Algebra

432 soru

Soru 201Soru

In the xyxy-plane, the system of linear equations below has infinitely many solutions, where aa, bb, and cc are constants and c>0c > 0:

3x4y=10ax+by=c\begin{aligned} 3x - 4y &= 10 \\ ax + by &= c \end{aligned}

If the graph of the second equation in the system passes through the point (a,b)(a, b), what is the value of cc?

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Cevap: 4

Cevap

The correct answer is 4.
Since the system has infinitely many solutions, the two equations are equivalent. This means the coefficients are proportional, so we can write a=3ka = 3k, b=4kb = -4k, and c=10kc = 10k for some constant kk. Because the line passes through (a,b)(a, b), substituting these coordinates into the second equation gives a2+b2=ca^2 + b^2 = c. Substituting the expressions in terms of kk results in (3k)2+(4k)2=10k(3k)^2 + (-4k)^2 = 10k, which simplifies to 25k2=10k25k^2 = 10k. Since c>0c > 0, we have k>0k > 0, and dividing by kk gives 25k=1025k = 10, so k=0.4k = 0.4. Finally, c=10(0.4)=4c = 10(0.4) = 4.

Adım Adım Çözüm

1
Set up a proportionality constant to relate the coefficients of the two equations.
a=3ka = 3k, b=4kb = -4k, and c=10kc = 10k for a constant kk.
Since the system has infinitely many solutions, the equations represent the same line, meaning their coefficients and constants must be proportional.
2
Substitute the point (a,b)(a, b) into the second equation ax+by=cax + by = c.
a2+b2=ca^2 + b^2 = c
The graph of the equation passes through the point (a,b)(a, b), so the coordinates must satisfy the equation.
3
Substitute the parametric expressions of aa, bb, and cc into the equation a2+b2=ca^2 + b^2 = c.
25k2=10k25k^2 = 10k
This allows us to solve for the parameter kk using a single variable quadratic equation.
4
Solve the equation 25k2=10k25k^2 = 10k for kk, given that k>0k > 0.
k=0.4k = 0.4
Since c>0c > 0 and c=10kc = 10k, kk must be strictly positive, allowing us to divide both sides by kk.
5
Compute the final value of cc using the value of kk.
c=4c = 4
Substituting k=0.4k = 0.4 back into the expression c=10kc = 10k gives the value of cc.

Anahtar Kavram

Systems of linear equations with infinitely many solutions and coordinate geometry constraints
Soru 202Soru

If 23(6x9)34(4x8)=12(x+10)\frac{2}{3}(6x - 9) - \frac{3}{4}(4x - 8) = \frac{1}{2}(x + 10), what is the value of xx?

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Cevap: 10

Cevap

The correct answer is 10.
Distributing the fractions on the left-hand side of the equation simplifies the expression to xx. Setting this equal to the right-hand side yields the equation x=12(x+10)x = \frac{1}{2}(x + 10). Multiplying both sides by 2 gives 2x=x+102x = x + 10, and subtracting xx from both sides gives the correct value of 10.

Adım Adım Çözüm

1
Distribute the fraction 23\frac{2}{3} to the terms inside the first parentheses, (6x9)(6x - 9), and distribute the fraction 34-\frac{3}{4} to the terms inside the second parentheses, (4x8)(4x - 8).
4x63x+6=12(x+10)4x - 6 - 3x + 6 = \frac{1}{2}(x + 10)
Applying the distributive property removes the parentheses so that like terms can be combined.
2
Combine the variable terms and constant terms on the left side of the equation.
x=12(x+10)x = \frac{1}{2}(x + 10)
Combining 4x4x and 3x-3x yields xx, while 6-6 and 66 cancel each other out.
3
Multiply both sides of the equation by 2 to eliminate the fraction.
2x=x+102x = x + 10
Multiplying by the denominator simplifies the equation by removing the fraction.
4
Subtract xx from both sides of the equation to isolate the variable.
x=10x = 10
Subtracting xx isolates the variable xx on the left side of the equation.

Anahtar Kavram

Solving linear equations in one variable by applying the distributive property and combining like terms.
Soru 203Soru

If 5(2a3)3(4a1)=(a8)5(2a - 3) - 3(4a - 1) = -(a - 8), what is the value of aa?

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Cevap: -20

Cevap

-20
Distributing the constants on both sides of the equation 5(2a3)3(4a1)=(a8)5(2a - 3) - 3(4a - 1) = -(a - 8) yields 10a1512a+3=a+810a - 15 - 12a + 3 = -a + 8. Combining like terms on the left side gives 2a12=a+8-2a - 12 = -a + 8. Adding 2a2a to both sides results in 12=a+8-12 = a + 8. Subtracting 88 from both sides gives the correct value of aa, which is 20-20.

Adım Adım Çözüm

1
Distribute the coefficients to the terms inside the parentheses on both sides of the equation.
10a1512a+3=a+810a - 15 - 12a + 3 = -a + 8
To eliminate parentheses and allow terms to be combined, apply the distributive property: 5(2a3)=10a155(2a - 3) = 10a - 15, 3(4a1)=12a+3-3(4a - 1) = -12a + 3, and (a8)=a+8-(a - 8) = -a + 8.
2
Combine like terms on the left side of the equation.
2a12=a+8-2a - 12 = -a + 8
Simplify the left side by combining the variable terms (10a12a=2a10a - 12a = -2a) and the constant terms (15+3=12-15 + 3 = -12).
3
Isolate the variable aa on one side of the equation.
a=20a = -20
Add 2a2a to both sides of the equation to get 12=a+8-12 = a + 8, then subtract 88 from both sides to find that a=20a = -20.

Anahtar Kavram

Solving linear equations in one variable using the distributive property, combining like terms, and isolating the variable.
Tahmini Süre:1m 30s
Soru 204Soru

Consider the system of linear equations below, where kk is a constant:

3x2y=7kx+3y=18\begin{aligned} 3x - 2y &= 7 \\ kx + 3y &= 18 \end{aligned}

If the system has a solution (x,y)(x, y) such that x+y=4x + y = 4, what is the value of kk?

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Cevap: 5

Cevap

5
The correct answer is 55. To find the value of kk, we first express xx in terms of yy using the given constraint equation: x=4yx = 4 - y. Next, we substitute this expression into the first equation of the system: 3(4y)2y=73(4 - y) - 2y = 7. Distributing and combining like terms yields 125y=712 - 5y = 7. Solving for yy gives y=1y = 1. Substituting this back into the constraint equation gives x=41=3x = 4 - 1 = 3. Finally, we substitute the solution point (3,1)(3, 1) into the second equation: k(3)+3(1)=18    3k+3=18    3k=15    k=5k(3) + 3(1) = 18 \implies 3k + 3 = 18 \implies 3k = 15 \implies k = 5.

Adım Adım Çözüm

1
Express one variable in terms of the other using the given constraint equation x+y=4x + y = 4.
x=4yx = 4 - y
This allows us to substitute the expression for xx into the first equation to reduce it to a single variable.
2
Substitute x=4yx = 4 - y into the first equation 3x2y=73x - 2y = 7 and solve for yy.
3(4y)2y=7    123y2y=7    125y=7    5y=5    y=13(4-y) - 2y = 7 \implies 12 - 3y - 2y = 7 \implies 12 - 5y = 7 \implies -5y = -5 \implies y = 1
By solving this linear equation, we find the unique y-coordinate of the system's solution.
3
Substitute the value of y=1y = 1 back into the constraint equation to find xx.
x=41=3x = 4 - 1 = 3
This determines the x-coordinate of the solution point, giving us the full solution (3,1)(3, 1).
4
Substitute the point (3,1)(3, 1) into the second equation kx+3y=18kx + 3y = 18 to solve for the constant kk.
k(3)+3(1)=18    3k+3=18    3k=15    k=5k(3) + 3(1) = 18 \implies 3k + 3 = 18 \implies 3k = 15 \implies k = 5
Since the solution must satisfy all equations in the system, we can solve for kk using the coordinates we found.

Anahtar Kavram

Solving systems of linear equations under linear constraints using algebraic substitution.
Tahmini Süre:2m 0s
Soru 205Soru
Consider the system of equations below:
13x+14y=5xy=8\begin{aligned} \frac{1}{3}x + \frac{1}{4}y &= 5 \\ x - y &= 8 \end{aligned}
If (x,y)(x, y) is the solution to the system, what is the value of yy?
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Cevap: 4

Cevap

The value of yy is 44.
Substituting x=y+8x = y + 8 from the second equation into the first equation yields 13(y+8)+14y=5\frac{1}{3}(y + 8) + \frac{1}{4}y = 5. Multiplying the entire equation by 1212 to clear denominators gives 4(y+8)+3y=604(y + 8) + 3y = 60, which simplifies to 7y+32=607y + 32 = 60. Solving for yy gives 7y=287y = 28, or y=4y = 4.

Adım Adım Çözüm

1
Express xx in terms of yy from the second equation.
x=y+8x = y + 8
This allows for substitution into the first equation to solve for yy directly.
2
Substitute x=y+8x = y + 8 into the first equation.
13(y+8)+14y=5_\frac{1}{3}(y + 8) + \frac{1}{4}y = 5
This reduces the system to a single-variable linear equation in terms of yy.
3
Multiply the entire equation by the least common multiple of the denominators, which is 1212.
4(y+8)+3y=604(y + 8) + 3y = 60
This clears the fractional coefficients and simplifies the arithmetic.
4
Distribute the 44 and combine like terms.
7y+32=607y + 32 = 60
Simplifies the equation to prepare for isolating the variable yy.
5
Isolate the variable term by subtracting 3232 from both sides, then dividing by 77.
y=4y = 4
This gives the final value of yy that satisfies the system.

Anahtar Kavram

Solving systems of linear equations using substitution and clearing fractional coefficients
Soru 206Soru

A state department of transportation models the relationship between the age of a highway, in years, and its road quality index on a scale from 00 to 100100. The index decreases at a constant rate with respect to the age of the highway. At age 44 years, the highway has a road quality index of 8282. At age 1212 years, the highway has a road quality index of 6666. According to the model, after how many years from its construction will the highway's road quality index reach 5050?

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Cevap: 20

Cevap

According to the model, the highway's road quality index will reach 5050 after 2020 years.
Since the relationship is linear, the rate of change is constant. Using the points (4,82)(4, 82) and (12,66)(12, 66), the slope is 6682124=2\frac{66 - 82}{12 - 4} = -2. The linear function can be written in point-slope form as I82=2(t4)I - 82 = -2(t - 4), which simplifies to I=2t+90I = -2t + 90. Setting I=50I = 50 yields the equation 50=2t+9050 = -2t + 90. Subtracting 9090 from both sides gives 40=2t-40 = -2t, and dividing by 2-2 results in t=20t = 20. Therefore, the index reaches 5050 after 2020 years.

Adım Adım Çözüm

1
Calculate the slope (rate of change) of the linear function.
The slope is 2-2.
Since the index decreases at a constant rate, the relationship is linear. The slope is calculated as the change in the road quality index divided by the change in the highway's age: 6682124=168=2\frac{66 - 82}{12 - 4} = \frac{-16}{8} = -2.
2
Determine the linear equation relating the road quality index, II, and the age, tt.
I=2t+90I = -2t + 90
Using the point-slope formula with the point (4,82)(4, 82) and slope 2-2: I82=2(t4)I82=2t+8I=2t+90I - 82 = -2(t - 4) \Rightarrow I - 82 = -2t + 8 \Rightarrow I = -2t + 90.
3
Solve for the age, tt, when the index II is 5050.
t=20t = 20
Substitute 5050 for II in the equation: 50=2t+9050 = -2t + 90. Subtract 9090 from both sides to get 40=2t-40 = -2t. Divide by 2-2 to find t=20t = 20.

Anahtar Kavram

Writing and solving linear equations from two points
Soru 207Soru

In the xyxy-plane, a point with coordinates (x,y)(x, y) lies in the solution set of the system of inequalities below.

yx+7y \leq -x + 7
y2x5y \geq 2x - 5
y0y \geq 0

What is the maximum possible value of xx?

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Cevap: 4

Cevap

The maximum possible value of xx is 4.
To find the maximum possible value of xx in the solution set, we analyze the boundaries of the system. The inequality yx+7y \leq -x + 7 can be rewritten as x7yx \leq 7 - y. The inequality y2x5y \geq 2x - 5 can be rewritten as x0.5y+2.5x \leq 0.5y + 2.5. For any point in the solution set, xx must be less than or equal to both 7y7 - y and 0.5y+2.50.5y + 2.5. Since y0y \geq 0, the maximum value of xx will occur where these two upper bounds are equal: 7y=0.5y+2.57 - y = 0.5y + 2.5, which simplifies to 1.5y=4.51.5y = 4.5, or y=3y = 3. Substituting y=3y = 3 back into either equation gives x=4x = 4. For any y>3y > 3, x7y<4x \leq 7 - y < 4. For any y<3y < 3, x0.5y+2.5<4x \leq 0.5y + 2.5 < 4. Thus, the maximum possible value of xx is 4.

Adım Adım Çözüm

1
Express the boundaries of xx in terms of yy from the given inequalities.
x7yx \leq 7 - y and x0.5y+2.5x \leq 0.5y + 2.5
To find the upper limits on xx, we solve each inequality for xx.
2
Find the intersection point of the two boundary lines by setting the expressions equal to each other.
7y=0.5y+2.5    1.5y=4.5    y=37 - y = 0.5y + 2.5 \implies 1.5y = 4.5 \implies y = 3. Substituting y=3y = 3 gives x=4x = 4.
The maximum value of xx occurs at the intersection of the two boundary constraints since one boundary increases with yy and the other decreases with yy.
3
Verify that the intersection point (4,3)(4, 3) satisfies all three inequalities.
34+73 \leq -4 + 7 (true), 32(4)53 \geq 2(4) - 5 (true), and 303 \geq 0 (true).
Ensuring the point lies within the solution set confirms it is a valid maximum.

Anahtar Kavram

Systems of Linear Inequalities in Two Variables
Soru 208Soru

A shipping company uses a cargo plane to transport two types of cargo containers: Type A and Type B. Let xx represent the number of Type A containers, and let yy represent the number of Type B containers. The constraints on the shipment are represented by the system of inequalities below:

x+y453x+5y165\begin{aligned} x + y &\leq 45 \\ 3x + 5y &\leq 165 \end{aligned}

If the plane must carry at least 1010 Type A containers, what is the maximum number of Type B containers the plane can transport?

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Cevap: 27

Cevap

27
The correct answer of 27 is found by substituting the minimum value of xx, which is 10, into the second inequality constraint. This yields 3(10)+5y1653(10) + 5y \leq 165, which simplifies to 5y1355y \leq 135, or y27y \leq 27. Since the coordinate pair (10, 27) also satisfies the first inequality constraint (10+27=374510 + 27 = 37 \leq 45), 27 is the maximum possible value for yy.

Adım Adım Çözüm

1
Identify the given constraints and the variable to maximize.
We are given the system of inequalities x+y45x + y \leq 45 and 3x+5y1653x + 5y \leq 165, with x10x \geq 10, and we want to find the maximum possible value of yy.
This establishes the mathematical model and boundaries for the problem.
2
Express yy in terms of xx for both inequalities to see which constraint is more restrictive.
From the first inequality: y45xy \leq 45 - x. From the second inequality: 3x+5y165    5y1653x    y330.6x3x + 5y \leq 165 \implies 5y \leq 165 - 3x \implies y \leq 33 - 0.6x.
This allows us to analyze yy as a function of xx under both constraints.
3
Substitute the minimum possible value of xx, which is 10, into both boundary expressions for yy.
Under the first constraint: y4510=35y \leq 45 - 10 = 35. Under the second constraint: y330.6(10)=27y \leq 33 - 0.6(10) = 27.
Since both boundary lines have negative slopes, the maximum value of yy will occur when xx is at its minimum value of 10.
4
Determine the most restrictive upper bound for yy when x=10x = 10.
The value of yy must satisfy both y35y \leq 35 and y27y \leq 27, so the maximum possible value is 27.
A solution to a system of inequalities must satisfy all inequalities in the system simultaneously.

Anahtar Kavram

Solving systems of linear inequalities in context by evaluating boundary conditions and identifying constraints.
Soru 209Soru

In the xyxy-plane, a point (x,y)(x, y) is in the solution set of the system of inequalities below:

x2y6x - 2y \leq -6
x+y11x + y \leq 11
y5y \leq 5

What is the maximum possible value of xx?

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Cevap: 4

Cevap

The maximum possible value of xx is 44.
The maximum possible value of xx is 44. For all points in the solution set where y5y \leq 5, the active upper bound is x2y6x \leq 2y - 6. Since 2y62y - 6 increases as yy increases, the maximum value of xx occurs at the maximum boundary y=5y = 5, giving x=2(5)6=4x = 2(5) - 6 = 4.

Adım Adım Çözüm

1
Express xx in terms of yy using the first two inequalities.
x2y6x \leq 2y - 6 and x11yx \leq 11 - y
To isolate the variable xx and analyze how its upper bound is constrained by yy.
2
Apply the third inequality constraint, y5y \leq 5, to find the limits on these upper bounds.
2y642y - 6 \leq 4 and 11y611 - y \geq 6
Since yy cannot exceed 55, the value of 2y62y - 6 is maximized when y=5y = 5, and 11y11 - y is minimized when y=5y = 5.
3
Compare the two upper bounds to determine the active constraint for the domain y5y \leq 5.
Since 2y642y - 6 \leq 4 and 11y611 - y \geq 6, the active bound is x2y6x \leq 2y - 6.
For any point to satisfy the system, xx must be less than or equal to both bounds, meaning it is restricted by the smaller of the two bounds.
4
Calculate the maximum value of xx at the boundary point.
x=4x = 4 at the point (4,5)(4, 5)
The function 2y62y - 6 is increasing with respect to yy, so its maximum value occurs at the largest possible value of yy, which is 55.

Anahtar Kavram

Finding the maximum value of a coordinate within a system of linear inequalities.
Soru 210Soru

In the xyxy-plane, a line with a positive slope mm passes through the points (2,5)(2, 5) and (m,13)(m, 13). Which of the following is the yy-intercept of this line?

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Cevap: (0,3)(0, -3)

Cevap

(0,3)(0, -3)
The correct answer is the point (0,3)(0, -3). The slope of the line passing through (2,5)(2, 5) and (m,13)(m, 13) is expressed as m=135m2=8m2m = \frac{13 - 5}{m - 2} = \frac{8}{m - 2}. Multiplying by m2m - 2 yields the quadratic equation m22m8=0m^2 - 2m - 8 = 0. Factoring this equation gives (m4)(m+2)=0(m - 4)(m + 2) = 0. Since the slope mm is given as positive, we select m=4m = 4. Using the point-slope form with m=4m = 4 and the point (2,5)(2, 5) yields the equation y5=4(x2)y - 5 = 4(x - 2), which simplifies to y=4x3y = 4x - 3. The yy-intercept of this line is found by setting x=0x = 0, giving y=3y = -3, or the coordinate point (0,3)(0, -3).

Adım Adım Çözüm

1
Use the slope formula to express the slope of the line passing through (2,5)(2, 5) and (m,13)(m, 13) in terms of mm.
m=135m2    m=8m2m = \frac{13 - 5}{m - 2} \implies m = \frac{8}{m - 2}
The slope of a line is defined as the ratio of the change in yy to the change in xx between any two points on the line.
2
Solve the equation m=8m2m = \frac{8}{m - 2} for mm by converting it into a quadratic equation.
m(m2)=8    m22m8=0    (m4)(m+2)=0m(m - 2) = 8 \implies m^2 - 2m - 8 = 0 \implies (m - 4)(m + 2) = 0, which gives m=4m = 4 or m=2m = -2. Since the slope is positive, m=4m = 4.
Multiplying both sides by the denominator clears the fraction and allows us to solve for the unknown parameter mm using factoring.
3
Determine the equation of the line using the point-slope form with m=4m = 4 and the point (2,5)(2, 5).
y5=4(x2)    y=4x8+5    y=4x3y - 5 = 4(x - 2) \implies y = 4x - 8 + 5 \implies y = 4x - 3
The point-slope form provides a direct way to write the linear equation using a known point and the calculated slope.
4
Find the yy-intercept by evaluating the line equation at x=0x = 0.
y=4(0)3    y=3y = 4(0) - 3 \implies y = -3, which corresponds to the point (0,3)(0, -3).
The yy-intercept of any line is the point where the line crosses the yy-axis, which occurs at x=0x = 0.

Anahtar Kavram

Linear Equations in Two Variables

Alternatif Yöntem

Alternatively, once the slope m=4m = 4 is found, we can write the equation of the line in slope-intercept form y=4x+by = 4x + b. Substituting the coordinates of the point (2,5)(2, 5) into the equation gives 5=4(2)+b    5=8+b5 = 4(2) + b \implies 5 = 8 + b. Solving for bb gives b=3b = -3. Since bb is the yy-intercept, the point is (0,3)(0, -3).
Tahmini Süre:2m 30s
Soru 211Soru

In the xyxy-plane, a point (x,y)(x, y) lies in the solution set of the system of inequalities below.

yx+8y \leq -x + 8
y2x+2y \leq 2x + 2

What is the maximum possible value of yy?

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Cevap: 6

Cevap

The maximum possible value of yy is 6.
The solution set to the system of inequalities is the region in the coordinate plane that lies on or below both boundary lines, y=x+8y = -x + 8 and y=2x+2y = 2x + 2. The maximum yy-value in this region occurs at the intersection of the two lines. Solving the system of equations by setting x+8=2x+2-x + 8 = 2x + 2 gives 3x=63x = 6, which simplifies to x=2x = 2. Substituting x=2x = 2 back into either equation yields y=6y = 6. Therefore, the maximum possible value of yy is 6.

Adım Adım Çözüm

1
Set the two boundary equations equal to each other to find the xx-coordinate of the intersection point.
x+8=2x+2    3x=6    x=2-x + 8 = 2x + 2 \implies 3x = 6 \implies x = 2
Since the solution region is bounded from above by both inequalities, the maximum value of yy must occur at the intersection of the two boundary lines.
2
Substitute the xx-value back into one of the equations to find the corresponding yy-value.
y=2(2)+2=6y = 2(2) + 2 = 6
This determines the yy-coordinate of the intersection point, which represents the maximum height of the shaded region.

Anahtar Kavram

Systems of Linear Inequalities in Two Variables
Tahmini Süre:45s
Soru 212Öğrencilerin %0'i bunu doğru yanıtladıSoru

In the system of linear equations below, cc is a constant.

2x+3y=12cxy=6\begin{aligned} 2x + 3y &= 12 \\ cx - y &= 6 \end{aligned}

If the system has a unique solution (x,y)(x, y) such that x>0x > 0 and y<0y < 0, which of the following could be the value of cc?

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Cevap: 12\frac{1}{2}

Cevap

The option containing the value 12\frac{1}{2} is correct.
The correct answer is the option containing the value 12\frac{1}{2}. Solving the system of linear equations in terms of the constant cc gives x=302+3cx = \frac{30}{2+3c} and y=12c122+3cy = \frac{12c-12}{2+3c}. For the solution (x,y)(x, y) to lie in the fourth quadrant, we require x>0x > 0 and y<0y < 0. The condition x>0x > 0 is satisfied when 2+3c>02+3c > 0, which simplifies to c>23c > -\frac{2}{3}. Using this result, the condition y<0y < 0 requires the numerator of yy to be negative, so 12c12<012c - 12 < 0, which simplifies to c<1c < 1. Combining these inequalities yields the interval 23<c<1-\frac{2}{3} < c < 1. The only value among the given options that falls within this interval is 12\frac{1}{2}.

Adım Adım Çözüm

1
Express yy in terms of xx and the constant cc using the second equation.
y=cx6y = cx - 6
This allows for substitution into the first equation to solve for xx.
2
Substitute the expression for yy into the first equation and solve for xx.
2x+3(cx6)=12    (2+3c)x18=12    (2+3c)x=30    x=302+3c2x + 3(cx - 6) = 12 \implies (2 + 3c)x - 18 = 12 \implies (2 + 3c)x = 30 \implies x = \frac{30}{2 + 3c}
This isolates the variable xx in terms of the constant cc.
3
Substitute the expression for xx back into the equation for yy to express yy in terms of cc.
y=c(302+3c)6=30c6(2+3c)2+3c=12c122+3cy = c\left(\frac{30}{2 + 3c}\right) - 6 = \frac{30c - 6(2 + 3c)}{2 + 3c} = \frac{12c - 12}{2 + 3c}
This isolates the variable yy in terms of the constant cc.
4
Apply the condition x>0x > 0 to find the constraint on cc.
Since x=302+3c>0x = \frac{30}{2 + 3c} > 0 and the numerator is positive, the denominator must also be positive: 2+3c>0    c>232 + 3c > 0 \implies c > -\frac{2}{3}.
This determines the lower bound for the constant cc.
5
Apply the condition y<0y < 0 to find the constraint on cc.
Since y=12c122+3c<0y = \frac{12c - 12}{2 + 3c} < 0 and the denominator 2+3c2 + 3c is positive, the numerator must be negative: 12c12<0    c<112c - 12 < 0 \implies c < 1.
This determines the upper bound for the constant cc.
6
Combine the inequalities to find the complete range for cc and identify the matching option.
23<c<1-\frac{2}{3} < c < 1. The only value among the options that lies in this interval is 12\frac{1}{2}.
This identifies the correct option based on the mathematical constraints.

Anahtar Kavram

Solving systems of linear equations with parameters and applying quadrant boundary constraints.
Soru 213Soru

Consider the system of inequalities shown below:

y2x+1y<x+6\begin{aligned} y &\geq 2x + 1 \\ y &< -x + 6 \end{aligned}

Which coordinate pair (x,y)(x, y) is a solution to the system?

Cevabı ve açıklamayı göster

Cevap: (1,4)(1, 4)

Cevap

The coordinate pair (1,4)(1, 4) is a solution to the system of inequalities.
The coordinate pair (1,4)(1, 4) is the correct answer because substituting x=1x = 1 and y=4y = 4 into both inequalities yields true statements: 42(1)+1434 \geq 2(1) + 1 \Rightarrow 4 \geq 3 is true, and 4<1+64<54 < -1 + 6 \Rightarrow 4 < 5 is true.

Adım Adım Çözüm

1
Substitute the coordinates of the correct pair, (1,4)(1, 4), into the first inequality, y2x+1y \geq 2x + 1.
42(1)+1434 \geq 2(1) + 1 \Rightarrow 4 \geq 3, which is true.
To be a solution to the system, the point must satisfy the first inequality.
2
Substitute the same coordinates, (1,4)(1, 4), into the second inequality, y<x+6y < -x + 6.
4<1+64<54 < -1 + 6 \Rightarrow 4 < 5, which is true.
The point must also satisfy the second inequality to be a solution to the entire system.
3
Conclude that since (1,4)(1, 4) satisfies both inequalities, it is a solution to the system.
The point (1,4)(1, 4) is in the solution set.
A coordinate pair is a solution to a system of inequalities if and only if it satisfies every inequality in the system.

Anahtar Kavram

Testing coordinate pairs in a system of linear inequalities by substitution.
Tahmini Süre:45s
Soru 214Soru

A nutritionist is designing a diet plan using two food types, Food A and Food B. The table below shows the amount of protein and carbohydrates, in grams, per gram of each food type:

Food TypeProtein (g)Carbohydrates (g)
Food A0.120.120.080.08
Food B0.180.180.050.05

The nutritionist wants to combine the two foods to obtain a mixture that has a total mass of 250250 grams and contains exactly 3636 grams of protein. How many grams of carbohydrates will be in this mixture?

Cevabı ve açıklamayı göster

Cevap: 17

Cevap

The total amount of carbohydrates in the mixture is 17 grams.
To find the total amount of carbohydrates in the mixture, we first define xx as the mass in grams of Food A and yy as the mass in grams of Food B. Since the total mass of the mixture is 250250 grams, we write the equation x+y=250x + y = 250. Since the total protein in the mixture must be 3636 grams, and Food A and Food B contain 0.120.12 grams and 0.180.18 grams of protein per gram respectively, we write the equation 0.12x+0.18y=360.12x + 0.18y = 36. Multiplying the first equation by 1212 yields 12x+12y=300012x + 12y = 3000, and multiplying the second equation by 100100 yields 12x+18y=360012x + 18y = 3600. Subtracting the first new equation from the second gives 6y=6006y = 600, which simplifies to y=100y = 100. Substituting this back into the first equation gives x+100=250x + 100 = 250, so x=150x = 150. Using these values, the total amount of carbohydrates is 0.08(150)+0.05(100)=12+5=170.08(150) + 0.05(100) = 12 + 5 = 17 grams.

Adım Adım Çözüm

1
Define variables for the mass of each food type.
Let xx be the mass, in grams, of Food A, and let yy be the mass, in grams, of Food B.
To represent the unknown quantities in the system of equations.
2
Set up the system of linear equations.
x+y=250x + y = 250 (total mass equation) and 0.12x+0.18y=360.12x + 0.18y = 36 (total protein equation).
The mixture has a total mass of 250250 grams and must contain exactly 3636 grams of protein.
3
Solve the system of equations for xx and yy.
Multiply the first equation by 1212 to get 12x+12y=300012x + 12y = 3000. Multiply the second equation by 100100 to get 12x+18y=360012x + 18y = 3600. Subtract the first modified equation from the second to get 6y=6006y = 600, which gives y=100y = 100. Substitute y=100y = 100 back into x+y=250x + y = 250 to get x=150x = 150.
To find the specific masses of Food A and Food B required for the mixture.
4
Calculate the total mass of carbohydrates in the mixture.
Total carbohydrates =0.08x+0.05y=0.08(150)+0.05(100)=12+5=17= 0.08x + 0.05y = 0.08(150) + 0.05(100) = 12 + 5 = 17 grams.
The question asks for the total grams of carbohydrates in the final mixture.

Anahtar Kavram

Systems of Linear Equations
Soru 215Soru

An empty water tank is being filled by two hoses. Hose A fills the tank at a constant rate of 12 gallons per minute. Hose B fills the tank at a constant rate of 15 gallons per minute. Hose A is turned on first, and 5 minutes later, Hose B is also turned on. If both hoses run until the tank contains a total of 330 gallons of water, for how many minutes was Hose A running?

Cevabı ve açıklamayı göster

Cevap: 15

Cevap

15
Let mm be the number of minutes Hose A was running. Since Hose B was turned on 5 minutes after Hose A, Hose B was running for m5m - 5 minutes. The volume of water contributed by Hose A is 12m12m gallons, and the volume of water contributed by Hose B is 15(m5)15(m - 5) gallons. The sum of these volumes is 330 gallons, which gives the equation 12m+15(m5)=33012m + 15(m - 5) = 330. Distributing 15 gives 12m+15m75=33012m + 15m - 75 = 330. Combining like terms yields 27m75=33027m - 75 = 330. Adding 75 to both sides gives 27m=40527m = 405. Dividing both sides by 27 yields m=15m = 15. Thus, Hose A was running for 15 minutes.

Adım Adım Çözüm

1
Define variables for the running time of each hose.
Let Hose A run for mm minutes. Then Hose B runs for m5m - 5 minutes.
Hose B started 5 minutes after Hose A, so it ran for 5 fewer minutes.
2
Set up a linear equation for the total gallons of water.
12m+15(m5)=33012m + 15(m - 5) = 330
The sum of the water from both hoses must equal 330 gallons.
3
Simplify and solve the linear equation.
27m=40527m = 405, which gives m=15m = 15.
Distribute, combine like terms, and isolate the variable mm.

Anahtar Kavram

Setting up and solving a multi-step linear equation in one variable from a real-world context.
Soru 216Soru

A public library is purchasing new books for its collection. The library plans to buy paperback books for 6eachandhardcoverbooksfor6 each and hardcover books for 20 each. The library has a budget of at most $1,200 for this purchase, wants to buy at most 120 total books, and must purchase at least 45 hardcover books. What is the maximum number of paperback books the library can purchase?

Cevabı ve açıklamayı göster

Cevap: 50

Cevap

The maximum number of paperback books the library can purchase is 50.
The correct maximum number of paperback books is 50. By expressing the budget constraint as p200103hp \le 200 - \frac{10}{3}h, we see that the number of paperback books is maximized when the number of hardcover books, hh, is minimized. Since the library must buy at least 45 hardcover books, we substitute h=45h = 45 into the inequality to get p50p \le 50. This combination also satisfies the total book constraint because 50+45=9550 + 45 = 95, which is less than or equal to 120.

Adım Adım Çözüm

1
Set up the system of inequalities representing the library's constraints.
Let pp be the number of paperbacks and hh be the number of hardcovers. The constraints are 6p+20h12006p + 20h \le 1200, p+h120p + h \le 120, and h45h \ge 45.
This translates the word problem into mathematical inequalities.
2
Isolate the variable pp in the budget inequality to express it in terms of hh.
p200103hp \le 200 - \frac{10}{3}h
This shows how the number of paperbacks depends on the number of hardcovers purchased.
3
Maximize pp by using the minimum possible value of hh.
p200103(45)=50p \le 200 - \frac{10}{3}(45) = 50
To maximize pp, we must minimize hh because buying more hardcovers decreases the remaining budget for paperbacks. The minimum value for hh is 45.
4
Verify if the solution satisfies the remaining total books constraint.
50+45=9512050 + 45 = 95 \le 120, which is true.
This ensures the solution is feasible and does not violate any other constraints.

Anahtar Kavram

Systems of Linear Inequalities in Two Variables
Soru 217Soru

For a constant kk, the graph of the linear equation kx4y=15kx - 4y = 15 in the xyxy-plane contains the point (3,3)(3, 3). What is the slope of the line?

Cevabı ve açıklamayı göster

Cevap: 2.25

Cevap

2.25
Substituting the coordinates of the point (3,3)(3, 3) into the given equation yields k(3)4(3)=15k(3) - 4(3) = 15, which simplifies to 3k12=153k - 12 = 15. Adding 1212 to both sides gives 3k=273k = 27, and dividing by 33 gives k=9k = 9. Substituting k=9k = 9 back into the original equation gives 9x4y=159x - 4y = 15. To find the slope of the line, the equation can be written in slope-intercept form, y=mx+by = mx + b, by isolating yy. Subtracting 9x9x from both sides gives 4y=9x+15-4y = -9x + 15. Dividing all terms by 4-4 yields y=94x154y = \frac{9}{4}x - \frac{15}{4}, or y=2.25x3.75y = 2.25x - 3.75. Therefore, the slope of the line is 94\frac{9}{4}, or 2.252.25.

Adım Adım Çözüm

1
Substitute the point (3,3)(3, 3) into the equation kx4y=15kx - 4y = 15
3k12=153k - 12 = 15
Since the graph of the equation contains the point (3,3)(3, 3), substituting x=3x = 3 and y=3y = 3 must satisfy the equation.
2
Solve for the constant kk
k=9k = 9
Adding 1212 to both sides of the equation gives 3k=273k = 27. Dividing both sides by 33 yields k=9k = 9.
3
Substitute k=9k = 9 into the equation and rewrite it in slope-intercept form (y=mx+by = mx + b)
y=94x154y = \frac{9}{4}x - \frac{15}{4}
Substituting k=9k = 9 gives 9x4y=159x - 4y = 15. Subtracting 9x9x from both sides gives 4y=9x+15-4y = -9x + 15. Dividing both sides by 4-4 isolates yy.
4
Identify the slope from the slope-intercept form
Slope = 2.252.25 (or 94\frac{9}{4})
In the slope-intercept form y=mx+by = mx + b, the coefficient mm represents the slope of the line.

Anahtar Kavram

Determining the slope of a line from a linear equation by first finding an unknown constant using a given point on the line.
Soru 218Soru

A beverage company produces a fruit juice blend using apple juice and cranberry juice. Let xx represent the volume, in liters, of apple juice, and let yy represent the volume, in liters, of cranberry juice used in one batch of the blend. The production constraints for each batch are modeled by the system of inequalities below:

x+y100x + y \geq 100
y13xy \geq \frac{1}{3}x
y12x+75y \leq -\frac{1}{2}x + 75

What is the maximum possible volume, in liters, of cranberry juice that can be used in a single batch?

Cevabı ve açıklamayı göster

Cevap: 50

Cevap

50
To find the maximum possible value of yy, we examine the bounds of the feasible region. Rewriting the inequalities in terms of xx gives x100yx \geq 100 - y and x1502yx \leq 150 - 2y. Since xx must satisfy both inequalities simultaneously, the lower bound must be less than or equal to the upper bound, meaning 100y1502y100 - y \leq 150 - 2y. Solving this inequality for yy gives y50y \leq 50. The point (50,50)(50, 50) also satisfies the remaining constraint y13xy \geq \frac{1}{3}x, confirming that 50 is the maximum possible value.

Adım Adım Çözüm

1
Isolate xx in the first inequality: x+y100x + y \geq 100 becomes x100yx \geq 100 - y.
x100yx \geq 100 - y
This establishes a lower bound for the volume of apple juice in terms of the volume of cranberry juice.
2
Isolate xx in the third inequality: y12x+75y \leq -\frac{1}{2}x + 75 can be rewritten by subtracting 75 from both sides to get y7512xy - 75 \leq -\frac{1}{2}x, then multiplying by 2-2 and reversing the inequality sign to get x1502yx \leq 150 - 2y.
x1502yx \leq 150 - 2y
This establishes an upper bound for the volume of apple juice in terms of the volume of cranberry juice.
3
Combine the lower and upper bounds of xx: 100yx1502y100 - y \leq x \leq 150 - 2y. For a valid solution to exist, the lower bound must be less than or equal to the upper bound.
100y1502y100 - y \leq 150 - 2y
This allows us to solve directly for the constraint on the cranberry juice volume yy.
4
Solve the inequality 100y1502y100 - y \leq 150 - 2y by adding 2y2y to both sides and subtracting 100 from both sides.
y50y \leq 50
This determines that the maximum possible value for yy is 50.
5
Substitute y=50y = 50 back into the compound inequality to find xx: 10050x1502(50)    50x50100 - 50 \leq x \leq 150 - 2(50) \implies 50 \leq x \leq 50, which means x=50x = 50. Check if the point (50,50)(50, 50) satisfies the remaining inequality y13xy \geq \frac{1}{3}x: 5013(50)16.6750 \geq \frac{1}{3}(50) \approx 16.67, which is true.
The point (50,50)(50, 50) is a valid solution to the system.
This confirms that 50 is a achievable value within the system of inequalities.

Anahtar Kavram

Finding the boundary limits and optimization points within a system of linear inequalities in two variables.
Soru 219Soru

A hot air balloon is at an altitude of hh meters. The balloon begins to descend at a constant rate. After 33 minutes, the altitude of the balloon is 540540 meters. After 88 minutes, the altitude of the balloon is 390390 meters. If the altitude of the balloon is modeled by a linear function of time, what was the initial altitude of the balloon, in meters?

Cevabı ve açıklamayı göster

Cevap: 630

Cevap

The initial altitude of the balloon was 630 meters.
To find the initial altitude, we model the balloon's descent as a linear equation of the form h(t)=mt+bh(t) = mt + b, where h(t)h(t) is the altitude at time tt, mm is the constant rate of change, and bb is the initial altitude. Using the given points (3,540)(3, 540) and (8,390)(8, 390), we find the slope m=39054083=30m = \frac{390 - 540}{8 - 3} = -30 meters per minute. Substituting m=30m = -30 and the point (3,540)(3, 540) into h(t)=mt+bh(t) = mt + b gives 540=30(3)+b540 = -30(3) + b. Solving for bb yields b=540+90=630b = 540 + 90 = 630 meters.

Adım Adım Çözüm

1
Identify two data points from the problem context
The coordinate points are (3,540)(3, 540) and (8,390)(8, 390)
To define the linear relationship, we need at least two coordinate points representing (time, altitude)
2
Calculate the slope (mm) of the linear function
m=39054083=1505=30m = \frac{390 - 540}{8 - 3} = \frac{-150}{5} = -30
The rate of change represents the speed at which the balloon descends each minute
3
Solve for the vertical intercept (bb) using the slope-intercept form y=mx+by = mx + b
540=30(3)+b    b=630540 = -30(3) + b \implies b = 630
The initial altitude corresponds to the altitude at time t=0t = 0, which is the vertical intercept of the linear function

Anahtar Kavram

Linear Functions and Graphs
Soru 220Soru

In the xyxy-plane, the region RR consists of all points (x,y)(x, y) that satisfy the system of inequalities below:

3x4y12y2x7x+2y2\begin{aligned} 3x - 4y &\geq -12 \\ y &\geq 2x - 7 \\ x + 2y &\geq 2 \end{aligned}

If (x,y)(x, y) is a point in region RR, what is the maximum possible value of the expression x2yx - 2y?

Cevabı ve açıklamayı göster

Cevap: 4.4

Cevap

4.4
The maximum value of a linear expression over a closed, bounded polygonal region must occur at one of the vertices of that region. By solving the systems of equations for each pair of boundary lines, the vertices of the triangular region are found to be (8,9)(8, 9), (3.2,0.6)(3.2, -0.6), and (1.6,1.8)(-1.6, 1.8). Evaluating the expression x2yx - 2y at each vertex gives 10-10 at (8,9)(8, 9), 4.44.4 at (3.2,0.6)(3.2, -0.6), and 5.2-5.2 at (1.6,1.8)(-1.6, 1.8). Comparing these values, 4.44.4 is the maximum possible value.

Adım Adım Çözüm

1
Find the intersection points of the boundary equations by solving the three systems of two linear equations.
System 1 (3x4y=123x - 4y = -12 and y=2x7y = 2x - 7) yields (8,9)(8, 9).
System 2 (y=2x7y = 2x - 7 and x+2y=2x + 2y = 2) yields (3.2,0.6)(3.2, -0.6).
System 3 (3x4y=123x - 4y = -12 and x+2y=2x + 2y = 2) yields (1.6,1.8)(-1.6, 1.8).
The boundaries of the region are defined by these lines, so the vertices of the region occur at their intersections.
2
Verify that the region defined by the inequalities is the interior of the triangle formed by these vertices by testing a point inside, such as (2,2)(2, 2).
The point (2,2)(2, 2) satisfies all three inequalities:
3(2)4(2)=2123(2) - 4(2) = -2 \geq -12 (True)
22(2)7=32 \geq 2(2) - 7 = -3 (True)
2+2(2)=622 + 2(2) = 6 \geq 2 (True)
This confirms that the region is bounded and the vertices are the extreme points of the closed triangular region.
3
Evaluate the expression x2yx - 2y at each of the three vertices.
At (8,9)(8, 9): 82(9)=108 - 2(9) = -10
At (3.2,0.6)(3.2, -0.6): 3.22(0.6)=3.2+1.2=4.43.2 - 2(-0.6) = 3.2 + 1.2 = 4.4
At (1.6,1.8)(-1.6, 1.8): 1.62(1.8)=1.63.6=5.2-1.6 - 2(1.8) = -1.6 - 3.6 = -5.2
A linear expression defined over a closed, bounded polygonal region reaches its maximum and minimum values at the vertices of that region.
4
Compare the evaluated values to identify the maximum value.
The maximum value is 4.44.4.
Among the three candidate values (10-10, 4.44.4, and 5.2-5.2), 4.44.4 is the greatest.

Anahtar Kavram

Linear programming vertex method for systems of linear inequalities.
Tahmini Süre:3m 0s
ÖncekiSayfa 11 / 22Sonraki
Algebra Alıştırma Soruları — SAT — Sayfa 11 | Examkin