Tüm alıştırma soruları

5215 soru

Soru 3221Soru →

A team of paleontologists discovers identical fossil specimens in thin sedimentary rock strata across three widely separated continents. Geological records show that this specific organism existed for only a brief interval of geologic time. Which of the following best describes the primary scientific value of this index fossil?

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Cevap: Correlating and establishing the relative ages of distant rock layers across different geographic regions

Cevap

Correlating and establishing the relative ages of distant rock layers across different geographic regions
An index fossil must be easily recognizable, abundant, geographically widespread, and restricted to a short geologic time range. When geologists find the same index fossil in different locations, they can conclude that the corresponding rock layers formed during the same geologic period, enabling precise stratigraphic correlation.

Adım Adım Çözüm

1
Identify the key defining characteristics of the fossil described in the scenario
The organism was geographically widespread (found on three continents) and existed for a short span of geologic time (confined to a thin stratum).
These are the diagnostic criteria that define an index fossil.
2
Determine how geologists utilize index fossils in stratigraphy
Because the organism only lived during one specific timeframe everywhere it existed, any rock layer containing it must have formed during that same time period.
This allows geologists to establish relative time equivalence across distant sedimentary formations.

Anahtar Kavram

Index fossils in stratigraphic correlation and relative dating
Tahmini Süre:1m 0s
Soru 3222Soru →

An electronics store purchases a computer monitor at wholesale cost. To determine the regular retail price, the store applies a 50%50\% markup to the wholesale cost. During a holiday sale, the monitor is discounted by 30%30\% off the regular retail price. A customer purchases the monitor during the sale and pays a final total of $453.60\$453.60, which includes an 8%8\% sales tax applied to the discounted price. What was the store's original wholesale cost for the monitor?

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Cevap: $400.00\$400.00

Cevap

The original wholesale cost was $400.00\$400.00.
The correct wholesale cost is found by working backward from the final paid amount. First, dividing $453.60\$453.60 by 1.081.08 removes the 8%8\% tax, revealing the discounted sale price of $420.00\$420.00. Since this sale price reflects a 30%30\% discount, it is 70%70\% of the retail price; dividing $420.00\$420.00 by 0.700.70 gives the retail price of $600.00\$600.00. Finally, the retail price includes a 50%50\% markup, making it 150%150\% of the wholesale cost. Dividing $600.00\$600.00 by 1.501.50 yields the correct original wholesale cost of $400.00\$400.00.

Adım Adım Çözüm

1
Remove the 8%8\% sales tax from the final total to find the discounted sale price.
$453.60÷1.08=$420.00\$453.60 \div 1.08 = \$420.00
The final total includes an 8%8\% tax applied to the sale price, which is mathematically equivalent to multiplying the sale price by 1.081.08.
2
Reverse the 30%30\% discount to determine the regular retail price.
$420.00÷0.70=$600.00\$420.00 \div 0.70 = \$600.00
The sale price represents 70%70\% (100%−30%100\% - 30\%) of the regular retail price.
3
Reverse the 50%50\% markup to find the original wholesale cost.
$600.00÷1.50=$400.00\$600.00 \div 1.50 = \$400.00
The retail price represents a 50%50\% increase over the wholesale cost, equivalent to 150%150\% of the original cost (or multiplying by 1.501.50).

Anahtar Kavram

Successive percentage changes and reversing percentages by division.
Soru 3223Soru →

A naval technician inspects a solid aluminum component intended for an aircraft assembly. The component has a mass of 162 g162\text{ g} and the density of aluminum is 2.7 g/cm32.7\text{ g/cm}^3. What is the volume of the component in cubic centimeters (cm3\text{cm}^3)?

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Cevap: 60

Cevap

The volume of the aluminum component is 60 cm360\text{ cm}^3.
Density is defined by the formula ρ=mV\rho = \frac{m}{V}. Rearranging algebraically to solve for volume yields V=mρV = \frac{m}{\rho}. Substituting the given values: V=162 g2.7 g/cm3=60 cm3V = \frac{162\text{ g}}{2.7\text{ g/cm}^3} = 60\text{ cm}^3.

Adım Adım Çözüm

1
Identify the relevant physical formula and isolate the unknown variable
Volume=MassDensity\text{Volume} = \frac{\text{Mass}}{\text{Density}}
Density (ρ\rho) is a characteristic physical property defined as mass per unit volume (ρ=mV\rho = \frac{m}{V}).
2
Substitute the measured mass and known density to calculate volume
Volume=162 g2.7 g/cm3=60 cm3\text{Volume} = \frac{162\text{ g}}{2.7\text{ g/cm}^3} = 60\text{ cm}^3
Dividing 162162 by 2.72.7 gives 6060, with units simplifying to cm3\text{cm}^3.

Anahtar Kavram

Density as a fundamental physical property relating mass and volume
Tahmini Süre:1m 0s
Soru 3224Soru →

A motorized winch pulls a 250 kg250\text{ kg} equipment sled across a level, frictionless sheet of ice. If the winch exerts a constant horizontal force of 750 N750\text{ N} starting from rest, what is the speed of the sled, in meters per second (m/s\text{m/s}), after 4 seconds4\text{ seconds}?

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Cevap: 12

Cevap

The sled reaches a speed of 12 m/s12\text{ m/s} after 4 seconds4\text{ seconds}.
Applying Newton's second law gives an acceleration of a=Fm=750 N250 kg=3 m/s2a = \frac{F}{m} = \frac{750\text{ N}}{250\text{ kg}} = 3\text{ m/s}^2. Since the sled begins at rest (v0=0v_0 = 0), its speed after 4 s4\text{ s} is v=at=3 m/s2×4 s=12 m/sv = at = 3\text{ m/s}^2 \times 4\text{ s} = 12\text{ m/s}.

Adım Adım Çözüm

1
Determine the acceleration produced by the net horizontal force
a=Fnetm=750 N250 kg=3 m/s2a = \frac{F_{\text{net}}}{m} = \frac{750\text{ N}}{250\text{ kg}} = 3\text{ m/s}^2
According to Newton's second law of motion (F=maF = ma), acceleration equals the net force divided by mass.
2
Calculate final speed from initial rest and constant acceleration over time
v=v0+at=0 m/s+(3 m/s2)(4 s)=12 m/sv = v_0 + at = 0\text{ m/s} + (3\text{ m/s}^2)(4\text{ s}) = 12\text{ m/s}
Uniform acceleration kinematic equation relates velocity change to acceleration multiplied by elapsed time.

Anahtar Kavram

Combining Newton's second law (F=maF = ma) with linear kinematics (v=v0+atv = v_0 + at) to determine final velocity under constant net force.

Alternatif Yöntem

Use the impulse-momentum theorem: Impulse=F⋅Δt=Δp=m⋅v\text{Impulse} = F \cdot \Delta t = \Delta p = m \cdot v. Substituting known values gives (750 N)(4 s)=(250 kg)(v)  ⟹  3,000 N⋅s=250 kg⋅v  ⟹  v=3,000250=12 m/s(750\text{ N})(4\text{ s}) = (250\text{ kg})(v) \implies 3,000\text{ N}\cdot\text{s} = 250\text{ kg} \cdot v \implies v = \frac{3,000}{250} = 12\text{ m/s}.
Tahmini Süre:1m 0s
Soru 3225Soru →

Fill in the blank with the correct numeric value to complete the statement.

Aşağıdaki boşlukları doldurun

A printing press can print 5050 identical banners in 22 minutes. At this constant rate, the press will print banners in 1010 minutes.
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Cevap

250
Because the printing press operates at a constant rate, the number of banners produced is directly proportional to the time spent printing. Since 1010 minutes is exactly 55 times longer than the initial 22 minutes, the press will produce 55 times as many banners. Multiplying the original 5050 banners by 55 results in 250250 banners.

Adım Adım Çözüm

1
Identify the given ratio of banners to time.
The press produces 5050 banners per 22 minutes.
Establishing the baseline rate is the first step in setting up a direct proportion.
2
Determine the scaling factor for the time.
The time increases from 22 minutes to 1010 minutes. The scaling factor is 102=5\frac{10}{2} = 5.
Finding how many times greater the new time is compared to the original time tells us how to scale the output.
3
Multiply the baseline production by the scaling factor.
50×5=25050 \times 5 = 250 banners.
In a direct proportion, as time increases by a certain multiple, the quantity produced increases by that exact same multiple.

Anahtar Kavram

Direct Proportions
Soru 3226Soru →

A storage warehouse is currently filled to 14\frac{1}{4} of its total capacity. A new shipment arrives and is stored, bringing the warehouse to 56\frac{5}{6} of its total capacity. What fraction of the warehouse's capacity was filled by the new shipment?

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Cevap: 712\frac{7}{12}

Cevap

The new shipment filled 712\frac{7}{12} of the warehouse's capacity.
To find the amount of capacity added, subtract the initial capacity from the final capacity (56−14\frac{5}{6} - \frac{1}{4}). Convert both fractions to a common denominator of 12, resulting in 1012\frac{10}{12} and 312\frac{3}{12}. Subtracting these fractions gives 712\frac{7}{12}.

Adım Adım Çözüm

1
Set up the subtraction expression to find the difference in capacity.
56−14\frac{5}{6} - \frac{1}{4}
The fraction added is equal to the final capacity minus the initial capacity.
2
Find the lowest common denominator (LCD) for the fractions with denominators 6 and 4.
The LCD is 12.
Fractions must have a common denominator before they can be added or subtracted.
3
Convert both fractions to equivalent fractions with a denominator of 12.
56=1012\frac{5}{6} = \frac{10}{12} and 14=312\frac{1}{4} = \frac{3}{12}
This standardizes the parts so they can be accurately subtracted.
4
Subtract the numerators and keep the common denominator.
1012−312=712\frac{10}{12} - \frac{3}{12} = \frac{7}{12}
The numerators represent the specific number of parts being subtracted from the whole.

Anahtar Kavram

Fraction Addition and Subtraction in Context
Soru 3227Soru →

Read the scenario below and calculate the final selling price.

Aşağıdaki boşlukları doldurun

A mechanic buys a used car for $3,500\$3,500 and spends $500\$500 on replacement parts. He marks up his total investment by 25%25\% to set the asking price. A customer then negotiates a 10%10\% discount off this asking price. The final selling price of the car is $\$.
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Cevap

4500
The total investment is the sum of the car and parts ($4,000\$4,000). The 25%25\% markup is calculated on this total base, resulting in a $5,000\$5,000 asking price ($4,000×1.25\$4,000 \times 1.25). Finally, the 10%10\% discount is calculated sequentially on the new $5,000\$5,000 asking price, giving a final selling price of $4,500\$4,500 ($5,000×0.90\$5,000 \times 0.90).

Adım Adım Çözüm

1
Calculate the mechanic's total investment.
$3,500+$500=$4,000\$3,500 + \$500 = \$4,000
The markup is applied to the total cost, which includes both the initial purchase price and the cost of the replacement parts.
2
Calculate the asking price by applying the 25% markup to the total investment.
$4,000×1.25=$5,000\$4,000 \times 1.25 = \$5,000
A 25%25\% markup means the asking price is 125%125\% of the total investment.
3
Calculate the final selling price by applying the 10% discount to the asking price.
$5,000×0.90=$4,500\$5,000 \times 0.90 = \$4,500
The discount is taken off the new marked-up asking price, leaving 90%90\% of that price to be paid.

Anahtar Kavram

Calculating successive percentage changes by updating the base amount for each step.
Soru 3228Soru →

In basic direct-current circuits, various fundamental electrical quantities describe the flow and use of electric energy. Match each electrical quantity on the left with its correct physical definition and standard unit on the right.

Soldaki öğeye tıklayın, sonra eşleşen sağdaki öğeye tıklayın

Öğeler

Voltage
Current
Resistance
Electrical Power

Eşleşmeler

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Cevap

Voltage matches the electrical potential difference driving charge (volts); Current matches the rate of charge flow (amperes); Resistance matches the opposition to current flow (ohms); Electrical Power matches the rate of energy transfer (watts).
Each electrical quantity is correctly matched to its standard SI unit and underlying physical definition based on Ohm's law and electrical power principles.

Adım Adım Çözüm

1
Identify the definitions and units for potential difference and charge flow.
Voltage provides the electrical push measured in volts (V\text{V}), while Current represents the flow rate of charge measured in amperes (A\text{A}).
These are the two driving and kinematic parameters of an active circuit.
2
Identify the definitions and units for circuit opposition and energy rate.
Resistance opposes current flow and is measured in ohms (Ω\Omega), while Electrical Power is the energy conversion rate measured in watts (W\text{W}).
These relate the load characteristics and total work rate in the circuit.

Anahtar Kavram

Fundamental electrical properties, units of measurement, and definitions in direct-current circuits.
Tahmini Süre:45s
Soru 3229Soru →

A bimetallic strip made of two different metals bonded firmly along their lengths bends into an arc when heated evenly. Which of the following best explains why this bending occurs?

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Cevap: The two metals expand at different rates as their temperature increases.

Cevap

The two metals expand at different rates as their temperature increases.
Thermal expansion causes materials to expand upon heating, but different materials expand by different amounts for the same temperature change due to differing coefficients of thermal expansion. Because the two metal strips are bonded together, the metal that expands more forms the outer, longer curve of the arc, causing the entire strip to bend predictably.

Adım Adım Çözüm

1
Identify the thermal property involved when solid objects change size upon heating.
Most solids undergo thermal expansion, increasing in length and volume as temperature rises.
Added thermal energy increases the average vibrational kinetic energy of atoms, pushing them slightly further apart.
2
Analyze how bonding two materials with different expansion rates affects the combined structure.
The metal with the higher coefficient of thermal expansion expands more in length than the metal with the lower coefficient.
Because the two strips are permanently joined, the longer expanded strip must curve around the shorter strip, resulting in a bent arc.

Anahtar Kavram

Thermal expansion and differential expansion in composite materials
Tahmini Süre:1m 0s
Soru 3230Soru →

When an ancient vertebrate organism undergoes permineralization to become a preserved body fossil, its remains pass through a distinct series of physical and chemical stages. What is the correct chronological sequence of these fossil formation events, ordered from the death of the organism to its eventual discovery?

Öğeleri doğru sıraya koymak için sürükleyin

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Cevap

The proper chronological order of fossilization by permineralization is: rapid burial in sediment, soft tissue decay and sediment compaction, groundwater infiltration into pore spaces, mineral crystallization to form petrified rock, and surface exposure via uplift and weathering.
Fossilization through permineralization begins when an organism is rapidly buried by sediments, protecting it from surface destruction. Next, soft tissues decompose, leaving only hard skeletal elements as increasing sediment load compacts the surroundings. Mineral-bearing groundwater then seeps through the open pore spaces of the bones. Over time, dissolved minerals like silica or calcite precipitate out and crystallize, turning the bone structure into stone. Finally, geological forces lift the strata and surface weathering erodes the covering rock, bringing the fossil to the surface.

Adım Adım Çözüm

1
Identify the initial preservation requirement.
Rapid burial beneath sediment prevents scavenging and biological decay.
Without immediate burial, remains are consumed or destroyed by physical weathering before preservation can begin.
2
Determine the intermediate chemical and physical transformation stages.
Soft tissues rot away, sediment layers compact into rock, and mineralized groundwater infiltrates the porous skeletal matrix.
Groundwater must gain access to internal bone cavities to deliver the dissolved minerals required for fossilization.
3
Trace the lithification and eventual surface discovery process.
Mineral precipitation hardens the bone into stone, followed by tectonic uplift and erosion exposing the fossil.
Permineralization must be completed deep underground before uplift and surface erosion can reveal the specimen.

Anahtar Kavram

Process of Fossil Formation by Permineralization
Tahmini Süre:1m 0s
Soru 3231Soru →

A contractor is assigned a specialized repair project with a labor budget of 121212 \frac{1}{2} hours. The contractor works 3343 \frac{3}{4} hours on Monday, 2582 \frac{5}{8} hours on Tuesday, and 44 hours and 1010 minutes on Wednesday. If no other time is spent on the project, how many hours of the budgeted time remain?

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Cevap: 123241 \frac{23}{24}

Cevap

The remaining time on the project budget is 123241 \frac{23}{24} hours.
To find the remaining time, first convert all time spent into fractions of an hour with a common denominator, sum them up, and subtract the total from the budgeted hours. Converting 10 minutes to a fraction of an hour yields 10/60=1/610/60 = 1/6 hour. The sum of the fractions is 334+258+4163 \frac{3}{4} + 2 \frac{5}{8} + 4 \frac{1}{6}. The lowest common denominator for 4, 8, and 6 is 24. Converting the fractions gives 31824+21524+4424=937243 \frac{18}{24} + 2 \frac{15}{24} + 4 \frac{4}{24} = 9 \frac{37}{24}, which simplifies to 10132410 \frac{13}{24} hours. Subtracting this from the budget requires regrouping: 121224−101324=113624−101324=1232412 \frac{12}{24} - 10 \frac{13}{24} = 11 \frac{36}{24} - 10 \frac{13}{24} = 1 \frac{23}{24} hours.

Adım Adım Çözüm

1
Convert the time worked on Wednesday into a mixed number with a fraction of an hour.
44 hours and 1010 minutes = 410604 \frac{10}{60} hours = 4164 \frac{1}{6} hours.
All quantities must be in the same unit (hours) and fraction format before adding.
2
Find a common denominator to add the hours worked on Monday, Tuesday, and Wednesday.
The lowest common denominator for 44, 88, and 66 is 2424. The fractions become 318243 \frac{18}{24}, 215242 \frac{15}{24}, and 44244 \frac{4}{24}.
Fractions can only be added when they share a common denominator.
3
Add the converted fractions to find the total time spent.
31824+21524+4424=937243 \frac{18}{24} + 2 \frac{15}{24} + 4 \frac{4}{24} = 9 \frac{37}{24}. Since 3724=11324\frac{37}{24} = 1 \frac{13}{24}, the total is 10132410 \frac{13}{24} hours.
Adding the individual shifts gives the combined total hours worked so far.
4
Subtract the total time spent from the budgeted time to find the remaining hours.
1212−101324=121224−10132412 \frac{1}{2} - 10 \frac{13}{24} = 12 \frac{12}{24} - 10 \frac{13}{24}. Regrouping 12122412 \frac{12}{24} gives 11362411 \frac{36}{24}. Subtracting yields 113624−101324=1232411 \frac{36}{24} - 10 \frac{13}{24} = 1 \frac{23}{24} hours.
Subtracting the part used from the whole budget determines the remaining balance.

Anahtar Kavram

Adding and subtracting mixed numbers with unlike denominators in real-world contexts, including unit conversions and regrouping.
Tahmini Süre:2m 30s
Soru 3232Soru →

A string of decorative holiday lights is designed such that removing a single bulb causes all the other bulbs on the strand to go out immediately. Which type of electrical circuit does this light strand represent?

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Cevap: A series circuit, because all components share a single continuous path for electric current

Cevap

A series circuit, because all components share a single continuous path for electric current
In a series circuit, all electrical loads are connected end-to-end along a single continuous path. Because electric current must travel through each component sequentially, removing or burning out any one bulb breaks the loop, creating an open circuit that immediately turns off all remaining bulbs.

Adım Adım Çözüm

1
Identify the pathway configuration of the electrical components in the circuit
The circuit contains only one continuous conducting path connecting every bulb in sequence.
Understanding the number of paths for current flow determines whether a circuit is wired in series or in parallel.
2
Analyze the effect of removing a component on the circuit loop
Removing one bulb creates a gap (open circuit), halting the flow of charge through the entire path.
Electric current requires an uninterrupted closed loop from the power source back to the source to flow.

Anahtar Kavram

Series vs. Parallel Circuits and Current Pathways
Tahmini Süre:45s
Soru 3233Soru →

Solve the following problem by determining the missing value. Enter your final numerical answer in the blank provided.

Aşağıdaki boşlukları doldurun

A base exchange purchases a batch of tactical backpacks from a distributor. The exchange applies a markup of 60%60\% over the distributor cost to determine the standard price. After a month, the backpacks are placed on clearance, reducing the standard price by 30%30\%. A service member buys a backpack using a special coupon that takes an additional 15%15\% off the clearance price. If the service member pays $66.64\$66.64 for the backpack (which is tax-exempt), the original distributor cost of the backpack was $\$$.
Cevabı ve açıklamayı göster

Cevap

70
The original cost is found by translating the successive markup and discounts into multipliers: 1.601.60 for the 60%60\% markup, 0.700.70 for the 30%30\% discount, and 0.850.85 for the 15%15\% discount. The product of these multipliers is 1.60×0.70×0.85=0.9521.60 \times 0.70 \times 0.85 = 0.952. This means the final price is 95.2%95.2\% of the original cost. Setting 0.952C=$66.640.952C = \$66.64 and dividing gives the original distributor cost of $70\$70.

Adım Adım Çözüm

1
Define a variable for the unknown original cost.
Let CC represent the original distributor cost of the backpack.
Setting up a variable allows us to build an algebraic equation to track the successive price changes.
2
Calculate the multiplier for the 60%60\% markup.
Standard Price = C×(1+0.60)=1.60CC \times (1 + 0.60) = 1.60C
A markup increases the cost by that percentage, making the new price 160%160\% of the original cost.
3
Apply the 30%30\% clearance discount to the standard price.
Clearance Price = 1.60C×(1−0.30)=1.60C×0.70=1.12C1.60C \times (1 - 0.30) = 1.60C \times 0.70 = 1.12C
The clearance reduction applies to the newly established standard price, leaving 70%70\% of that price.
4
Apply the additional 15%15\% coupon discount to the clearance price.
Final Price = 1.12C×(1−0.15)=1.12C×0.85=0.952C1.12C \times (1 - 0.15) = 1.12C \times 0.85 = 0.952C
The coupon applies sequentially to the clearance price, meaning the customer pays 85%85\% of that discounted amount.
5
Set the final price expression equal to the known amount paid and solve for CC.
0.952C=66.64⇒C=66.640.952=700.952C = 66.64 \Rightarrow C = \frac{66.64}{0.952} = 70
Equating the algebraic expression to the actual dollar amount allows us to isolate and calculate the original distributor cost.

Anahtar Kavram

Solving multi-step percentage changes by applying successive multipliers to find an unknown base value.
Soru 3234Soru →

A supply pump transfers 1010 gallons of aviation fuel every 1515 seconds. At this rate, how many gallons of fuel will it transfer in 33 minutes?

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Cevap: 120

Cevap

120
The problem establishes a constant rate, which requires a direct proportion to solve. First, convert the 33-minute time period into 180180 seconds to match the units of the given rate. Then, set up the proportion 1015=x180\frac{10}{15} = \frac{x}{180}. Cross-multiplying 1010 by 180180 yields 18001800, and dividing that product by 1515 results in 120120 gallons.

Adım Adım Çözüm

1
Harmonize the time units by converting minutes to seconds.
33 minutes =3×60=180= 3 \times 60 = 180 seconds.
The initial rate is given in seconds, so the target time must also be in seconds to set up an accurate mathematical proportion.
2
Set up a direct proportion using the given rate.
1010 gallons / 1515 seconds =x= x gallons / 180180 seconds.
The pump operates at a constant rate, meaning the ratio of volume to time remains equivalent.
3
Solve for the unknown volume xx.
x=10×18015=180015=120x = \frac{10 \times 180}{15} = \frac{1800}{15} = 120 gallons.
Cross-multiplying and dividing isolates the variable, providing the total gallons transferred.

Anahtar Kavram

Direct proportions represent situations where two quantities increase at the same relative rate. When setting up proportions, it is critical to ensure that corresponding units match.
Soru 3235Soru →

A sporting goods store owner buys a pair of running shoes from a manufacturer for $80.00\$80.00. He applies a 30%30\% markup to the wholesale cost to determine the final retail price. What is the retail selling price of the running shoes?

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Cevap: $104.00\$104.00

Cevap

$104.00\$104.00
The correct answer accurately calculates the 30%30\% markup as $24.00\$24.00 ($80.00×0.30\$80.00 \times 0.30) and correctly adds this markup to the original wholesale cost ($80.00+$24.00\$80.00 + \$24.00) to reach the final retail price of $104.00\$104.00.

Adım Adım Çözüm

1
Calculate the markup amount by finding 30%30\% of the wholesale cost.
$80.00×0.30=$24.00\$80.00 \times 0.30 = \$24.00
The markup is a percentage of the original wholesale cost, which must be converted to a dollar amount.
2
Add the markup amount to the original wholesale cost to find the retail selling price.
$80.00+$24.00=$104.00\$80.00 + \$24.00 = \$104.00
The retail selling price is the sum of the wholesale cost and the markup.

Anahtar Kavram

Calculating a percentage of a quantity and adding it to the original value to determine a final marked-up price.

Alternatif Yöntem

Instead of calculating the markup and adding it to the wholesale cost, you can multiply the wholesale cost directly by 1.301.30 (which represents the 100%100\% original cost plus the 30%30\% markup). Thus, $80.00×1.30=$104.00\$80.00 \times 1.30 = \$104.00.
Tahmini Süre:1m 0s
Soru 3236Soru →

During a routine vehicle maintenance check, a technician records four distinct observations about an engine and its fluid systems. Which of the following observations describes a physical change rather than a chemical change?

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Cevap: Engine oil decreasing in viscosity and flowing more freely as operating temperature rises

Cevap

Engine oil decreasing in viscosity and flowing more freely as operating temperature rises
The observation describing engine oil thinning as temperature increases represents a physical change. Viscosity is a physical property governed by intermolecular forces; heating increases molecular motion and reduces resistance to flow without altering the chemical composition of the oil.

Adım Adım Çözüm

1
Distinguish between physical and chemical changes
A physical change alters the form, state, or appearance of a substance without changing its chemical identity. A chemical change produces one or more new substances through bond breaking and formation.
Correct classification requires evaluating whether the molecular structure of the substance is modified.
2
Evaluate the fluid behavior under temperature change
When engine oil is heated, thermal energy reduces intermolecular attractions, causing the fluid to thin (lower viscosity). The chemical structure of the hydrocarbon base oil remains identical.
Since no new substance is formed and the process is reversible upon cooling, the change in flow properties is purely physical.

Anahtar Kavram

Physical versus chemical changes in matter
Tahmini Süre:45s
Soru 3237Soru →

An equipment container weighs 120 N120\text{ N} on Earth, where the acceleration due to gravity is approximately 10 m/s210\text{ m/s}^2. The container is transported to an orbital space station where it is in a weightless environment. If an astronaut applies a constant net horizontal force of 36 N36\text{ N} to the container, what is its resulting acceleration?

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Cevap: 3 m/s23\text{ m/s}^2

Cevap

3 m/s23\text{ m/s}^2
Mass measures an object's inertia and does not change when moving between Earth and orbit. Using the Earth weight W=120 NW = 120\text{ N} and gravity g=10 m/s2g = 10\text{ m/s}^2, the container's mass is m=12 kgm = 12\text{ kg}. In orbit, applying a net force of 36 N36\text{ N} yields an acceleration of a=F/m=36 N/12 kg=3 m/s2a = F/m = 36\text{ N} / 12\text{ kg} = 3\text{ m/s}^2.

Adım Adım Çözüm

1
Determine the mass of the container from its Earth weight
Mass m=Wg=120 N10 m/s2=12 kg\text{Mass } m = \frac{W}{g} = \frac{120\text{ N}}{10\text{ m/s}^2} = 12\text{ kg}
Weight is the force of gravity acting on mass (W=mgW = mg). Mass is an intrinsic property of the object and remains unchanged regardless of location.
2
Apply Newton's Second Law of Motion (F=maF = ma) in the orbital environment
a=Fnetm=36 N12 kg=3 m/s2a = \frac{F_{\text{net}}}{m} = \frac{36\text{ N}}{12\text{ kg}} = 3\text{ m/s}^2
Although the container is weightless in orbit, its inertia (mass) remains 12 kg12\text{ kg}. A net force produces an acceleration inversely proportional to that mass.

Anahtar Kavram

Newton's Second Law (F=maF = ma) and the distinction between mass (inertia) and weight (gravitational force).
Tahmini Süre:1m 0s
Soru 3238Soru →

Thermal energy transfer and thermodynamic properties govern many practical engineering and natural systems. Match each thermal physics principle with the real-world application that most directly relies on it.

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Öğeler

High specific heat capacity
Latent heat of vaporization
Thermal conduction
Radiation reflection

Eşleşmeler

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Cevap

High specific heat capacity matches engine water cooling; Latent heat of vaporization matches sweating/evaporative cooling; Thermal conduction matches a copper base plate on an electronic heat sink; Radiation reflection matches a shiny foil emergency blanket.
Each principle is paired with its primary physical mechanism: high specific heat capacity explains water's resistance to rapid temperature spikes in cooling systems; latent heat of vaporization explains how phase transitions remove heat during evaporation; conduction explains direct contact heat flow through solid copper; and radiation reflection explains how metallic foil redirects infrared waves.

Adım Adım Çözüm

1
Analyze the role of coolant fluids in temperature regulation
Water requires a large amount of heat energy to raise its temperature (4.184 J/(g⋅∘C)4.184\text{ J}/(\text{g}\cdot^\circ\text{C})), demonstrating high specific heat capacity.
Identify the property responsible for heat absorption without rapid temperature spikes.
2
Examine the mechanism of evaporative cooling
Sweat absorbing energy to undergo a phase change from liquid to vapor demonstrates latent heat of vaporization.
Phase transitions at constant temperature absorb latent heat from surrounding tissue.
3
Evaluate heat transfer across solid interfaces in contact
Thermal energy moving directly through a dense metallic copper plate into a heat sink operates by conduction.
Conduction is the primary mode of thermal transfer through stationary solids.
4
Determine how reflective barriers preserve body warmth
Shiny aluminized foil redirecting electromagnetic infrared radiation back to a person demonstrates radiation reflection.
Radiant heat transfers via electromagnetic waves without requiring a physical medium and can be reflected by polished surfaces.

Anahtar Kavram

Thermodynamic properties and heat transfer mechanisms in applied physical systems
Tahmini Süre:1m 0s
Soru 3239Soru →

Solve the following word problem and enter your final answer. You may use a mixed number, improper fraction, or decimal format.

Aşağıdaki boşlukları doldurun

A Navy seaman is painting the exterior of a ship. He uses 3123 \frac{1}{2} gallons of gray paint on the port side and 2142 \frac{1}{4} gallons on the starboard side. In total, he used gallons of paint.
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Cevap

5 3/4
To find the total amount of paint used, the two quantities must be added together. By finding a common denominator of 4, the fraction 12\frac{1}{2} is converted to 24\frac{2}{4}. Adding the fractions 24\frac{2}{4} and 14\frac{1}{4} yields 34\frac{3}{4}. Adding the whole numbers 3 and 2 gives 5. The combined total is 5345 \frac{3}{4} gallons.

Adım Adım Çözüm

1
Set up the addition problem to combine the two quantities of paint.
312+2143 \frac{1}{2} + 2 \frac{1}{4}
The total amount of paint used is the sum of the paint used on both sides of the ship.
2
Find a common denominator for the fractional parts (2 and 4).
The least common multiple of 2 and 4 is 4.
Fractions must have the same denominator before they can be added together.
3
Convert the first fraction to an equivalent fraction with a denominator of 4.
312=3243 \frac{1}{2} = 3 \frac{2}{4}
This allows the fractional parts to be added seamlessly.
4
Add the whole numbers and the fractions.
Whole numbers: 3+2=53 + 2 = 5. Fractions: 24+14=34\frac{2}{4} + \frac{1}{4} = \frac{3}{4}. Final total: 5345 \frac{3}{4}.
Combining the separate sums gives the total value of the mixed numbers.

Anahtar Kavram

Adding mixed numbers with unlike denominators
Soru 3240Soru →

An industrial cleaning solvent requires a mixture of Chemical A and Chemical B in a ratio of 5:25:2 by volume. If a worker uses 300300 milliliters of Chemical B, how many liters of the final cleaning solvent will be produced?

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Cevap: 1.05

Cevap

1.05
The correct answer accurately scales the mixture from parts to a total volume. Since the ratio of Chemical A to B is 5:2, there are 7 total parts in the mixture. Chemical B makes up 2 of these 7 parts. Setting up the proportion 2/7 = 300/x gives a total volume of 1050 mL. Converting this volume to liters by dividing by 1000 results in 1.05 liters.

Adım Adım Çözüm

1
Identify the ratio of Chemical B to the total mixture.
The mixture has 5 parts Chemical A and 2 parts Chemical B, making 7 total parts. The ratio of Chemical B to the total is 2:7.
To find the total volume based on the volume of one component, we need the part-to-whole relationship.
2
Set up and solve a proportion to find the total volume in milliliters.
2 / 7 = 300 / x. Cross-multiplying gives 2x = 2100, which simplifies to x = 1050 milliliters.
Direct proportions allow us to scale the ratio up to find the actual combined volume of the mixture.
3
Convert the total volume from milliliters to liters.
1050 / 1000 = 1.05 liters.
The question explicitly requires the final answer to be stated in liters.

Anahtar Kavram

Direct proportions and unit conversions in part-to-whole relationships

Alternatif Yöntem

Instead of setting up a formal proportion, use the unitary method. If 2 parts represent 300 mL, then 1 part equals 150 mL (300 / 2). The total mixture requires 7 parts, so the total volume is 7 * 150 = 1050 mL. Converting to liters gives 1.05 L.
Tahmini Süre:1m 30s
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