Linear Equations in Two Variables

60 soru

Soru 1Soru

A florist sells carnations for 1.501.50 each and roses for 3.003.00 each. The equation 1.50c+3.00r=45.001.50c + 3.00r = 45.00 represents the possible number of carnations, cc, and roses, rr, that a customer can buy for exactly 45.0045.00. If the customer buys 8 carnations, how many roses can they buy?

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Cevap: 11

Cevap

11
To find the number of roses the customer can buy, substitute the number of carnations bought, which is 8, for cc in the given equation. This yields 1.50(8)+3.00r=45.001.50(8) + 3.00r = 45.00. Simplifying the product gives 12.00+3.00r=45.0012.00 + 3.00r = 45.00. Subtracting 12.00 from both sides of the equation gives 3.00r=33.003.00r = 33.00. Finally, dividing both sides by 3.00 yields r=11r = 11. Thus, the customer can buy 11 roses.

Adım Adım Çözüm

1
Substitute the given value for carnations, c=8c = 8, into the linear equation.
1.50(8)+3.00r=45.001.50(8) + 3.00r = 45.00
We are given that the customer buys 8 carnations, so cc is replaced by 8 to solve for the number of roses, rr.
2
Multiply 1.501.50 by 88 to simplify the term.
12.00+3.00r=45.0012.00 + 3.00r = 45.00
Simplifying the constant term on the left side of the equation.
3
Subtract 12.0012.00 from both sides of the equation to isolate the term with rr.
3.00r=33.003.00r = 33.00
To solve for rr, we must get the term 3.00r3.00r by itself on one side.
4
Divide both sides of the equation by 3.003.00 to solve for rr.
r=11r = 11
Dividing isolates the variable rr.

Anahtar Kavram

Solving a linear equation in two variables by substitution when one variable's value is known.
Soru 2Soru

A landscaping company uses the equation 12x+18y=24012x + 18y = 240 to model the total cost, in dollars, of renting a wood chipper for xx hours and a soil aerator for yy hours. If the wood chipper was rented for 5 more hours than the soil aerator, and the company spent a total of 240240 on these rentals, for how many hours was the soil aerator rented?

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Cevap: 6

Cevap

The soil aerator was rented for 6 hours.
The correct answer is 6. By writing the relationship between the rental hours as x=y+5x = y + 5 and substituting this expression into the cost equation, we obtain 12(y+5)+18y=24012(y + 5) + 18y = 240. Distributing the 12 results in 12y+60+18y=24012y + 60 + 18y = 240. Combining the like terms gives 30y+60=24030y + 60 = 240. Subtracting 60 from both sides of the equation yields 30y=18030y = 180. Dividing both sides by 30 results in y=6y = 6. Therefore, the soil aerator was rented for 6 hours.

Adım Adım Çözüm

1
Express the relationship between the rental hours of the wood chipper (xx) and the soil aerator (yy) as an equation.
x=y+5x = y + 5
The wood chipper was rented for 5 more hours than the soil aerator.
2
Substitute the expression for xx into the cost equation 12x+18y=24012x + 18y = 240.
12(y+5)+18y=24012(y + 5) + 18y = 240
Substitution reduces the equation to a single variable, allowing us to solve for yy.
3
Distribute the 12 and combine like terms.
12y+60+18y=240    30y+60=24012y + 60 + 18y = 240 \implies 30y + 60 = 240
Simplification isolates the variable terms on one side.
4
Isolate yy by subtracting 60 from both sides and then dividing by 30.
30y=180    y=630y = 180 \implies y = 6
This calculation yields the rental hours for the soil aerator.

Anahtar Kavram

Solving a system of linear equations in two variables where one equation represents a budget constraint and the other relates the quantities of the two variables.
Soru 3Soru

The graph of the linear equation y=3x7y = 3x - 7 contains the point (k,5)(k, 5). What is the value of kk?

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Cevap: 44

Cevap

The value of kk is 44.
Substituting the coordinates of the point (k,5)(k, 5) into the linear equation y=3x7y = 3x - 7 gives 5=3k75 = 3k - 7. Solving for kk involves adding 77 to both sides of the equation to get 12=3k12 = 3k, and then dividing both sides by 33 to find k=4k = 4.

Adım Adım Çözüm

1
Substitute the point (k,5)(k, 5) into the equation of the line y=3x7y = 3x - 7 by setting x=kx = k and y=5y = 5.
5=3k75 = 3k - 7
Since the point lies on the graph of the equation, its coordinates must satisfy the equation.
2
Isolate the term with kk by adding 77 to both sides of the equation.
12=3k12 = 3k
Adding 77 to both sides cancels the 7-7 on the right side.
3
Solve for kk by dividing both sides of the equation by 33.
k=4k = 4
Dividing by 33 isolates kk.

Anahtar Kavram

Determining an unknown coordinate of a point on a line by substituting the point's coordinates into the linear equation in two variables.
Soru 4Soru

A community garden charges a one-time registration fee plus a monthly fee to plot and maintain a garden bed. The total cost, yy, in dollars, of maintaining a garden bed for xx months is given by the equation y=15x+45y = 15x + 45. If a gardener spent a total of 165165 dollars, for how many months did they maintain the garden bed?

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Cevap: 8

Cevap

The correct answer is 8. Setting the total cost y equal to 165 in the linear equation yields 165 = 15x + 45. Subtracting 45 from both sides gives 120 = 15x, and dividing by 15 results in x = 8 months.
To find the number of months the gardener maintained the garden bed, substitute the total spent, 165165, for yy in the equation y=15x+45y = 15x + 45. This results in 165=15x+45165 = 15x + 45. Subtracting 4545 from both sides of the equation yields 120=15x120 = 15x. Dividing both sides by 1515 gives x=8x = 8. Thus, the garden bed was maintained for 8 months.

Adım Adım Çözüm

1
Substitute 165 for y in the equation.
165=15x+45165 = 15x + 45
The variable y represents the total cost in dollars, which is given as 165.
2
Subtract 45 from both sides of the equation.
120=15x120 = 15x
This isolates the variable term by subtracting the constant registration fee.
3
Divide both sides of the equation by 15.
x=8x = 8
This solves for x, the number of months.

Anahtar Kavram

Solving for a variable in a linear equation representing a real-world scenario.
Soru 5Soru

An online bookstore charges a flat shipping fee plus a fixed price per book purchased. The total cost, yy, in dollars, for purchasing xx books is given by the equation y=8.5x+4.5y = 8.5x + 4.5. If a customer's total cost was 4747 dollars, how many books did the customer purchase?

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Cevap: 5

Cevap

The customer purchased 5 books.
To find the number of books purchased, substitute the total cost of 47 for yy in the equation y=8.5x+4.5y = 8.5x + 4.5, yielding 47=8.5x+4.547 = 8.5x + 4.5. Subtracting 4.54.5 from both sides gives 42.5=8.5x42.5 = 8.5x. Dividing both sides by 8.58.5 results in x=5x = 5. Thus, the customer purchased 5 books.

Adım Adım Çözüm

1
Substitute the total cost of 47 into the equation for y
47=8.5x+4.547 = 8.5x + 4.5
Since the total cost is represented by y and is given as 47 dollars, we substitute 47 for y in the equation.
2
Subtract 4.5 from both sides of the equation
42.5=8.5x42.5 = 8.5x
Subtracting the flat fee from both sides isolates the variable term representing the total cost of the books.
3
Divide both sides by 8.5
x=5x = 5
Dividing the remaining cost by the price per book yields the total number of books purchased.

Anahtar Kavram

Linear Equations in Two Variables
Soru 6Soru

A linear equation models the total cost, in dollars, of purchasing xx pounds of almonds and yy pounds of walnuts. Under the original pricing, purchasing 88 pounds of almonds and 1515 pounds of walnuts costs cc dollars. If the price per pound of almonds is increased by 25%25\% and the price per pound of walnuts is decreased by 10%10\%, the cost of purchasing 88 pounds of almonds and 1515 pounds of walnuts is still cc dollars. Under the original pricing, a customer can purchase exactly 2222 pounds of almonds and no walnuts for cc dollars. How many pounds of walnuts and no almonds can the customer purchase for cc dollars under the original pricing?

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Cevap: 16.5

Cevap

16.5
Under the original pricing, the cost of 88 pounds of almonds at aa dollars per pound and 1515 pounds of walnuts at bb dollars per pound is represented by the linear equation 8a+15b=c8a + 15b = c. Under promotional pricing, the cost of almonds increases by 25%25\% to 1.25a1.25a, and the cost of walnuts decreases by 10%10\% to 0.90b0.90b. The new cost for the same amounts of nuts is 8(1.25a)+15(0.90b)=10a+13.5b=c8(1.25a) + 15(0.90b) = 10a + 13.5b = c. Setting the two cost equations equal to each other gives 8a+15b=10a+13.5b8a + 15b = 10a + 13.5b, which simplifies to 1.5b=2a1.5b = 2a, or a=0.75ba = 0.75b. Since 2222 pounds of almonds can be purchased for cc dollars, we have 22a=c22a = c. Substituting a=0.75ba = 0.75b yields 22(0.75b)=c22(0.75b) = c, which simplifies to 16.5b=c16.5b = c. Thus, exactly 16.516.5 pounds of walnuts can be purchased for cc dollars.

Adım Adım Çözüm

1
Set up the equation representing the total cost of the initial purchase under the original pricing.
8a+15b=c8a + 15b = c, where aa is the original price per pound of almonds and bb is the original price per pound of walnuts.
To represent the cost relation using the original individual prices of almonds and walnuts.
2
Modify the individual prices for the promotional rates and write the new total cost equation.
8(1.25a)+15(0.90b)=c    10a+13.5b=c8(1.25a) + 15(0.90b) = c \implies 10a + 13.5b = c.
The price per pound of almonds increases by 25%25\% (multiplied by 1.251.25) and the price per pound of walnuts decreases by 10%10\% (multiplied by 0.900.90).
3
Equate the two expressions representing cc to find the ratio between the prices aa and bb.
8a+15b=10a+13.5b    2a=1.5b    a=0.75b8a + 15b = 10a + 13.5b \implies 2a = 1.5b \implies a = 0.75b.
Since both purchasing combinations yield the same total budget cc, their cost equations are equal.
4
Use the budget equation for purchasing only almonds to determine the equivalent purchase in walnuts.
22a=c    22(0.75b)=c    16.5b=c22a = c \implies 22(0.75b) = c \implies 16.5b = c. Therefore, 16.516.5 pounds of walnuts can be bought for cc dollars.
Substituting the price relationship a=0.75ba = 0.75b allows expressing the budget cc purely in terms of the price of walnuts bb.

Anahtar Kavram

Modeling linear relationships in two variables and analyzing changes in coefficients.
Soru 7Soru

A project manager uses the linear equation ax+by=cax + by = c to model the allocation of resources, where xx represents the number of hours spent on research, yy represents the number of hours spent on development, and a,b,a, b, and cc are positive constants. Initially, the project manager allocates 4040 hours for research and 3030 hours for development. To optimize the project, the manager decides to increase the research hours by 25%25\% and decrease the development hours by 20%20\% such that the total resource value, cc, remains unchanged. Which of the following equations correctly expresses aa in terms of bb?

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Cevap: a=0.6ba = 0.6b

Cevap

The equation a=0.6ba = 0.6b correctly expresses aa in terms of bb.
The correct equation is a=0.6ba = 0.6b. The initial resource allocation is represented by 40a+30b=c40a + 30b = c. Increasing 4040 by 25%25\% gives 5050, and decreasing 3030 by 20%20\% gives 2424, which yields the new equation 50a+24b=c50a + 24b = c. Equating these two expressions since cc is constant gives 40a+30b=50a+24b40a + 30b = 50a + 24b. Simplifying this equation results in 6b=10a6b = 10a, which gives a=0.6ba = 0.6b.

Adım Adım Çözüm

1
Write the linear equation representing the initial allocation of resources.
40a+30b=c40a + 30b = c
The initial values are 4040 hours for research (xx) and 3030 hours for development (yy).
2
Calculate the new values of xx and yy after the percentage changes are applied.
x=40×1.25=50x = 40 \times 1.25 = 50 and y=30×0.80=24y = 30 \times 0.80 = 24
Research hours increase by 25%25\% and development hours decrease by 20%20\%.
3
Write the new linear equation with the updated resource allocations.
50a+24b=c50a + 24b = c
The total resource value cc remains unchanged.
4
Equate the two expressions for cc and solve for aa in terms of bb.
40a+30b=50a+24b    6b=10a    a=0.6b40a + 30b = 50a + 24b \implies 6b = 10a \implies a = 0.6b
Since both equations equal the same constant cc, we set them equal to each other and isolate the variable aa.

Anahtar Kavram

Expressing and manipulating linear relationships in two variables with constraints.

Alternatif Yöntem

Instead of keeping cc general, we can choose a convenient value for cc, such as c=120c = 120. This gives two linear equations in terms of aa and bb: 40a+30b=12040a + 30b = 120 and 50a+24b=12050a + 24b = 120. Solving this system for the ratio of aa to bb yields a=1.33a = 1.33 and b=2.22b = 2.22, which confirms that a/b=0.6a/b = 0.6, or a=0.6ba = 0.6b.
Tahmini Süre:3m 0s
Soru 8Soru

A student tracks the remaining battery percentage, yy, of a tablet after xx hours of use. The table below shows the battery percentage at three different times:

Time (xx, hours)Battery percentage (yy)
090
375
660

Which of the following equations represents the relationship between xx and yy?

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Cevap: y=5x+90y = -5x + 90

Cevap

y = -5x + 90
The correct equation is y=5x+90y = -5x + 90. According to the table, when time x=0x = 0, the battery percentage y=90y = 90, which indicates that the y-intercept of the line is 9090. The slope can be determined using any two points from the table, such as (0,90)(0, 90) and (3,75)(3, 75): slope=759030=153=5\text{slope} = \frac{75 - 90}{3 - 0} = \frac{-15}{3} = -5. Writing this in slope-intercept form gives y=5x+90y = -5x + 90.

Adım Adım Çözüm

1
Identify the y-intercept from the table.
The y-intercept bb is 9090.
When the time x=0x = 0 hours, the battery percentage y=90y = 90. This corresponds to the y-intercept of the linear equation.
2
Calculate the slope (rate of change) using two points from the table.
The slope mm is 5-5.
Using the points (0,90)(0, 90) and (3,75)(3, 75), the slope is calculated as the change in yy divided by the change in xx: m=759030=153=5m = \frac{75 - 90}{3 - 0} = \frac{-15}{3} = -5.
3
Substitute the slope and y-intercept into the slope-intercept form equation.
y=5x+90y = -5x + 90
Plugging m=5m = -5 and b=90b = 90 into y=mx+by = mx + b yields the final equation.

Anahtar Kavram

Determining a linear equation in two variables from a table of values.
Tahmini Süre:1m 0s
Soru 9Soru

The equation 3x+4y=363x + 4y = 36 represents the relationship between the number of small boxes, xx, and large boxes, yy, that can fit in a delivery van. If the van is loaded with exactly 6 large boxes, what is the number of small boxes that can also fit in the van?

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Cevap: 4

Cevap

The number of small boxes that can also fit in the van is 4.
Substituting y=6y = 6 into the equation 3x+4y=363x + 4y = 36 gives 3x+24=363x + 24 = 36. Subtracting 24 from both sides results in 3x=123x = 12. Dividing both sides by 3 yields x=4x = 4. Thus, the number of small boxes that can fit is 4.

Adım Adım Çözüm

1
Substitute 6 for yy in the equation 3x+4y=363x + 4y = 36.
3x+4(6)=363x + 4(6) = 36
The variable yy represents the number of large boxes, which is given as 6.
2
Simplify the multiplication in the equation.
3x+24=363x + 24 = 36
To simplify the terms before solving for xx.
3
Subtract 24 from both sides of the equation.
3x=123x = 12
To isolate the variable term 3x3x on one side of the equation.
4
Divide both sides of the equation by 3.
x=4x = 4
To solve for xx, the number of small boxes.

Anahtar Kavram

Evaluating and solving a linear equation in two variables given the value of one variable.
Tahmini Süre:45s
Soru 10Soru

In the xyxy-plane, a line with a positive slope mm and a yy-intercept of (0,b)(0, b) passes through the point (b,12)(b, 12), where b>0b > 0. If the area of the triangle bounded by the line, the xx-axis, and the yy-axis is 44, what is the value of mm?

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Cevap: 2

Cevap

2
The line equation is y=mx+by = mx + b. Substituting the point (b,12)(b, 12) gives 12=b(m+1)12 = b(m + 1). The xx-intercept of the line is at (bm,0)(-\frac{b}{m}, 0), which gives a base length of bm\frac{b}{m} for the right triangle, while the height is bb. The area of the triangle is b22m=4    b2=8m\frac{b^2}{2m} = 4 \implies b^2 = 8m. Substituting b=12m+1b = \frac{12}{m + 1} into this equation yields 144(m+1)2=8m    m(m+1)2=18\frac{144}{(m + 1)^2} = 8m \implies m(m + 1)^2 = 18. Solving this for positive values of mm gives the unique solution m=2m = 2.

Adım Adım Çözüm

1
Express the line equation and substitute the given point (b,12)(b, 12).
b(m+1)=12b(m + 1) = 12
Since the line has a yy-intercept of (0,b)(0, b) and a slope of mm, its equation is y=mx+by = mx + b. Substituting the point (b,12)(b, 12) yields 12=m(b)+b=b(m+1)12 = m(b) + b = b(m + 1).
2
Determine the lengths of the base and height of the triangle formed by the line and the coordinate axes.
Base =bm= \frac{b}{m}, Height =b= b
The yy-intercept is at (0,b)(0, b) and the xx-intercept is at (bm,0)(-\frac{b}{m}, 0). Since b>0b > 0 and m>0m > 0, the height is bb and the base is the absolute value of the xx-intercept, which is bm\frac{b}{m}.
3
Write the area equation of the triangle and simplify it.
b2=8mb^2 = 8m
The area of the right triangle is 12×base×height=12(bm)b=b22m\frac{1}{2} \times \text{base} \times \text{height} = \frac{1}{2} \left(\frac{b}{m}\right)b = \frac{b^2}{2m}. Setting this equal to the given area of 44 gives b22m=4    b2=8m\frac{b^2}{2m} = 4 \implies b^2 = 8m.
4
Solve the system of equations for mm.
m=2m = 2
Substituting b=12m+1b = \frac{12}{m + 1} into b2=8mb^2 = 8m yields (12m+1)2=8m    144(m+1)2=8m    m(m+1)2=18\left(\frac{12}{m + 1}\right)^2 = 8m \implies \frac{144}{(m + 1)^2} = 8m \implies m(m + 1)^2 = 18. Since m(m+1)2m(m + 1)^2 is strictly increasing for positive mm, testing small integers shows 2(3)2=182(3)^2 = 18, so m=2m = 2 is the unique positive real solution.

Anahtar Kavram

Formulating linear equations in slope-intercept form and solving non-linear systems of equations derived from geometric constraints.

Alternatif Yöntem

Instead of algebraically expanding the cubic equation, one can test small positive integers for mm in the equation m(m+1)2=18m(m + 1)^2 = 18. Testing m=1m = 1 yields 1(2)2=41(2)^2 = 4 (too small), and testing m=2m = 2 yields 2(3)2=182(3)^2 = 18 (correct). Because m(m+1)2m(m + 1)^2 is strictly increasing for m>0m > 0, m=2m = 2 is the only positive real root.
Tahmini Süre:3m 0s
Soru 11Soru

A linear relationship between xx and yy is defined by the values in the table below.

xxyy
27
413
619

Which of the following equations represents this relationship?

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Cevap: y=3x+1y = 3x + 1

Cevap

The equation representing the relationship is y=3x+1y = 3x + 1.
The correct equation is y=3x+1y = 3x + 1. The slope mm of the linear function can be determined from the table values (2,7)(2, 7) and (4,13)(4, 13) as 13742=62=3\frac{13 - 7}{4 - 2} = \frac{6}{2} = 3. Substituting the slope m=3m = 3 and the point (2,7)(2, 7) into the slope-intercept form y=mx+by = mx + b gives 7=3(2)+b7 = 3(2) + b, which simplifies to 7=6+b7 = 6 + b, so b=1b = 1. Therefore, the equation is y=3x+1y = 3x + 1.

Adım Adım Çözüm

1
Find the slope (mm) of the linear relationship using the points (2,7)(2, 7) and (4,13)(4, 13) from the table.
m=3m = 3
The slope is the ratio of the change in yy to the change in xx between any two points on the line: m=13742=62=3m = \frac{13 - 7}{4 - 2} = \frac{6}{2} = 3.
2
Use the slope m=3m = 3 and the point (2,7)(2, 7) to find the yy-intercept (bb) of the line.
b=1b = 1
Substituting the coordinates and slope into the slope-intercept equation y=mx+by = mx + b gives 7=3(2)+b7 = 3(2) + b, which simplifies to 7=6+b7 = 6 + b, leading to b=1b = 1.
3
Substitute the slope and yy-intercept into the slope-intercept form.
y=3x+1y = 3x + 1
Combining the slope of 33 and yy-intercept of 11 yields the equation y=3x+1y = 3x + 1.

Anahtar Kavram

Determining a linear equation from a table of values
Tahmini Süre:45s
Soru 12Soru

A line in the xyxy-plane is represented by the equation 3x4y=243x - 4y = 24. What is the yy-coordinate of the yy-intercept of this line?

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Cevap: -6

Cevap

The yy-coordinate of the yy-intercept is 6-6.
The correct answer is 6-6. The yy-intercept of a line is the point where it intersects the yy-axis, which occurs when the xx-coordinate is 00. Substituting x=0x = 0 into the given equation 3x4y=243x - 4y = 24 yields 4y=24-4y = 24. Dividing both sides by 4-4 gives y=6y = -6.

Adım Adım Çözüm

1
Substitute x=0x = 0 into the equation to find the yy-intercept.
3(0)4y=243(0) - 4y = 24
By definition, the yy-intercept of a line in the coordinate plane is the point where the line crosses the yy-axis, which always has an xx-coordinate of 00.
2
Simplify the equation.
4y=24-4y = 24
Multiplying 33 by 00 yields 00, leaving only the term containing yy on the left side of the equation.
3
Solve for yy by isolating the variable.
y=6y = -6
Dividing both sides of the simplified equation by 4-4 isolates yy and gives the final coordinate value.

Anahtar Kavram

Finding the y-intercept of a linear equation in two variables by setting x = 0.
Tahmini Süre:45s
Soru 13Soru

In the xyxy-plane, line L1L_1 is defined by the equation ax+by=cax + by = c, where aa, bb, and cc are non-zero constants. Line L2L_2 is perpendicular to line L1L_1 and has a yy-intercept that is twice the yy-intercept of line L1L_1. If the xx-intercept of line L2L_2 is dd, which of the following expressions represents dd in terms of aa, bb, and cc?

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Cevap: 2acb2-\frac{2ac}{b^2}

Cevap

The expression that represents dd in terms of aa, bb, and cc is 2acb2-\frac{2ac}{b^2}.
The correct answer is found by first rewriting the equation of the first line in slope-intercept form to determine its slope, ab-\frac{a}{b}, and its yy-intercept, cb\frac{c}{b}. The second line is perpendicular to the first, so its slope is the negative reciprocal, ba\frac{b}{a}. Its yy-intercept is twice that of the first line, which is 2cb\frac{2c}{b}. Setting y=0y = 0 in the equation of the second line, y=bax+2cby = \frac{b}{a}x + \frac{2c}{b}, and solving for xx yields the xx-intercept d=2acb2d = -\frac{2ac}{b^2}.

Adım Adım Çözüm

1
Rewrite the equation of line L1L_1 in slope-intercept form.
y=abx+cby = -\frac{a}{b}x + \frac{c}{b}
To identify the slope and yy-intercept of the first line.
2
Determine the slope and yy-intercept of line L2L_2.
Slope of L2L_2 is ba\frac{b}{a}; yy-intercept of L2L_2 is 2cb\frac{2c}{b}.
Line L2L_2 is perpendicular to L1L_1 (so its slope is the negative reciprocal of ab-\frac{a}{b}) and its yy-intercept is twice that of L1L_1.
3
Write the equation of line L2L_2.
y=bax+2cby = \frac{b}{a}x + \frac{2c}{b}
Using the slope-intercept form y=mx+ky = mx + k for the second line.
4
Find the xx-intercept dd of line L2L_2 by setting y=0y = 0.
d=2acb2d = -\frac{2ac}{b^2}
The xx-intercept is the value of xx when y=0y = 0.

Anahtar Kavram

Linear Equations in Two Variables

Alternatif Yöntem

Instead of converting to slope-intercept form, one can use the general form relationships. For ax+by=cax + by = c, the slope is a/b-a/b and the yy-intercept is c/bc/b. A perpendicular line has slope b/ab/a. With double the yy-intercept, its equation can be written as y2cb=baxy - \frac{2c}{b} = \frac{b}{a}x. Setting y=0y=0 directly gives 2cb=bad    d=2acb2-\frac{2c}{b} = \frac{b}{a}d \implies d = -\frac{2ac}{b^2}.
Tahmini Süre:2m 0s
Soru 14Soru

An artist sells customized prints online. The total price, yy, in dollars, for an order of xx prints is given by the equation y=8.50x+4.00y = 8.50x + 4.00, where 4.004.00 represents a flat shipping fee. If a customer's total order price is 38.0038.00, how many prints did the customer order?

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Cevap: 4

Cevap

4
Substituting 38.0038.00 for yy in the given linear equation y=8.50x+4.00y = 8.50x + 4.00 yields 38.00=8.50x+4.0038.00 = 8.50x + 4.00. Subtracting 4.004.00 from both sides of the equation results in 34.00=8.50x34.00 = 8.50x. Dividing both sides of the equation by 8.508.50 yields x=4x = 4. Therefore, the customer ordered 4 prints.

Adım Adım Çözüm

1
Substitute the given total price of 38.0038.00 for yy in the equation.
38.00=8.50x+4.0038.00 = 8.50x + 4.00
The variable yy represents the total price of the order in dollars, which is given as 38.0038.00.
2
Subtract the shipping fee of 4.004.00 from both sides of the equation.
34.00=8.50x34.00 = 8.50x
Subtracting 4.004.00 from both sides isolates the variable term 8.50x8.50x.
3
Divide both sides of the equation by 8.508.50.
x=4x = 4
Dividing the remaining cost of 34.0034.00 by the unit price per print of 8.508.50 yields the total number of prints ordered.

Anahtar Kavram

Solving a linear equation in two variables for one variable when the value of the other variable is given.
Tahmini Süre:45s
Soru 15Soru

In the xyxy-plane, a line with a negative slope passes through the point (4,3)(4, 3) and intersects the positive xx-axis at (a,0)(a, 0) and the positive yy-axis at (0,b)(0, b). If the area of the triangle formed by this line and the coordinate axes is 2424, what is the value of bb?

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Cevap: 6

Cevap

The value of bb is 6.
The correct value is 6. By representing the linear equation in intercept form as xa+yb=1\frac{x}{a} + \frac{y}{b} = 1 and substituting the given point (4,3)(4, 3), we obtain 4a+3b=1\frac{4}{a} + \frac{3}{b} = 1. Using the area of the triangle, 12ab=24\frac{1}{2}ab = 24, we can write a=48ba = \frac{48}{b}. Substituting this into the intercept equation yields b12+3b=1\frac{b}{12} + \frac{3}{b} = 1. Multiplying by 12b12b leads to the quadratic equation b212b+36=0b^2 - 12b + 36 = 0, which factors as (b6)2=0(b-6)^2 = 0, giving the unique solution b=6b = 6.

Adım Adım Çözüm

1
Express the line in intercept form
xa+yb=1\frac{x}{a} + \frac{y}{b} = 1
Since the intercepts are (a,0)(a, 0) and (0,b)(0, b) with a>0a > 0 and b>0b > 0, the intercept form of a linear equation is the most direct representation.
2
Substitute the given point (4,3)(4, 3) into the intercept form
4a+3b=1\frac{4}{a} + \frac{3}{b} = 1
The line passes through (4,3)(4, 3), so these coordinates must satisfy the equation of the line.
3
Express aa in terms of bb using the area of the triangle
a=48ba = \frac{48}{b}
The area of the right triangle with base aa and height bb is 12ab=24\frac{1}{2}ab = 24, which gives ab=48ab = 48.
4
Substitute a=48ba = \frac{48}{b} into the equation from Step 2
b12+3b=1\frac{b}{12} + \frac{3}{b} = 1
This reduces the equation to a single variable bb.
5
Clear denominators and write the equation in standard quadratic form
b212b+36=0b^2 - 12b + 36 = 0
Multiplying both sides by 12b12b allows us to form a quadratic equation.
6
Factor the quadratic equation to solve for bb
b=6b = 6
The quadratic expression is a perfect square trinomial, (b6)2=0(b-6)^2 = 0, which yields b=6b = 6.

Anahtar Kavram

Using the intercept form of a linear equation and geometric properties of linear graphs to solve for unknown parameters.
Soru 16Soru

In the xyxy-plane, the graph of the linear equation ax+by=cax + by = c, where aa, bb, and cc are non-zero constants, has a positive slope and a negative yy-intercept. If the line passes through the point (b,a)(b, a), which of the following inequalities must be true?

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Cevap: ac>0ac > 0

Cevap

The inequality ac>0ac > 0 must be true.
The correct inequality is ac>0ac > 0. Rearranging ax+by=cax + by = c into slope-intercept form gives y=abx+cby = -\frac{a}{b}x + \frac{c}{b}. A positive slope means ab>0-\frac{a}{b} > 0, so ab<0\frac{a}{b} < 0, indicating that aa and bb have opposite signs (ab<0ab < 0). A negative yy-intercept means cb<0\frac{c}{b} < 0, indicating that bb and cc have opposite signs (bc<0bc < 0). Substituting the point (b,a)(b, a) into the line's equation gives 2ab=c2ab = c. Since ab<0ab < 0, it follows that c<0c < 0. Using the relation bc<0bc < 0 with c<0c < 0, we find b>0b > 0. Using ab<0ab < 0 with b>0b > 0, we find aa is negative. Since both aa and cc are negative, their product acac must be positive.

Adım Adım Çözüm

1
Rearrange the standard form equation ax+by=cax + by = c into slope-intercept form.
y=abx+cby = -\frac{a}{b}x + \frac{c}{b}
To identify the expressions for the slope and the yy-intercept in terms of the constants aa, bb, and cc.
2
Determine the sign relationships between the coefficients based on the given signs of the slope and yy-intercept.
Since the slope is positive, ab>0    ab<0-\frac{a}{b} > 0 \implies ab < 0. Since the yy-intercept is negative, cb<0    bc<0\frac{c}{b} < 0 \implies bc < 0.
This establishes that aa and bb have opposite signs, and bb and cc have opposite signs.
3
Substitute the coordinates of the point (b,a)(b, a) into the original equation ax+by=cax + by = c.
a(b)+b(a)=c    2ab=ca(b) + b(a) = c \implies 2ab = c
Since the point lies on the line, substituting its coordinates must satisfy the equation.
4
Analyze the sign of cc using the relation c=2abc = 2ab.
Since ab<0ab < 0, it follows that 2ab<02ab < 0, which means c<0c < 0.
To determine whether the constant cc is positive or negative.
5
Determine the individual signs of bb and aa.
Since bc<0bc < 0 and c<0c < 0, bb must be positive (b>0b > 0). Since ab<0ab < 0 and b>0b > 0, aa must be negative (a<0a < 0).
To find the sign of each coefficient individually.
6
Determine the sign of the product acac.
Since both a<0a < 0 and c<0c < 0, their product acac must be positive (ac>0ac > 0).
To evaluate which inequality must be true.

Anahtar Kavram

Analyzing slope, intercepts, and points on a linear equation in two variables using sign analysis of its constants.

Alternatif Yöntem

Instead of solving for the individual signs of all variables, we can choose test values that satisfy the conditions. For example, let a=1a = -1 and b=2b = 2, which gives a positive slope of ab=12-\frac{a}{b} = \frac{1}{2}. Since the line passes through (b,a)=(2,1)(b, a) = (2, -1), we can find cc: ax+by=c    (1)(2)+(2)(1)=4ax + by = c \implies (-1)(2) + (2)(-1) = -4, so c=4c = -4. The yy-intercept is cb=42=2\frac{c}{b} = \frac{-4}{2} = -2, which is negative, satisfying all conditions. Evaluating the product of aa and cc gives (1)(4)=4>0(-1)(-4) = 4 > 0, confirming that the product of these constants must be positive.
Tahmini Süre:3m 0s
Soru 17Soru

In the xyxy-plane, a line with a positive slope mm passes through the point (4,3)(4, -3) and intersects the xx-axis at (p,0)(p, 0) and the yy-axis at (0,q)(0, q), where pp and qq are non-zero constants. If p+q=5p + q = 5, what is the value of mm?

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Cevap: 0.5

Cevap

The value of mm is 0.50.5 (or 1/21/2).
To find the slope mm, write the equation of the line in point-slope form: y(3)=m(x4)y - (-3) = m(x - 4), which simplifies to y=mx4m3y = mx - 4m - 3. The yy-intercept is found by setting x=0x = 0, giving q=4m3q = -4m - 3. The xx-intercept is found by setting y=0y = 0, giving p=4+3mp = 4 + \frac{3}{m}. Substituting these expressions into p+q=5p + q = 5 gives 4+3m4m3=54 + \frac{3}{m} - 4m - 3 = 5, which simplifies to 4m4+3m=0-4m - 4 + \frac{3}{m} = 0. Multiplying this equation by m-m yields the quadratic equation 4m2+4m3=04m^2 + 4m - 3 = 0. Factoring the quadratic gives (2m1)(2m+3)=0(2m - 1)(2m + 3) = 0. Since the line is defined to have a positive slope, the value of mm must be positive, which is 0.50.5 (or 1/21/2).

Adım Adım Çözüm

1
Write the general equation of a line passing through (4,3)(4, -3) with slope mm.
y=mx4m3y = mx - 4m - 3
Using the point-slope form yy1=m(xx1)y - y_1 = m(x - x_1) with (x1,y1)=(4,3)(x_1, y_1) = (4, -3) establishes the relationship between xx, yy, and mm.
2
Determine the value of qq by finding the yy-intercept of the line.
q=4m3q = -4m - 3
The yy-intercept (0,q)(0, q) occurs when x=0x = 0.
3
Determine the value of pp by finding the xx-intercept of the line.
p=4+3mp = 4 + \frac{3}{m}
The xx-intercept (p,0)(p, 0) occurs when y=0y = 0.
4
Substitute the expressions for pp and qq into the given equation p+q=5p + q = 5.
4+3m4m3=54 + \frac{3}{m} - 4m - 3 = 5
This sets up a single equation with the variable mm using the given relationship.
5
Simplify the equation and rewrite it in standard quadratic form.
4m2+4m3=04m^2 + 4m - 3 = 0
Multiplying the simplified expression 4m4+3m=0-4m - 4 + \frac{3}{m} = 0 by m-m eliminates the fraction and aligns it to standard quadratic form.
6
Factor the quadratic equation to find the possible values of mm.
m=0.5m = 0.5 or m=1.5m = -1.5
Factoring (2m1)(2m+3)=0(2m - 1)(2m + 3) = 0 gives the roots of the equation.
7
Filter the results based on the positive slope constraint.
m=0.5m = 0.5
The problem states that the line has a positive slope, so we must reject the negative root.

Anahtar Kavram

Using linear intercepts to solve system constraints

Alternatif Yöntem

Instead of using point-slope form, use the intercept form of a linear equation: xp+yq=1\frac{x}{p} + \frac{y}{q} = 1. Since the line passes through the point (4,3)(4, -3), substitute x=4x = 4 and y=3y = -3 to get 4p3q=1\frac{4}{p} - \frac{3}{q} = 1. Given p+q=5p + q = 5, substitute p=5qp = 5 - q into the equation to get 45q3q=1\frac{4}{5 - q} - \frac{3}{q} = 1. Multiply both sides by the common denominator q(5q)q(5 - q) to obtain 4q3(5q)=q(5q)    7q15=5qq2    q2+2q15=04q - 3(5 - q) = q(5 - q) \implies 7q - 15 = 5q - q^2 \implies q^2 + 2q - 15 = 0. Factoring gives (q+5)(q3)=0(q + 5)(q - 3) = 0. This yields q=5q = -5 or q=3q = 3. If q=3q = 3, then p=2p = 2, and the slope is m=qp=32m = -\frac{q}{p} = -\frac{3}{2} (negative). If q=5q = -5, then p=10p = 10, and the slope is m=qp=510=0.5m = -\frac{q}{p} = -\frac{-5}{10} = 0.5 (positive). Since the slope must be positive, the slope of the line is 0.50.5.
Tahmini Süre:2m 30s
Soru 18Soru

In the xyxy-plane, a line has an xx-intercept of (k+2,0)(k + 2, 0) and a yy-intercept of (0,2k+2)(0, 2k + 2), where kk is a positive constant. If the line passes through the point (3,5)(3, 5), what is the value of kk?

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Cevap: 4

Cevap

4
The correct answer is the value 4. By substituting the point (3,5)(3, 5) into the intercept form of the line equation xk+2+y2k+2=1\frac{x}{k+2} + \frac{y}{2k+2} = 1, we obtain 3k+2+52k+2=1\frac{3}{k+2} + \frac{5}{2k+2} = 1. Multiplying by the common denominator (k+2)(2k+2)(k+2)(2k+2) and simplifying results in the quadratic equation 2k25k12=02k^2 - 5k - 12 = 0. Factoring this equation yields (2k+3)(k4)=0(2k+3)(k-4) = 0. Since kk must be a positive constant, we select k=4k = 4.

Adım Adım Çözüm

1
Write the equation of the line using intercept form.
The equation of a line with xx-intercept (k+2,0)(k+2, 0) and yy-intercept (0,2k+2)(0, 2k+2) is xk+2+y2k+2=1\frac{x}{k+2} + \frac{y}{2k+2} = 1.
Intercept form xa+yb=1\frac{x}{a} + \frac{y}{b} = 1 is the most direct way to represent a line when both intercepts are given.
2
Substitute the given point (3,5)(3, 5) into the line's equation.
Substituting x=3x = 3 and y=5y = 5 yields the equation 3k+2+52k+2=1\frac{3}{k+2} + \frac{5}{2k+2} = 1.
Since the line passes through (3,5)(3, 5), these coordinates must satisfy the equation of the line.
3
Eliminate the denominators by multiplying both sides of the equation by the least common denominator.
Multiplying by (k+2)(2k+2)(k+2)(2k+2) gives 3(2k+2)+5(k+2)=(k+2)(2k+2)3(2k+2) + 5(k+2) = (k+2)(2k+2).
This clears the fractions and allows us to rewrite the equation in polynomial form.
4
Expand both sides of the equation and combine like terms.
Expanding both sides gives 6k+6+5k+10=2k2+2k+4k+4    11k+16=2k2+6k+46k + 6 + 5k + 10 = 2k^2 + 2k + 4k + 4 \implies 11k + 16 = 2k^2 + 6k + 4.
To solve a polynomial equation, we need to simplify the algebraic expressions on both sides.
5
Rearrange the equation into standard quadratic form.
Moving all terms to one side gives 2k25k12=02k^2 - 5k - 12 = 0.
Standard quadratic form Ax2+Bx+C=0Ax^2 + Bx + C = 0 is required to apply factoring or the quadratic formula.
6
Factor and solve the quadratic equation.
(2k+3)(k4)=0(2k+3)(k-4) = 0, which gives k=1.5k = -1.5 or k=4k = 4.
Factoring determines the values of kk that satisfy the quadratic relation.
7
Apply the constraint that kk is a positive constant.
Since k>0k > 0, we discard k=1.5k = -1.5, leaving k=4k = 4.
The problem specifies that kk must be a positive constant.

Anahtar Kavram

Using the intercepts of a line to formulate its equation and solving the resulting rational/quadratic equation given a point on the line.

Alternatif Yöntem

Instead of using the intercept form of the line, you can equate the slope calculated between the y-intercept (0,2k+2)(0, 2k+2) and the point (3,5)(3,5) to the slope calculated between the point (3,5)(3,5) and the x-intercept (k+2,0)(k+2,0). This yields the equation 5(2k+2)30=05(k+2)3\frac{5 - (2k+2)}{3 - 0} = \frac{0 - 5}{(k+2) - 3}, which simplifies to 32k3=5k1\frac{3 - 2k}{3} = \frac{-5}{k - 1}. Cross-multiplying and simplifying leads to the same quadratic equation, 2k25k12=02k^2 - 5k - 12 = 0.
Tahmini Süre:2m 30s
Soru 19Soru

If 3x2(y5)=123x - 2(y - 5) = 12 and x=8x = 8, what is the value of yy?

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Cevap: 11

Cevap

11
The correct answer is 11. Substituting x=8x = 8 into the equation gives 3(8)2(y5)=123(8) - 2(y - 5) = 12, which simplifies to 242y+10=1224 - 2y + 10 = 12. Combining the constants on the left side yields 342y=1234 - 2y = 12. Subtracting 34 from both sides gives 2y=22-2y = -22. Finally, dividing both sides by 2-2 yields y=11y = 11.

Adım Adım Çözüm

1
Substitute x=8x = 8 into the given equation.
3(8)2(y5)=123(8) - 2(y - 5) = 12, which simplifies to 242(y5)=1224 - 2(y - 5) = 12.
This isolates the variable yy by replacing the variable xx with its given value.
2
Distribute 2-2 to the terms inside the parentheses.
242y+10=1224 - 2y + 10 = 12.
Multiplying 2-2 by yy gives 2y-2y, and multiplying 2-2 by 5-5 gives +10+10 because the product of two negative numbers is positive.
3
Combine the constant terms on the left side of the equation and subtract the result from both sides.
342y=122y=2234 - 2y = 12 \Rightarrow -2y = -22.
Combining 2424 and 1010 gives 3434. Subtracting 3434 from both sides isolates the variable term 2y-2y.
4
Divide both sides by 2-2 to solve for yy.
y=11y = 11.
Dividing both sides of the equation by the coefficient of the variable term isolates the variable.

Anahtar Kavram

Solving linear equations in two variables by substitution and isolation.
Tahmini Süre:45s
Soru 20Soru

In the xyxy-plane, a line passes through the points (2,9)(2, 9) and (5,21)(5, 21). What is the slope of this line?

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Cevap: 4

Cevap

The slope of the line is 4.
The slope mm of a line passing through the points (x1,y1)(x_1, y_1) and (x2,y2)(x_2, y_2) is determined by the formula m=y2y1x2x1m = \frac{y_2 - y_1}{x_2 - x_1}. Substituting the given points (2,9)(2, 9) and (5,21)(5, 21) into the formula gives m=21952=123=4m = \frac{21 - 9}{5 - 2} = \frac{12}{3} = 4.

Adım Adım Çözüm

1
Identify the coordinates of the two points on the line.
(x1,y1)=(2,9)(x_1, y_1) = (2, 9) and (x2,y2)=(5,21)(x_2, y_2) = (5, 21)
These points are used in the slope formula.
2
Apply the slope formula m=y2y1x2x1m = \frac{y_2 - y_1}{x_2 - x_1} to set up the calculation.
m=21952m = \frac{21 - 9}{5 - 2}
The slope is defined as the change in yy divided by the change in xx.
3
Simplify the fraction to calculate the final slope.
m=123=4m = \frac{12}{3} = 4
Dividing the vertical change by the horizontal change yields the slope.

Anahtar Kavram

Calculating the slope of a line given two points in the coordinate plane.
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Linear Equations in Two Variables Alıştırma Soruları — SAT | Examkin