each. The store can spend at most 22002{}200 dollars on this order. The distributor requires the store to order at least 6060 helmets in total. If the store decides to order at least 1515 premium helmets, what is the maximum number of standard helmets that the store can order?

Cevabı ve açıklamayı göster

Cevap: 72

Cevap

The maximum number of standard helmets the store can order is 72.
By setting the number of premium helmets to its minimum allowed value of 1515 to maximize the budget remaining for standard helmets, we find 20x145020x \leq 1450, which yields x72.5x \leq 72.5. Since standard helmets must be ordered in whole numbers, the maximum number is 7272, which also satisfies the minimum total order of 6060 helmets (72+15=876072 + 15 = 87 \geq 60).

Adım Adım Çözüm

1
Define variables and translate constraints into inequalities
Let xx be the number of standard helmets and yy be the number of premium helmets. The constraints are 20x+50y220020x + 50y \leq 2200, x+y60x + y \geq 60, and y15y \geq 15.
To represent the problem's mathematical relationships using a system of linear inequalities.
2
Solve for the upper limit of xx using the budget constraint and the minimum value of yy
Since 20x220050y20x \leq 2200 - 50y, xx is maximized when yy is at its minimum value, y=15y = 15. Substituting y=15y = 15 yields 20x+7502200    20x1450    x72.520x + 750 \leq 2200 \implies 20x \leq 1450 \implies x \leq 72.5.
To find the maximum possible value of standard helmets under the budget constraint.
3
Verify with the minimum total order constraint and determine the maximum integer value
Checking x+y60x + y \geq 60 with y=15y = 15 gives x+1560    x45x + 15 \geq 60 \implies x \geq 45. Since xx must satisfy 45x72.545 \leq x \leq 72.5 and must be an integer, the maximum integer value is 7272.
To ensure the solution is physically possible as a whole number of items and satisfies all constraints.

Anahtar Kavram

Systems of Linear Inequalities in Two Variables
Soru 124Soru

A drone's battery charge is at 98%98\% when it begins a mission. During the mission, the battery charge decreases by 1.5%1.5\% per minute when the drone is hovering, and by 2.5%2.5\% per minute when it is flying horizontally. The drone flies horizontally for exactly twice as many minutes as it hovers. If the battery charge is at 33%33\% at the end of the mission, for how many minutes did the drone hover?

Cevabı ve açıklamayı göster

Cevap: 10

Cevap

The drone hovered for 10 minutes.
Let tt represent the number of minutes the drone hovers. Since the drone flies horizontally for twice as long as it hovers, it flies horizontally for 2t2t minutes. The total percentage drop in battery is 9833=6598 - 33 = 65. The equation representing the total decrease in battery charge is 1.5t+2.5(2t)=651.5t + 2.5(2t) = 65. Simplifying the equation yields 1.5t+5t=651.5t + 5t = 65, which becomes 6.5t=656.5t = 65. Dividing both sides of the equation by 6.56.5 gives t=10t = 10.

Adım Adım Çözüm

1
Define the variable for the unknown quantity.
Let tt be the number of minutes the drone spent hovering. The time spent flying horizontally is then 2t2t minutes.
The problem states that the horizontal flight time is exactly twice the hovering time.
2
Set up an equation representing the total decrease in battery charge.
The total percentage decrease is 1.5t+2.5(2t)=98331.5t + 2.5(2t) = 98 - 33.
The battery decreases by 1.5%1.5\% per minute of hovering, 2.5%2.5\% per minute of horizontal flight, and the total change is from 98%98\% to 33%33\%.
3
Simplify the equation and solve for tt.
6.5t=656.5t = 65, which gives t=10t = 10.
Combine like terms and divide both sides by 6.56.5 to isolate the variable.

Anahtar Kavram

Setting up and solving a linear equation in one variable from a real-world scenario.
Soru 125Soru

If the expression (2x+3)(3x+1)6x2(2x + 3)(3x + 1) - 6x^2 is rewritten in the form bx+cbx + c, where bb and cc are constants, what is the value of bb?

Cevabı ve açıklamayı göster

Cevap: 11

Cevap

The value of bb is 1111.
Expanding the expression (2x+3)(3x+1)6x2(2x + 3)(3x + 1) - 6x^2 yields (6x2+2x+9x+3)6x2(6x^2 + 2x + 9x + 3) - 6x^2. Combining the linear terms simplifies the expression to (6x2+11x+3)6x2(6x^2 + 11x + 3) - 6x^2, which further simplifies to 11x+311x + 3. Comparing this to the form bx+cbx + c, we see that the coefficient bb of the xx term is 1111.

Adım Adım Çözüm

1
Expand the product of the binomials (2x+3)(3x+1)(2x + 3)(3x + 1) using the distributive property.
6x2+2x+9x+36x^2 + 2x + 9x + 3
To rewrite the factored part of the expression in polynomial form.
2
Combine the linear terms 2x2x and 9x9x.
6x2+11x+36x^2 + 11x + 3
To simplify the expanded polynomial expression.
3
Subtract 6x26x^2 from the simplified polynomial expression.
11x+311x + 3
To complete the subtraction indicated in the original expression.
4
Compare the resulting expression 11x+311x + 3 to the form bx+cbx + c to identify the coefficient bb.
b=11b = 11
To determine the constant coefficient of the xx term.

Anahtar Kavram

Expanding products of binomials and combining like terms to find equivalent expressions.
Soru 126Soru

A chef is preparing portions of roasted vegetables and mashed potatoes for a catered event. Each portion of roasted vegetables requires 33 ounces of potatoes, and each portion of mashed potatoes requires 66 ounces of potatoes. The chef has a total of at most 9090 ounces of potatoes available. The chef must prepare at least 88 portions of roasted vegetables and at least 55 portions of mashed potatoes. If vv represents the number of portions of roasted vegetables that the chef prepares, what is the maximum possible value of vv?

Cevabı ve açıklamayı göster

Cevap: 20

Cevap

The maximum possible value of vv is 20.
The maximum number of portions of roasted vegetables the chef can prepare is 20 because minimizing the number of mashed potato portions to its boundary constraint of 5 maximizes the remaining resources, yielding 3v906(5)    3v60    v203v \leq 90 - 6(5) \implies 3v \leq 60 \implies v \leq 20.

Adım Adım Çözüm

1
Formulate the inequality representing the potato weight constraint.
3v+6p903v + 6p \leq 90, where vv is the number of portions of roasted vegetables and pp is the number of portions of mashed potatoes.
Each portion of roasted vegetables uses 33 ounces of potatoes, each portion of mashed potatoes uses 66 ounces of potatoes, and the total amount used cannot exceed 9090 ounces.
2
Formulate the inequalities representing the minimum quantity constraints.
v8v \geq 8 and p5p \geq 5
The chef must make at least 88 portions of roasted vegetables and at least 55 portions of mashed potatoes.
3
Isolate the variable vv in the potato limit inequality.
v302pv \leq 30 - 2p
Subtracting 6p6p from both sides of 3v+6p903v + 6p \leq 90 yields 3v906p3v \leq 90 - 6p, and dividing the entire inequality by 33 gives v302pv \leq 30 - 2p.
4
Determine the maximum value of vv by substituting the minimum possible value of pp.
v302(5)    v20v \leq 30 - 2(5) \implies v \leq 20
To maximize vv, we must minimize the subtracted term 2p2p. The minimum allowed value of pp is 55.

Anahtar Kavram

Optimization in systems of linear inequalities
Soru 127Soru

For the linear function ff, the graph of y=f(x)y = f(x) has a slope of 33 and contains the point (2,7)(2, 7). The graph of another linear function, gg, is parallel to the graph of ff. If g(0)=4g(0) = -4, what is the value of g(5)g(5)?

Cevabı ve açıklamayı göster

Cevap: 11

Cevap

11
Since the graph of gg is parallel to the graph of ff, it has the same slope of 33. The value g(0)=4g(0) = -4 indicates that the yy-intercept of the graph of gg is 4-4. Thus, the equation for g(x)g(x) is g(x)=3x4g(x) = 3x - 4. Evaluating this function at x=5x = 5 gives g(5)=3(5)4=11g(5) = 3(5) - 4 = 11.

Adım Adım Çözüm

1
Determine the slope of the function gg.
The slope of gg is 33.
Parallel lines in the coordinate plane have equal slopes, and the slope of the graph of ff is given as 33.
2
Write the equation for g(x)g(x).
g(x)=3x4g(x) = 3x - 4
Using the slope-intercept form g(x)=mx+bg(x) = mx + b with slope m=3m = 3 and yy-intercept b=g(0)=4b = g(0) = -4.
3
Evaluate g(5)g(5).
1111
Substitute x=5x = 5 into the equation for g(x)g(x) to get g(5)=3(5)4=11g(5) = 3(5) - 4 = 11.

Anahtar Kavram

Parallel lines have the same slope. A linear function can be written in slope-intercept form, y=mx+by = mx + b, where mm is the slope and bb is the yy-intercept.
Soru 128Soru

A local library has two types of study rooms: small rooms, which can accommodate up to 33 people, and large rooms, which can accommodate up to 88 people. The library has a total of 1515 study rooms. If the maximum capacity of all the study rooms combined is 8080 people, how many large study rooms does the library have?

Cevabı ve açıklamayı göster

Cevap: 7

Cevap

The correct answer is 7.
By representing the number of small rooms as ss and large rooms as ll, we set up the system of linear equations s+l=15s + l = 15 and 3s+8l=803s + 8l = 80. Solving the first equation for ss gives s=15ls = 15 - l. Substituting this into the second equation yields 3(15l)+8l=803(15 - l) + 8l = 80. Distributing and combining like terms results in 45+5l=8045 + 5l = 80. Subtracting 45 from both sides gives 5l=355l = 35, which simplifies to l=7l = 7. Thus, there are 7 large study rooms.

Adım Adım Çözüm

1
Set up the system of linear equations representing the total number of rooms and their total capacity.
s+l=15s + l = 15 and 3s+8l=803s + 8l = 80
We define ss as the number of small study rooms and ll as the number of large study rooms. The total number of rooms is 15, and the total capacity is 80.
2
Express the number of small rooms, ss, in terms of the number of large rooms, ll, using the first equation.
s=15ls = 15 - l
This allows for substitution into the capacity equation so that we can solve directly for the number of large study rooms.
3
Substitute the expression for ss into the capacity equation and solve the resulting single-variable equation for ll.
3(15l)+8l=80    453l+8l=80    45+5l=80    5l=35    l=73(15 - l) + 8l = 80 \implies 45 - 3l + 8l = 80 \implies 45 + 5l = 80 \implies 5l = 35 \implies l = 7
Substituting ss eliminates one variable, leaving a linear equation in terms of ll that can be solved using standard algebraic steps.

Anahtar Kavram

Solving systems of linear equations in a real-world context using substitution.
Soru 129Soru

If the expression 5(x22x)3(x24x)5(x^2 - 2x) - 3(x^2 - 4x) is rewritten in the form ax2+bxax^2 + bx, where aa and bb are constants, what is the value of aa?

Cevabı ve açıklamayı göster

Cevap: 2

Cevap

The value of aa is 22.
Distributing the constants outside the parentheses yields 5x210x3x2+12x5x^2 - 10x - 3x^2 + 12x. Combining the x2x^2 terms (5x23x2=2x25x^2 - 3x^2 = 2x^2) and the xx terms (10x+12x=2x-10x + 12x = 2x) gives the simplified equivalent expression 2x2+2x2x^2 + 2x. Comparing this directly to the form ax2+bxax^2 + bx, we find that the coefficient aa is 22.

Adım Adım Çözüm

1
Distribute the coefficients to the terms inside the parentheses.
5x210x3x2+12x5x^2 - 10x - 3x^2 + 12x
To expand the expression so that like terms can be combined.
2
Combine the coefficients of x2x^2 and the coefficients of xx.
2x2+2x2x^2 + 2x
To write the expression in simplified form.
3
Identify the value of aa by matching the simplified expression with ax2+bxax^2 + bx.
a=2a = 2
The constant aa represents the coefficient of the x2x^2 term.

Anahtar Kavram

Simplifying polynomial expressions by distributing constants and combining like terms.
Tahmini Süre:45s
Soru 130Soru

An artist sells small prints for 44 dollars each and large prints for 99 dollars each. The artist wants to sell at least 1515 prints in total and earn at least 8080 dollars from these sales. If the artist sells 55 small prints, what is the minimum number of large prints the artist must sell to meet both conditions?

Cevabı ve açıklamayı göster

Cevap: 10

Cevap

The minimum number of large prints the artist must sell is 10.
Substituting the value of small prints (x=5x = 5) into the total count inequality x+y15x + y \geq 15 gives 5+y155 + y \geq 15, which simplifies to y10y \geq 10. Substituting it into the earnings inequality 4x+9y804x + 9y \geq 80 yields 20+9y8020 + 9y \geq 80, which simplifies to y6.67y \geq 6.67. To satisfy both conditions, the value of yy must be at least 10.

Adım Adım Çözüm

1
Set up the inequalities for the system.
Let xx represent the number of small prints and yy represent the number of large prints. The constraint for the minimum number of prints is x+y15x + y \geq 15. The constraint for the minimum earnings is 4x+9y804x + 9y \geq 80.
To represent the given conditions as a system of linear inequalities in two variables.
2
Substitute the known value of small prints (x=5x = 5) into the inequalities.
Substituting x=5x = 5 into the first inequality gives 5+y155 + y \geq 15, which simplifies to y10y \geq 10. Substituting x=5x = 5 into the second inequality gives 4(5)+9y804(5) + 9y \geq 80, which simplifies to 20+9y8020 + 9y \geq 80, then 9y609y \geq 60, resulting in y2036.67y \geq \frac{20}{3} \approx 6.67.
To determine the range of values for the number of large prints (yy) under both constraints.
3
Determine the minimum integer value for yy that satisfies both inequalities.
The first constraint requires y10y \geq 10, and the second constraint requires y6.67y \geq 6.67. Since the number of prints must be an integer and both conditions must be satisfied, the minimum value is 1010.
To satisfy both inequalities simultaneously with the smallest possible integer value.

Anahtar Kavram

Systems of Linear Inequalities in Two Variables
Tahmini Süre:1m 0s
Soru 131Soru
The system of linear equations shown below contains constants aa and bb.
12(ax4y)=x12y+62xy=b\begin{aligned} \frac{1}{2}(ax - 4y) &= x - \frac{1}{2}y + 6 \\ 2x - y &= b \end{aligned}
If the system has infinitely many solutions, what is the value of a+ba + b?
Cevabı ve açıklamayı göster

Cevap: 12

Cevap

The correct answer is 12.
To find the value of a+ba + b that yields infinitely many solutions, we rewrite both equations in the standard form Ax+By=CAx + By = C. Simplifying the first equation gives (a2)x3y=12(a - 2)x - 3y = 12. Multiplying the second equation 2xy=b2x - y = b by 33 gives 6x3y=3b6x - 3y = 3b. For the system to have infinitely many solutions, the two equations must be equivalent, meaning a2=6a - 2 = 6 (which gives a=8a = 8) and 3b=123b = 12 (which gives b=4b = 4). The sum of these values is 8+4=128 + 4 = 12.

Adım Adım Çözüm

1
Distribute the fraction 12\frac{1}{2} on the left side of the first equation.
12ax2y=x12y+6\frac{1}{2}ax - 2y = x - \frac{1}{2}y + 6
To expand the expression and prepare it for simplification.
2
Group the xx and yy terms on the left side of the equation and the constants on the right side.
(12a1)x32y=6\left(\frac{1}{2}a - 1\right)x - \frac{3}{2}y = 6
To write the equation in standard linear form.
3
Multiply the entire equation by 22 to eliminate the fractional coefficients.
(a2)x3y=12(a - 2)x - 3y = 12
To simplify comparison with the second equation by working with integer coefficients.
4
Multiply the second equation, 2xy=b2x - y = b, by 33 to align the yy-coefficients with the first equation.
6x3y=3b6x - 3y = 3b
Two linear equations have infinitely many solutions if they represent the same line, which requires matching coefficients and constants.
5
Equate the corresponding xx-coefficients and constant terms from (a2)x3y=12(a - 2)x - 3y = 12 and 6x3y=3b6x - 3y = 3b.
a2=6    a=8a - 2 = 6 \implies a = 8 and 3b=12    b=43b = 12 \implies b = 4
To solve for the values of the constants aa and bb.
6
Calculate the sum of aa and bb.
8+4=128 + 4 = 12
To find the final requested value of a+ba + b.

Anahtar Kavram

Determining parameters for infinitely many solutions in a system of linear equations
Soru 132Soru

A company plans to install standard-charging ports and fast-charging ports at its office building. The company must install at least 1515 charging ports in total. Each fast-charging port requires 1212 kilowatts of power, and each standard-charging port requires 44 kilowatts of power. The electrical grid can supply a maximum of 120120 kilowatts of power for these ports. Additionally, the number of standard-charging ports must be at least twice the number of fast-charging ports. What is the maximum number of fast-charging ports the company can install?

Cevabı ve açıklamayı göster

Cevap: 6

Cevap

The maximum number of fast-charging ports the company can install is 6.
Representing the number of fast-charging ports by xx and standard-charging ports by yy yields the system of inequalities: x+y15x + y \geq 15, 12x+4y12012x + 4y \leq 120, and y2xy \geq 2x. The power constraint simplifies to 3x+y303x + y \leq 30, or y303xy \leq 30 - 3x. Combining this with y2xy \geq 2x gives 2x303x2x \leq 30 - 3x, which simplifies to 5x305x \leq 30, or x6x \leq 6. Substituting x=6x = 6 into the constraints gives y=12y = 12, which satisfies the total port constraint because 6+12=18156 + 12 = 18 \geq 15. Therefore, the maximum number of fast-charging ports is 6.

Adım Adım Çözüm

1
Define variables and write the system of inequalities representing the constraints.
Let xx be the number of fast-charging ports and yy be the number of standard-charging ports. The constraints are:
1) x+y15x + y \geq 15
2) 12x+4y12012x + 4y \leq 120
3) y2xy \geq 2x
4) x0,y0x \geq 0, y \geq 0
This translates the word problem constraints into a system of linear inequalities.
2
Simplify the power capacity inequality.
3x+y303x + y \leq 30, which can be rewritten as y303xy \leq 30 - 3x.
Dividing the terms by 4 simplifies the coefficients, making algebraic manipulation easier.
3
Combine the simplified inequality with the charging port ratio constraint to find the upper limit for xx.
Since 2xy2x \leq y and y303xy \leq 30 - 3x, we have 2x303x2x \leq 30 - 3x.
Adding 3x3x to both sides yields 5x305x \leq 30.
Dividing by 5 gives x6x \leq 6.
This determines the maximum possible value for the number of fast-charging ports.
4
Verify that the upper limit x=6x = 6 satisfies all system constraints with integer values.
If x=6x = 6, then y2(6)=12y \geq 2(6) = 12 and y303(6)=12y \leq 30 - 3(6) = 12, which means y=12y = 12.
Checking the total port constraint: x+y=6+12=18x + y = 6 + 12 = 18. Since 181518 \geq 15, the point (6,12)(6, 12) satisfies all constraints.
Since the number of ports must be integers, we must confirm that x=6x = 6 yields a valid integer coordinate (6,12)(6, 12) that lies within the feasible region.

Anahtar Kavram

Maximizing a variable under a system of linear inequalities in two variables.
Soru 133Soru

In the xyxy-plane, the graph of the equation ax+by=24ax + by = 24, where aa and bb are constants, is a line. The line has an xx-intercept of (d,0)(d, 0) and a yy-intercept of (0,d6)(0, d - 6), where d>6d > 6 is a constant. If the line passes through the point (2,5)(2, 5), what is the value of a+ba + b?

Cevabı ve açıklamayı göster

Cevap: 6

Cevap

6
Substituting the intercepts (d,0)(d, 0) and (0,d6)(0, d-6) into ax+by=24ax + by = 24 gives a=24/da = 24/d and b=24/(d6)b = 24/(d-6). Using the point (2,5)(2, 5), we get 2(24/d)+5(24/(d6))=242(24/d) + 5(24/(d-6)) = 24, which simplifies to 2/d+5/(d6)=12/d + 5/(d-6) = 1. Solving for dd yields d213d+12=0d^2 - 13d + 12 = 0, giving d=12d = 12 or d=1d = 1. Given d>6d > 6, we have d=12d = 12. Substituting d=12d = 12 back gives a=2a = 2 and b=4b = 4, so a+b=6a + b = 6.

Adım Adım Çözüm

1
Find expressions for aa and bb in terms of dd by substituting the given intercepts.
a=24da = \frac{24}{d} and b=24d6b = \frac{24}{d-6}
The xx-intercept (d,0)(d, 0) and yy-intercept (0,d6)(0, d-6) lie on the line ax+by=24ax + by = 24.
2
Substitute the point (2,5)(2, 5) into the line's equation.
2a+5b=242a + 5b = 24
The point (2,5)(2, 5) lies on the line.
3
Substitute the expressions for aa and bb into 2a+5b=242a + 5b = 24 and simplify.
2d+5d6=1\frac{2}{d} + \frac{5}{d-6} = 1
To create a single equation in terms of the variable dd.
4
Solve the rational equation for dd.
d=12d = 12
Multiplying by the common denominator d(d6)d(d-6) leads to the quadratic equation d213d+12=0d^2 - 13d + 12 = 0, which factors as (d12)(d1)=0(d-12)(d-1) = 0. Since the problem states d>6d > 6, the only valid solution is d=12d = 12.
5
Calculate aa and bb using d=12d = 12, and find their sum.
a=2a = 2, b=4b = 4, and a+b=6a + b = 6
Substituting d=12d = 12 into the expressions for aa and bb yields the constant coefficients, and summing them provides the final requested value.

Anahtar Kavram

Using intercepts and a given point on a line in the coordinate plane to solve for the parameters of its linear equation.
Soru 134Soru

In the xyxy-plane, the system of linear equations below has infinitely many solutions, where aa, bb, and cc are constants and c>0c > 0:

3x4y=10ax+by=c\begin{aligned} 3x - 4y &= 10 \\ ax + by &= c \end{aligned}

If the graph of the second equation in the system passes through the point (a,b)(a, b), what is the value of cc?

Cevabı ve açıklamayı göster

Cevap: 4

Cevap

The correct answer is 4.
Since the system has infinitely many solutions, the two equations are equivalent. This means the coefficients are proportional, so we can write a=3ka = 3k, b=4kb = -4k, and c=10kc = 10k for some constant kk. Because the line passes through (a,b)(a, b), substituting these coordinates into the second equation gives a2+b2=ca^2 + b^2 = c. Substituting the expressions in terms of kk results in (3k)2+(4k)2=10k(3k)^2 + (-4k)^2 = 10k, which simplifies to 25k2=10k25k^2 = 10k. Since c>0c > 0, we have k>0k > 0, and dividing by kk gives 25k=1025k = 10, so k=0.4k = 0.4. Finally, c=10(0.4)=4c = 10(0.4) = 4.

Adım Adım Çözüm

1
Set up a proportionality constant to relate the coefficients of the two equations.
a=3ka = 3k, b=4kb = -4k, and c=10kc = 10k for a constant kk.
Since the system has infinitely many solutions, the equations represent the same line, meaning their coefficients and constants must be proportional.
2
Substitute the point (a,b)(a, b) into the second equation ax+by=cax + by = c.
a2+b2=ca^2 + b^2 = c
The graph of the equation passes through the point (a,b)(a, b), so the coordinates must satisfy the equation.
3
Substitute the parametric expressions of aa, bb, and cc into the equation a2+b2=ca^2 + b^2 = c.
25k2=10k25k^2 = 10k
This allows us to solve for the parameter kk using a single variable quadratic equation.
4
Solve the equation 25k2=10k25k^2 = 10k for kk, given that k>0k > 0.
k=0.4k = 0.4
Since c>0c > 0 and c=10kc = 10k, kk must be strictly positive, allowing us to divide both sides by kk.
5
Compute the final value of cc using the value of kk.
c=4c = 4
Substituting k=0.4k = 0.4 back into the expression c=10kc = 10k gives the value of cc.

Anahtar Kavram

Systems of linear equations with infinitely many solutions and coordinate geometry constraints
Soru 135Soru

If 23(6x9)34(4x8)=12(x+10)\frac{2}{3}(6x - 9) - \frac{3}{4}(4x - 8) = \frac{1}{2}(x + 10), what is the value of xx?

Cevabı ve açıklamayı göster

Cevap: 10

Cevap

The correct answer is 10.
Distributing the fractions on the left-hand side of the equation simplifies the expression to xx. Setting this equal to the right-hand side yields the equation x=12(x+10)x = \frac{1}{2}(x + 10). Multiplying both sides by 2 gives 2x=x+102x = x + 10, and subtracting xx from both sides gives the correct value of 10.

Adım Adım Çözüm

1
Distribute the fraction 23\frac{2}{3} to the terms inside the first parentheses, (6x9)(6x - 9), and distribute the fraction 34-\frac{3}{4} to the terms inside the second parentheses, (4x8)(4x - 8).
4x63x+6=12(x+10)4x - 6 - 3x + 6 = \frac{1}{2}(x + 10)
Applying the distributive property removes the parentheses so that like terms can be combined.
2
Combine the variable terms and constant terms on the left side of the equation.
x=12(x+10)x = \frac{1}{2}(x + 10)
Combining 4x4x and 3x-3x yields xx, while 6-6 and 66 cancel each other out.
3
Multiply both sides of the equation by 2 to eliminate the fraction.
2x=x+102x = x + 10
Multiplying by the denominator simplifies the equation by removing the fraction.
4
Subtract xx from both sides of the equation to isolate the variable.
x=10x = 10
Subtracting xx isolates the variable xx on the left side of the equation.

Anahtar Kavram

Solving linear equations in one variable by applying the distributive property and combining like terms.
Soru 136Soru

For all positive values of xx and yy, the expression (3x2y4)39x4y7\frac{(3x^2 y^4)^3}{9x^4 y^7} can be written in the form axbyca x^b y^c, where aa, bb, and cc are constants. What is the value of a+b+ca + b + c?

Cevabı ve açıklamayı göster

Cevap: 10

Cevap

The value of a+b+ca + b + c is 1010.
To find the value of a+b+ca + b + c, we simplify the given expression using the rules of exponents. First, apply the power of a product rule and power of a power rule to the numerator: (3x2y4)3=33(x2)3(y4)3=27x6y12(3x^2 y^4)^3 = 3^3 (x^2)^3 (y^4)^3 = 27x^6y^{12}. Next, divide this by the denominator: 27x6y129x4y7\frac{27x^6y^{12}}{9x^4y^7}. Divide the coefficients to get 279=3\frac{27}{9} = 3, and apply the quotient rule for exponents to the variable terms: x64=x2x^{6-4} = x^2 and y127=y5y^{12-7} = y^5. The fully simplified expression is 3x2y53x^2y^5, which matches the form axbyca x^b y^c. Comparing coefficients and exponents, we find a=3a = 3, b=2b = 2, and c=5c = 5. Summing these values gives 3+2+5=103 + 2 + 5 = 10.

Adım Adım Çözüm

1
Simplify the numerator of the expression using exponent rules.
27x6y1227x^6y^{12}
Applying the power of a product rule (ab)n=anbn(ab)^n = a^n b^n and the power of a power rule (am)n=amn(a^m)^n = a^{mn} to (3x2y4)3(3x^2 y^4)^3 gives 33x2×3y4×3=27x6y123^3 \cdot x^{2 \times 3} \cdot y^{4 \times 3} = 27x^6y^{12}.
2
Divide the simplified numerator by the denominator.
3x2y53x^2y^5
Divide the coefficients (27÷9=327 \div 9 = 3) and subtract the exponents of the corresponding variables using the quotient of powers rule aman=amn\frac{a^m}{a^n} = a^{m-n} (x64=x2x^{6-4} = x^2 and y127=y5y^{12-7} = y^5).
3
Identify the values of the constants aa, bb, and cc from the simplified expression 3x2y53x^2y^5.
a=3a = 3, b=2b = 2, and c=5c = 5
Comparing the simplified expression 3x2y53x^2y^5 with the template axbyca x^b y^c yields a=3a = 3, b=2b = 2, and c=5c = 5.
4
Calculate the sum of aa, bb, and cc.
1010
Adding the identified constant values together: 3+2+5=103 + 2 + 5 = 10.

Anahtar Kavram

Simplifying exponential expressions using exponent rules
Soru 137Soru
Consider the system of equations below:
13x+14y=5xy=8\begin{aligned} \frac{1}{3}x + \frac{1}{4}y &= 5 \\ x - y &= 8 \end{aligned}
If (x,y)(x, y) is the solution to the system, what is the value of yy?
Cevabı ve açıklamayı göster

Cevap: 4

Cevap

The value of yy is 44.
Substituting x=y+8x = y + 8 from the second equation into the first equation yields 13(y+8)+14y=5\frac{1}{3}(y + 8) + \frac{1}{4}y = 5. Multiplying the entire equation by 1212 to clear denominators gives 4(y+8)+3y=604(y + 8) + 3y = 60, which simplifies to 7y+32=607y + 32 = 60. Solving for yy gives 7y=287y = 28, or y=4y = 4.

Adım Adım Çözüm

1
Express xx in terms of yy from the second equation.
x=y+8x = y + 8
This allows for substitution into the first equation to solve for yy directly.
2
Substitute x=y+8x = y + 8 into the first equation.
13(y+8)+14y=5_\frac{1}{3}(y + 8) + \frac{1}{4}y = 5
This reduces the system to a single-variable linear equation in terms of yy.
3
Multiply the entire equation by the least common multiple of the denominators, which is 1212.
4(y+8)+3y=604(y + 8) + 3y = 60
This clears the fractional coefficients and simplifies the arithmetic.
4
Distribute the 44 and combine like terms.
7y+32=607y + 32 = 60
Simplifies the equation to prepare for isolating the variable yy.
5
Isolate the variable term by subtracting 3232 from both sides, then dividing by 77.
y=4y = 4
This gives the final value of yy that satisfies the system.

Anahtar Kavram

Solving systems of linear equations using substitution and clearing fractional coefficients
Soru 138Soru

A state department of transportation models the relationship between the age of a highway, in years, and its road quality index on a scale from 00 to 100100. The index decreases at a constant rate with respect to the age of the highway. At age 44 years, the highway has a road quality index of 8282. At age 1212 years, the highway has a road quality index of 6666. According to the model, after how many years from its construction will the highway's road quality index reach 5050?

Cevabı ve açıklamayı göster

Cevap: 20

Cevap

According to the model, the highway's road quality index will reach 5050 after 2020 years.
Since the relationship is linear, the rate of change is constant. Using the points (4,82)(4, 82) and (12,66)(12, 66), the slope is 6682124=2\frac{66 - 82}{12 - 4} = -2. The linear function can be written in point-slope form as I82=2(t4)I - 82 = -2(t - 4), which simplifies to I=2t+90I = -2t + 90. Setting I=50I = 50 yields the equation 50=2t+9050 = -2t + 90. Subtracting 9090 from both sides gives 40=2t-40 = -2t, and dividing by 2-2 results in t=20t = 20. Therefore, the index reaches 5050 after 2020 years.

Adım Adım Çözüm

1
Calculate the slope (rate of change) of the linear function.
The slope is 2-2.
Since the index decreases at a constant rate, the relationship is linear. The slope is calculated as the change in the road quality index divided by the change in the highway's age: 6682124=168=2\frac{66 - 82}{12 - 4} = \frac{-16}{8} = -2.
2
Determine the linear equation relating the road quality index, II, and the age, tt.
I=2t+90I = -2t + 90
Using the point-slope formula with the point (4,82)(4, 82) and slope 2-2: I82=2(t4)I82=2t+8I=2t+90I - 82 = -2(t - 4) \Rightarrow I - 82 = -2t + 8 \Rightarrow I = -2t + 90.
3
Solve for the age, tt, when the index II is 5050.
t=20t = 20
Substitute 5050 for II in the equation: 50=2t+9050 = -2t + 90. Subtract 9090 from both sides to get 40=2t-40 = -2t. Divide by 2-2 to find t=20t = 20.

Anahtar Kavram

Writing and solving linear equations from two points
Soru 139Soru

In the xyxy-plane, a point (x,y)(x, y) is in the solution set of the system of inequalities below:

x2y6x - 2y \leq -6
x+y11x + y \leq 11
y5y \leq 5

What is the maximum possible value of xx?

Cevabı ve açıklamayı göster

Cevap: 4

Cevap

The maximum possible value of xx is 44.
The maximum possible value of xx is 44. For all points in the solution set where y5y \leq 5, the active upper bound is x2y6x \leq 2y - 6. Since 2y62y - 6 increases as yy increases, the maximum value of xx occurs at the maximum boundary y=5y = 5, giving x=2(5)6=4x = 2(5) - 6 = 4.

Adım Adım Çözüm

1
Express xx in terms of yy using the first two inequalities.
x2y6x \leq 2y - 6 and x11yx \leq 11 - y
To isolate the variable xx and analyze how its upper bound is constrained by yy.
2
Apply the third inequality constraint, y5y \leq 5, to find the limits on these upper bounds.
2y642y - 6 \leq 4 and 11y611 - y \geq 6
Since yy cannot exceed 55, the value of 2y62y - 6 is maximized when y=5y = 5, and 11y11 - y is minimized when y=5y = 5.
3
Compare the two upper bounds to determine the active constraint for the domain y5y \leq 5.
Since 2y642y - 6 \leq 4 and 11y611 - y \geq 6, the active bound is x2y6x \leq 2y - 6.
For any point to satisfy the system, xx must be less than or equal to both bounds, meaning it is restricted by the smaller of the two bounds.
4
Calculate the maximum value of xx at the boundary point.
x=4x = 4 at the point (4,5)(4, 5)
The function 2y62y - 6 is increasing with respect to yy, so its maximum value occurs at the largest possible value of yy, which is 55.

Anahtar Kavram

Finding the maximum value of a coordinate within a system of linear inequalities.
Soru 140Soru

In the xyxy-plane, a point (x,y)(x, y) lies in the solution set of the system of inequalities below.

yx+8y \leq -x + 8
y2x+2y \leq 2x + 2

What is the maximum possible value of yy?

Cevabı ve açıklamayı göster

Cevap: 6

Cevap

The maximum possible value of yy is 6.
The solution set to the system of inequalities is the region in the coordinate plane that lies on or below both boundary lines, y=x+8y = -x + 8 and y=2x+2y = 2x + 2. The maximum yy-value in this region occurs at the intersection of the two lines. Solving the system of equations by setting x+8=2x+2-x + 8 = 2x + 2 gives 3x=63x = 6, which simplifies to x=2x = 2. Substituting x=2x = 2 back into either equation yields y=6y = 6. Therefore, the maximum possible value of yy is 6.

Adım Adım Çözüm

1
Set the two boundary equations equal to each other to find the xx-coordinate of the intersection point.
x+8=2x+2    3x=6    x=2-x + 8 = 2x + 2 \implies 3x = 6 \implies x = 2
Since the solution region is bounded from above by both inequalities, the maximum value of yy must occur at the intersection of the two boundary lines.
2
Substitute the xx-value back into one of the equations to find the corresponding yy-value.
y=2(2)+2=6y = 2(2) + 2 = 6
This determines the yy-coordinate of the intersection point, which represents the maximum height of the shaded region.

Anahtar Kavram

Systems of Linear Inequalities in Two Variables
Tahmini Süre:45s
ÖncekiSayfa 7 / 31Sonraki
Tüm alıştırma soruları — SAT | Examkin