Linear Inequalities in One Variable

41 soru

Soru 21Soru

For which values of xx is the inequality 4(2x5)3x+9-4(2x - 5) \geq 3x + 9 true?

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Cevap: x1x \leq 1

Cevap

The inequality is true for all values of xx such that xx is less than or equal to 11.
The correct inequality representing the solution set is the one that shows the variable is less than or equal to one.

Adım Adım Çözüm

1
Distribute the factor of 4-4 to the terms inside the parentheses on the left side of the inequality.
8x+203x+9-8x + 20 \geq 3x + 9
Applying the distributive property gives 4×2x=8x-4 \times 2x = -8x and 4×5=20-4 \times -5 = 20.
2
Subtract 3x3x from both sides of the inequality to collect all terms with the variable xx on the left side.
11x+209-11x + 20 \geq 9
Grouping the variable terms helps isolate the variable.
3
Subtract 2020 from both sides of the inequality to isolate the variable term.
11x11-11x \geq -11
Subtracting twenty from both sides moves the constant terms to the right side of the inequality.
4
Divide both sides by 11-11 and reverse the direction of the inequality sign.
x1x \leq 1
Dividing or multiplying an inequality by a negative number requires flipping the inequality symbol.

Anahtar Kavram

Linear Inequalities in One Variable
Soru 22Soru

A rideshare driver has a daily goal of earning at least 150.Sofartoday,thedriverhasearned150. So far today, the driver has earned 45. The driver earns 12perrideplusanaveragetipof12 per ride plus an average tip of 3 per ride. If the driver must pay a daily vehicle fee of $15, what is the minimum number of additional rides the driver must complete today to meet or exceed the daily earnings goal?

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Cevap: 8

Cevap

The minimum number of additional rides the driver must complete today is 8.
The driver earns 12plusa12 plus a 3 tip per ride, which is 15perride.Startingwith15 per ride. Starting with 45 and subtracting the 15feeleavesthedriverwith15 fee leaves the driver with 30 before completing any new rides. To reach at least 150,thedriverneedstoearnatleast150, the driver needs to earn at least 120 more. Dividing 120bythe120 by the 15 rate per ride gives a minimum of 8 rides.

Adım Adım Çözüm

1
Define the variable xx for the number of additional rides and write an inequality representing the total net earnings.
45+12x+3x1515045 + 12x + 3x - 15 \geq 150
To represent the condition that the driver's total earnings, including initial earnings and new rides, minus the fee, must be at least $150.
2
Simplify the left side of the inequality by combining the constants and the xx terms.
30+15x15030 + 15x \geq 150
To group like terms and simplify the expression before solving.
3
Subtract 30 from both sides of the inequality to isolate the variable term.
15x12015x \geq 120
To isolate the term with the variable on one side of the inequality.
4
Divide both sides of the inequality by 15 to solve for xx.
x8x \geq 8
To find the minimum value of xx that satisfies the inequality.

Anahtar Kavram

Solving linear inequalities in one variable to find a minimum threshold value in a real-world scenario.
Soru 23Soru

A catering company charges a flat setup fee of 500plus500 plus 35 per guest. A company has budgeted at most 2,400forabanquet.Ifthecompanyalsowantstopurchaseacelebrationcakefor2,400 for a banquet. If the company also wants to purchase a celebration cake for 150, what is the maximum number of guests they can invite to the banquet without exceeding their budget?

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Cevap: 50

Cevap

The maximum number of guests the company can invite without exceeding their budget is 50.
The total cost of the banquet consists of a flat setup fee (500),acelebrationcake(500), a celebration cake ( 150), and a variable cost of 35perguest(35 per guest ( 35g ,where, where g representsthenumberofguests).Sincethecompanyhasbudgetedatmost represents the number of guests). Since the company has budgeted at most 2,400, the sum of these expenses must be less than or equal to 2,400.Thisisrepresentedbytheinequality2,400. This is represented by the inequality 35g + 500 + 150 \le 2400 .Combiningtheconstantsyields. Combining the constants yields 35g + 650 \le 2400 .Subtracting650frombothsidesgives. Subtracting 650 from both sides gives 35g \le 1750 .Dividingbothsidesby35resultsin. Dividing both sides by 35 results in g \le 50$. Therefore, the maximum number of guests they can invite without exceeding their budget is 50.

Adım Adım Çözüm

1
Set up the inequality representing the total expenses.
35g+500+150240035g + 500 + 150 \le 2400
The sum of the fixed setup fee, the cake cost, and the variable per-guest cost must not exceed the maximum budget of $2,400.
2
Simplify the inequality by combining the constants.
35g+650240035g + 650 \le 2400
Combining the fixed expenses (500setupfeeand500 setup fee and 150 cake) simplifies the calculation.
3
Isolate the variable term by subtracting the fixed cost from both sides.
35g175035g \le 1750
This determines the portion of the budget that can be allocated specifically to guests.
4
Solve for the variable by dividing both sides by the cost per guest.
g50g \le 50
Dividing the remaining guest budget by the rate per guest gives the maximum number of guests allowed.

Anahtar Kavram

Formulating and solving multi-step linear inequalities in one variable to determine a maximum value in context.
Soru 24Soru

Which of the following represents all possible values of xx that satisfy the inequality 3(2x5)4x35-3(2x - 5) - 4x \geq 35?

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Cevap: x2x \leq -2

Cevap

The inequality is satisfied by all values of xx such that x2x \leq -2.
To solve the inequality, distribute 3-3 across the terms in the parentheses to get 6x+154x35-6x + 15 - 4x \geq 35. Grouping the xx terms gives 10x+1535-10x + 15 \geq 35. Subtracting 15 from both sides yields 10x20-10x \geq 20. Finally, dividing both sides by 10-10 and reversing the inequality symbol gives x2x \leq -2.

Adım Adım Çözüm

1
Distribute the negative coefficient 3-3 to both terms inside the parentheses.
6x+154x35-6x + 15 - 4x \geq 35
Applying the distributive property a(b+c)=ab+aca(b + c) = ab + ac allows the removal of parentheses to simplify the expression.
2
Combine the variable terms 6x-6x and 4x-4x on the left side of the inequality.
10x+1535-10x + 15 \geq 35
Combining like terms simplifies the left side of the inequality to prepare for isolating the variable.
3
Isolate the variable term by subtracting 15 from both sides of the inequality.
10x20-10x \geq 20
Using the subtraction property of inequality maintains the balance of the inequality while isolating the term with the variable.
4
Divide both sides of the inequality by 10-10 and reverse the direction of the inequality symbol.
x2x \leq -2
Dividing both sides of an inequality by a negative number requires reversing the inequality sign to keep the inequality statement true.

Anahtar Kavram

Solving multi-step linear inequalities in one variable, including distributing terms and reversing the inequality direction when dividing by a negative number.
Tahmini Süre:1m 30s
Soru 25Soru

An online retailer offers free shipping on orders of 75ormore.Acustomerhasplacedashirtcosting75 or more. A customer has placed a shirt costing 22.50 and a pair of pants costing 34.80intheirshoppingcart.Theywanttobuysomepairsofsocksthatcost34.80 in their shopping cart. They want to buy some pairs of socks that cost 4.50 per pair to qualify for free shipping. What is the minimum number of pairs of socks the customer must add to their cart to qualify for free shipping?

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Cevap: 4

Cevap

The minimum number of pairs of socks the customer must add to the cart is 4.
The customer needs to spend at least 75toqualifyforfreeshipping.Thecurrentsubtotalofthecartis75 to qualify for free shipping. The current subtotal of the cart is 22.50 + 34.80=34.80 = 57.30. The remaining amount needed to reach 75is75 is 75.00 - 57.30=57.30 = 17.70. Let ss represent the number of pairs of socks purchased at 4.50perpair.Thiscanberepresentedbytheinequality4.50 per pair. This can be represented by the inequality 4.50s \geq 17.70 .Dividingbothsidesoftheinequalityby. Dividing both sides of the inequality by 4.50 gives gives s \geq 3.93$. Since the customer cannot purchase a fraction of a pair of socks, the minimum number of pairs of socks they must purchase is 4.

Adım Adım Çözüm

1
Calculate the total cost of the items already in the shopping cart.
22.50+22.50 + 34.80 = $57.30
To determine how much has already been spent before adding socks.
2
Set up an inequality to represent the total cost of the order including ss pairs of socks meeting the free shipping threshold of $75.
57.30+4.50s7557.30 + 4.50s \geq 75
The total cost of the shirt, pants, and socks must be greater than or equal to $75.
3
Subtract $57.30 from both sides of the inequality to find the minimum amount that needs to be spent on socks.
4.50s17.704.50s \geq 17.70
To isolate the term representing the cost of the socks.
4
Divide both sides of the inequality by $4.50 to find the minimum number of pairs of socks.
s3.93s \geq 3.93
To isolate the variable representing the number of pairs of socks.
5
Determine the smallest integer value of ss that satisfies the inequality.
4
The number of pairs of socks must be a whole number, and 4 is the smallest integer greater than or equal to 3.93.

Anahtar Kavram

Solving linear inequalities in one variable to find the minimum integer solution in a real-world context.
Tahmini Süre:1m 30s
Soru 26Soru

What is the complete set of solutions for the inequality 73(2x5)4x+87 - 3(2x - 5) \leq -4x + 8?

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Cevap: x7x \geq 7

Cevap

The complete set of solutions is represented by the inequality x7x \geq 7.
To solve the inequality 73(2x5)4x+87 - 3(2x - 5) \leq -4x + 8, we first distribute 3-3 to get 76x+154x+87 - 6x + 15 \leq -4x + 8. Combining constant terms on the left side gives 226x4x+822 - 6x \leq -4x + 8. Adding 4x4x and subtracting 2222 from both sides isolates the variable, resulting in 2x14-2x \leq -14. Dividing both sides by 2-2 and flipping the inequality symbol yields the solution x7x \geq 7.

Adım Adım Çözüm

1
Distribute the 3-3 to both terms inside the parentheses.
76x+154x+87 - 6x + 15 \leq -4x + 8
Applying the distributive property, 3(2x)=6x-3(2x) = -6x and 3(5)=15-3(-5) = 15.
2
Combine the constant terms on the left side of the inequality.
226x4x+822 - 6x \leq -4x + 8
Adding 77 and 1515 yields 2222.
3
Isolate the variable term on one side and the constant term on the other side.
2x14-2x \leq -14
Adding 4x4x to both sides yields 2x-2x, and subtracting 2222 from both sides yields 14-14.
4
Divide both sides by 2-2 and flip the inequality sign.
x7x \geq 7
Dividing both sides of an inequality by a negative number reverses the direction of the inequality symbol.

Anahtar Kavram

Solving multi-step linear inequalities in one variable including negative coefficient division and the distributive property.
Soru 27Soru

To calculate the remaining budget, BB, in dollars, for a community project, a coordinator uses the formula B=1,2003(2x+50)B = 1,200 - 3(2x + 50), where xx is the number of volunteer shifts scheduled. If the coordinator wants the remaining budget to be at most 450,whichofthefollowinginequalitiesrepresentsallpossiblevaluesof450, which of the following inequalities represents all possible values of x$?

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Cevap: x100x \ge 100

Cevap

The correct answer is x100x \ge 100.
The correct answer is the inequality stating that xx is greater than or equal to 100100. Distributing 3-3 to both terms inside the parentheses gives 1,2006x1504501,200 - 6x - 150 \le 450. Combining the constant terms on the left side results in 1,0506x4501,050 - 6x \le 450. Subtracting 1,0501,050 from both sides gives 6x600-6x \le -600. Dividing both sides by 6-6 and reversing the inequality sign because of the division by a negative number yields x100x \ge 100.

Adım Adım Çözüm

1
Substitute the formula for the remaining budget BB into the inequality B450B \le 450.
1,2003(2x+50)4501,200 - 3(2x + 50) \le 450
To find the possible values of xx when the budget is at most 450450.
2
Distribute 3-3 to both terms inside the parentheses.
1,2006x1504501,200 - 6x - 150 \le 450
To simplify the expression by removing the parentheses.
3
Combine the constant terms 1,2001,200 and 150-150 on the left side.
1,0506x4501,050 - 6x \le 450
To simplify the inequality further before isolating the variable.
4
Subtract 1,0501,050 from both sides of the inequality.
6x600-6x \le -600
To isolate the variable term on one side of the inequality.
5
Divide both sides of the inequality by 6-6 and reverse the inequality sign.
x100x \ge 100
Dividing by a negative number requires reversing the direction of the inequality sign to maintain the truth value.

Anahtar Kavram

Solving linear inequalities in one variable, including the distributive property and sign reversal when dividing by a negative number.
Soru 28Soru

If 3(2x5)+4x7-3(2x - 5) + 4x \geq -7, what is the maximum possible value of xx?

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Cevap: 11

Cevap

The maximum possible value of xx is 1111.
By applying the distributive property, combining like terms, and dividing by 2-2 (while reversing the inequality sign), we find that the solution is x11x \leq 11. Thus, the maximum possible value of xx is 1111.

Adım Adım Çözüm

1
Apply the distributive property to simplify the left side of the inequality.
6x+15+4x7 -6x + 15 + 4x \geq -7
Multiplying 3-3 by each term inside the parentheses (2x5)(2x - 5) yields 6x-6x and +15+15.
2
Combine the variable terms on the left side.
2x+157 -2x + 15 \geq -7
Combining 6x-6x and 4x4x gives 2x-2x.
3
Subtract 1515 from both sides of the inequality.
2x22 -2x \geq -22
To isolate the variable term 2x-2x on the left side.
4
Divide both sides by 2-2 and flip the inequality sign.
x11 x \leq 11
Dividing both sides of an inequality by a negative number reverses the direction of the inequality sign.
5
Determine the maximum value from the solution set.
11
The solution set consists of all values less than or equal to 1111, so the greatest value is 1111.

Anahtar Kavram

Solving multi-step linear inequalities, including applying the distributive property and reversing the inequality sign when dividing by a negative number.
Soru 29Soru

A shipping container initially holds 450 packages. A crew unloads the container at a rate of 15 packages per hour, while an automated sorting machine unloads packages at a rate of xx packages per hour. The number of packages remaining in the container after 8 hours must be at most 130. The inequality 4508(15+x)130450 - 8(15 + x) \leq 130 models this scenario. What is the minimum possible value of xx?

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Cevap: 25

Cevap

The minimum possible value of xx is 25.
To find the minimum possible value of xx, solve the inequality 4508(15+x)130450 - 8(15 + x) \leq 130. First, distribute the 8-8 to obtain 4501208x130450 - 120 - 8x \leq 130. Simplify the constant terms on the left side to get 3308x130330 - 8x \leq 130. Subtract 330 from both sides, yielding 8x200-8x \leq -200. Finally, divide both sides by 8-8 and reverse the inequality sign because of the division by a negative number, which results in x25x \geq 25. The minimum possible value of xx is 25.

Adım Adım Çözüm

1
Distribute the factor of 8-8 to both terms inside the parentheses.
4501208x130450 - 120 - 8x \leq 130
To remove the parentheses and prepare to combine like terms.
2
Subtract 120 from 450 to simplify the constants on the left side.
3308x130330 - 8x \leq 130
To simplify the left side of the inequality before isolating the variable.
3
Subtract 330 from both sides of the inequality.
8x200-8x \leq -200
To isolate the variable term on the left-hand side.
4
Divide both sides by 8-8 and reverse the direction of the inequality symbol.
x25x \geq 25
Dividing by a negative value reverses the inequality sign. Since xx must be greater than or equal to 25, the minimum possible value is 25.

Anahtar Kavram

Solving multi-step linear inequalities in one variable, including distributing coefficients and reversing the inequality sign when multiplying or dividing by a negative number.
Soru 30Soru

For the inequality 2(3x4)+5>3x12-2(3x - 4) + 5 > -3x - 12, which inequality represents all possible values of xx?

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Cevap: x<253x < \frac{25}{3}

Cevap

x<253x < \frac{25}{3}
The correct inequality is obtained by first distributing 2-2 to the terms inside the parentheses to get 6x+8+5>3x12-6x + 8 + 5 > -3x - 12. Combining the constants on the left yields 6x+13>3x12-6x + 13 > -3x - 12. Adding 3x3x to both sides results in 3x+13>12-3x + 13 > -12, and subtracting 13 from both sides gives 3x>25-3x > -25. Finally, dividing by 3-3 and flipping the inequality sign results in the correct solution.

Adım Adım Çözüm

1
Distribute 2-2 to the terms inside the parentheses on the left side of the inequality.
6x+8+5>3x12-6x + 8 + 5 > -3x - 12
Applying the distributive property simplifies the expression.
2
Combine the constant terms on the left side.
6x+13>3x12-6x + 13 > -3x - 12
Simplifying the constant terms makes it easier to isolate the variable.
3
Add 3x3x to both sides to move all variable terms to the left side.
3x+13>12-3x + 13 > -12
This isolates the variable terms on one side of the inequality.
4
Subtract 13 from both sides to isolate the variable term.
3x>25-3x > -25
This isolates the term containing xx.
5
Divide both sides by 3-3 and reverse the direction of the inequality sign.
x<253x < \frac{25}{3}
Dividing by a negative number requires reversing the inequality sign.

Anahtar Kavram

Solving linear inequalities in one variable using the distributive property and sign reversal rules.
Soru 31Soru

A science museum offers two ticketing options for groups. Option A is a flat group rate of 125plus125 plus 9.50 per person. Option B is a flat group rate of 50plus50 plus 12.50 per person. For a group of pp people, Option A is less expensive than Option B. What is the minimum number of people in the group for this to be true?

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Cevap: 26

Cevap

The minimum number of people in the group is 26.
To find when Option A is less expensive than Option B, we set up the inequality representing their respective costs: 125+9.5p<50+12.5p125 + 9.5p < 50 + 12.5p. Subtracting 9.5p9.5p from both sides gives 125<50+3p125 < 50 + 3p. Subtracting 5050 from both sides yields 75<3p75 < 3p. Dividing by 33 gives p>25p > 25. Because the group must consist of a whole number of people, the minimum integer value of pp that is strictly greater than 2525 is 2626.

Adım Adım Çözüm

1
Write the inequality representing the cost comparison between the two ticketing options.
125+9.5p<50+12.5p125 + 9.5p < 50 + 12.5p
Option A's cost must be strictly less than Option B's cost for Option A to be less expensive.
2
Isolate the variable pp by subtracting 9.5p9.5p and 5050 from both sides of the inequality.
p>25p > 25
Subtracting 9.5p9.5p yields 125<50+3p125 < 50 + 3p. Subtracting 5050 yields 75<3p75 < 3p. Dividing by 33 yields p>25p > 25.
3
Identify the minimum integer value of pp that satisfies the inequality.
26
Since the number of people must be a positive integer, the smallest integer strictly greater than 2525 is 2626.

Anahtar Kavram

Solving linear inequalities in one variable and interpreting the solution set within a discrete real-world context.
Tahmini Süre:1m 30s
Soru 32Soru

What is the solution set for the inequality 52(3x1)4x+115 - 2(3x - 1) \geq -4x + 11?

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Cevap: x2x \leq -2

Cevap

The correct solution is xx is less than or equal to 2-2.
To solve the inequality, first distribute the negative two to the terms inside the parentheses to get 56x+24x+115 - 6x + 2 \geq -4x + 11. Combining the constants on the left side yields 76x4x+117 - 6x \geq -4x + 11. Adding four xx to both sides results in 72x117 - 2x \geq 11, and subtracting seven from both sides isolates the variable term, giving 2x4-2x \geq 4. Dividing both sides by negative two and reversing the inequality sign yields the correct solution, xx is less than or equal to negative two.

Adım Adım Çözüm

1
Distribute the 2-2 to the terms inside the parentheses.
56x+24x+115 - 6x + 2 \geq -4x + 11
To simplify the expression by removing the parentheses.
2
Combine the constant terms on the left side of the inequality.
76x4x+117 - 6x \geq -4x + 11
To group like terms together before isolating the variable.
3
Add 4x4x to both sides of the inequality.
72x117 - 2x \geq 11
To move all variable terms to one side of the inequality.
4
Subtract 77 from both sides of the inequality.
2x4-2x \geq 4
To isolate the variable term.
5
Divide both sides by 2-2 and reverse the inequality sign.
x2x \leq -2
Dividing an inequality by a negative number requires reversing the direction of the inequality sign to keep the statement true.

Anahtar Kavram

Solving linear inequalities in one variable using the distributive property and applying the sign reversal rule when dividing by a negative number.
Tahmini Süre:1m 30s
Soru 33Soru

If 5(2x9)+318-5(2x - 9) + 3 \geq 18, what is the maximum possible value of xx?

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Cevap: 3

Cevap

The correct answer is 3.
Distributing the 5-5 gives 10x+45+318-10x + 45 + 3 \geq 18. Combining constants yields 10x+4818-10x + 48 \geq 18. Subtracting 48 from both sides gives 10x30-10x \geq -30. Finally, dividing both sides by 10-10 and reversing the inequality sign gives x3x \leq 3. The maximum possible value is therefore 3.

Adım Adım Çözüm

1
Distribute 5-5 to the terms inside the parentheses.
10x+45+318-10x + 45 + 3 \geq 18
Simplify the expression by expanding the parentheses.
2
Combine the constant terms 4545 and 33 on the left side.
10x+4818-10x + 48 \geq 18
Group like terms together.
3
Subtract 4848 from both sides of the inequality.
10x30-10x \geq -30
Isolate the variable term.
4
Divide both sides by 10-10 and reverse the inequality symbol.
x3x \leq 3
Dividing by a negative number reverses the direction of the inequality.

Anahtar Kavram

Solving multi-step linear inequalities in one variable, applying the distributive property, and reversing the inequality sign when multiplying or dividing by a negative number.
Soru 34Soru

What is the complete set of solutions to the inequality 23(6x9)+4>12-\frac{2}{3}(6x - 9) + 4 > 12?

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Cevap: x<12x < -\frac{1}{2}

Cevap

The inequality is satisfied for all values of xx such that x<12x < -\frac{1}{2}.
Distributing 23-\frac{2}{3} across (6x9)(6x - 9) yields 4x+6-4x + 6. Adding 4 gives 4x+10>12-4x + 10 > 12. Subtracting 10 from both sides results in 4x>2-4x > 2. Dividing by 4-4 and reversing the inequality sign yields x<12x < -\frac{1}{2}.

Adım Adım Çözüm

1
Distribute 23-\frac{2}{3} to both terms inside the parentheses: (6x9)(6x - 9).
4x+6+4>12-4x + 6 + 4 > 12, which simplifies to 4x+10>12-4x + 10 > 12.
Applying the distributive property removes the parentheses.
2
Subtract 10 from both sides of the inequality to isolate the term with xx.
4x>2-4x > 2
Subtracting 10 from both sides maintains the inequality while simplifying the constant terms.
3
Divide both sides by 4-4 and reverse the inequality sign.
x<12x < -\frac{1}{2}
Dividing both sides of an inequality by a negative number requires reversing the direction of the inequality symbol.

Anahtar Kavram

Solving linear inequalities in one variable requires distributing coefficient terms, combining constants, and reversing the inequality sign when multiplying or dividing by a negative number.
Tahmini Süre:1m 15s
Soru 35Soru

In the inequality 3(2x5)+82(kx3)1-3(2x - 5) + 8 \geq 2(kx - 3) - 1, kk is a constant. If the solution set for xx is x2x \leq 2, what is the value of kk?

Cevabı ve açıklamayı göster

Cevap: 4.5

Cevap

4.5
To find the value of kk, simplify both sides of the inequality: 3(2x5)+82(kx3)1-3(2x - 5) + 8 \geq 2(kx - 3) - 1 becomes 6x+232kx7-6x + 23 \geq 2kx - 7. Grouping the variable terms on the left and constants on the right gives (6+2k)x30-(6 + 2k)x \geq -30. Because the solution set is x2x \leq 2, dividing by the negative coefficient reverses the inequality sign to yield x306+2kx \leq \frac{30}{6 + 2k}. Setting the boundary value 306+2k\frac{30}{6 + 2k} equal to 2 gives the equation 30=2(6+2k)=12+4k30 = 2(6 + 2k) = 12 + 4k. Subtracting 12 from both sides gives 18=4k18 = 4k, which results in k=4.5k = 4.5.

Adım Adım Çözüm

1
Simplify both sides of the inequality
6x+232kx7-6x + 23 \geq 2kx - 7
Distribute the constants on both sides: 3(2x5)+8=6x+15+8=6x+23-3(2x - 5) + 8 = -6x + 15 + 8 = -6x + 23, and 2(kx3)1=2kx61=2kx72(kx - 3) - 1 = 2kx - 6 - 1 = 2kx - 7.
2
Isolate the variable terms on the left side and constants on the right side
(6+2k)x30-(6 + 2k)x \geq -30
Subtract 2kx2kx and 2323 from both sides to get 6x2kx723-6x - 2kx \geq -7 - 23, then factor out xx to get (6+2k)x30-(6 + 2k)x \geq -30.
3
Relate the inequality to the given solution boundary
x306+2kx \leq \frac{30}{6 + 2k}
Since the solution is x2x \leq 2, dividing both sides by the negative coefficient (6+2k)-(6 + 2k) reverses the inequality sign, yielding x30(6+2k)=306+2kx \leq \frac{-30}{-(6 + 2k)} = \frac{30}{6 + 2k}.
4
Solve for kk using the boundary equation
k=4.5k = 4.5
Set the boundary expression equal to 2: 306+2k=2\frac{30}{6 + 2k} = 2. Multiply both sides by 6+2k6 + 2k to get 30=12+4k30 = 12 + 4k, which simplifies to 18=4k18 = 4k, giving k=4.5k = 4.5.

Anahtar Kavram

Solving linear inequalities in one variable involving variable coefficients and applying the inequality direction flip when dividing by a negative value.
Soru 36Soru

Which of the following represents all possible values of xx that satisfy the inequality 2(x4)+9>2x+5-2(x - 4) + 9 > 2x + 5?

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Cevap: x<3x < 3

Cevap

x<3x < 3
Expanding the inequality by distributing 2-2 yields 2x+8+9>2x+5-2x + 8 + 9 > 2x + 5, which simplifies to 2x+17>2x+5-2x + 17 > 2x + 5. Subtracting 2x2x and 1717 from both sides isolates the variable terms, giving 4x>12-4x > -12. Dividing both sides by the negative coefficient 4-4 and reversing the inequality sign results in the solution set representing all values of xx less than 33.

Adım Adım Çözüm

1
Distribute the coefficient 2-2 to the terms inside the parentheses on the left side of the inequality.
2x+8+9>2x+5-2x + 8 + 9 > 2x + 5
Applying the distributive property removes the parentheses so like terms can be combined.
2
Combine the constant terms on the left side.
2x+17>2x+5-2x + 17 > 2x + 5
Simplifying the constant terms makes it easier to isolate the variable.
3
Subtract 2x2x and 1717 from both sides of the inequality.
4x>12-4x > -12
This groups all terms containing the variable on the left side and all constant terms on the right side.
4
Divide both sides by 4-4 and reverse the inequality sign.
x<3x < 3
Dividing both sides of an inequality by a negative number requires reversing the direction of the inequality sign.

Anahtar Kavram

To solve a multi-step linear inequality, apply the distributive property, combine like terms, isolate the variable, and reverse the inequality sign when multiplying or dividing both sides by a negative number.
Soru 37Soru

A truck rental company charges a daily fee of 45.00plus45.00 plus 0.75 per mile driven. A driver rents a truck for one day, has a budget of at most $150.00, and is required to drive at least 60 miles for a delivery. What is the maximum number of additional miles the driver can drive beyond the required 60 miles without exceeding the budget?

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Cevap: 80

Cevap

80
To find the maximum number of additional miles, we set up the inequality 45+0.75(60+a)15045 + 0.75(60 + a) \leq 150, where aa represents the number of additional miles driven. Distributing 0.750.75 yields 45+45+0.75a15045 + 45 + 0.75a \leq 150, which simplifies to 90+0.75a15090 + 0.75a \leq 150. Subtracting 9090 from both sides gives 0.75a600.75a \leq 60. Finally, dividing by 0.750.75 gives a80a \leq 80. The maximum value of aa is therefore 80.

Adım Adım Çözüm

1
Set up the inequality representing the total budget constraint.
45+0.75(60+a)15045 + 0.75(60 + a) \leq 150, where aa is the number of additional miles.
The daily fee is 45,thepermilerateis45, the per-mile rate is 0.75, the driver must drive at least 60 miles plus aa additional miles, and the total cost cannot exceed the $150 budget.
2
Simplify the expression by distributing 0.750.75 and combining constant terms.
90+0.75a15090 + 0.75a \leq 150
0.75×60=450.75 \times 60 = 45, and adding the daily fee of 4545 gives 9090.
3
Isolate the variable term by subtracting 9090 from both sides.
0.75a600.75a \leq 60
This determines the remaining budget available for the additional miles.
4
Solve for aa by dividing both sides by 0.750.75.
a80a \leq 80
Dividing 6060 by 0.750.75 gives the maximum number of additional miles.

Anahtar Kavram

Solving multi-step linear inequalities in context
Soru 38Soru

Which inequality is equivalent to 3(3x5)4<2x+18-3(3x - 5) - 4 < -2x + 18?

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Cevap: x>1x > -1

Cevap

x>1x > -1
The correct inequality is found by first expanding 3(3x5)-3(3x - 5) to get 9x+15-9x + 15. The inequality becomes 9x+154<2x+18-9x + 15 - 4 < -2x + 18, which simplifies to 9x+11<2x+18-9x + 11 < -2x + 18. Adding 2x2x to both sides gives 7x+11<18-7x + 11 < 18. Subtracting 1111 from both sides gives 7x<7-7x < 7. Dividing both sides by the negative coefficient 7-7 requires reversing the inequality sign, yielding x>1x > -1.

Adım Adım Çözüm

1
Distribute 3-3 to both terms inside the parentheses: 3(3x5)-3(3x - 5).
9x+154<2x+18-9x + 15 - 4 < -2x + 18
This expands the expression using the distributive property, making sure to multiply both 3x3x and 5-5 by 3-3, which changes the sign of the constant term to positive 1515.
2
Combine the constant terms on the left side of the inequality.
9x+11<2x+18-9x + 11 < -2x + 18
Simplifying the constant terms (154=1115 - 4 = 11) makes it easier to isolate the variable.
3
Add 2x2x to both sides of the inequality to group the variable terms on the left.
7x+11<18-7x + 11 < 18
This combines the xx terms on one side of the inequality.
4
Subtract 1111 from both sides of the inequality to group the constant terms on the right.
7x<7-7x < 7
This isolates the term with the variable on the left side.
5
Divide both sides of the inequality by 7-7 and reverse the inequality sign.
x>1x > -1
Since we are dividing by a negative number, the inequality sign must be reversed from less than (<<) to greater than (>>).

Anahtar Kavram

Solving linear inequalities in one variable, including the distributive property and division by negative numbers.
Soru 39Soru

In a certain board game, a player receives 1515 points for each quest completed, but loses 44 points for each penalty card drawn. A player completes 1212 quests and draws cc penalty cards. If the player's total score is greater than 120120 points, what is the maximum possible value of cc?

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Cevap: 14

Cevap

14
The player earns a base score of 15×12=18015 \times 12 = 180 points from quests, and loses 44 points for each of the cc penalty cards, resulting in a total score of 1804c180 - 4c points. Because the score must be greater than 120120, we write the inequality 1804c>120180 - 4c > 120. Subtracting 180180 from both sides yields 4c>60-4c > -60. Dividing by 4-4 and reversing the inequality sign gives c<15c < 15. Since cc must represent a whole number of cards, the maximum possible value is the largest integer less than 1515, which is 1414.

Adım Adım Çözüm

1
Set up the inequality representing the score constraint.
1804c>120180 - 4c > 120
The player earns 1515 points for each of the 1212 quests (15×12=18015 \times 12 = 180) and loses 44 points for each of the cc penalty cards (4c4c), and this total must exceed 120120.
2
Isolate the variable term by subtracting 180180 from both sides.
4c>60-4c > -60
To solve for cc, we first subtract the constant term 180180 from both sides of the inequality.
3
Divide both sides by 4-4 and reverse the inequality sign.
c<15c < 15
Dividing an inequality by a negative number requires reversing the direction of the inequality sign.
4
Determine the maximum integer value for cc.
1414
Since the number of penalty cards cc must be a whole number and cc must be strictly less than 1515, the largest possible value is 1414.

Anahtar Kavram

Solving linear inequalities in one variable involving multiplication or division by a negative number and interpreting the solution set in a discrete context.
Soru 40Soru

What is the solution set for the inequality 2(3x4)+5x+3-2(3x - 4) + 5 \leq -x + 3?

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Cevap: x2x \geq 2

Cevap

x2x \geq 2
Distributing 2-2 over 3x43x - 4 yields 6x+8-6x + 8. Combining the constants on the left gives 6x+13x+3-6x + 13 \leq -x + 3. Subtracting 1313 and adding xx to both sides results in 5x10-5x \leq -10. Dividing both sides by 5-5 and flipping the inequality symbol yields the solution set of all values greater than or equal to 22.

Adım Adım Çözüm

1
Distribute the 2-2 coefficient on the left side of the inequality.
6x+8+5x+3-6x + 8 + 5 \leq -x + 3
Applying the distributive property simplifies the expression inside the parentheses.
2
Combine the constant terms on the left side of the inequality.
6x+13x+3-6x + 13 \leq -x + 3
Combining like terms simplifies the left-hand side before isolating the variable.
3
Subtract 1313 from both sides of the inequality.
6xx10-6x \leq -x - 10
This begins the process of isolating the variable terms on one side and constant terms on the other.
4
Add xx to both sides of the inequality.
5x10-5x \leq -10
This groups all variable terms together on the left-hand side.
5
Divide both sides of the inequality by 5-5 and reverse the direction of the inequality sign.
x2x \geq 2
Dividing an inequality by a negative number requires reversing the inequality sign to maintain a true statement.

Anahtar Kavram

Solving linear inequalities in one variable using algebraic properties, specifically distributing a negative value and reversing the inequality direction when dividing by a negative number.
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Linear Inequalities in One Variable Alıştırma Soruları — SAT — Sayfa 2 | Examkin