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188 questions

Question 141Question

In the annual budget estimates of a state government, the following budgetary figures are reported for a given financial year:
- Total Revenue Receipts: 2,50,000₹ 2,50,000 crore
- Non-debt Capital Receipts: 15,000₹ 15,000 crore
- Revenue Expenditure: ���3,10,000��� 3,10,000 crore
- Capital Expenditure: 75,000₹ 75,000 crore
- Interest Payments on past public debt: 45,000₹ 45,000 crore

Based on the provided figures, what is the Primary Deficit of the state government for that financial year (in crore)?

Show answer & explanation

Answer: 75000

Answer

The Primary Deficit of the government is ₹ 75,000 crore.
The Primary Deficit reflects the net borrowing required to meet current year expenses excluding committed interest costs. It is derived as Fiscal Deficit minus Interest Payments. First, Total Expenditure (3,10,000+75,000=3,85,0003,10,000 + 75,000 = 3,85,000 crore) minus Total Non-Debt Receipts (2,50,000+15,000=2,65,0002,50,000 + 15,000 = 2,65,000 crore) gives a Fiscal Deficit of 1,20,000₹ 1,20,000 crore. Subtracting the interest payments of 45,000₹ 45,000 crore yields a Primary Deficit of 75,000₹ 75,000 crore.

Step-by-Step Solution

1
Calculate Total Expenditure
₹ 3,85,000 crore
Total Expenditure includes both current operational expenses (Revenue Expenditure) and creation of assets (Capital Expenditure).
2
Calculate Total Non-Debt Receipts
₹ 2,65,000 crore
Non-Debt Receipts consist of tax/non-tax revenues and capital receipts that do not create future repayment obligations (such as loan recoveries).
3
Calculate Fiscal Deficit
₹ 1,20,000 crore
Fiscal Deficit measures the total borrowing requirement of the government, obtained by subtracting total non-debt receipts from total expenditure.
4
Calculate Primary Deficit
₹ 75,000 crore
Primary Deficit indicates the current fiscal imbalances by excluding interest burdens accumulated from past debt liabilities.

Key Concept

Primary Deficit and Fiscal Deficit Metrics in Public Finance
Estimated Time:1m 30s
Question 142Question

According to a state economic survey on income distribution, the top 10%10\% of the population holds 52%52\% of the total gross income, whereas the bottom 40%40\% of the population accounts for 13%13\% of the total gross income. Based on the standard Palma ratio metric for income inequality, what is the calculated Palma ratio for this state?

Show answer & explanation

Answer: 4

Answer

The calculated Palma ratio for the state is 4.04.0.
The Palma ratio is defined as the ratio of the richest 10%10\% of the population's share of gross national income divided by the poorest 40%s40\%'s share. Substituting the given values (52%52\% divided by 13%13\%) gives a Palma ratio of 4.04.0.

Step-by-Step Solution

1
Extract the relevant income shares from the economic survey data.
Income share of top 10%=52%10\% = 52\%, Income share of bottom 40%=13%40\% = 13\%.
The Palma ratio specifically compares the income share of the top decile to that of the bottom four deciles.
2
Calculate the ratio of the top decile share to the bottom four deciles share.
\text{Palma Ratio} = \frac{52}{13} = 4.0
Applying the formula: Palma Ratio = (Income share of top 10%) / (Income share of bottom 40%).

Key Concept

Palma Ratio as an Inequality Metric
Question 143Question

Consider the following numerical series: 4,7,12,19,28,4, 7, 12, 19, 28, \dots. What is the next number in this series?

Show answer & explanation

Answer: 39

Answer

The next number in the series is 3939.
The difference between consecutive terms increases by 2 each time (+3,+5,+7,+9+3, +5, +7, +9). The next difference to add is +11+11, yielding 28+11=3928 + 11 = 39.

Step-by-Step Solution

1
Calculate the difference between each pair of consecutive terms.
The differences are 3,5,7,93, 5, 7, 9.
Identifying the first-order difference sequence reveals the pattern of progression.
2
Find the next value in the difference sequence.
The next odd number after 99 is 1111.
The pattern of differences consists of consecutive prime/odd increments (specifically, odd numbers +2+2 each step).
3
Add the calculated difference to the final given term of the series.
28+11=3928 + 11 = 39
Applying the pattern to find the subsequent term.

Key Concept

Number series completion using a sequence of increasing odd differences.
Question 144Question

Consider the numerical sequence: 5,11,24,51,106,217,5, 11, 24, 51, 106, 217, \dots. What is the value of the next term in this sequence?

Show answer & explanation

Answer: 440

Answer

The next term in the sequence is 440.
The sequence follows the recurrence pattern where each term is twice the previous term plus an increasing integer offset: 5×2+1=115 \times 2 + 1 = 11, 11×2+2=2411 \times 2 + 2 = 24, 24×2+3=5124 \times 2 + 3 = 51, 51×2+4=10651 \times 2 + 4 = 106, 106×2+5=217106 \times 2 + 5 = 217. Following this pattern, the next term is 217×2+6=440217 \times 2 + 6 = 440.

Step-by-Step Solution

1
Examine the relationship between successive terms.
The differences between successive terms are 6,13,27,55,1116, 13, 27, 55, 111, and the second-level differences are 7,14,28,567, 14, 28, 56 (doubling each step). Alternatively, each term is multiplied by 2 and increased by an incrementing integer.
Analyzing both direct operations and higher-order differences establishes the recurrence rule an+1=2an+na_{n+1} = 2a_n + n.
2
Determine the required operation for the next step in the sequence.
Multiply the 6th term (217) by 2 and add 6.
The additive component increases by 1 at each term (+1,+2,+3,+4,+5+6+1, +2, +3, +4, +5 \rightarrow +6).
3
Calculate the value of the next term.
217×2+6=440217 \times 2 + 6 = 440.
217×2=434217 \times 2 = 434, and adding 6 yields 440.

Key Concept

Recurrent series with multiplicative factor and sequential linear increment
Estimated Time:1m 30s
Question 145Question

A surveyor mapping a nature reserve starts from a base station. He walks 14 km14\text{ km} due East, turns 9090^\circ to his right, and walks 20 km20\text{ km}. Next, he turns 135135^\circ to his left and walks 102 km10\sqrt{2}\text{ km}. Finally, he turns 4545^\circ to his left and walks 3 km3\text{ km} due North to reach an observation point. What is the shortest straight-line distance (in km) between the base station and the observation point?

Show answer & explanation

Answer: 25

Answer

The shortest straight-line distance between the base station and the observation point is 25 km.
Resolving each displacement into Cartesian coordinates gives a net horizontal displacement of Δx=14+10=24 km\Delta x = 14 + 10 = 24\text{ km} (East) and a net vertical displacement of Δy=20+10+3=7 km\Delta y = -20 + 10 + 3 = -7\text{ km} (South). Applying the Pythagorean theorem yields 242+(7)2=625=25 km\sqrt{24^2 + (-7)^2} = \sqrt{625} = 25\text{ km}.

Step-by-Step Solution

1
Establish a Cartesian coordinate system with the base station as the origin (0,0)(0,0).
Initial coordinates are (0,0)(0,0) facing East.
Assigning coordinates simplifies multi-turn vector displacement tracking.
2
Calculate coordinates after moving 14 km14\text{ km} East, turning 9090^\circ right (facing South), and walking 20 km20\text{ km}.
Position is (14,20)(14, -20) facing South.
Moving East adds 1414 to the x-coordinate, and moving South subtracts 2020 from the y-coordinate.
3
Resolve the 102 km10\sqrt{2}\text{ km} walk after a 135135^\circ left turn from South into components.
Facing North-East, displacement components are +10 km+10\text{ km} East and +10 km+10\text{ km} North, yielding coordinates (24,10)(24, -10).
Turning 135135^\circ left from South points directly North-East (4545^\circ north of east). The components are 102cos(45)=10 km10\sqrt{2}\cos(45^\circ) = 10\text{ km} East and 102sin(45)=10 km10\sqrt{2}\sin(45^\circ) = 10\text{ km} North.
4
Update coordinates after turning 4545^\circ left from North-East (facing North) and walking 3 km3\text{ km}.
Final position is (24,10+3)=(24,7)(24, -10 + 3) = (24, -7).
A 4545^\circ left turn aligns the direction due North, adding 3 km3\text{ km} to the y-coordinate.
5
Calculate the straight-line displacement from (0,0)(0,0) to (24,7)(24, -7) using the distance formula.
Distance d=242+(7)2=576+49=625=25 kmd = \sqrt{24^2 + (-7)^2} = \sqrt{576 + 49} = \sqrt{625} = 25\text{ km}.
The shortest distance between origin and final point is given by d=Δx2+Δy2d = \sqrt{\Delta x^2 + \Delta y^2}.

Key Concept

Direction and Distance Test involving multi-turn vector resolution, angular rotations, and Pythagorean straight-line distance calculation.
Question 146Question
Consider the following numerical sequence:
3,11,38,102,227,3, 11, 38, 102, 227, \dots
What is the value of the next term in this sequence?
Show answer & explanation

Answer: 443

Answer

The next term in the sequence is 443.
Each term increases by the cube of consecutive natural numbers starting from 2: +2³, +3³, +4³, +5³, and +6³. Adding 6³ (which equals 216) to the preceding term 227 yields 443.

Step-by-Step Solution

1
Find the difference between consecutive terms in the given sequence.
The differences are 8, 27, 64, and 125.
Analyzing first-order differences reveals the rate of increase between terms.
2
Identify the logical pattern governing the sequence of differences.
The differences correspond to consecutive perfect cubes: 2³, 3³, 4³, and 5³.
Recognizing that 8 = 2³, 27 = 3³, 64 = 4³, and 125 = 5³ establishes the cubic growth rule.
3
Calculate the next term by extending the identified pattern.
Next difference = 6³ = 216, resulting in next term = 227 + 216 = 443.
Following the consecutive cubic sequence, the fifth difference must be 6³.

Key Concept

Cube-Difference Series Progression
Question 147Question

What is the simplified value of the following mathematical expression?

45÷5×3+[18{14(83)}]45 \div 5 \times 3 + [18 - \{14 - (8 - 3)\}]
Show answer & explanation

Answer: 36

Answer

36
Following the BODMAS rule step by step:
1. Innermost parenthesis: 83=58 - 3 = 5.
2. Curly braces: 145=914 - 5 = 9.
3. Square brackets: 189=918 - 9 = 9.
4. Left-to-right division and multiplication: 45÷5×3=9×3=2745 \div 5 \times 3 = 9 \times 3 = 27.
5. Addition: 27+9=3627 + 9 = 36.

Step-by-Step Solution

1
Evaluate the innermost round brackets
8 - 3 = 5
According to the BODMAS rule, operations inside the innermost brackets must be solved first.
2
Evaluate the expression inside the curly braces
14 - 5 = 9
Substitute the result from the round brackets into the curly braces.
3
Evaluate the expression inside the square brackets
18 - 9 = 9
Substitute the result from the curly braces into the square brackets.
4
Perform Division and Multiplication from left to right
45 / 5 * 3 = 9 * 3 = 27
Division and multiplication have equal precedence and must be evaluated strictly from left to right.
5
Add the result of the bracket terms to the result of the arithmetic terms
27 + 9 = 36
Final addition yields the simplified result.

Key Concept

BODMAS Rule (Brackets, Orders, Division and Multiplication left-to-right, Addition and Subtraction left-to-right)
Question 148Question

The table below presents the freshwater fish production and pricing metrics across four regional inland lake zones managed by the State Fisheries Development Board for the year 2025:

Lake ZoneTotal Catch (in Tonnes)Export Grade Share (%)Local Market Price (in ₹ per kg)Export Market Price (in ₹ per kg)
Lake Alpha40030%150350
Lake Beta50040%160400
Lake Gamma35020%140300
Lake Delta60025%180420

Note: 1 Tonne=1,000 kg1\text{ Tonne} = 1,000\text{ kg} and 1 Lakh=100,0001\text{ Lakh} = 100,000.

Based on the table, calculate the total revenue (in ₹ Lakhs) generated by Lake Beta from both local and export market sales combined.

Show answer & explanation

Answer: 1280

Answer

The total revenue generated by Lake Beta from local and export market sales combined is ₹1,280 Lakhs.
Lake Beta produces 500 tonnes=500,000 kg500\text{ tonnes} = 500,000\text{ kg} of fish. 40%40\% of this (200,000 kg200,000\text{ kg}) is exported at ₹400/kg400/\text{kg}, yielding ₹800 Lakhs800\text{ Lakhs}. The remaining 60%60\% (300,000 kg300,000\text{ kg}) is sold locally at ₹160/kg160/\text{kg}, yielding ₹480 Lakhs480\text{ Lakhs}. Combining both gives ₹1,280 Lakhs1,280\text{ Lakhs}.

Step-by-Step Solution

1
Convert the total catch of Lake Beta to kilograms.
500 tonnes=500,000 kg500\text{ tonnes} = 500,000\text{ kg}.
Prices are given per kilogram, so total mass must be in kilograms.
2
Partition the total catch into export grade and local market quantities.
Export quantity = 40%×500,000=200,000 kg40\% \times 500,000 = 200,000\text{ kg}; Local quantity = 60%×500,000=300,000 kg60\% \times 500,000 = 300,000\text{ kg}.
Different market prices apply to export grade vs local grade catch.
3
Calculate monetary revenue for each grade and find their sum in ₹ Lakhs.
Export revenue = 200,000×400=80,000,000=800 Lakhs200,000 \times 400 = ₹80,000,000 = ₹800\text{ Lakhs}; Local revenue = 300,000×160=48,000,000=480 Lakhs300,000 \times 160 = ₹48,000,000 = ₹480\text{ Lakhs}; Total = 800+480=1,280 Lakhs800 + 480 = ₹1,280\text{ Lakhs}.
Summing both revenue streams gives the total earnings for Lake Beta.

Key Concept

Weighted revenue calculation from multi-column tabular data
Estimated Time:1m 30s
Question 149Question

What is the unit digit of 7827^{82}?

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Answer: 9

Answer

The unit digit of 7827^{82} is 9.
The unit digits of powers of 7 repeat in a pattern of 4 (7, 9, 3, 1). Dividing the exponent 82 by 4 yields a remainder of 2. The second number in the cyclic pattern is 9, making 9 the unit digit of 7827^{82}.

Step-by-Step Solution

1
Find the cyclicity of the base number 7
The unit digits follow a repeating 4-step sequence: 7, 9, 3, 1.
Powers of 7 cycle every 4 powers because 71=77^1=7, 72=497^2=49, 73=3437^3=343, and 74=24017^4=2401.
2
Divide the exponent by the cyclicity period
82÷4=2082 \div 4 = 20 with a remainder of 2.
The remainder determines the equivalent power position within the 4-step cycle.
3
Determine the unit digit from the remainder
The unit digit of 727^2 is 9.
A remainder of 2 corresponds to 727^2, giving 9.

Key Concept

Unit Digit Cyclicity
Question 150Question

Calculate the exact numerical value of the following mathematical expression by applying the standard order of operations (BODMAS):

36.4[12.8+{6.5×(4.42.6+0.8)}÷1.3]36.4 - \left[ 12.8 + \left\{ 6.5 \times \left( 4.4 - \overline{2.6 + 0.8} \right) \right\} \div 1.3 \right]
Show answer & explanation

Answer: 18.6

Answer

The simplified value of the mathematical expression is 18.6.
Strict application of BODMAS requires simplifying grouping symbols from the innermost vinculum outward, followed by resolving division prior to addition within brackets, yielding an exact answer of 18.6.

Step-by-Step Solution

1
Evaluate the expression underneath the vinculum (bar line)
\overline{2.6 + 0.8} = 3.4
The vinculum functions as an innermost bracket with highest evaluation priority.
2
Evaluate the terms inside the round brackets
4.4 - 3.4 = 1.0
Process operations inside round brackets next.
3
Perform multiplication within the curly braces
6.5×1.0=6.56.5 \times 1.0 = 6.5
Complete operations within the curly braces.
4
Execute division inside the square brackets
6.5÷1.3=5.06.5 \div 1.3 = 5.0
Division takes precedence over addition according to BODMAS rules.
5
Perform addition within the square brackets
12.8 + 5.0 = 17.8
Finish evaluating all operations contained within the square brackets.
6
Perform final subtraction from left to right
36.4 - 17.8 = 18.6
Complete the outermost subtraction to arrive at the final simplified value.

Key Concept

BODMAS Rule with Vinculum and Decimals
Question 151Question

What is the simplified value of 7+433\sqrt{7 + 4\sqrt{3}} - \sqrt{3}?

Show answer & explanation

Answer: 2

Answer

The simplified value is 2.
Expressing 7+437 + 4\sqrt{3} as (2+3)2(2 + \sqrt{3})^2 allows the square root to simplify directly to 2+32 + \sqrt{3}. Subtracting 3\sqrt{3} leaves the exact numerical answer 2.

Step-by-Step Solution

1
Rewrite the expression under the square root as a perfect square of a binomial.
7+43=22+(3)2+2(2)(3)=(2+3)27 + 4\sqrt{3} = 2^2 + (\sqrt{3})^2 + 2(2)(\sqrt{3}) = (2 + \sqrt{3})^2
Using the identity (a+b)2=a2+b2+2ab(a+b)^2 = a^2 + b^2 + 2ab, setting a=2a = 2 and b=3b = \sqrt{3} yields a2+b2=4+3=7a^2 + b^2 = 4 + 3 = 7 and 2ab=432ab = 4\sqrt{3}.
2
Evaluate the square root of the perfect square.
(2+3)2=2+3\sqrt{(2 + \sqrt{3})^2} = 2 + \sqrt{3}
The principal square root of a positive squared expression x2\sqrt{x^2} is xx.
3
Perform the subtraction indicated in the stem.
(2+3)3=2(2 + \sqrt{3}) - \sqrt{3} = 2
The radical terms 3\sqrt{3} and 3-\sqrt{3} cancel out, leaving the integer 2.

Key Concept

Simplification of Nested Surds
Question 152Question
Find the exact numerical value of the following mathematical expression evaluated strictly according to the VBODMAS rule:
75% of 160[3.5×8+{48÷(145×2)}]75\% \text{ of } 160 - \left[ 3.5 \times 8 + \left\{ 48 \div \left( 14 - \overline{5 \times 2} \right) \right\} \right]
Show answer & explanation

Answer: 80

Answer

The simplified numerical value of the expression is 8080.
Evaluating the expression following strict VBODMAS hierarchy: bar expression 5×2=10\overline{5 \times 2} = 10, round brackets 1410=414 - 10 = 4, curly brackets 48÷4=1248 \div 4 = 12, square brackets 3.5×8+12=403.5 \times 8 + 12 = 40, and percentage 'of' term 75% of 160=12075\% \text{ of } 160 = 120. Finally, 12040=80120 - 40 = 80.

Step-by-Step Solution

1
Evaluate the expression under the vinculum (bar)
5×2=10\overline{5 \times 2} = 10
According to VBODMAS, operations grouped under a bar take highest priority.
2
Evaluate inside the innermost round brackets (1410)(14 - 10)
1410=414 - 10 = 4
Perform subtraction inside the parentheses.
3
Evaluate inside the curly brackets {48÷4}\{48 \div 4\}
48÷4=1248 \div 4 = 12
Divide the number outside the round bracket by the result of the round bracket.
4
Evaluate inside the square brackets [3.5×8+12][3.5 \times 8 + 12]
28+12=4028 + 12 = 40
Perform multiplication (3.5×8=283.5 \times 8 = 28) before adding 1212.
5
Calculate the percentage term 75% of 16075\% \text{ of } 160
75100×160=120\frac{75}{100} \times 160 = 120
Evaluate the 'of' operation before final subtraction.
6
Perform final subtraction 12040120 - 40
80
Subtract the total result of the bracketed expression from the percentage term.

Key Concept

Order of Operations (VBODMAS Rule)
Question 153Question
Evaluate the following numerical expression strictly according to the VBODMAS rule:
2.5×12[8+{15÷(4.52.1+0.9)}]2.5 \times 12 - \left[ 8 + \left\{ 15 \div \left( 4.5 - \overline{2.1 + 0.9} \right) \right\} \right]
What is the final calculated value?
Show answer & explanation

Answer: 12

Answer

12
Evaluating the expression following strict VBODMAS priority yields: Vinculum (2.1 + 0.9 = 3) -> Round brackets (4.5 - 3 = 1.5) -> Curly brackets (15 / 1.5 = 10) -> Square brackets (8 + 10 = 18) -> Multiplication (2.5 * 12 = 30) -> Subtraction (30 - 18 = 12).

Step-by-Step Solution

1
Evaluate the expression under the vinculum bar
2.1 + 0.9 = 3
According to the VBODMAS rule, operations under a vinculum take highest priority.
2
Evaluate the innermost round brackets
4.5 - 3 = 1.5
Perform subtraction inside the round brackets after resolving the vinculum.
3
Perform division within the curly brackets
15 / 1.5 = 10
Division inside curly brackets must be calculated before simplifying the outer bracket.
4
Perform addition within the square brackets
8 + 10 = 18
Complete the evaluation of the square bracket section.
5
Perform multiplication outside the brackets
2.5 * 12 = 30
Multiplication takes precedence over final subtraction.
6
Perform final subtraction
30 - 18 = 12
Complete the expression by subtracting the bracket result from the product.

Key Concept

VBODMAS Rule (Vinculum, Brackets, Orders, Division, Multiplication, Addition, Subtraction)
Question 154Question

Find the total number of positive factors of the integer 7575.

Show answer & explanation

Answer: 6

Answer

The total number of positive factors of 75 is 6.
The prime factorization of 75 is 31×523^1 \times 5^2. The number of positive factors is obtained by adding 1 to each exponent in the prime factorization and multiplying the results: (1+1)×(2+1)=2×3=6(1 + 1) \times (2 + 1) = 2 \times 3 = 6. The complete list of positive factors is 1, 3, 5, 15, 25, and 75.

Step-by-Step Solution

1
Express 75 in terms of its prime factors.
75=31×5275 = 3^1 \times 5^2
Prime factorization breaks down the number into prime components essential for counting factors.
2
Apply the standard formula for total positive factors of a number N=pa×qbN = p^a \times q^b.
Total factors =(1+1)×(2+1)=2×3=6= (1 + 1) \times (2 + 1) = 2 \times 3 = 6
Each factor is formed by choosing a power of 3 (2 choices: 30,313^0, 3^1) and a power of 5 (3 choices: 50,51,525^0, 5^1, 5^2).

Key Concept

Total Number of Positive Factors from Prime Factorization
Question 155Question

What is the total number of positive integer factors of 120120?

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Answer: 16

Answer

The total number of positive integer factors of 120120 is 1616.
By prime factorizing 120120, we get 23×31×512^3 \times 3^1 \times 5^1. Applying the factor count formula (a+1)(b+1)(c+1)(a+1)(b+1)(c+1), we obtain (3+1)(1+1)(1+1)=4×2×2=16(3+1)(1+1)(1+1) = 4 \times 2 \times 2 = 16.

Step-by-Step Solution

1
Find the prime factorization of 120120
120=23×31×51120 = 2^3 \times 3^1 \times 5^1
To calculate the total number of factors systematically, express the number as a product of prime factors.
2
Apply the total factor count formula
Number of factors = (3+1)(1+1)(1+1)(3 + 1)(1 + 1)(1 + 1)
If a number N=pa×qb×rcN = p^a \times q^b \times r^c, the total number of positive factors is (a+1)(b+1)(c+1)(a+1)(b+1)(c+1).
3
Compute the product
4×2×2=164 \times 2 \times 2 = 16
Multiplying the incremented prime exponents gives the total count of factors.

Key Concept

Number of Positive Factors from Prime Factorization
Question 156Question

If 2x+342x18x+1=64\frac{2^{x+3} \cdot 4^{2x-1}}{8^{x+1}} = 64, what is the value of (x+2)2(x + 2)^2?

Show answer & explanation

Answer: 36

Answer

The value of (x+2)2(x + 2)^2 is 36.
Converting all terms to base 2 simplifies the equation to 22x2=262^{2x-2} = 2^6. Equating the powers gives 2x2=62x - 2 = 6, so x=4x = 4. Substituting x=4x = 4 into (x+2)2(x + 2)^2 yields (4+2)2=36(4 + 2)^2 = 36.

Step-by-Step Solution

1
Convert all exponential terms to base 2
Numerator term 42x1=24x24^{2x-1} = 2^{4x-2}, denominator term 8x+1=23x+38^{x+1} = 2^{3x+3}, and right-hand side 64=2664 = 2^6.
To combine powers using index laws, all expressions must share a common base.
2
Simplify the left-hand side expression using exponent laws
2x+324x223x+3=25x+123x+3=2(5x+1)(3x+3)=22x2\frac{2^{x+3} \cdot 2^{4x-2}}{2^{3x+3}} = \frac{2^{5x+1}}{2^{3x+3}} = 2^{(5x+1)-(3x+3)} = 2^{2x-2}.
Apply product law aman=am+na^m \cdot a^n = a^{m+n} and quotient law aman=amn\frac{a^m}{a^n} = a^{m-n}.
3
Solve for the variable x
22x2=26    2x2=6    x=42^{2x-2} = 2^6 \implies 2x - 2 = 6 \implies x = 4.
When bases are equal, exponents must be equal.
4
Evaluate the requested target expression
(4+2)2=62=36(4 + 2)^2 = 6^2 = 36.
Substitute the calculated value of x=4x = 4 into (x+2)2(x + 2)^2.

Key Concept

Laws of Indices and Exponential Equations
Estimated Time:1m 30s
Question 157Question

Consider the number obtained by multiplying 4848 and 5353. If this product is divided by 5050, what is the resulting positive remainder?

Show answer & explanation

Answer: 44

Answer

44
Applying the properties of modular arithmetic, 4848 is congruent to 2(mod50)-2 \pmod{50} and 5353 is congruent to 3(mod50)3 \pmod{50}. Multiplying these gives a remainder of 6(mod50)-6 \pmod{50}. To find the standard positive remainder, we add the divisor 5050 to 6-6, resulting in 4444. Alternatively, direct calculation gives 48×53=254448 \times 53 = 2544, and 25442544 divided by 5050 yields a quotient of 5050 with a remainder of 4444.

Step-by-Step Solution

1
Find the remainder of 48 divided by 50.
-2
Using a negative remainder simplifies the multiplication step.
2
Find the remainder of 53 divided by 50.
3
Individual remainders are needed to apply the product rule of modular arithmetic.
3
Multiply the individual remainders.
2×3=6-2 \times 3 = -6
The remainder of a product is congruent to the product of the individual remainders.
4
Convert the negative remainder to a positive remainder.
50 - 6 = 44
A standard remainder must be a non-negative integer strictly less than the divisor.

Key Concept

Remainder Theorem and Negative Modulus
Question 158Question

A cryptography algorithm generates a continuous stream of security tokens based on a polynomial progression. The first five tokens generated by the system are 55, 1212, 3131, 6868, and 129129.

What is the numerical value of the sixth token generated by this algorithm?

Show answer & explanation

Answer: 220

Answer

220
The sequence follows the mathematical rule where the nn-th term is equal to n3+4n^3 + 4. The first term is 13+4=51^3 + 4 = 5, the second is 23+4=122^3 + 4 = 12, up to the fifth which is 53+4=1295^3 + 4 = 129. Applying this rule to the sixth position yields 63+4=216+4=2206^3 + 4 = 216 + 4 = 220. Alternatively, solving via successive differences confirms that the constant third difference is 6, which accurately points to 220.

Step-by-Step Solution

1
Calculate the first-level differences between the given consecutive tokens.
The sequence of differences is 7, 19, 37, and 61.
Establishing the initial rate of change helps identify if a linear or higher-order polynomial pattern exists.
2
Calculate the second-level differences from the results of Step 1.
The differences between the differences are 12, 18, and 24.
Finding the differences of the differences reveals simpler underlying arithmetic progressions.
3
Identify the pattern in the second-level differences and extrapolate the next value.
The values (12, 18, 24) increase by exactly 6 each time. The next second-level difference is 24 + 6 = 30.
Extending this constant third-level difference (+6) is required to build the sequence forward.
4
Calculate the next first-level difference and the final sequence term.
Next first-level difference = 61 + 30 = 91. Next sequence term = 129 + 91 = 220.
Applying the extrapolated values back up the chain yields the target term in the main sequence.

Key Concept

Number series completion using the method of successive differences or cube offsets.
Estimated Time:1m 15s
Question 159Question

If the equation x+x9=9\sqrt{x} + \sqrt{x - 9} = 9 holds true, what is the exact value of xx?

Show answer & explanation

Answer: 25

Answer

25
The exact value of xx is 25. By moving one radical to the right side and squaring both sides, we eliminate one square root. Simplifying and isolating the remaining square root allows us to square both sides a second time, revealing the final value. Alternatively, using the conjugate property of surds: multiplying both sides of the identity (x)2(x9)2=9(\sqrt{x})^2 - (\sqrt{x-9})^2 = 9 by their difference gives (xx9)(x+x9)=9(\sqrt{x} - \sqrt{x-9})(\sqrt{x} + \sqrt{x-9}) = 9. Since the sum is 9, the difference must be 1 (i.e., xx9=1\sqrt{x} - \sqrt{x-9} = 1). Adding this back to the original equation yields 2x=102\sqrt{x} = 10, so x=5\sqrt{x} = 5 and x=25x = 25.

Step-by-Step Solution

1
Isolate one of the square root terms on one side of the equation.
x=9x9\sqrt{x} = 9 - \sqrt{x - 9}
Isolating a radical makes it easier to eliminate it by squaring both sides.
2
Square both sides of the equation and expand the right side.
x=8118x9+(x9)x = 81 - 18\sqrt{x - 9} + (x - 9)
Squaring eliminates the isolated radical. The right side is expanded using the algebraic identity (ab)2=a22ab+b2(a - b)^2 = a^2 - 2ab + b^2.
3
Simplify the equation by canceling xx from both sides and combining constant terms.
x=x+7218x918x9=72x = x + 72 - 18\sqrt{x - 9} \Rightarrow 18\sqrt{x - 9} = 72
Combining like terms simplifies the equation, leaving only a single radical expression.
4
Divide by 18 and square both sides one final time to solve for xx.
x9=4x9=16x=25\sqrt{x - 9} = 4 \Rightarrow x - 9 = 16 \Rightarrow x = 25
Isolating the final radical and squaring removes the remaining root, yielding a simple linear equation for xx.

Key Concept

Solving radical equations and applying algebraic identities with surds.
Question 160Question

A language institute conducted a survey among 400400 civil service aspirants to assess their proficiency in three foreign languages: French, German, and Spanish. The survey revealed the following data:
- 180180 aspirants are proficient in French.
- 150150 aspirants are proficient in German.
- 160160 aspirants are proficient in Spanish.
- 4040 aspirants are proficient in exactly French and German, but not Spanish.
- 3030 aspirants are proficient in exactly German and Spanish, but not French.
- 5050 aspirants are proficient in exactly French and Spanish, but not German.
- 7070 aspirants are not proficient in any of these three languages.

What is the number of aspirants who are proficient in all three languages?

Show answer & explanation

Answer: 20

Answer

20
By determining the union of the three sets (40070=330400 - 70 = 330) and applying the inclusion-exclusion principle while correctly distinguishing between 'exactly two' and the full intersection of two sets, we find that 2020 aspirants are proficient in all three languages.

Step-by-Step Solution

1
Determine the number of aspirants proficient in at least one of the three languages.
n(FGS)=40070=330n(F \cup G \cup S) = 400 - 70 = 330
The total population consists of those who speak at least one language and those who speak none.
2
Set up an equation using the Principle of Inclusion-Exclusion for three sets. Let xx be the number of aspirants proficient in all three languages.
n(FG)=40+xn(F \cap G) = 40 + x, n(GS)=30+xn(G \cap S) = 30 + x, and n(FS)=50+xn(F \cap S) = 50 + x
The total intersection of any two sets includes those in exactly those two sets plus those in all three sets.
3
Substitute all values into the union formula.
330=180+150+160(40+x)(30+x)(50+x)+x330 = 180 + 150 + 160 - (40 + x) - (30 + x) - (50 + x) + x
The formula n(FGS)=n(F)+n(G)+n(S)n(FG)n(GS)n(FS)+n(FGS)n(F \cup G \cup S) = n(F) + n(G) + n(S) - n(F \cap G) - n(G \cap S) - n(F \cap S) + n(F \cap G \cap S) accounts for all overlapping regions.
4
Simplify the equation and solve for xx.
330=4901202x    330=3702x    2x=40    x=20330 = 490 - 120 - 2x \implies 330 = 370 - 2x \implies 2x = 40 \implies x = 20
Basic algebraic simplification yields the final value for the intersection of all three sets.

Key Concept

Principle of Inclusion-Exclusion for Three Sets

Alternative Method

Instead of using the union formula, use a region-based approach in a Venn diagram. Let the central 'all three' region be xx. Calculate the 'only one' regions in terms of xx: Only French = 180(40+50+x)=90x180 - (40 + 50 + x) = 90 - x. Only German = 150(40+30+x)=80x150 - (40 + 30 + x) = 80 - x. Only Spanish = 160(50+30+x)=80x160 - (50 + 30 + x) = 80 - x. The sum of all disjoint regions inside the union is (90x)+(80x)+(80x)+40+30+50+x=3702x(90 - x) + (80 - x) + (80 - x) + 40 + 30 + 50 + x = 370 - 2x. Since the union is 40070=330400 - 70 = 330, we have 3702x=330370 - 2x = 330, which gives x=20x = 20.
Estimated Time:2m 0s
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