Tüm alıştırma soruları

5215 soru

Soru 3241Soru →

Match each physical or chemical concept related to matter with its corresponding scientific description.

Soldaki öğeye tıklayın, sonra eşleşen sağdaki öğeye tıklayın

Öğeler

Density
Deposition
Thermal conductivity
Oxidation

Eşleşmeler

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Cevap

Density matches 'The measure of mass per unit volume of a substance', Deposition matches 'A physical phase transition where a gas converts directly into a solid', Thermal conductivity matches 'The rate at which heat energy is transferred through a material', and Oxidation matches 'A chemical change in which a substance reacts with oxygen to form a new compound'.
Each concept accurately pairs with its foundational physical or chemical definition: Density is mass per unit volume, deposition is the gas-to-solid phase change, thermal conductivity is the heat transfer capability, and oxidation is a chemical change involving reaction with oxygen.

Adım Adım Çözüm

1
Identify the definitions of volumetric and mass relationships
Density is identified as the intensive property representing mass per unit volume (D=mVD = \frac{m}{V}).
This establishes the direct relationship between matter's mass and the volume it occupies.
2
Distinguish between phase changes and chemical changes
Deposition is identified as the direct gas-to-solid phase change, while oxidation is identified as a chemical reaction forming new substances.
Phase changes retain chemical identity, whereas oxidation alters the chemical formula and bonds.
3
Classify transport properties of matter
Thermal conductivity is identified as the property dictating heat flow rate through a substance.
Thermal conductivity describes the physical transport of thermal energy across a temperature gradient.

Anahtar Kavram

Physical Properties, Chemical Properties, and State Changes of Matter
Tahmini Süre:1m 0s
Soru 3242Soru →

A military dining facility begins the week with 301230 \frac{1}{2} gallons of cooking oil. On Monday, the kitchen uses 123412 \frac{3}{4} gallons of the oil. On Tuesday, the kitchen uses another 9239 \frac{2}{3} gallons. How many gallons of cooking oil remain at the facility?

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Cevap: 81128 \frac{1}{12}

Cevap

81128 \frac{1}{12}
The correct answer is found by first calculating the total oil used by finding a common denominator of 12 and regrouping (1234+923=2251212 \frac{3}{4} + 9 \frac{2}{3} = 22 \frac{5}{12} gallons). Then, this combined amount is subtracted from the initial inventory using the same common denominator (3012−22512=30612−22512=811230 \frac{1}{2} - 22 \frac{5}{12} = 30 \frac{6}{12} - 22 \frac{5}{12} = 8 \frac{1}{12} gallons).

Adım Adım Çözüm

1
Find the total amount of oil used by adding the amounts from Monday and Tuesday.
1234+92312 \frac{3}{4} + 9 \frac{2}{3}
To find out how much oil is left, we must first know the total volume that was removed from the initial inventory.
2
Convert the fractions to a common denominator to add them.
The least common multiple of 44 and 33 is 1212. The fractions become 912\frac{9}{12} and 812\frac{8}{12}.
Fractions must have the same denominator before they can be added together.
3
Add the converted mixed numbers and regroup the improper fraction.
12912+9812=21171212 \frac{9}{12} + 9 \frac{8}{12} = 21 \frac{17}{12}. Since 1712\frac{17}{12} is 15121 \frac{5}{12}, the total used is 2251222 \frac{5}{12} gallons.
Simplifying the combined total makes the final subtraction step accurate and easier to perform.
4
Subtract the total amount used from the initial inventory to find the remaining oil.
3012−2251230 \frac{1}{2} - 22 \frac{5}{12}
Subtracting the part used from the whole gives the remaining balance.
5
Find a common denominator for the final subtraction.
The least common multiple of 22 and 1212 is 1212. The initial amount becomes 3061230 \frac{6}{12}.
Again, fractions require a common denominator for subtraction.
6
Perform the subtraction.
30612−22512=811230 \frac{6}{12} - 22 \frac{5}{12} = 8 \frac{1}{12} gallons.
This calculation yields the final volume of oil remaining in the facility.

Anahtar Kavram

Adding and subtracting mixed numbers with unlike denominators by finding the lowest common denominator and regrouping improper fractions.
Soru 3243Soru →

A paleontologist unearths a well-preserved fern fossil within a horizontal layer of shale situated directly between two distinct volcanic ash beds. Radiometric dating reveals that the underlying ash bed is 65 million years old, while the overlying ash bed is 60 million years old. Based on these stratigraphic relationships, which conclusion about the age of the fossil is most accurate?

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Cevap: The fossil organism lived between 60 and 65 million years ago.

Cevap

The fossil organism lived between 60 and 65 million years ago.
According to the Law of Superposition in undisturbed strata, lower layers are older than upper layers. Because the fossil-bearing shale was deposited on top of the 65-million-year-old ash bed and was subsequently covered by the 60-million-year-old ash bed, the fern fossil is reliably bracketed to an age between 60 and 65 million years old.

Adım Adım Çözüm

1
Apply the Law of Superposition to determine the relative sequence of the strata.
The lower volcanic ash is the oldest layer, the middle shale layer containing the fossil is intermediate in age, and the upper volcanic ash is the youngest layer.
In an undisturbed geological column, rock layers are deposited sequentially with older beds on the bottom and younger beds on top.
2
Bracket the age of the fossil-bearing shale using the numerical dates of the bounding volcanic ash beds.
The shale and its enclosed fossil must be younger than 65 million years and older than 60 million years.
The sedimentary layer was deposited after the lower ash layer settled but before the upper ash layer was laid down.

Anahtar Kavram

Radiometric age bracketing and the Law of Superposition
Tahmini Süre:1m 0s
Soru 3244Soru →

On a clear, sunny afternoon at the beach, the dry sand becomes hot enough to burn bare feet, while the adjacent ocean water remains relatively cool despite receiving identical amounts of solar radiation. Which property accounts for this difference in temperature?

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Cevap: Water has a significantly higher specific heat capacity than sand.

Cevap

Water has a significantly higher specific heat capacity than sand.
Specific heat capacity is the amount of heat energy needed to raise the temperature of a given mass of a substance by one degree Celsius. Water has one of the highest specific heat capacities of common natural substances (around 4.184 J/(g⋅∘C)4.184\text{ J}/(\text{g}\cdot^\circ\text{C})), whereas dry sand has a relatively low specific heat capacity (around 0.80 J/(g⋅∘C)0.80\text{ J}/(\text{g}\cdot^\circ\text{C})). As a result, receiving the same amount of solar radiation causes sand to experience a rapid and dramatic temperature increase, while water exhibits only a modest temperature change.

Adım Adım Çözüm

1
Analyze the thermal conditions described in the scenario
Both the sand and the water absorb equal radiant solar energy per unit area over the same duration, but the sand reaches a much higher temperature.
Establishing equal energy input isolates material-specific thermal properties as the cause of the temperature variance.
2
Apply the thermodynamic definition of specific heat capacity (Q=mcΔTQ = mc\Delta T)
Temperature change is inversely proportional to specific heat capacity (ΔT=Qmc\Delta T = \frac{Q}{mc}).
Specific heat capacity (cc) measures the amount of heat energy required to raise the temperature of one unit of mass by one degree Celsius.
3
Compare the specific heat capacities of water and sand
Water has a specific heat capacity of approximately 4.184 J/(g⋅∘C)4.184\text{ J}/(\text{g}\cdot^\circ\text{C}), whereas dry sand has a specific heat capacity of approximately 0.80 J/(g⋅∘C)0.80\text{ J}/(\text{g}\cdot^\circ\text{C}).
Because water requires roughly five times more energy per gram to raise its temperature by one degree, it warms up far more slowly than sand under the same sun exposure.

Anahtar Kavram

Specific Heat Capacity and Thermal Inertia
Tahmini Süre:1m 0s
Soru 3245Soru →

A portable work light operates on a simple direct-current circuit. When switched on, an electric current of 2 A2\text{ A} passes through the bulb, which has a resistance of 3 Ω3\,\Omega. According to Ohm's law (V=I×RV = I \times R), what is the voltage supplied by the battery?

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Cevap: 6 V6\text{ V}

Cevap

The voltage supplied by the battery is 6 V6\text{ V}.
According to Ohm's law, voltage (VV) equals current (II) multiplied by resistance (RR). Multiplying 2 A2\text{ A} by 3 Ω3\,\Omega gives 6 V6\text{ V}.

Adım Adım Çözüm

1
Identify the given electrical quantities from the problem.
Current I=2 AI = 2\text{ A} and resistance R=3 ΩR = 3\,\Omega.
Ohm's law requires current and resistance to determine voltage.
2
Apply Ohm's law formula V=I×RV = I \times R.
V=2 A×3 Ω=6 VV = 2\text{ A} \times 3\,\Omega = 6\text{ V}.
Multiplying electric current by internal resistance calculates the total potential difference (voltage).

Anahtar Kavram

Ohm's law states that the electrical potential difference (voltage) across a conductor is directly proportional to the current flowing through it, given by V=I×RV = I \times R.
Tahmini Süre:40s
Soru 3246Soru →

A maintenance technician needs to identify an unknown metal sample by evaluating its characteristics in a testing laboratory. Which of the following procedures tests a chemical property of the metal rather than a physical property?

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Cevap: Applying a drop of concentrated hydrochloric acid to observe whether hydrogen gas is produced

Cevap

Applying a drop of concentrated hydrochloric acid to observe whether hydrogen gas is produced
Applying hydrochloric acid to observe gas production directly tests chemical reactivity, which is a chemical property because the metal undergoes a reaction to form new chemical substances (a metal salt and hydrogen gas).

Adım Adım Çözüm

1
Define the difference between physical and chemical properties
Physical properties can be observed or measured without changing the chemical composition of the substance (e.g., melting point, density, mass, volume). Chemical properties describe how a substance interacts with other substances to form entirely new materials (e.g., reactivity with acid, flammability, oxidation).
Establishing the fundamental definitions allows proper classification of each lab procedure.
2
Evaluate the procedure testing reaction with acid
When acid is placed on the metal, the formation of hydrogen gas demonstrates a chemical reaction (M+2HCl→MCl2+H2M + 2HCl \rightarrow MCl_2 + H_2), altering the chemical bonds and forming new compounds.
A change in chemical composition indicates the measurement of a chemical property.

Anahtar Kavram

Distinction between physical properties (observable without altering composition) and chemical properties (observable only during a reaction that changes composition)
Tahmini Süre:1m 0s
Soru 3247Soru →

A local boutique acquires a designer winter coat from a distributor for a wholesale cost of $125.00\$125.00. The store manager applies a 60%60\% markup to establish the regular retail price. Later in the season, the coat is moved to the clearance rack, receiving a 30%30\% discount off its regular retail price. A shopper buys the coat using a loyalty reward that takes an additional 10%10\% off the clearance price. If a 5%5\% sales tax is calculated on the final discounted price, what is the total amount the shopper pays at the register?

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Cevap: $132.30\$132.30

Cevap

The shopper pays a total of $132.30\$132.30 at the register.
The total amount is found by applying each percentage change successively to the new amount from the previous step. First, the 60% markup sets the price at 200.00.The30200.00. The 30% clearance discount reduces this to 140.00. The 10% loyalty discount further reduces it to 126.00.Finally,a5126.00. Finally, a 5% tax on the 126.00 final price adds 6.30,resultinginatotalof6.30, resulting in a total of 132.30.

Adım Adım Çözüm

1
Calculate the regular retail price by applying the 60%60\% markup to the wholesale cost.
$125.00×1.60=$200.00\$125.00 \times 1.60 = \$200.00
The markup increases the base cost to establish the starting retail price.
2
Calculate the clearance price by applying the 30%30\% discount to the regular retail price.
$200.00×(1−0.30)=$140.00\$200.00 \times (1 - 0.30) = \$140.00
The first discount is taken from the current retail price, not the wholesale cost.
3
Calculate the final item price by applying the 10%10\% loyalty discount to the clearance price.
$140.00×(1−0.10)=$126.00\$140.00 \times (1 - 0.10) = \$126.00
Successive discounts must be applied sequentially to the newly discounted price.
4
Calculate the total amount paid by adding the 5%5\% sales tax to the final item price.
$126.00×1.05=$132.30\$126.00 \times 1.05 = \$132.30
Sales tax is calculated strictly on the final discounted price of the item.

Anahtar Kavram

Calculating successive percentages for markups, discounts, and taxes sequentially based on the updated price at each step.
Soru 3248Soru →

A building contractor purchases a shipment of lumber with a regular retail price of $800.00\$800.00. The supplier offers a 15%15\% trade discount for professional contractors. After the discount is applied, a 6%6\% sales tax is added to the purchase. What is the final total cost of the lumber?

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Cevap: $720.80\$720.80

Cevap

The correct answer is $720.80\$720.80.
The correct answer is found by taking the multi-step percentage changes in order. First, find the 15%15\% discount on the regular price: 0.15×$800.00=$120.000.15 \times \$800.00 = \$120.00. Subtract this from the original price to get the discounted price: $800.00−$120.00=$680.00\$800.00 - \$120.00 = \$680.00. Next, calculate the 6%6\% sales tax on this new subtotal: 0.06×$680.00=$40.800.06 \times \$680.00 = \$40.80. Finally, add the sales tax to the discounted price: $680.00+$40.80=$720.80\$680.00 + \$40.80 = \$720.80.

Adım Adım Çözüm

1
Calculate the discount amount.
15%15\% of $800.00\$800.00 is $120.00\$120.00.
The trade discount is a percentage reduction based on the regular retail price.
2
Determine the discounted price.
$800.00−$120.00=$680.00\$800.00 - \$120.00 = \$680.00.
Subtracting the discount from the original price gives the subtotal before tax.
3
Calculate the sales tax.
6%6\% of $680.00\$680.00 is $40.80\$40.80.
Sales tax is applied to the discounted price, not the original retail price.
4
Find the final total cost.
$680.00+$40.80=$720.80\$680.00 + \$40.80 = \$720.80.
Adding the calculated sales tax to the discounted subtotal yields the final amount paid.

Anahtar Kavram

Calculating successive percentage changes (a discount followed by a tax) on a principal amount.
Soru 3249Soru →

A logistics convoy is assigned an 8080-mile supply route. During the morning phase, the convoy travels 223822 \frac{3}{8} miles. In the afternoon, they travel an additional 184518 \frac{4}{5} miles before halting for a security check. After resuming, they cover another 141214 \frac{1}{2} miles before nightfall. How many miles remain to complete the entire route? (Enter your answer as a decimal)

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Cevap: 24.325

Cevap

24.325
The total distance traveled is calculated by converting the fractional parts of the mixed numbers to a common denominator of 40. Adding 221540+183240+14204022 \frac{15}{40} + 18 \frac{32}{40} + 14 \frac{20}{40} gives 55274055 \frac{27}{40} miles. Subtracting this from the 8080-mile total route leaves 24134024 \frac{13}{40} miles. Converting 1340\frac{13}{40} to a decimal yields 0.325, giving a final answer of 24.325.

Adım Adım Çözüm

1
Determine the least common denominator (LCD) for the fractional parts of the distances traveled.
The denominators are 8, 5, and 2. The LCD is 40.
Fractions must have a common denominator before they can be added together.
2
Convert each mixed number to have the common denominator of 40 and add them to find the total distance traveled.
221540+183240+142040=54674022 \frac{15}{40} + 18 \frac{32}{40} + 14 \frac{20}{40} = 54 \frac{67}{40}, which simplifies to 55274055 \frac{27}{40} miles.
Adding the individual segments provides the total distance covered so far.
3
Subtract the total distance traveled from the overall route distance to find the remaining distance.
80−552740=794040−552740=24134080 - 55 \frac{27}{40} = 79 \frac{40}{40} - 55 \frac{27}{40} = 24 \frac{13}{40} miles.
Subtracting the part completed from the whole gives the remaining distance.
4
Convert the remaining distance into a decimal format.
1340=0.325\frac{13}{40} = 0.325, making the final distance 24.32524.325 miles.
The question specifically asks for the answer to be entered as a decimal.

Anahtar Kavram

Adding mixed numbers with unlike denominators and subtracting from a whole number.
Soru 3250Soru →

A light training aircraft with a mass of 750 kg750\text{ kg} accelerates from rest along a straight runway under a constant net forward force of 1500 N1{}500\text{ N}. What is the velocity of the aircraft, in meters per second (m/s\text{m/s}), after 8 seconds8\text{ seconds}?

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Cevap: 16

Cevap

16 m/s
According to Newton's second law (F=maF = ma), a net force of 1500 N1{}500\text{ N} applied to a mass of 750 kg750\text{ kg} produces a constant acceleration of a=1500750=2 m/s2a = \frac{1{}500}{750} = 2\text{ m/s}^2. Starting from rest (v0=0v_0 = 0), the velocity after 8 seconds8\text{ seconds} is v=at=2 m/s2×8 s=16 m/sv = at = 2\text{ m/s}^2 \times 8\text{ s} = 16\text{ m/s}.

Adım Adım Çözüm

1
Calculate the constant acceleration of the aircraft using Newton's second law of motion (Fnet=maF_{\text{net}} = ma).
a=1500 N750 kg=2 m/s2a = \frac{1{}500\text{ N}}{750\text{ kg}} = 2\text{ m/s}^2
Acceleration is directly proportional to net force and inversely proportional to mass.
2
Calculate the final velocity after 8 seconds8\text{ seconds} using the kinematic equation for uniform acceleration (v=v0+atv = v_0 + at).
v=0 m/s+(2 m/s2)(8 s)=16 m/sv = 0\text{ m/s} + (2\text{ m/s}^2)(8\text{ s}) = 16\text{ m/s}
Starting from rest, the final velocity equals the constant acceleration multiplied by elapsed time.

Anahtar Kavram

Newton's Second Law and Uniform Acceleration

Alternatif Yöntem

Apply the impulse-momentum theorem: Impulse=Fnet×Δt=Δp=m×v\text{Impulse} = F_{\text{net}} \times \Delta t = \Delta p = m \times v. Solving for velocity gives v=Fnet×Δtm=1500 N×8 s750 kg=12000750=16 m/sv = \frac{F_{\text{net}} \times \Delta t}{m} = \frac{1{}500\text{ N} \times 8\text{ s}}{750\text{ kg}} = \frac{12{}000}{750} = 16\text{ m/s}.
Tahmini Süre:1m 0s
Soru 3251Soru →

A maintenance technician needs to cut a continuous length of electrical wire into smaller segments. If the technician has a piece of wire that is 4545 feet long and each segment must be 3343 \frac{3}{4} feet long, how many full segments can be cut?

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Cevap: 12

Cevap

12
To find the total number of segments, the total length of wire (4545 feet) must be divided by the length of each individual segment (3343 \frac{3}{4} feet). Converting 3343 \frac{3}{4} to the improper fraction 154\frac{15}{4} and multiplying 4545 by its reciprocal (415\frac{4}{15}) yields exactly 1212 segments.

Adım Adım Çözüm

1
Convert the mixed number to an improper fraction.
334=1543 \frac{3}{4} = \frac{15}{4}
Division operations with mixed numbers require converting them to improper fractions first.
2
Set up the division equation.
45÷15445 \div \frac{15}{4}
To find how many smaller segments fit into the total length, you must divide the total wire length by the length of one individual segment.
3
Convert the division into multiplication.
45×41545 \times \frac{4}{15}
Dividing by a fraction is mathematically equivalent to multiplying by its reciprocal.
4
Simplify the expression and calculate the final value.
3×4=123 \times 4 = 12
Cross-canceling 4545 and 1515 leaves a factor of 33, which is then multiplied by 44 to reach the final whole number answer.

Anahtar Kavram

Dividing a whole quantity by a mixed number using improper fractions and reciprocals.
Soru 3252Soru →

Different materials transfer thermal energy by conduction at significantly different rates. Arrange the following substances in order of increasing thermal conductivity, starting from the poorest conductor (best thermal insulator) and ending with the best thermal conductor.

Öğeleri doğru sıraya koymak için sürükleyin

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Cevap

Trapped air, Liquid water, Iron, Copper
Thermal conductivity measures a material's ability to conduct heat. Gases like trapped air have widely dispersed molecules and are the poorest conductors. Liquids like water have closer molecules and conduct heat moderately better than gases. Solid metals conduct heat rapidly due to free electrons, with copper exhibiting superior conduction compared to iron.

Adım Adım Çözüm

1
Identify the state of matter and thermal mechanism for each substance
Trapped air is a gas, liquid water is a non-metallic liquid, while iron and copper are solid metals.
Thermal conduction occurs through particle collisions and free electron movement, which depends heavily on state of matter and atomic bonding.
2
Rank the non-metals based on molecular density
Trapped air has the lowest thermal conductivity (k≈0.026 W/(m⋅K)k \approx 0.026\text{ W/(m}\cdot\text{K)}), followed by liquid water (k≈0.6 W/(m⋅K)k \approx 0.6\text{ W/(m}\cdot\text{K)}).
Gases have large intermolecular distances leading to rare collisions, whereas liquids are denser and transfer kinetic energy more readily.
3
Rank the metals based on electronic thermal transport
Iron has a thermal conductivity of approximately 80 W/(m⋅K)80\text{ W/(m}\cdot\text{K)}, whereas copper has a thermal conductivity of approximately 400 W/(m⋅K)400\text{ W/(m}\cdot\text{K)}.
Both metals conduct heat via free valence electrons, but copper's electronic structure allows significantly higher conductivity.

Anahtar Kavram

Thermal Conductivity of Materials
Tahmini Süre:1m 0s
Soru 3253Soru →

A rescue drone with a mass of 40 kg40\text{ kg} is ascending vertically. If the drone's motors generate a constant upward lift force of 520 N520\text{ N} in an area where the acceleration due to gravity is 8 m/s28\text{ m/s}^2, what is the net upward acceleration of the drone?

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Cevap: 5 m/s25\text{ m/s}^2

Cevap

5 m/s25\text{ m/s}^2
The upward thrust of 520 N520\text{ N} is opposed by the downward gravitational force of 320 N320\text{ N} (40 kg×8 m/s240\text{ kg} \times 8\text{ m/s}^2). The resulting net upward force is 200 N200\text{ N}. Dividing this net force by the mass of 40 kg40\text{ kg} gives an upward acceleration of 5 m/s25\text{ m/s}^2.

Adım Adım Çözüm

1
Calculate the downward force of gravity (weight) acting on the drone.
W=m×g=40 kg×8 m/s2=320 NW = m \times g = 40\text{ kg} \times 8\text{ m/s}^2 = 320\text{ N} downward.
Gravity exerts a constant downward force equal to the product of mass and local gravitational acceleration.
2
Determine the net vertical force acting on the drone.
Fnet=Flift−W=520 N−320 N=200 NF_{\text{net}} = F_{\text{lift}} - W = 520\text{ N} - 320\text{ N} = 200\text{ N} upward.
The upward lift and downward weight act in opposite directions along the vertical axis, so their magnitudes subtract.
3
Apply Newton's second law (Fnet=maF_{\text{net}} = ma) to solve for acceleration.
a=Fnetm=200 N40 kg=5 m/s2a = \frac{F_{\text{net}}}{m} = \frac{200\text{ N}}{40\text{ kg}} = 5\text{ m/s}^2.
Acceleration equals the net unbalanced force divided by the total mass of the object.

Anahtar Kavram

Newton's Second Law and Net Force in Vertical Motion

Alternatif Yöntem

Calculate the upward acceleration produced by the motor thrust alone (athrust=520 N40 kg=13 m/s2a_{\text{thrust}} = \frac{520\text{ N}}{40\text{ kg}} = 13\text{ m/s}^2) and subtract the downward acceleration due to gravity (8 m/s28\text{ m/s}^2), which gives 13 m/s2−8 m/s2=5 m/s213\text{ m/s}^2 - 8\text{ m/s}^2 = 5\text{ m/s}^2.
Tahmini Süre:1m 0s
Soru 3254Soru →

Solve the following word problem by calculating the missing value.

Aşağıdaki boşlukları doldurun

An engineering battalion can lay 4040 feet of runway matting in 1515 minutes. Operating at this constant rate, the battalion will lay feet of matting in 1.51.5 hours.
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Cevap

240
Because 1.51.5 hours is equivalent to 9090 minutes, the time period is exactly 66 times longer than the original 1515-minute period (90÷15=690 \div 15 = 6). In a direct proportion, the amount of matting laid increases by the same factor, so 40 feet×6=240 feet40 \text{ feet} \times 6 = 240 \text{ feet}.

Adım Adım Çözüm

1
Convert the target time frame into the same units used for the known rate.
1.5 hours=1.5×60 minutes=90 minutes1.5 \text{ hours} = 1.5 \times 60 \text{ minutes} = 90 \text{ minutes}
Units of time must match to set up a valid direct proportion.
2
Set up a proportion relating feet of matting to minutes.
40 feet15 minutes=x feet90 minutes\frac{40 \text{ feet}}{15 \text{ minutes}} = \frac{x \text{ feet}}{90 \text{ minutes}}
Because the rate is constant, the ratio of distance to time remains the same.
3
Solve for the unknown value xx.
x=40×9015=40×6=240x = \frac{40 \times 90}{15} = 40 \times 6 = 240
Isolating xx provides the total feet of matting laid in 9090 minutes.

Anahtar Kavram

Direct proportions with unit conversion
Soru 3255Soru →

A maintenance crew can paint 120120 square feet of a ship's hull in 22 hours. Working at this same constant rate, how many square feet can the crew paint in 55 hours?

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Cevap: 300

Cevap

300
Because the work happens at a constant rate, the area painted is directly proportional to the time spent working. Finding the unit rate (6060 square feet per hour) and multiplying it by the target time (55 hours) yields the correct total of 300300 square feet.

Adım Adım Çözüm

1
Calculate the unit rate of painting.
6060 square feet per hour
To find how much is painted in a different amount of time, we first need to know how much is painted in one hour. We do this by dividing the total area (120120) by the total time (22).
2
Calculate the total area painted in the new timeframe.
300300 square feet
Multiply the unit rate (6060 square feet per hour) by the new target time (55 hours) to find the final proportional amount.

Anahtar Kavram

Direct Proportions
Soru 3256Soru →

A logistics specialist is calculating the total weight of cargo for a transport flight. The first crate weighs 451345 \frac{1}{3} pounds, and the second crate weighs 321632 \frac{1}{6} pounds. What is the total combined weight of both crates?

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Cevap: 771277 \frac{1}{2} pounds

Cevap

The total combined weight is 771277 \frac{1}{2} pounds.
The correct answer is found by identifying a common denominator of 6 for the fractions. The fraction 1/3 becomes 2/6. Adding 2/6 and 1/6 equals 3/6, which reduces to 1/2. Adding the whole numbers 45 and 32 gives 77. The combined weight is 77 1/2 pounds.

Adım Adım Çözüm

1
Set up the addition problem for the two mixed numbers.
4513+321645 \frac{1}{3} + 32 \frac{1}{6}
The question asks for the total combined weight, requiring addition.
2
Find a common denominator for the fractional parts.
The lowest common multiple of 33 and 66 is 66. Convert 13\frac{1}{3} by multiplying both numerator and denominator by 2 to get 26\frac{2}{6}.
Fractions must have the same denominator before they can be added together.
3
Add the whole numbers and the fractions, then simplify.
Whole numbers: 45+32=7745 + 32 = 77. Fractions: 26+16=36\frac{2}{6} + \frac{1}{6} = \frac{3}{6}. Simplifying 36\frac{3}{6} yields 12\frac{1}{2}. The final result is 771277 \frac{1}{2}.
Combining the sums of the whole numbers and the simplified fraction gives the final total weight.

Anahtar Kavram

Adding Mixed Numbers with Unlike Denominators
Tahmini Süre:45s
Soru 3257Soru →

An office manager is purchasing a commercial printer with a regular retail price of $1,200.00\$1,200.00. The store is offering a 20%20\% discount on all electronics. Using a corporate account, the manager receives an additional 10%10\% discount applied to the reduced sale price. Finally, a 5%5\% sales tax is added to the discounted total. What is the final total cost of the printer in dollars?

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Cevap: 907.2

Cevap

The final total cost of the printer is $907.20\$907.20.
The correct answer is derived by first taking 20%20\% off the $1,200.00\$1,200.00 base price to get $960.00\$960.00. Then, the 10%10\% corporate discount is taken off the $960.00\$960.00, bringing the subtotal down to $864.00\$864.00. Lastly, a 5%5\% tax on the $864.00\$864.00 subtotal adds $43.20\$43.20, resulting in a final cost of $907.20\$907.20.

Adım Adım Çözüm

1
Calculate the price after the initial 20%20\% electronics discount.
$1,200.00−($1,200.00×0.20)=$1,200.00−$240.00=$960.00\$1,200.00 - (\$1,200.00 \times 0.20) = \$1,200.00 - \$240.00 = \$960.00
The first discount is applied to the original retail price of the printer.
2
Calculate the price after the additional 10%10\% corporate discount.
$960.00−($960.00×0.10)=$960.00−$96.00=$864.00\$960.00 - (\$960.00 \times 0.10) = \$960.00 - \$96.00 = \$864.00
Successive discounts are calculated based on the previously reduced price, not the original price.
3
Calculate the 5%5\% sales tax on the final discounted price and add it to the total.
$864.00×0.05=$43.20\$864.00 \times 0.05 = \$43.20. Total = $864.00+$43.20=$907.20\$864.00 + \$43.20 = \$907.20
Sales tax is always applied to the final discounted sale price before checkout.

Anahtar Kavram

Successive discounts must be applied sequentially to the new reduced price at each step, and sales tax is computed on the final discounted price.
Soru 3258Soru →

A military transport unit has a fuel reserve of 420420 gallons. On the first day of a field exercise, the unit consumes 27\frac{2}{7} of the total reserve. On the second day, they consume 35\frac{3}{5} of the remaining fuel. If the fuel that is left after the second day is divided equally among 44 vehicles for a final patrol, how many gallons of fuel will each vehicle receive?

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Cevap: 3030

Cevap

Each vehicle will receive 3030 gallons of fuel.
To find the final amount per vehicle, calculate the remainder after each step. Day 1 consumes 120120 gallons, leaving 300300 gallons (420−120420 - 120). Day 2 uses 35\frac{3}{5} of 300300, which is 180180 gallons, leaving a final remainder of 120120 gallons. Dividing these 120120 gallons evenly among the 44 vehicles yields exactly 3030 gallons per vehicle.

Adım Adım Çözüm

1
Calculate the amount of fuel consumed on the first day and find the remaining balance.
First day consumption: 420×27=120420 \times \frac{2}{7} = 120 gallons. Remaining fuel: 420−120=300420 - 120 = 300 gallons.
The first day's usage is given as a fraction of the total initial reserve.
2
Calculate the amount of fuel consumed on the second day from the remaining balance, and find the new remainder.
Second day consumption: 300×35=180300 \times \frac{3}{5} = 180 gallons. Remaining fuel: 300−180=120300 - 180 = 120 gallons.
The problem explicitly states the second day's consumption is a fraction of the remaining fuel, not the original total.
3
Divide the final remaining fuel equally among the 44 vehicles.
120÷4=30120 \div 4 = 30 gallons per vehicle.
The total leftover fuel must be distributed evenly to find the specific amount allocated to each vehicle.

Anahtar Kavram

Applying sequential fraction multiplication to calculate remaining quantities in multi-step word problems.

Alternatif Yöntem

Use multiplication of the remaining fractions directly. After Day 1, 1−27=571 - \frac{2}{7} = \frac{5}{7} of the fuel is left. After Day 2, 1−35=251 - \frac{3}{5} = \frac{2}{5} of that remainder is left. The total fraction remaining of the original amount is 57×25=27\frac{5}{7} \times \frac{2}{5} = \frac{2}{7}. Multiply this by the original amount: 420×27=120420 \times \frac{2}{7} = 120 gallons. Finally, divide by 44 to get 3030 gallons per vehicle.
Tahmini Süre:1m 15s
Soru 3259Soru →

Electromagnetic principles are applied in many common electrical machines and tools. Match each device with its primary operational function.

Soldaki öğeye tıklayın, sonra eşleşen sağdaki öğeye tıklayın

Öğeler

Electric Generator
Electric Motor
Transformer
Electromagnet

Eşleşmeler

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Cevap

Electric Generator matches with converting mechanical energy to electrical energy; Electric Motor matches with converting electrical energy to mechanical rotation; Transformer matches with adjusting alternating current voltage levels; Electromagnet matches with producing a controllable magnetic field from electric current.
Each electromagnetic device corresponds directly to its defined operational function: generators convert mechanical work into electricity, motors convert electricity into mechanical rotation, transformers step AC voltage up or down, and electromagnets create temporary magnetic fields via electric current.

Adım Adım Çözüm

1
Identify the energy transformation in an electric generator.
Mechanical energy is converted into electrical energy via induction.
Generators are driven by mechanical power to produce current.
2
Identify the energy transformation in an electric motor.
Electrical energy is converted into mechanical motion.
Motors consume electricity to produce physical torque and rotation.
3
Identify the primary role of a transformer in power distribution.
Voltage levels of alternating current are increased or decreased.
Transformers rely on changing magnetic flux between primary and secondary coils to adjust voltage.
4
Identify the mechanism of an electromagnet.
Current flowing through a coil creates a magnetic field.
Moving electric charges naturally produce magnetic fields around the coil.

Anahtar Kavram

Electromagnetic Devices and Energy Transformations
Tahmini Süre:45s
Soru 3260Soru →

A commercial bakery makes a standard pastry dough using a ratio of 77 parts flour to 33 parts butter by weight. If a daily batch requires 4242 pounds of flour, how many pounds of butter are needed?

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Cevap: 1818

Cevap

1818
The ratio of flour to butter is given as 7:37:3. Setting up a direct proportion where xx is the pounds of butter needed: 73=42x\frac{7}{3} = \frac{42}{x}. Cross-multiplying gives 7x=1267x = 126. Solving for xx yields x=18x = 18 pounds of butter.

Adım Adım Çözüm

1
Identify the given ratio and the known quantity.
The ratio of flour to butter is 7:37:3. The known quantity of flour is 4242 pounds.
To set up a proportion, we must align the correct parts of the ratio with the real-world amounts.
2
Set up a direct proportion equation.
73=42x\frac{7}{3} = \frac{42}{x}
The ratio of parts must equal the ratio of the actual weights.
3
Solve for the unknown value xx.
7x=3×42→7x=126→x=187x = 3 \times 42 \rightarrow 7x = 126 \rightarrow x = 18
Cross-multiplying and dividing isolates the variable to find the required pounds of butter.

Anahtar Kavram

Direct Proportions
ÖncekiSayfa 163 / 261Sonraki