Tüm alıştırma soruları

5215 soru

Tüm türler5,215 Çoktan seçmeli2,665 Çoklu seçim6 Doğru / Yanlış260 Sayısal512 Eşleştirme930 Sıralama396 Boşluk doldurma397 Kısa cevap49

Soru 1341Soru →

A dual-power electronic circuit uses two silicon diodes to connect a primary $12\text{ V}$ DC power supply and a secondary $9\text{ V}$ backup battery to a single shared load. The anode of each diode is connected to the positive terminal of its respective source, and both cathodes are connected together at the positive terminal of the load. When the $12\text{ V}$ primary supply is operating normally, which of the following best describes the condition of the diode connected to the $9\text{ V}$ battery?

Forward-biased, because current from the higher-voltage supply flows backward into the battery

Reverse-biased, because the cathode voltage established by the primary supply is higher than the battery anode voltage

Forward-biased, because both voltage sources continuously force current simultaneously through the load

Reverse-biased, because the diode converts the direct-current input into alternating current to block it

Cevabı ve açıklamayı göster

Cevap: Reverse-biased, because the cathode voltage established by the primary supply is higher than the battery anode voltage

Cevap

Reverse-biased, because the cathode voltage established by the primary supply is higher than the battery anode voltage

A standard silicon diode becomes forward-biased only when its anode is roughly

0.7\text{ V}

more positive than its cathode. When the primary

12\text{ V}

DC supply conducts, the common cathode bus is held at approximately

12\text{ V} - 0.7\text{ V} = 11.3\text{ V}

. Because the backup battery diode has only

9\text{ V}

at its anode while its cathode is at

11.3\text{ V}

, the cathode is more positive than the anode, placing the backup diode into a reverse-biased (cutoff) state.

Adım Adım Çözüm

Determine the voltage at the shared cathode connection using the active primary source.

The primary

12\text{ V}

supply forward-biases its diode, dropping approximately

0.7\text{ V}

and establishing a common cathode bus potential of approximately

11.3\text{ V}

Silicon diodes in the conducting state exhibit a standard forward voltage drop of roughly

0.7\text{ V}

Compare the voltage at the anode of the backup battery diode to the shared cathode voltage.

The backup diode anode is held at

+9\text{ V}

by the battery, while its cathode is held at

+11.3\text{ V}

A diode requires its anode to be more positive than its cathode by at least

0.7\text{ V}

to conduct.

Determine the biasing state of the backup diode.

Because the cathode potential (

11.3\text{ V}

) exceeds the anode potential (

9\text{ V}

), the backup diode is reverse-biased (in cutoff) and conducts negligible current.

When the cathode is at a higher electrical potential than the anode, the semiconductor PN junction depletion region widens, blocking current flow.

Anahtar Kavram

Diode Biasing and Power-OR Steering

Tahmini Süre:1m 0s

Soru 1342Soru →

When a passenger vehicle equipped with an open differential makes a sharp right turn on dry pavement, how do the internal differential gears interact to allow smooth cornering?

The spider gears lock against the differential carrier case, forcing both the left and right side gears to rotate at identical speeds.

The spider gears disengage mechanically from the left side gear, allowing the outside wheel to freewheel without receiving drive torque.

The spider gears rotate on their shaft as they walk around the slower right side gear, driving the left side gear faster than carrier speed.

The spider gears hold both axle side gears stationary relative to the axle housing while power bypasses them through an internal viscous coupling.

Cevabı ve açıklamayı göster

Cevap: The spider gears rotate on their shaft as they walk around the slower right side gear, driving the left side gear faster than carrier speed.

Cevap

The spider gears rotate on their shaft as they walk around the slower right side gear, driving the left side gear faster than carrier speed.

In an open differential, the differential carrier rotates at ring gear speed. When negotiating a right turn, the inner right wheel meets higher rolling resistance and slows down. This forces the bevel spider gears to rotate on their differential cross pin as they walk around the slower right side gear. This rotational motion directly increases the speed of the outer left side gear, making it turn faster than the carrier while maintaining equal torque distribution across both drive axles.

Adım Adım Çözüm

Determine the relative wheel speeds required during a right-hand turn.

The inside (right) wheel travels along a smaller arc and slows down relative to the differential carrier, while the outside (left) wheel must cover a greater distance and rotate faster.

Geometry dictates that tires on the outer radius of a corner must travel farther in the same amount of time than tires on the inner radius.

Analyze the mechanical response of the differential spider gears on their cross shaft.

The slower-turning right side gear causes the spider gears to pivot and walk around it on their differential pinion shaft rather than remaining stationary relative to the carrier.

When both wheels turn at the same speed (straight line), the spider gears do not rotate on their pin; a speed difference between side gears forces them to turn.

Identify the kinematic effect on the opposite (outer/left) side gear.

The rotation of the spider gears adds speed to the left side gear, increasing its rotational velocity above carrier speed by the exact amount the right side gear decreased below carrier speed.

The differential carrier speed equals the average rotational speed of both axle side gears.

Anahtar Kavram

Kinematic operation of open differential spider and side gears during vehicle cornering

Tahmini Süre:1m 15s

Soru 1343Soru →

A technician and an assistant are performing a standard two-person manual brake bleeding procedure to purge trapped air from a vehicle's hydraulic brake lines. In what chronological sequence should the steps of a single bleeding cycle be performed?

Öğeleri doğru sıraya koymak için sürükleyin

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Cevap

The correct sequence begins with depressing and holding the brake pedal, followed by opening the bleeder screw to vent air, tightening the bleeder screw, and finally releasing the brake pedal.

During a two-person manual brake bleed, the system must first be pressurized by depressing and holding the brake pedal. Opening the bleeder screw then allows trapped air bubbles and fluid to escape under pressure. Closing the bleeder screw before releasing the pedal ensures that atmospheric air is not drawn back into the hydraulic system when the master cylinder piston returns.

Adım Adım Çözüm

Instruct the assistant to depress and hold down the brake pedal.

Hydraulic pressure builds within the master cylinder and brake lines.

Pressure is required to push fluid and trapped air out of the open valve.

Loosen the bleeder screw on the caliper or wheel cylinder roughly a quarter to half turn.

Air bubbles and fluid escape through the bleeder port into the tubing/container.

The differential between hydraulic line pressure and atmospheric pressure expels the air.

Tighten and close the bleeder screw before signaling the assistant.

The hydraulic system is sealed against atmospheric air entry.

Prevents air from being drawn into the caliper or cylinder when the pedal returns.

Signal the assistant to release the brake pedal.

The master cylinder piston returns, drawing fresh fluid from the reservoir into the bore.

Completes the bleeding cycle and prepares the system for the next stroke.

Anahtar Kavram

Manual Hydraulic Brake Bleeding Procedure

Tahmini Süre:45s

Soru 1344Soru →

A rotary potentiometer has a total resistance of $50\text{ k}\Omega$ across its two outer fixed terminals (Terminals A and C). If the center wiper (Terminal B) is adjusted so that the resistance between Terminal A and Terminal B is $32\text{ k}\Omega$ , what is the resistance between Terminal B and Terminal C?

32\text{ k}\Omega

18\text{ k}\Omega

82\text{ k}\Omega

1.8\text{ k}\Omega

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Cevap: $18\text{ k}\Omega$

Cevap

The resistance between Terminal B and Terminal C is

18\text{ k}\Omega

A potentiometer contains a single continuous resistive track between its two outer terminals (

A

and

C

). The center wiper (

B

) contacts this track at an intermediate point, splitting the total resistance into two complementary series sections such that

R_{AC} = R_{AB} + R_{BC}

. Given a total resistance of

50\text{ k}\Omega

and a segment of

32\text{ k}\Omega

, the remaining segment between the wiper and the other outer terminal must be

50\text{ k}\Omega - 32\text{ k}\Omega = 18\text{ k}\Omega

Adım Adım Çözüm

Identify the relationship between the three terminals of a potentiometer.

The total resistance between outer terminals A and C equals the sum of the two sub-segments created by wiper B:

R_{AC} = R_{AB} + R_{BC}

A potentiometer consists of a single continuous resistive element where the movable wiper divides the total track into two series-connected resistive portions.

Subtract the known segment resistance from the total end-to-end resistance to find

R_{BC}

R_{BC} = 50\text{ k}\Omega - 32\text{ k}\Omega = 18\text{ k}\Omega

Isolating

R_{BC}

algebraically provides the remaining resistance along the element to the opposite outer terminal.

Anahtar Kavram

Potentiometer resistive track division

Tahmini Süre:45s

Soru 1345Soru →

An offset screwdriver is designed specifically for turning fasteners in confined locations where overhead clearance prevents the use of a standard straight-shank screwdriver.

Doğru

Yanlış

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Cevap: True

Cevap

True

The statement is true because the 90-degree bent ends of an offset screwdriver enable engagement with screw heads where straight-line access is physically blocked.

Adım Adım Çözüm

Identify the defining physical design and operating purpose of an offset screwdriver.

An offset screwdriver has driving tips set at right angles (90 degrees) to the main handle shaft.

This right-angle profile allows the tool to fit into narrow gaps where a straight handle cannot stand upright.

Compare the tool's design function with the scenario in the statement.

The statement correctly describes the primary shop application of the tool.

When vertical access is obstructed by nearby vehicle components or structural frames, an offset driver is the proper hand tool choice.

Anahtar Kavram

Offset Screwdriver Design and Confined-Space Application

Tahmini Süre:30s

Soru 1346Soru →

In electronics assembly and repair, technicians employ various soldering tools and accessories. Match each soldering item to its primary function.

Soldaki öğeye tıklayın, sonra eşleşen sağdaki öğeye tıklayın

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Cevap

Heat sink clip matches diverting thermal energy away from heat-sensitive semiconductor leads; Desoldering wick matches drawing away molten solder via capillary action; Rosin-core solder matches cleaning surface metal oxides while depositing joining alloy; Soldering iron stand matches securing the hot iron heating element when idle to prevent fire hazards.

Each item corresponds to a specific workshop role: heat sink clips protect sensitive semiconductor leads by dissipating heat, desoldering wick uses capillary absorption to remove molten solder, rosin-core solder cleans oxides and bonds conductors, and iron stands provide passive thermal safety.

Adım Adım Çözüm

Identify the thermal protection device used during component soldering.

The heat sink clip clamps onto semiconductor leads to conduct excessive heat away from internal junctions.

Semiconductor components can be permanently destroyed if thermal limits are exceeded during soldering.

Identify the capillary-based desoldering material.

Desoldering wick consists of woven copper strands that absorb liquid solder off a joint.

Desoldering wick relies on molten solder naturally flowing into the hot, tightly braided copper.

Identify the primary electrical joining consumable.

Rosin-core solder delivers both non-corrosive flux for oxide cleaning and the metallic alloy for bonding.

Electrical work requires non-corrosive rosin flux rather than acid flux to preserve copper traces.

Identify the bench safety holder.

The soldering iron stand isolates the heated tip from surrounding workspace materials.

Soldering irons reach operating temperatures of 600°F to 800°F and require dedicated resting stands.

Anahtar Kavram

Functions and safety roles of essential electronics soldering tools and consumables

Tahmini Süre:1m 0s

Soru 1347Soru →

Match each automotive clutch and transmission component with its specific mechanical or hydraulic operational function.

Soldaki öğeye tıklayın, sonra eşleşen sağdaki öğeye tıklayın

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Cevap

The Stator assembly matches redirecting returning fluid flow to achieve torque multiplication; the Synchronizer blocker ring matches equalizing speed between the mainshaft and selected gear cone; the Release (throwout) bearing matches transferring axial force to the rotating diaphragm spring fingers; and the Sun gear matches serving as the central gear member in a planetary gearset.

Each component is correctly paired to its primary operational mechanism: the torque converter stator redirects fluid to generate torque multiplication; the synchronizer blocker ring matches rotational speeds through friction to avoid gear grinding; the release bearing allows stationary linkage to push rotating clutch diaphragm fingers; and the sun gear functions as the central member in automatic planetary gearsets.

Adım Adım Çözüm

Analyze the role of the torque converter stator.

Identified as the stationary fluid redirection element between the impeller and turbine responsible for torque multiplication.

When turbine speed is significantly lower than impeller speed, fluid exiting the turbine pushes backward; the locked stator redirects this fluid to assist impeller rotation.

Analyze the role of manual transmission synchronizer blocker rings.

Identified as the friction device that matches rotational speeds of meshing components.

Preventing gear clash requires matching the rotational velocity of the gear to the synchronizer sleeve before mechanical engagement occurs.

Analyze the operation of the clutch release (throwout) bearing.

Identified as the contact interface between the stationary release fork and rotating diaphragm spring.

Depressing the clutch pedal forces the bearing against the spinning diaphragm fingers, removing clamping force from the clutch disc.

Analyze the function of the planetary sun gear.

Identified as the central driving, driven, or held member in an epicyclic gear train.

Automatic transmissions vary gear ratios by using bands and multi-disc clutches to hold or drive specific planetary members including the sun gear, carrier, or ring gear.

Anahtar Kavram

Clutch and transmission component functions across manual friction clutches, synchromesh manual gearboxes, torque converters, and automatic planetary gearsets.

Tahmini Süre:1m 30s

Soru 1348Soru →

A bench technician uses a $100\text{ k}\Omega$ linear potentiometer as an adjustable control element in a circuit. If the wiper is adjusted to $75\%$ of its full mechanical travel away from the lower reference terminal, what is the resulting resistance between the wiper and the upper terminal in kilo-ohms ( $\text{k}\Omega$ )?

Cevabı ve açıklamayı göster

Cevap: 25

Cevap

25 kilo-ohms (

25\text{ k}\Omega

)

In a linear-taper potentiometer, the total end-to-end resistance (

100\text{ k}\Omega

) is distributed uniformly across the resistive track between the outer fixed terminals. When the wiper is moved

75\%

of the travel distance from the lower terminal, the remaining segment between the wiper and the upper terminal comprises

25\%

(

100\% - 75\%

) of the total resistance. Multiplying

100\text{ k}\Omega \times 0.25

gives

25\text{ k}\Omega

Adım Adım Çözüm

Find the percentage of the resistive element situated between the wiper contact and the upper terminal.

100\% - 75\% = 25\%

The total resistive track spans

100\%

of the component's resistance between its two outer end terminals.

Calculate the resistance across this upper portion of the track.

100\text{ k}\Omega \times 0.25 = 25\text{ k}\Omega

Because the potentiometer is linear, resistance is directly proportional to the physical position of the wiper along the track.

Anahtar Kavram

Linear potentiometer terminal division and wiper position relationships

Alternatif Yöntem

Calculate the resistance from the lower terminal to the wiper first (

100\text{ k}\Omega \times 0.75 = 75\text{ k}\Omega

), and subtract that value from the total resistance:

100\text{ k}\Omega - 75\text{ k}\Omega = 25\text{ k}\Omega

Tahmini Süre:45s

Soru 1349Soru →

Automotive driveline assemblies rely on specialized mechanical components to transfer rotational power reliably to the wheels as suspension geometry changes. Match each component below to its primary operational role.

Soldaki öğeye tıklayın, sonra eşleşen sağdaki öğeye tıklayın

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Cevap

Universal joint matches transmitting torque across changing angles; Slip yoke matches compensating for changes in driveline length; Ring and pinion gear set matches redirecting force 90 degrees and providing final drive gear reduction; Differential spider gears match enabling left and right wheels to rotate at different speeds during cornering.

Each drivetrain component addresses a specific kinematic necessity: universal joints provide angular flexibility, slip yokes provide axial sliding length adjustments, the ring and pinion changes drive orientation by 90 degrees with torque multiplication, and differential spider gears allow speed variance between drive wheels during turns.

Adım Adım Çözüm

Identify the primary motion accommodated by universal joints.

Universal joints accommodate angular misalignment between the transmission output shaft and the rear axle pinion shaft.

Vehicle suspension movement constantly alters the operating angle of the driveshaft.

Identify the primary motion accommodated by a slip yoke.

The slip yoke slides back and forth over splines to alter overall shaft length.

Suspension travel swings the rear axle along an arc, changing the distance between transmission and differential.

Identify the primary mechanical function of the ring and pinion gear set.

The ring and pinion gears turn the power flow by 90 degrees and multiply engine torque via gear reduction.

Driveshafts run along the vehicle's centerline, while axle shafts run laterally to the wheels.

Identify the role of the internal differential spider gears.

Spider gears spin on their pins to allow differential wheel rotational speeds when cornering.

The outside wheel travels a larger radius and must rotate faster than the inside wheel during turns.

Anahtar Kavram

Core mechanical roles of driveline joints, length compensation mechanisms, and differential gearing in automotive powertrains.

Tahmini Süre:45s

Soru 1350Soru →

When performing routine maintenance on a vehicle's liquid cooling system, a technician needs to drain, refill, and bleed the system. In what sequential order should the technician perform these maintenance steps?

Öğeleri doğru sıraya koymak için sürükleyin

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Cevap

The correct sequence is: allow the engine to cool completely before removing the cap, open the drain petcock to empty the old coolant, close the drain and refill with fresh 50/50 mixture, and finally run the engine with the heater on to bleed trapped air pockets.

Proper cooling system servicing follows an essential chronological order: first, allowing the engine to cool prevents burn hazards when opening the radiator cap; second, opening the drain petcock drains the old fluid; third, closing the drain allows refilling with fresh 50/50 mixture; and fourth, running the engine with the heater on circulates coolant through the open thermostat and heater core to purge trapped air pockets.

Adım Adım Çözüm

Wait for the engine to cool and carefully remove the radiator pressure cap.

The cooling system is safely opened without risk of scalding steam release.

Safety protocol requires relieving pressure only when liquid temperatures have dropped.

Locate and open the radiator drain petcock at the lowest point of the radiator.

Spent coolant flows out into an approved disposal container.

All old fluid must be evacuated before introducing new coolant.

Tighten the drain petcock and fill the system with a 50/50 mix of ethylene glycol and distilled water.

The radiator and engine block are refilled with clean coolant.

The 50/50 mixture provides optimal freeze protection and boil-over resistance.

Start the engine, set the heater controls to maximum heat, and allow the thermostat to open.

Air bubbles escape through the filler neck as coolant circulates through the entire loop.

Bleeding prevents localized overheating caused by trapped air locks in the cylinder head.

Anahtar Kavram

Cooling System Service and Air Bleeding Procedure

Tahmini Süre:45s

Soru 1351Soru →

When a driver turns the steering wheel in a vehicle equipped with a recirculating-ball steering system, mechanical force transfers through several internal gearbox components before reaching the steering linkage. In what order does mechanical force travel through the internal components of a recirculating-ball steering gearbox to move the Pitman arm?

Öğeleri doğru sıraya koymak için sürükleyin

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Cevap

The correct sequence of mechanical force transfer is: (1) The steering shaft rotates the threaded worm gear inside the gearbox housing, (2) Steel ball bearings roll along the worm gear grooves to drive the ball nut linearly, (3) Gear teeth on the ball nut engage and turn the sector gear on the sector shaft, and (4) The sector shaft swings the Pitman arm to push or pull the steering linkage.

In a recirculating-ball steering gearbox, rotation from the steering wheel turns the worm gear first. The rolling ball bearings transfer this rotation to drive the ball nut linearly along the worm shaft. Teeth on the exterior of the ball nut mesh with the sector gear on the sector shaft, and the sector shaft rotates the splined Pitman arm to actuate the steering linkage.

Adım Adım Çözüm

Identify the mechanical input into the steering gearbox.

Driver input rotates the steering column and steering shaft, turning the threaded worm gear.

The worm gear is the direct input component inside the recirculating-ball gearbox housing.

Trace how rotational motion is converted into linear motion inside the gearbox.

Steel ball bearings circulate through the matching grooves between the worm gear and the ball nut, pushing the ball nut along the shaft.

The recirculating balls act as rolling threads that convert rotary input into linear motion with minimal friction.

Trace the engagement between the linear ball nut and the output gear.

Teeth machined into the exterior of the ball nut mesh with the sector gear, rotating the sector shaft.

The rack teeth on the ball nut convert linear movement back into rotational output at the cross shaft.

Identify the output component that connects the gearbox to the chassis linkage.

Rotation of the sector shaft swings the Pitman arm.

The Pitman arm is splined to the sector shaft and provides the mechanical leverage to move the center link and tie rods.

Anahtar Kavram

Internal mechanical power flow in a recirculating-ball steering gearbox

Tahmini Süre:1m 0s

Soru 1352Soru →

During a multi-point vehicle inspection, an automotive technician observes several distinct tire wear patterns across different fleet vehicles. Match each observed tire wear pattern with its primary operational or mechanical root cause.

Soldaki öğeye tıklayın, sonra eşleşen sağdaki öğeye tıklayın

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Cevap

Match symmetrical dual-shoulder wear with chronic underinflation; center rib wear with chronic overinflation; feathered saw-tooth wear with improper toe alignment; and cupping or scalloping with worn shock absorbers or dynamic wheel imbalance.

Each tire wear profile represents a distinct mechanical or operating fault: underinflation unloads the center and overloads both shoulders; overinflation crowns the center rib; toe misalignment causes horizontal dragging that feathers tread blocks; and weak suspension damping allows uncontrolled vertical bouncing that cuts rhythmic cupped dips into the tread circumference.

Adım Adım Çözüm

Analyze contact patch physics related to pneumatic inflation errors.

Determined that dual-shoulder wear indicates low tire pressure (underinflation), whereas center-crown wear indicates excessive tire pressure (overinflation).

Inflation pressure controls the transverse contact patch profile across the tread.

Distinguish between lateral alignment friction and vertical suspension/balance oscillation.

Determined that feathered edges result from lateral scrubbing caused by toe angle misalignment, while cupping and scalloping result from cyclic vertical impacts caused by failing dampers or wheel imbalance.

Toe angles create continuous horizontal dragging across the tread face, whereas degraded suspension dampers permit dynamic bouncing along the circumference.

Anahtar Kavram

Tire Wear Pattern Diagnostics and Chassis Alignment Relationships

Tahmini Süre:1m 30s

Soru 1353Soru →

An electrical technician evaluates four material samples of identical length and cross-sectional area under standard test conditions. Arrange these materials in order of their electrical resistance, from lowest resistance (best conductor) to highest resistance (best insulator).

Öğeleri doğru sıraya koymak için sürükleyin

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Cevap

The correct sequence from lowest resistance to highest resistance is Copper wire, followed by Nichrome alloy wire, then Germanium crystal, and finally Glass rod.

Copper provides the lowest resistance due to abundant free electrons. Nichrome is also a conductor but exhibits higher metallic resistance. Germanium is a semiconductor with intermediate resistance governed by four valence electrons. Glass is an insulator whose tightly bound atomic structure provides the highest resistance.

Adım Adım Çözüm

Identify and order the metallic conductors based on relative resistivity.

Copper wire has the lowest resistance, followed by Nichrome alloy wire.

Metals have 1 to 3 loosely bound valence electrons that allow free electron movement. Copper is a prime conductor with minimal resistance, whereas Nichrome is an alloy specifically designed to offer higher metallic resistance.

Identify the semiconductor and position it after the metallic conductors.

Germanium crystal is placed in the third position.

Semiconductors have four valence electrons forming covalent bonds. Their conductivity is intermediate between conductors and insulators, giving them moderate resistance.

Identify the insulator and position it at the end of the sequence.

Glass rod is placed in the final position.

Insulators have tightly bound outer shell electrons and extremely wide energy band gaps, preventing electron flow and producing the highest electrical resistance.

Anahtar Kavram

Classification of electrical materials (conductors, semiconductors, and insulators) determined by electron mobility, valence structure, and relative resistance.

Tahmini Süre:1m 0s

Soru 1354Soru →

During a routine vehicle maintenance inspection, a technician discovers a distinct cupped and scalloped wear pattern across the tire tread. Which worn or defective component is the most likely cause of this specific tire wear?

Suspension coil spring

Shock absorber

Brake caliper assembly

Differential spider gear

Cevabı ve açıklamayı göster

Cevap: Shock absorber

Cevap

Worn shock absorber

Worn shock absorbers fail to control spring oscillations, allowing the wheel assembly to bounce excessively as the vehicle travels. This continuous bouncing causes the tire to repeatedly hit the road surface with high impact, resulting in a scalloped or cupped wear pattern around the tread.

Adım Adım Çözüm

Identify the characteristic tire wear symptom described in the stem.

The symptom is cupping or scalloping (alternating high and low dips along the tread circumference).

Recognizing the physical wear pattern is the first step in automotive wheel and tire diagnostics.

Determine the mechanical mechanism that produces repeated vertical bouncing on the road surface.

Shock absorbers and struts are responsible for dampening spring oscillations; when worn, they allow uncontrolled wheel hop.

Uncontrolled bouncing repeatedly slams the tire tread into the pavement at periodic intervals, digging out distinct cups in the rubber.

Anahtar Kavram

Tire wear diagnostics and shock absorber dampening function

Tahmini Süre:45s

Soru 1355Soru →

A vehicle's manual transmission operates in first gear using a compound gear train. The input shaft gear with 15 teeth drives a countershaft cluster gear with 30 teeth. On the same countershaft, another gear with 10 teeth meshes with and drives a mainshaft output gear with 40 teeth. If the engine rotates the input shaft at 2,400 RPM, what is the resulting rotational speed of the mainshaft?

1,200 RPM

300 RPM

600 RPM

4,800 RPM

Cevabı ve açıklamayı göster

Cevap: 300 RPM

Cevap

300 RPM

The correct answer is 300 RPM because a manual gearbox in lower gears utilizes a two-step compound reduction. The first mesh between the 15-tooth input gear and 30-tooth countershaft gear yields a 2:1 reduction ratio (

30 \div 15 = 2

). The second mesh between the 10-tooth countershaft gear and 40-tooth mainshaft gear yields a 4:1 reduction ratio (

40 \div 10 = 4

). Multiplying both stage ratios gives an overall gear ratio of 8:1 (

2 \times 4 = 8

). Dividing the engine input speed of 2,400 RPM by the total ratio of 8 yields an output mainshaft speed of 300 RPM.

Adım Adım Çözüm

Calculate the first-stage gear reduction from the input shaft to the countershaft

Gear Ratio 1 = 30 teeth ÷ 15 teeth = 2:1 reduction; Countershaft speed = 2,400 RPM ÷ 2 = 1,200 RPM

The input shaft drives the larger gear on the countershaft, reducing rotational speed by half.

Calculate the second-stage gear reduction from the countershaft to the mainshaft

Gear Ratio 2 = 40 teeth ÷ 10 teeth = 4:1 reduction

The smaller driving gear on the countershaft turns the larger driven gear on the mainshaft.

Determine total transmission gear reduction and compute the final output speed

Overall Gear Ratio = 2 × 4 = 8:1; Mainshaft output speed = 2,400 RPM ÷ 8 = 300 RPM

Compound gear ratios multiply across successive mesh stages to determine total drivetrain mechanical advantage and output shaft speed.

Anahtar Kavram

Compound gear ratios and mechanical power flow in manual transmissions

Tahmini Süre:1m 30s

Soru 1356Soru →

Following a front-end suspension overhaul, an automobile exhibits highway wandering and poor steering wheel returnability after completing turns, even though tire wear remains completely normal. Which steering geometry alignment setting is most likely out of specification?

Camber angle

Caster angle

Brake caliper slide pin clearance

Differential drive pinion preload

Cevabı ve açıklamayı göster

Cevap: Caster angle

Cevap

Caster angle is the primary alignment angle responsible for directional stability and returning the steering wheel to center after a turn.

Caster is defined as the forward (negative) or rearward (positive) tilt of the steering axis when viewed from the side of the vehicle. Positive caster places the steering axis pivot point ahead of the tire contact patch on the road surface, creating a mechanical trailing effect. This geometry produces directional stability at highway speeds and generates the self-aligning torque necessary to pull the front wheels back to the straight-ahead position after a turn. In addition, incorrect caster does not cause accelerated tire wear, matching the reported scenario.

Adım Adım Çözüm

Analyze the vehicle symptoms described in the scenario

Identified highway wandering and lack of steering wheel returnability without abnormal tire wear.

Different alignment and chassis angles cause distinct driving symptoms and tire wear patterns.

Evaluate the functional role of steering geometry angles

Positive caster projects the steering axis forward of the tire contact patch, creating a self-aligning torque that stabilizes the vehicle at speed and returns the front wheels to straight-ahead.

Insufficient positive caster causes steering wander and sluggish returnability without directly scrubbing tire tread.

Differentiate from alternative chassis settings

Camber and toe errors produce noticeable tread wear, while braking and differential components do not govern steering returnability.

Isolating caster aligns with both the symptom profile and lack of tire wear.

Anahtar Kavram

Steering Geometry Alignment Angles (Caster, Camber, and Toe)

Tahmini Süre:1m 0s

Soru 1357Soru →

A technician is testing a telemetry circuit board and measures a steady direct current of $40\text{ mA}$ flowing through a $750\ \Omega$ load resistor. What is the voltage drop across this resistor?

300\text{ V}

18.75\text{ V}

30\text{ V}

3.0\text{ V}

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Cevap: $30\text{ V}$

Cevap

30\text{ V}

According to Ohm's Law (

V = I \times R

), the voltage drop across a component is calculated by multiplying the current flowing through it by its resistance. Converting

40\text{ mA}

to standard amperes gives

0.040\text{ A}

. Multiplying

0.040\text{ A}

750\ \Omega

yields a potential difference of

30\text{ V}

Adım Adım Çözüm

Convert current from milliamperes (mA) to base amperes (A)

I = 40\text{ mA} = 40 \times 10^{-3}\text{ A} = 0.040\text{ A}

Standard electrical calculations using Ohm's Law require base units of amperes, ohms, and volts.

Apply Ohm's Law to determine the potential difference (

V = I \times R

)

V = 0.040\text{ A} \times 750\ \Omega = 30\text{ V}

Voltage drop across a resistive element is directly proportional to the product of the current and resistance.

Anahtar Kavram

Ohm's Law (

V = I \times R

) and metric unit conversion

Tahmini Süre:45s

Soru 1358Soru →

As rotational power enters an automotive rear axle assembly, torque transfers through several internal differential parts to drive the vehicle. In what order does mechanical torque travel through these internal components, starting from the differential housing input and ending at the axle shafts?

Öğeleri doğru sıraya koymak için sürükleyin

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Cevap

The correct torque path through the internal differential starts at the Drive pinion gear, transfers to the Ring gear, moves to the Differential carrier (case), passes through the Differential pinion (spider) gears, and concludes at the Differential side gears.

Rotational power from the driveshaft enters the differential through the drive pinion gear. The drive pinion meshes with the larger ring gear to change the direction of rotation by 90 degrees and provide gear reduction. Because the differential carrier (case) is bolted directly to the ring gear, it rotates at the same speed. Inside the carrier, the differential pinion (spider) gears are supported on a cross pin and revolve with the case. These spider gears mesh with and drive the differential side gears, which are splined to the axle shafts that turn the drive wheels.

Adım Adım Çözüm

Identify the initial mechanical input to the differential housing.

The drive pinion gear receives rotational torque directly from the propeller shaft pinion flange.

The drive pinion is the physical input gear entering the axle housing.

Trace torque from the input pinion to the perpendicular drive gear.

The drive pinion gear rotates the much larger ring gear.

The hypoid or bevel gear mesh changes the axis of rotation by 90 degrees to drive the transverse axle line.

Identify the housing component driven directly by the ring gear.

The ring gear turns the differential carrier (case).

The ring gear is securely bolted to the flange of the differential carrier, making them spin as a single unit.

Follow the mechanical connection inside the rotating carrier.

The rotating differential carrier drives the differential pinion (spider) gears.

The spider gears are mounted on a shaft pinned inside the carrier and revolve around the axle centerline with the carrier.

Determine the final internal output gears before the axle shafts.

The spider gears drive the differential side gears.

The side gears mesh with the spider gears and contain internal splines that lock directly onto the axle shafts.

Anahtar Kavram

Differential internal power flow and torque path

Tahmini Süre:1m 0s

Soru 1359Soru →

A direct-current ( $24\text{ V}$ DC) cooling fan motor installed in an electronics enclosure has an internal resistance of $16\text{ }\Omega$ . What is the total electrical power consumed by the fan motor during normal operation?

1.5\text{ W}

24\text{ W}

36\text{ W}

384\text{ W}

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Cevap: $36\text{ W}$

Cevap

The total electrical power consumed by the fan motor is

36\text{ W}

Electrical power (

P

) delivered to a resistive load is given by

P = \frac{V^2}{R}

. Substituting the given parameters yields

P = \frac{(24\text{ V})^2}{16\text{ }\Omega} = \frac{576}{16} = 36\text{ W}

. Alternatively, by Ohm's Law, the current drawn is

I = \frac{24\text{ V}}{16\text{ }\Omega} = 1.5\text{ A}

, yielding

P = V \times I = 24\text{ V} \times 1.5\text{ A} = 36\text{ W}

Adım Adım Çözüm

Determine the current flowing through the motor using Ohm's Law (

I = \frac{V}{R}

I = \frac{24\text{ V}}{16\text{ }\Omega} = 1.5\text{ A}

Current is needed to calculate power using Watt's Law (

P = V \times I

Calculate the electrical power using Watt's Law (

P = V \times I

) or directly using

P = \frac{V^2}{R}

P = 24\text{ V} \times 1.5\text{ A} = 36\text{ W}

(or

P = \frac{24^2}{16} = \frac{576}{16} = 36\text{ W}

)

Electrical power is the rate of energy consumption and is given by the product of voltage and current.

Anahtar Kavram

Electrical power dissipation in a resistive direct-current load calculated from voltage and resistance (

P = \frac{V^2}{R} = V \times I

Tahmini Süre:1m 0s

Soru 1360Soru →

A cross-recess screw head features sharp internal corners and a pointed center with $45^\circ$ flutes. Which type of screwdriver is designed to fit this specific fastener without camming out?

Phillips screwdriver

Frearson (Reed & Prince) screwdriver

Clutch-head screwdriver

Cabinet-tip slotted screwdriver

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Cevap: Frearson (Reed & Prince) screwdriver

Cevap

Frearson (Reed & Prince) screwdriver

The Frearson (also known as Reed & Prince) screwdriver is engineered with a sharp, pointed cross tip and true

45^\circ

flutes, allowing one driver size to fit multiple screw sizes while preventing slippage under high torque.

Adım Adım Çözüm

Analyze the fastener head geometry described in the stem.

The fastener has a cross-recess with a pointed center, sharp internal corners, and

45^\circ

flutes.

Identifying specific drive geometry prevents tool slippage and fastener damage.

Distinguish between cross-slot drive profiles.

While Phillips drivers have blunt tips and rounded internal corners, Frearson drivers come to a sharp point with straight

45^\circ

flutes.

Matching the driver tip to the recess profile ensures proper torque transfer and prevents cam-out.

Anahtar Kavram

Distinguishing Frearson (Reed & Prince) cross-slot screwdrivers from Phillips drivers based on tip point sharpness and flute geometry.

Tahmini Süre:40s

ÖncekiSayfa 68 / 261Sonraki

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