Tüm alıştırma soruları

Soru 581Soru →

When a bipolar junction transistor operates in its cutoff region, the collector-to-emitter path behaves as an open switch, preventing significant current flow through the output circuit.

Doğru

Yanlış

Cevabı ve açıklamayı göster

Cevap: True

Cevap

True

In the cutoff region, the control junction receives negligible bias voltage, preventing base current from flowing. Consequently, the output conduction path between the collector and emitter remains non-conductive, functioning electrically like an open switch.

Adım Adım Çözüm

1

Identify the specified operating state of the transistor

The statement specifies operation in the cutoff region.

A transistor's conductivity between its output terminals depends directly on its operating state: cutoff, active, or saturation.

2

Evaluate the current conduction characteristics in cutoff

Without base drive voltage, base current is zero, which halts collector current and creates an open-circuit condition.

In electronic switching applications, cutoff represents the 'off' or open-switch state where current cannot pass to the load.

Anahtar Kavram

Transistor Cutoff Region and Switching Operation

Tahmini Süre:45s

Soru 582Soru →

In an alternating current (AC) circuit, the direction of electron flow periodically reverses, whereas in a direct current (DC) circuit, electrons flow in only one continuous direction.

Doğru

Yanlış

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Cevap: True

Cevap

True

The statement is true because the defining characteristic distinguishing AC from DC is the direction of current flow: direct current flows in a single direction with constant polarity, whereas alternating current regularly reverses direction over time.

Adım Adım Çözüm

1

Analyze the fundamental definition of direct current (DC).

Direct current is characterized by electric charges flowing exclusively in a single, constant direction through a circuit.

Direct current power sources, such as chemical batteries, provide a fixed polarity across their terminals.

2

Analyze the fundamental definition of alternating current (AC).

Alternating current periodically cycles between positive and negative polarities, causing charge carriers to oscillate back and forth.

AC generators produce an alternating sinusoidal voltage waveform that regularly inverts direction.

3

Compare the definitions against the provided statement.

The statement accurately reflects the defining behavioral distinction between alternating and direct current.

Both halves of the statement describe standard electrical principles correctly.

Anahtar Kavram

Directional characteristics of alternating current (AC) versus direct current (DC)

Soru 583Soru →

A fuel tank on a generator is initially $\frac{7}{8}$ full. After the generator consumes $15$ gallons of fuel, the tank is exactly $\frac{1}{4}$ full. What is the total capacity of the fuel tank in gallons?

Cevabı ve açıklamayı göster

Cevap: 24

Cevap

The total capacity of the fuel tank is 24 gallons.

The correct answer is derived by finding the difference in the fraction of the tank's capacity (

\frac{7}{8} - \frac{1}{4} = \frac{5}{8}

). Since this

\frac{5}{8}

portion corresponds to

15

gallons, the total capacity is found by dividing

15

by

\frac{5}{8}

, which yields

24

gallons.

Adım Adım Çözüm

1

Find a common denominator for the given fractions.

\frac{1}{4} = \frac{2}{8}

To subtract the fractions, they must have the same denominator.

2

Calculate the fraction of the tank that was consumed by the generator.

\frac{7}{8} - \frac{2}{8} = \frac{5}{8}

The difference between the initial and final fuel levels represents the exact amount consumed.

3

Set up an algebraic equation linking the fraction consumed to the actual volume in gallons.

\frac{5}{8} \times \text{Capacity} = 15

We know that

\frac{5}{8}

of the total capacity corresponds directly to the

15

gallons used.

4

Solve the equation for the total capacity.

15 \times \frac{8}{5} = 24

Multiplying by the reciprocal of the fraction isolates the capacity variable.

Anahtar Kavram

Applying fraction subtraction with unlike denominators and solving a missing-value equation using a reciprocal.

Soru 584Soru →

Unlike current-driven bipolar devices, an enhancement-mode metal-oxide-semiconductor field-effect transistor (MOSFET) conducts significant current between its drain and source terminals when its gate-to-source voltage is zero.

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Cevabı ve açıklamayı göster

Cevap: False

Cevap

False. Enhancement-mode MOSFETs are normally-off devices that require a gate-to-source voltage exceeding the threshold voltage to establish a channel and conduct current.

The evaluation 'False' is correct because enhancement-mode MOSFETs are normally-off solid-state devices. Without an applied gate-to-source voltage exceeding the device's threshold voltage (

V_{th}

), the channel between the drain and source remains non-conductive, preventing drain current from flowing.

Adım Adım Çözüm

1

Identify the component classification and operating archetype specified in the statement.

The statement specifies an enhancement-mode metal-oxide-semiconductor field-effect transistor (MOSFET).

Different transistor families (bipolar vs. field-effect) and operational modes (enhancement vs. depletion) exhibit distinct default conduction states.

2

Analyze the channel status of an enhancement-mode device at zero gate-to-source voltage (

V_{GS} = 0\text{ V}

).

At

V_{GS} = 0\text{ V}

, no conductive channel connects the drain and source regions across the substrate, resulting in an open circuit where drain current (

I_D

) is approximately zero.

Enhancement-mode devices are manufactured without a pre-formed channel and operate as normally-off switches.

3

Determine what electrical condition is required to initiate conduction.

An electric field created by applying a gate-to-source voltage greater than the threshold voltage (

V_{GS} > V_{th}

) is mandatory to enhance/induce a channel.

Because current does not flow at zero bias, the assertion that it conducts significant current at zero gate voltage is incorrect.

Anahtar Kavram

Default conduction state and threshold voltage mechanics of enhancement-mode field-effect transistors

Alternatif Yöntem

Recall the root word 'enhance': the channel must be actively enhanced (created) by gate voltage, meaning at zero gate voltage, no channel exists and no current flows.

Tahmini Süre:45s

Soru 585Soru →

The value $x = 2$ is a valid solution for the inequality $5 - 2(3x + 1) < 4x - 17$ .

Doğru

Yanlış

Cevabı ve açıklamayı göster

Cevap: False

Cevap

False

Substituting

x = 2

into both sides of the inequality results in

-9 < -9

. Because

-9

is equal to

-9

and not strictly less than it, the mathematical statement is false. Alternatively, fully solving the inequality yields

x > 2

, which does not include

2

as a solution.

Adım Adım Çözüm

1

Substitute

x = 2

into the left side of the inequality.

5 - 2(3(2) + 1) = 5 - 2(6 + 1) = 5 - 2(7) = 5 - 14 = -9

To evaluate the numerical value of the left expression for the given test value.

2

Substitute

x = 2

into the right side of the inequality.

4(2) - 17 = 8 - 17 = -9

To evaluate the numerical value of the right expression for the given test value.

3

Compare the two evaluated sides using the strict inequality symbol (

<

).

-9 < -9

To determine if the resulting mathematical relationship is true.

4

Evaluate the truth of the final statement.

Since

-9

is exactly equal to

-9

, it is not strictly less than

-9

. The statement is therefore false.

A strict inequality requires the left side value to be genuinely smaller than the right side value.

Anahtar Kavram

Solving One-Variable Inequalities

Soru 586Soru →

Read the passage below. Based on the contrast context clue provided in the text, what word correctly completes the sentence?

Aşağıdaki boşlukları doldurun

Whereas previous navigational charts contained ambiguous depth markers that frequently confused the cutter's bridge crew during nighttime maneuvers, the updated digital display provided depth contours and bearings. This clarity allowed the helmsman to guide the vessel into port without hesitation or uncertainty.

Cevabı ve açıklamayı göster

Cevap

precise (or an equivalent antonym of ambiguous such as clear, exact, accurate, or unambiguous)

The transitional conjunction 'Whereas' sets up a direct contrast between the old navigational charts and the updated digital display. Because the old markers were 'ambiguous' and caused confusion, the new display's contours must possess the opposite quality—namely, being 'precise', 'clear', or 'unambiguous'—which enabled safe transit without hesitation.

Adım Adım Çözüm

1

Identify the contrast indicator and the contrasting quality described in the passage.

The transitional word 'Whereas' establishes an opposition between the 'ambiguous' markers of previous charts and the new display.

Contrast signal words indicate that the target descriptor in the second clause must have the opposite meaning of the descriptor in the first clause.

2

Determine the antonym needed to complete the sentence logically.

The antonym of 'ambiguous' (meaning unclear, vague, or doubtful) is 'precise', 'clear', or 'unambiguous', which is further corroborated by the mention of 'clarity' and navigation 'without hesitation'.

The blank must describe depth contours that eliminate confusion and provide exact guidance.

Anahtar Kavram

Identifying Antonym and Contrast Context Clues

Soru 587Soru →

An audio receiver circuit contains three capacitors arranged in a sub-network. Two $8\text{ }\mu\text{F}$ capacitors are connected in series with each other, and this series combination is connected in parallel with a third capacitor rated at $16\text{ }\mu\text{F}$ . What is the total equivalent capacitance of this sub-network in microfarads ( $\mu\text{F}$ )?

Cevabı ve açıklamayı göster

Cevap: 20

Cevap

20 μF

The equivalent capacitance of two

8\text{ }\mu\text{F}

capacitors in series is

4\text{ }\mu\text{F}

because series capacitors follow the formula

\frac{1}{C_s} = \frac{1}{8} + \frac{1}{8} = \frac{2}{8} = \frac{1}{4}

, resulting in

C_s = 4\text{ }\mu\text{F}

. When this

4\text{ }\mu\text{F}

equivalent section is wired in parallel with the

16\text{ }\mu\text{F}

capacitor, their values add directly (

4\text{ }\mu\text{F} + 16\text{ }\mu\text{F} = 20\text{ }\mu\text{F}

).

Adım Adım Çözüm

1

Calculate the equivalent capacitance of the two series-connected capacitors (

C_1 = 8\text{ }\mu\text{F}

and

C_2 = 8\text{ }\mu\text{F}

).

C_{\text{series}} = 4\text{ }\mu\text{F}

Capacitors in series combine reciprocally:

\frac{1}{C_{\text{series}}} = \frac{1}{C_1} + \frac{1}{C_2} = \frac{1}{8} + \frac{1}{8} = \frac{2}{8} = \frac{1}{4}\text{ }\mu\text{F}^{-1}

, which yields

C_{\text{series}} = 4\text{ }\mu\text{F}

.

2

Add the series branch equivalent capacitance (

4\text{ }\mu\text{F}

) to the parallel branch capacitor (

C_3 = 16\text{ }\mu\text{F}

).

C_{\text{total}} = 20\text{ }\mu\text{F}

Capacitors connected in parallel add directly:

C_{\text{total}} = C_{\text{series}} + C_3 = 4\text{ }\mu\text{F} + 16\text{ }\mu\text{F} = 20\text{ }\mu\text{F}

.

Anahtar Kavram

Series and Parallel Capacitance Calculation

Tahmini Süre:1m 0s

Soru 588Soru →

A technician is troubleshooting a solid-state switching circuit that utilizes a silicon PNP bipolar junction transistor. The emitter terminal is connected directly to a +12V DC power source, and the collector is wired in series with a ground-referenced load. In order to drive this transistor into saturation and fully power the load, what specific voltage condition must exist at the base terminal, and what is the direction of conventional current flow through the device?

The base must be at a higher voltage potential than the emitter; conventional current flows from the collector to the emitter.

The base must be at a higher voltage potential than the emitter; conventional current flows from the emitter to the collector.

The base must be at a lower voltage potential than the emitter; conventional current flows from the emitter to the collector.

The base must be at a lower voltage potential than the emitter; conventional current flows from the collector to the emitter.

Cevabı ve açıklamayı göster

Cevap: The base must be at a lower voltage potential than the emitter; conventional current flows from the emitter to the collector.

Cevap

The base must be at a lower voltage potential than the emitter; conventional current flows from the emitter to the collector.

The correct response accurately synthesizes both fundamental rules for a PNP transistor. First, to achieve saturation (full conduction), the base must be at a lower potential than the emitter to forward-bias the emitter-base junction. Second, unlike NPN devices, conventional current in a PNP transistor enters through the emitter and exits through the collector, following the direction of the emitter arrow on its schematic symbol.

Adım Adım Çözüm

1

Identify the type of transistor and its fundamental biasing requirements.

The device is a PNP transistor. To turn it on (saturation), the base must be negative relative to the emitter.

PNP transistors operate with opposite polarities compared to NPN transistors. Forward-biasing the emitter-base junction requires the P-type emitter to be more positive than the N-type base.

2

Determine the direction of conventional current flow through the component.

Conventional current flows from the emitter to the collector.

The schematic symbol for a PNP transistor has an arrow on the emitter pointing inward (towards the base), which indicates the direction of conventional current flow from emitter to collector.

3

Synthesize the findings to select the correct operational state.

Base voltage must be lower than emitter voltage, with current flowing emitter-to-collector.

Combining the biasing rule (V_base < V_emitter) and the current path establishes the correct parameters for full conduction.

Anahtar Kavram

PNP Transistor Biasing and Current Flow

Soru 589Soru →

A battery pack is constructed using six $1.5\text{ V}$ cells connected in series. If five of the cells are connected in series-aiding polarity and one cell is accidentally connected in reverse (series-opposing polarity), what is the total electromotive force (EMF) across the output terminals in volts?

Cevabı ve açıklamayı göster

Cevap: 6

Cevap

The net electromotive force across the terminals is

6.0\text{ V}

.

Electromotive force (EMF) values in a series circuit combine algebraically according to polarity. The five aiding cells provide

+7.5\text{ V}

(

5 \times 1.5\text{ V}

), while the single reversed cell opposes the chain with

-1.5\text{ V}

. The resulting net output voltage is

7.5\text{ V} - 1.5\text{ V} = 6.0\text{ V}

.

Adım Adım Çözüm

1

Calculate the combined electromotive force of the cells connected in series-aiding polarity.

5 \times 1.5\text{ V} = 7.5\text{ V}

Cells oriented in the same aiding polarity add their potential differences directly.

2

Subtract the potential difference of the reversed (series-opposing) cell from the aiding sum.

7.5\text{ V} - 1.5\text{ V} = 6.0\text{ V}

A reversed cell creates an electromotive force in the opposite direction, opposing the aiding cells and subtracting from the net terminal voltage.

Anahtar Kavram

Series cell electromotive force addition and opposing polarity subtraction

Tahmini Süre:1m 0s

Soru 590Soru →

A technician mistakenly connects the primary coil of a 1:2 step-up transformer directly to a steady 12-volt automotive battery. After the initial connection is made and the circuit reaches a steady state, what voltage is continuously induced across the secondary coil, and what is the fundamental reason for this result?

0 volts, because a steady direct current creates a static magnetic field that cannot induce a continuous voltage.

24 volts, because the transformer winding ratio doubles the input voltage regardless of the current type.

12 volts, because the direct current passes completely through the magnetic core without being stepped up by frequency alternation.

24 volts, because the continuous electron flow from the battery maintains a constantly expanding magnetic field.

Cevabı ve açıklamayı göster

Cevap: 0 volts, because a steady direct current creates a static magnetic field that cannot induce a continuous voltage.

Cevap

0 volts, because a steady direct current creates a static magnetic field that cannot induce a continuous voltage.

The correct answer identifies that a 12-volt battery provides steady Direct Current (DC). While DC will create a magnetic field in the transformer's primary coil, that field will quickly become static. Electromagnetic induction requires a continuously moving or fluctuating magnetic field—which is why transformers run on Alternating Current (AC). Without a changing magnetic field, no continuous voltage is induced in the secondary coil, resulting in 0 volts.

Adım Adım Çözüm

1

Identify the type of electrical source being used.

An automotive battery provides steady Direct Current (DC).

Understanding the source dictates how current will flow through the circuit.

2

Determine the characteristics of the magnetic field produced by the source.

Steady DC produces a static, unchanging magnetic field in the primary coil.

Magnetic field strength is proportional to current; a constant current yields a constant magnetic field.

3

Apply the principles of electromagnetic induction for transformers.

Induction requires a changing magnetic field (flux) to produce a voltage in the secondary coil.

Transformers rely on Alternating Current (AC) to constantly expand and collapse the magnetic field.

4

Calculate the continuous induced voltage on the secondary coil.

The induced voltage is 0 volts.

Because the DC magnetic field is static and not changing, no continuous voltage can be induced across the secondary coil, rendering the step-up ratio irrelevant.

Anahtar Kavram

Direct Current (DC) characteristics vs. Alternating Current (AC) in Electromagnetic Induction

Soru 591Soru →

A military field radio power pack contains four $3.6\text{ V}$ direct-current battery cells connected in series. During maintenance, three cells are placed in series-aiding polarity, but one cell is accidentally reversed into a series-opposing polarity. The power pack is also connected in series with an auxiliary charging module that supplies an aiding electromotive force (EMF) of $850\text{ mV}$ and a protective component that produces an opposing voltage drop of $650\text{ mV}$ . What is the net electromotive force, in volts ( $\text{V}$ ), delivered across the radio terminals?

Cevabı ve açıklamayı göster

Cevap: 7.4

Cevap

The net electromotive force delivered across the radio terminals is

7.4\text{ V}

.

In a series circuit, total electromotive force is the algebraic sum of all individual aiding and opposing potentials. The three aiding

3.6\text{ V}

cells contribute

+10.8\text{ V}

, while the reversed cell subtracts

-3.6\text{ V}

, leaving

+7.2\text{ V}

. Converting the auxiliary units (

850\text{ mV} = +0.85\text{ V}

and

650\text{ mV} = -0.65\text{ V}

) yields a net auxiliary contribution of

+0.20\text{ V}

. Adding these gives a total net terminal EMF of

7.2\text{ V} + 0.20\text{ V} = 7.4\text{ V}

.

Adım Adım Çözüm

1

Determine the net voltage contribution from the battery cells

Net battery EMF =

7.2\text{ V}

When cells are connected in series, aiding voltages add while opposing voltages subtract. With three cells aiding and one cell opposing:

V_{\text{cells}} = (3.6\text{ V} + 3.6\text{ V} + 3.6\text{ V}) - 3.6\text{ V} = 7.2\text{ V}

.

2

Convert auxiliary voltage values from millivolts to volts

Auxiliary aiding EMF =

0.85\text{ V}

, opposing drop =

0.65\text{ V}

Since

1\text{ V} = 1000\text{ mV}

, divide millivolts by

1000

:

850\text{ mV} = 0.85\text{ V}

and

650\text{ mV} = 0.65\text{ V}

.

3

Calculate the net contribution from the auxiliary components

Net auxiliary voltage =

+0.20\text{ V}

Subtract the opposing voltage drop from the aiding auxiliary EMF:

0.85\text{ V} - 0.65\text{ V} = +0.20\text{ V}

.

4

Combine the net battery EMF and net auxiliary voltage

Total EMF =

7.4\text{ V}

Add the net auxiliary contribution to the net battery bank voltage:

7.2\text{ V} + 0.20\text{ V} = 7.4\text{ V}

.

Anahtar Kavram

Series Electromotive Force (EMF) Addition, Opposing Polarity, and Metric Prefix Conversion

Tahmini Süre:1m 30s

Soru 592Soru →

Connect each unsimplified exponential operation to its mathematically equivalent simplified form.

Soldaki öğeye tıklayın, sonra eşleşen sağdaki öğeye tıklayın

Cevabı ve açıklamayı göster

Cevap

The correct pairings are: (3a^2)(2a^4) pairs with 6a^6, (12a^6)/(2a^2) pairs with 6a^4, (2a^3)^2 pairs with 4a^6, and 6a^-2 pairs with 6/a^2.

Each pair represents a fundamental rule of exponents applied to a one-step algebraic expression involving both coefficients and variables.

Adım Adım Çözüm

1

Evaluate the product

(3a^2)(2a^4)

.

6a^6

By the product rule, multiply coefficients (

3 \times 2 = 6

) and add the exponents of the same base (

2 + 4 = 6

).

2

Evaluate the quotient

\frac{12a^6}{2a^2}

.

6a^4

By the quotient rule, divide coefficients (

12 \div 2 = 6

) and subtract the bottom exponent from the top exponent (

6 - 2 = 4

).

3

Evaluate the power

(2a^3)^2

.

4a^6

By the power of a product rule, apply the exponent to both the coefficient (

2^2 = 4

) and the variable (

3 \times 2 = 6

).

4

Evaluate the negative exponent expression

6a^{-2}

.

\frac{6}{a^2}

By the negative exponent rule,

a^{-2}

becomes

\frac{1}{a^2}

. The coefficient 6 is not raised to the negative power, so it stays in the numerator.

Anahtar Kavram

Operations with Variable Exponents

Soru 593Soru →

Simplify the following algebraic expression completely. Write your final answer in standard form (highest to lowest power):

-2(n^2 - 4n + 3) + 3n(n - 2)

Cevabı ve açıklamayı göster

Cevap: n^2 + 2n - 6; n^2+2n-6; 1n^2 + 2n - 6; n^2 + 2n -6; n^2+2n - 6; 1n^2+2n-6

Cevap

n^2 + 2n - 6

The completely simplified form is determined by first distributing the multipliers into their respective parentheses. For the first group, -2(n^2 - 4n + 3) expands to -2n^2 + 8n - 6. For the second group, 3n(n - 2) expands to 3n^2 - 6n. Combining the expansions results in -2n^2 + 8n - 6 + 3n^2 - 6n. By adding the coefficients of like terms, the final standard form evaluates to n^2 + 2n - 6.

Adım Adım Çözüm

1

Distribute -2 into the first polynomial, (n^2 - 4n + 3).

-2n^2 + 8n - 6

The distributive property requires multiplying the outside term by every term inside the parentheses. Care must be taken with the negative sign: -2 multiplied by -4n becomes positive 8n.

2

Distribute 3n into the second binomial, (n - 2).

3n^2 - 6n

Using the distributive property again, multiplying 3n by n gives 3n^2, and 3n multiplied by -2 gives -6n.

3

Group the like terms from both expansions together.

(-2n^2 + 3n^2) + (8n - 6n) - 6

Like terms are terms that share the exact same variables raised to the exact same power. Grouping them helps systematically combine the coefficients.

4

Simplify the grouped terms.

n^2 + 2n - 6

Adding the coefficients of the grouped terms: -2 + 3 = 1 for the n^2 terms, and 8 - 6 = 2 for the n terms.

Anahtar Kavram

Simplifying algebraic expressions via polynomial expansion and combining like terms.

Soru 594Soru →

The solution set for the linear inequality $2(3x - 5) - 4x > 8x - 22$ is $x > 2$ .

Doğru

Yanlış

Cevabı ve açıklamayı göster

Cevap: False

Cevap

The statement is false. The correct solution set is

x < 2

.

The statement is false because solving the inequality gives

x < 2

. The inequality symbol must be flipped when dividing the final term

-6x > -12

by the negative coefficient

-6

.

Adım Adım Çözüm

1

Distribute the

2

across the terms inside the parentheses.

6x - 10 - 4x > 8x - 22

To eliminate the parentheses and prepare the terms for combining.

2

Combine like terms on the left side of the inequality.

2x - 10 > 8x - 22

To simplify the expression on the left side (

6x - 4x = 2x

).

3

Subtract

8x

from both sides.

-6x - 10 > -22

To gather all the variable terms on one side of the inequality.

4

Add

10

to both sides.

-6x > -12

To isolate the variable term completely.

5

Divide both sides by

-6

and reverse the inequality sign.

x < 2

Dividing an inequality by a negative number requires flipping the inequality symbol to maintain a mathematically true statement.

Anahtar Kavram

Solving multi-step linear inequalities and reversing the inequality symbol when dividing by a negative number.

Soru 595Soru →

An avionics communication filter assembly contains a capacitor network designed for signal conditioning. The network consists of two $40\text{ }\mu\text{F}$ capacitors connected in series. This series combination is connected in parallel with an $80\text{ }\mu\text{F}$ capacitor. Finally, this entire parallel arrangement is connected in series with a single $25\text{ }\mu\text{F}$ capacitor. What is the total equivalent capacitance of the network, in microfarads ( $\mu\text{F}$ )?

Cevabı ve açıklamayı göster

Cevap: 20

Cevap

The total equivalent capacitance of the network is

20\text{ }\mu\text{F}

.

The correct equivalent capacitance is

20\text{ }\mu\text{F}

. In capacitor networks, series components combine reciprocally (

\frac{1}{C_s} = \frac{1}{C_1} + \frac{1}{C_2}

) and parallel components add directly (

C_p = C_1 + C_2

). Resolving the initial series branch yields

20\text{ }\mu\text{F}

, which in parallel with

80\text{ }\mu\text{F}

produces

100\text{ }\mu\text{F}

. Finally, combining

100\text{ }\mu\text{F}

in series with

25\text{ }\mu\text{F}

results in

\frac{100 \times 25}{100 + 25} = 20\text{ }\mu\text{F}

.

Adım Adım Çözüm

1

Calculate the equivalent capacitance of the initial series branch consisting of two

40\text{ }\mu\text{F}

capacitors.

C_{s1} = 20\text{ }\mu\text{F}

Capacitors in series combine reciprocally:

\frac{1}{C_{s1}} = \frac{1}{40\text{ }\mu\text{F}} + \frac{1}{40\text{ }\mu\text{F}} = \frac{2}{40\text{ }\mu\text{F}} = \frac{1}{20\text{ }\mu\text{F}}

.

2

Calculate the equivalent capacitance of the parallel combination formed by

C_{s1}

and the

80\text{ }\mu\text{F}

capacitor.

C_p = 100\text{ }\mu\text{F}

Capacitors in parallel add directly:

C_p = C_{s1} + C_3 = 20\text{ }\mu\text{F} + 80\text{ }\mu\text{F} = 100\text{ }\mu\text{F}

.

3

Calculate the total circuit capacitance by placing the parallel equivalent

C_p

in series with the

25\text{ }\mu\text{F}

capacitor.

C_{\text{total}} = 20\text{ }\mu\text{F}

Applying the series formula for the final combination:

\frac{1}{C_{\text{total}}} = \frac{1}{C_p} + \frac{1}{C_4} = \frac{1}{100\text{ }\mu\text{F}} + \frac{1}{25\text{ }\mu\text{F}} = \frac{1+4}{100\text{ }\mu\text{F}} = \frac{5}{100\text{ }\mu\text{F}} = \frac{1}{20\text{ }\mu\text{F}}

.

Anahtar Kavram

Calculation of total equivalent capacitance in compound series-parallel networks using reciprocal series addition and direct parallel addition rules.

Alternatif Yöntem

Use the product-over-sum shortcut for each two-component series reduction:

C_{s1} = \frac{40 \times 40}{40 + 40} = \frac{1600}{80} = 20\text{ }\mu\text{F}

. Next, add the parallel component directly:

C_p = 20 + 80 = 100\text{ }\mu\text{F}

. Finally, apply product-over-sum for the last series stage:

C_{\text{total}} = \frac{100 \times 25}{100 + 25} = \frac{2500}{125} = 20\text{ }\mu\text{F}

.

Tahmini Süre:1m 30s

Soru 596Soru →

Which of the following correctly identifies the three terminal leads of a standard bipolar junction transistor (BJT)?

Source, gate, and drain

Anode, cathode, and gate

Emitter, base, and collector

Positive, negative, and ground

Cevabı ve açıklamayı göster

Cevap: Emitter, base, and collector

Cevap

Emitter, base, and collector

A standard bipolar junction transistor (BJT) is a three-terminal semiconductor device consisting of the emitter (which emits charge carriers), the base (the thin middle region that controls current), and the collector (which gathers the charge carriers).

Adım Adım Çözüm

1

Identify the component family and type specified in the question.

The component is a bipolar junction transistor (BJT).

Different transistor families utilize different lead naming conventions.

2

Recall the fundamental three-layer structure of a BJT.

A BJT is formed by two p-n junctions creating three regions: emitter, base, and collector.

The base controls current flow between the emitter and the collector.

Anahtar Kavram

Bipolar Junction Transistor (BJT) Terminals

Tahmini Süre:45s

Soru 597Soru →

In the physical construction of a standard fixed capacitor, what is the primary role of the dielectric material placed between the two conductive plates?

To create an electromagnetic field that opposes rapid changes in circuit current

To act as an insulating barrier that prevents direct electrical contact between the plates while supporting an electrostatic field

To provide a low-resistance path for direct current while completely blocking alternating current

To act as a conductive bridge that allows continuous electron flow across the gap between the plates

Cevabı ve açıklamayı göster

Cevap: To act as an insulating barrier that prevents direct electrical contact between the plates while supporting an electrostatic field

Cevap

To act as an insulating barrier that prevents direct electrical contact between the plates while supporting an electrostatic field

The dielectric in a capacitor is an electrical insulator (such as ceramic, mica, paper, or air) placed between the conductive plates. Its primary purpose is to physically isolate the plates so direct current cannot cross the gap, thereby allowing equal and opposite charges to accumulate and establish an electrostatic field.

Adım Adım Çözüm

1

Identify the basic construction of a capacitor

A capacitor consists of two conducting plates separated by an insulating layer known as the dielectric.

Understanding the physical structure establishes the role of each component.

2

Determine the electrical function of the dielectric material

The dielectric prevents charges on opposite plates from neutralizing each other through direct contact, allowing an electric field to be established and energy to be stored.

Insulators do not allow free electrons to flow through them, maintaining the potential difference between the plates.

Anahtar Kavram

Dielectric function and energy storage in capacitors

Tahmini Süre:45s

Soru 598Soru →

In a direct current electrical circuit, a power source supplies an electromotive force (EMF). What is the primary function of this electromotive force?

To act as the opposition that resists the flow of electrical charge

To provide the electrical pressure that causes electrons to move through the circuit

To determine the rate of electron flow passing a point per second

To convert direct current into oscillating alternating current

Cevabı ve açıklamayı göster

Cevap: To provide the electrical pressure that causes electrons to move through the circuit

Cevap

To provide the electrical pressure that causes electrons to move through the circuit

Electromotive force (EMF), expressed in volts, represents the electrical potential difference or electrical pressure that drives free electrons through a complete circuit path.

Adım Adım Çözüm

1

Identify the fundamental nature of electromotive force (EMF)

EMF is the electrical potential difference produced by an energy source such as a battery or generator.

Establishing the definition helps distinguish the driving potential from resulting current or circuit opposition.

2

Relate EMF to electrical circuit operation

EMF functions as electrical pressure that forces free electrons to drift through conductors in a closed loop.

Without an electromotive force, charge carriers lack the directional push required to produce an electrical current.

Anahtar Kavram

Electromotive force (EMF) is the electrical potential difference or pressure supplied by a power source that forces electrons through a circuit.

Tahmini Süre:45s

Soru 599Soru →

Rechargeable electronic devices store energy in batteries that require direct current (DC) to charge. Which device is specifically designed to convert the alternating current (AC) supplied by a wall outlet into direct current (DC)?

An inverter

A rectifier

A transformer

An alternator

Cevabı ve açıklamayı göster

Cevap: A rectifier

Cevap

A rectifier is the device that converts alternating current (AC) into direct current (DC).

A rectifier is an electrical circuit consisting of diodes that permits current flow in only one direction, transforming bidirectional alternating current (AC) into unidirectional direct current (DC).

Adım Adım Çözüm

1

Identify the type of incoming electrical supply and the required output format.

The source is alternating current (AC) from a utility outlet, and the target load requires direct current (DC).

Battery charging requires unidirectional current flow (DC), whereas grid power supplies bidirectional oscillating current (AC).

2

Select the electrical conversion device that turns bidirectional AC into unidirectional DC.

A rectifier (typically using semiconductor diodes) accomplishes AC-to-DC conversion.

Diodes conduct current in only one direction, converting the alternating wave into a unidirectional direct current.

Anahtar Kavram

Direct current (DC) flows continuously in one direction, whereas alternating current (AC) periodically reverses direction. Conversion from AC to DC is accomplished using a rectifier, while conversion from DC to AC is performed by an inverter.

Tahmini Süre:40s

Soru 600Soru →

A field-effect transistor (FET) regulates current flow through a semiconductor channel using an electrostatic field. Which terminal receives the controlling input voltage to modulate this current?

Drain

Gate

Source

Cathode

Cevabı ve açıklamayı göster

Cevap: Gate

Cevap

The gate terminal is the input control electrode of a field-effect transistor that receives voltage to regulate channel current.

In a field-effect transistor (FET), the gate terminal functions as the control element. An applied input voltage at the gate generates an electrostatic field that modulates the resistance and carrier flow through the channel connecting the source and drain.

Adım Adım Çözüm

1

Identify the standard three terminals of a field-effect transistor (FET).

A field-effect transistor consists of the source, drain, and gate terminals.

Identifying the terminal designations is the first step in determining their functional roles.

2

Differentiate between the current-carrying terminals and the control terminal.

Current travels through the channel between the source and drain terminals, while voltage applied to the gate terminal establishes an electric field that widens or restricts the channel.

The gate provides voltage-based control over current conduction without requiring significant input current.

Anahtar Kavram

Field-Effect Transistor (FET) Terminal Roles and Electrostatic Control

Tahmini Süre:45s

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