Tüm alıştırma soruları

Soru 121Soru →

Which electrical principle or formula defines each parameter in a standard parallel circuit? Match each circuit parameter on the left with its corresponding characteristic on the right.

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Cevap

Voltage across each branch matches 'Remains equal across every branch and matches the source voltage'; Total circuit current matches 'Equals the sum of all individual branch currents'; Total equivalent resistance matches 'Is always less than the resistance of the smallest branch resistor'; Current through an individual branch matches 'Calculated by dividing source voltage by the branch resistance (

I_n = \frac{V}{R_n}

)'.

In parallel circuits, voltage is identical across every branch. Total current is the sum of all individual branch currents. Total equivalent resistance decreases as more branches are added and is always less than the smallest individual resistor. Each branch current is calculated independently using Ohm's Law with the common voltage.

Adım Adım Çözüm

1

Determine the voltage rule for parallel connections

Branch voltage is identical to source voltage (

V_{\text{total}} = V_1 = V_2 = \dots

)

All parallel branches share common input and return connection points.

2

Determine the total current rule for parallel connections

Total current is the sum of branch currents (

I_{\text{total}} = I_1 + I_2 + \dots

)

Current divides among all available parallel conducting branches according to Kirchhoff's Current Law.

3

Determine the equivalent resistance behavior

Equivalent resistance is less than the smallest branch resistance (

R_{\text{eq}} < R_{\text{smallest}}

)

Each additional parallel path increases overall circuit conductance.

4

Apply Ohm's law to calculate individual branch current

Branch current is

I_n = \frac{V}{R_n}

Ohm's law applies directly across each branch using the common source voltage.

Anahtar Kavram

Fundamental voltage, current, and equivalent resistance relationships in parallel circuits

Soru 122Soru →

Match each electromagnetic component or induction phenomenon with its precise operational principle.

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Cevap

Electromagnetic Relay pairs with low-current coil energization pulling isolated contacts; Inductive Back-EMF pairs with counter-EMF resisting instantaneous current changes; Step-Down Transformer pairs with mutual induction reducing voltage while increasing current capacity; Ferromagnetic Core Solenoid pairs with concentrating flux lines via high permeability to maximize mechanical force.

Each electromagnetic concept directly reflects its physical mechanism: relays isolate circuits through electromagnetically actuated mechanical contacts, back-EMF generates an opposing counter-voltage during current shifts, step-down transformers exchange voltage for current via mutual AC induction, and iron-core solenoids maximize pull force by concentrating magnetic flux density.

Adım Adım Çözüm

1

Analyze the electrical isolation and mechanical switching mechanism of an electromagnetic relay.

Identify that a relay enables a low-power circuit to safely switch a separate heavy-duty circuit via magnetic pull on an armature.

Relays function as electrically operated mechanical switches where the control coil is isolated from the load contacts.

2

Apply Lenz's Law and Faraday's Law to evaluate inductive back-EMF behavior.

Determine that the self-induced voltage always acts in the opposite polarity to the change in circuit current (

V = -L \frac{di}{dt}

).

Inductors store energy in magnetic fields and resist rapid current fluctuations by generating counter-electromotive force.

3

Examine power conservation and mutual induction relationships in a step-down transformer.

Confirm that fewer secondary turns reduce secondary voltage while stepping up current proportionally under AC operation.

Assuming ideal transformer efficiency (

P_{in} = P_{out}

), a decrease in voltage requires an inverse, proportional increase in current.

4

Assess the effect of magnetic core material on solenoid pulling performance.

Recognize that a ferromagnetic core lowers magnetic reluctance and concentrates flux lines, amplifying linear physical force.

High-permeability materials channel magnetic flux far more effectively than air, boosting magnetic field density.

Anahtar Kavram

Fundamental principles of electromagnetism, self-induction, mutual induction, and magnetic flux concentration

Tahmini Süre:2m 0s

Soru 123Soru →

In direct current (DC) electronics, circuit modifications and faults alter overall circuit parameters. Match each series circuit condition on the left with its correct electrical effect on the right.

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Cevap

Adding a series resistor increases total resistance and decreases loop current; an open circuit drops current to zero; shorting a resistor reduces total resistance and increases current and remaining voltage drops; doubling source voltage doubles both total current and individual voltage drops.

In a series circuit, current flows through a single continuous path. Total resistance is the sum of all individual resistances (

R_T = R_1 + R_2 + \dots

). Adding a resistor increases total resistance, reducing current. Shorting a resistor bypasses that element, lowering total resistance and increasing loop current, which increases the voltage drop across the remaining resistors (

V = I \times R

). An open circuit breaks the loop, reducing current to zero. Doubling the source voltage across a fixed total resistance doubles the current and doubles each individual voltage drop proportionally.

Adım Adım Çözüm

1

Analyze the resistance relationship for series circuits.

Total resistance is the direct sum of all individual resistors:

R_T = R_1 + R_2 + \dots + R_n

.

Adding a resistor increases

R_T

, while shorting out a resistor removes its resistance from the sum, lowering

R_T

.

2

Apply Ohm's Law (

I = \frac{V_T}{R_T}

) to determine current behavior under each modification.

Higher resistance reduces current, lower resistance increases current, and doubled voltage with fixed resistance doubles current.

Current is directly proportional to voltage and inversely proportional to total circuit resistance.

3

Evaluate the single-path property of a series circuit under open fault conditions.

An open circuit provides infinite resistance (

R = \infty

), causing

I = 0\text{ A}

.

A continuous closed path is mandatory for current flow in any series circuit.

Anahtar Kavram

Series Circuit Governing Rules and Fault Characteristics

Tahmini Süre:1m 15s

Soru 124Soru →

Match each voltage and electromotive force (EMF) concept on the left with its correct technical definition or operating behavior on the right.

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Cevap

Electromotive Force (EMF) pairs with total electrical energy generated per unit charge; Terminal Voltage pairs with actual electrical potential delivered across the load under current; Internal Voltage Drop pairs with potential difference consumed within the source due to internal resistance; Open-Circuit Voltage pairs with potential difference measured across terminals when no current is drawn.

Electromotive Force (EMF) represents the total energy supplied per unit charge inside an electrical generator or chemical cell. Under no-load conditions (zero current), the open-circuit voltage equals the EMF. When connected to a load, current produces an internal voltage drop across the internal resistance, resulting in a lower measured terminal voltage available to the circuit.

Adım Adım Çözüm

1

Identify the fundamental energy conversion definition of source potential

Electromotive Force (EMF) corresponds to the total work converted to electrical energy per unit charge (

1\text{ Volt} = 1\text{ Joule per Coulomb}

).

EMF defines the driving force created by non-electrical mechanisms before any internal losses occur.

2

Differentiate between loaded operating potential and no-load terminal potential

Terminal Voltage is the operational output under load, whereas Open-Circuit Voltage is the static terminal measurement when current is zero.

When an external circuit is closed, current flowing through internal resistance reduces terminal voltage below the generated EMF.

3

Isolate the effect of internal resistance on source performance

Internal Voltage Drop represents the product of load current and internal resistance (

I \cdot r_{int}

).

Internal losses account for the discrepancy between total EMF and measured terminal voltage under load.

Anahtar Kavram

Distinction between source electromotive force, internal resistance drop, and loaded versus unloaded terminal voltage

Tahmini Süre:1m 0s

Soru 125Soru →

Specialized semiconductor diodes are engineered with distinct physical and electrical properties to perform specific functions in electronic circuits. Match each specialized diode and operating condition on the left with its corresponding functional characteristic or application on the right.

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Cevap

The Zener diode in reverse breakdown matches stable voltage regulation; the Varactor diode under reverse bias matches voltage-variable capacitance for RF tuning; the Schottky diode matches fast switching with low forward voltage drop; and the Light-Emitting Diode matches electroluminescent photon emission.

Each diode type corresponds to its unique semiconductor junction physics: Zener diodes maintain stable reverse breakdown voltages for regulation; varactor diodes provide voltage-dependent junction capacitance; Schottky diodes utilize metal-semiconductor junctions for high-speed switching and low forward drop; and LEDs release photons through forward-biased electron-hole recombination.

Adım Adım Çözüm

1

Analyze the operational principle of the Zener diode in reverse bias.

Identified as maintaining a constant voltage (

V_Z

) across terminals.

Zener diodes are specifically doped to operate safely in the avalanche or Zener breakdown region to provide voltage regulation.

2

Analyze the operational principle of the Varactor diode under reverse bias.

Identified as a voltage-controlled variable capacitor.

The reverse bias modulates the width of the dielectric depletion region, changing junction capacitance proportionally to the applied reverse voltage.

3

Analyze the construction and forward characteristics of the Schottky barrier diode.

Identified by its metal-semiconductor junction providing low forward drop (

0.2\text{--}0.3\text{ V}

) and negligible reverse recovery time.

Because majority carriers dominate conduction, there is no minority carrier recombination delay, enabling high-frequency switching.

4

Analyze the forward bias behavior of the Light-Emitting Diode (LED).

Identified as emitting light via electroluminescence.

Direct bandgap semiconductor recombination converts injected forward current into light.

Anahtar Kavram

Operating characteristics and specialized semiconductor applications of Zener, Varactor, Schottky, and Light-Emitting Diodes.

Tahmini Süre:1m 30s

Soru 126Soru →

Match each direct current (DC) circuit scenario on the left with its corresponding calculated electrical quantity on the right using Ohm's law ( $V = I \times R$ ).

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Cevap

The

120\text{ V}

load with

2.4\text{ k}\Omega

matches the resulting current of

50\text{ mA}

; the

5\text{ V}

circuit drawing

20\text{ mA}

matches the circuit resistance of

250\text{ }\Omega

; the

400\text{ mA}

current through

50\text{ }\Omega

matches the voltage drop of

20\text{ V}

; and the

36\text{ V}

loop carrying

3\text{ mA}

matches the loop resistance of

12\text{ k}\Omega

.

Each circuit condition correctly maps to its target electrical parameter by converting metric prefixes (

1\text{ k}\Omega = 1000\text{ }\Omega

,

1\text{ mA} = 0.001\text{ A}

) and applying the appropriate algebraic form of Ohm's law:

I = \frac{V}{R}

,

R = \frac{V}{I}

, and

V = I \times R

.

Adım Adım Çözüm

1

Calculate current for the

120\text{ V}

,

2.4\text{ k}\Omega

circuit

I = \frac{120\text{ V}}{2400\text{ }\Omega} = 0.05\text{ A} = 50\text{ mA}

Ohm's law states

I = \frac{V}{R}

, requiring resistance in fundamental ohms (

1\text{ k}\Omega = 1000\text{ }\Omega

).

2

Calculate resistance for the

5\text{ V}

,

20\text{ mA}

circuit branch

R = \frac{5\text{ V}}{0.02\text{ A}} = 250\text{ }\Omega

Rearranging Ohm's law gives

R = \frac{V}{I}

, requiring current in amperes (

20\text{ mA} = 0.02\text{ A}

).

3

Calculate voltage drop across the

50\text{ }\Omega

element carrying

400\text{ mA}

V = 0.4\text{ A} \times 50\text{ }\Omega = 20\text{ V}

Ohm's law formula

V = I \times R

computes potential difference when current and resistance are known.

4

Calculate total resistance for the

36\text{ V}

,

3\text{ mA}

sensor loop

R = \frac{36\text{ V}}{0.003\text{ A}} = 12000\text{ }\Omega = 12\text{ k}\Omega

Applying

R = \frac{V}{I}

with

3\text{ mA} = 0.003\text{ A}

yields

12000\text{ }\Omega

, or

12\text{ k}\Omega

.

Anahtar Kavram

Ohm's law mathematically relates voltage (

V

), current (

I

), and resistance (

R

) via

V = I \times R

,

I = \frac{V}{R}

, and

R = \frac{V}{I}

, requiring consistent base metric units.

Tahmini Süre:1m 15s

Soru 127Soru →

An electronics technician is organizing replacement components for various power supply and control circuits. Pair each protective device with its designated operational response or circuit function. What is the correct match for each component?

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Cevap

Fast-acting fuse matches with melting an internal sacrificial element almost instantaneously during overcurrent; Slow-blow fuse matches with tolerating momentary startup inrush currents while melting under sustained overload; Metal-oxide varistor (MOV) matches with clamping transient high-voltage spikes by rapidly dropping resistance; Bimetallic thermal circuit breaker matches with using heat-induced mechanical deflection of bonded metals to trip a reusable switch.

Each protective component operates on a specific physical mechanism: fast-acting fuses melt rapidly to safeguard delicate electronics; slow-blow fuses incorporate intentional thermal delays to permit harmless inrush currents; MOVs clamp high-voltage spikes by conducting heavily above their rated clamping voltage; and thermal circuit breakers employ bimetallic strip bending to offer resettable overcurrent interruption.

Adım Adım Çözüm

1

Identify the primary fault type (overcurrent vs. overvoltage) addressed by each protective component.

Fast-acting fuses, slow-blow fuses, and thermal circuit breakers protect against excessive current, whereas metal-oxide varistors protect against transient high-voltage surges.

Categorizing devices by their primary protection role prevents confusing overvoltage suppressors with overcurrent interrupters.

2

Distinguish between the response speeds and mechanisms of the overcurrent protective devices.

Fast-acting fuses blow instantly; slow-blow fuses accommodate brief inrush surges; thermal breakers provide resettable mechanical tripping via bimetallic heating.

Different circuit loads, such as inductive motors versus sensitive solid-state electronics, require tailored opening times and reset capabilities.

3

Correlate each device with its matching functional description.

All four protective devices are correctly paired with their physical operating characteristics.

Accurate pairing verifies mastery of basic electronic protection principles.

Anahtar Kavram

Operational characteristics, response times, and functions of circuit protective devices

Tahmini Süre:1m 0s

Soru 128Soru →

Electromechanical relays and manual switches use specific contact arrangements to govern how electrical circuits open, close, and divert current under various operating states. Which of the following correctly pairs each switch configuration or relay contact state on the left with its functional definition on the right?

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The correct pairings are: Normally Open (NO) Relay Contact matches with 'Remains open to block current when de-energized, closing to complete the circuit only when the coil is energized'; Normally Closed (NC) Relay Contact matches with 'Maintains continuity in the unpowered resting state and opens to interrupt current when the relay coil is energized'; Single-Pole, Double-Throw (SPDT) Switch matches with 'Routes current from a single common input terminal to either of two separate output paths depending on the actuator position'; and Double-Pole, Single-Throw (DPST) Switch matches with 'Simultaneously opens or closes two separate, electrically isolated circuits using a single mechanical actuator'.

Each contact type is paired based on standard electrical conventions: Normally Open contacts require coil excitation to establish continuity; Normally Closed contacts conduct by default until coil energization breaks continuity; SPDT switches route one source line between two alternate destinations; and DPST switches control two isolated lines in tandem.

Adım Adım Çözüm

1

Analyze the Normally Open (NO) relay contact behavior.

Identified as an open circuit in the resting state that closes upon coil energization.

'Normal' in relay terminology denotes the de-energized or unpowered coil state; thus, an NO contact remains disconnected until magnetic attraction pulls the contacts shut.

2

Analyze the Normally Closed (NC) relay contact behavior.

Identified as a closed circuit in the resting state that opens when the coil is energized.

An NC contact provides continuous circuit conduction until an energized coil generates a magnetic field that pulls the armature away to break continuity.

3

Evaluate the Single-Pole, Double-Throw (SPDT) switch configuration.

Identified as one input pole with two selectable throw positions.

'Single-Pole' means one circuit path is controlled; 'Double-Throw' means the common terminal can connect to either of two output load contacts.

4

Evaluate the Double-Pole, Single-Throw (DPST) switch configuration.

Identified as two electrically isolated circuit poles that simultaneously turn on or off.

'Double-Pole' designates two separate conductive lines controlled by a unified toggle/actuator; 'Single-Throw' indicates simple open/closed switching for both.

Anahtar Kavram

Switch pole/throw nomenclature and electromechanical relay contact states

Tahmini Süre:1m 0s

Soru 129Soru →

In electrical circuits, the physical characteristics of a conductor govern its opposition to current flow. Match each conductor modification on the left with its resulting effect on electrical resistance on the right.

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Cevap

Extending length matches with increasing resistance due to a longer path; increasing diameter matches with decreasing resistance due to a wider cross-section; elevating temperature matches with increasing resistance due to increased atomic vibrations; replacing copper with nichrome matches with increasing resistance due to higher intrinsic resistivity.

Each modification is correctly paired according to the fundamental resistance formula

R = \rho \frac{L}{A}

and the positive temperature coefficient of metallic conductors: increasing length increases

R

, increasing cross-sectional area decreases

R

, heating the metal increases

R

, and selecting a higher resistivity material increases

R

.

Adım Adım Çözüm

1

Analyze the relationship between wire length and resistance using

R = \rho \frac{L}{A}

Resistance increases linearly as length increases.

Electrons encounter more resistive material over a longer distance.

2

Analyze the relationship between wire cross-sectional area (thickness) and resistance

Resistance decreases as area increases.

A greater cross-sectional area allows more electrons to pass simultaneously with fewer collisions.

3

Determine the effect of thermal energy on metallic conductors

Resistance increases as temperature rises.

Thermal energy causes metal lattice ions to vibrate more vigorously, impeding the drift of free electrons.

4

Compare material resistivity (

\rho

) between copper and nichrome

Nichrome creates greater resistance than copper of identical dimensions.

Nichrome is a high-resistivity alloy specifically designed to impede current flow and generate heat.

Anahtar Kavram

The resistance of a conductor is determined by its physical dimensions (length and cross-sectional area), material resistivity, and operating temperature.

Tahmini Süre:45s

Soru 130Soru →

Electromagnetic components are essential for controlling current and voltage levels in alternating current circuits. Which characteristic or operational principle correctly corresponds to each listed component or term?

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Cevap

Step-up transformer matches a device with more secondary turns than primary turns that increases alternating voltage; Inductor matches a device that opposes rapid changes in electric current by storing energy in a magnetic field; Henry matches the standard unit of measurement for electrical inductance; Mutual induction matches the process by which a changing current in one coil induces an electromotive force in an adjacent coil.

Each item is matched to its exact operational role and definition: the step-up transformer increases AC voltage via a greater secondary turn count; the inductor resists current changes through magnetic storage; the henry serves as the unit of inductance; and mutual induction represents the principle of transferring energy across coupled coils.

Adım Adım Çözüm

1

Identify the function of a step-up transformer.

A step-up transformer increases alternating voltage because its secondary winding has more turns than its primary winding (

N_s > N_p

).

According to the transformer turns ratio formula,

\frac{V_s}{V_p} = \frac{N_s}{N_p}

, higher secondary turns produce higher secondary voltage.

2

Identify the operating behavior of an inductor.

An inductor resists sudden current fluctuations by temporarily storing electrical energy in a concentrated magnetic field.

Lenz's law states that the induced back-EMF always acts to oppose the original change in current.

3

Identify the standard unit for inductance.

The henry (

\text{H}

) is the recognized unit of electrical inductance.

One henry of inductance induces an electromotive force of one volt when the current changes at a rate of one ampere per second.

4

Identify the definition of mutual induction.

Mutual induction is the magnetic coupling effect where current variations in a primary winding induce a voltage across a separate secondary winding.

This electromagnetic linkage allows electrical energy to transfer between isolated circuits without direct conductive contact.

Anahtar Kavram

Core definitions, units, and operational characteristics of inductors and transformers

Tahmini Süre:45s

Soru 131Soru →

Match each Watt's Law power formula or electrical power unit on the left with its corresponding definition or application condition on the right.

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Cevap

P = V \times I

matches power from voltage and current;

P = I^2 R

matches power from current and resistance;

P = \frac{V^2}{R}

matches power from voltage and resistance;

1\text{ Watt (W)}

matches the unit equivalent to one joule per second.

Each formula represents a direct algebraic variation of Watt's Law derived by combining

P = V \times I

with Ohm's Law (

V = IR

), and the watt is defined as one joule per second.

Adım Adım Çözüm

1

Identify the base relationship of Watt's Law

P = V \times I

Electrical power is defined as the rate at which electrical energy is transferred, calculated by multiplying voltage across a load by the current flowing through it.

2

Derive the formula relating power to current and resistance

P = I^2 R

By substituting

V = I \times R

from Ohm's Law into

P = V \times I

, power is expressed in terms of current squared times resistance.

3

Derive the formula relating power to voltage and resistance

P = \frac{V^2}{R}

By substituting

I = \frac{V}{R}

from Ohm's Law into

P = V \times I

, power is expressed in terms of voltage squared divided by resistance.

4

Identify the standard unit and definition of power

1\text{ W} = 1\text{ J/s}

Power measures the rate of doing work or dissipating energy, where one watt equals one joule per second.

Anahtar Kavram

Watt's Law and Electrical Power Formulas

Tahmini Süre:45s

Soru 132Soru →

A technician is evaluating the electrical characteristics of a direct-current parallel circuit network. Match each circuit parameter on the left with its corresponding behavior or rule on the right.

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Cevap

Branch Voltage matches 'Remains constant and equal across all connected branches'; Total Current matches 'Equals the sum of the individual currents flowing through all branches'; Equivalent Resistance matches 'Is always lower than the resistance of the smallest branch resistor'; Branch Current matches 'Varies inversely with the branch resistance according to

I = \frac{V}{R}

'.

In parallel circuits, all components share common connection points, maintaining equal voltage across each branch. Total current equals the sum of all individual branch currents. Total equivalent resistance decreases as more branches are added (remaining less than the smallest branch resistance). Individual branch current is calculated via Ohm's Law as voltage divided by that branch's resistance.

Adım Adım Çözüm

1

Determine the voltage relationship across parallel branches.

Branch Voltage (

V_{\text{branch}}

) is equal across all branches (

V_{\text{total}} = V_1 = V_2 = \dots

).

All branches connect across the same two common nodes to the power supply.

2

Determine the total current relationship for a parallel network.

Total Current (

I_{\text{total}}

) equals the sum of branch currents (

I_{\text{total}} = I_1 + I_2 + \dots

).

Current splits at junction nodes according to Kirchhoff's Current Law.

3

Determine how total equivalent resistance behaves in a parallel circuit.

Equivalent Resistance (

R_{\text{eq}}

) is always smaller than the smallest branch resistance.

Adding parallel branches adds additional conductive paths for electron flow.

4

Determine how current through a specific branch is calculated.

Branch Current (

I_{\text{branch}}

) is calculated using Ohm's Law (

I_{\text{branch}} = \frac{V}{R_{\text{branch}}}

).

Branch current depends on the common branch voltage divided by the individual branch resistance.

Anahtar Kavram

Fundamental rules governing voltage, current, and resistance in DC parallel circuits.

Tahmini Süre:45s

Soru 133Soru →

A logistics officer is analyzing data from various base operations. Match each statistical description on the left with its correctly calculated value on the right.

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Cevap

The mean crate weight matches with 50, the median supply request matches with 16.5, the missing shipment for a target mean matches with 31, and the mode of repair times matches with 4.

Each pairing correctly applies the fundamental rules of mean, median, mode, and algebraic representation of statistical targets. The calculations strictly follow the rules for measures of central tendency.

Adım Adım Çözüm

1

Calculate the mean for the first description.

(45 + 60 + 55 + 40 + 50) / 5 = 50

The mean is the arithmetic average of a data set.

2

Calculate the median for the second description.

Sorted list:

12, 14, 15, 18, 20, 22

. Average of middle two:

(15 + 18) / 2 = 16.5

The median is the middle value of an ordered set, or the average of the two middle values for an even number of items.

3

Calculate the missing value for the third description.

125 - (20 + 24 + 28 + 22) = 31

The sum of all values must equal the target mean multiplied by the total number of values.

4

Identify the mode for the fourth description.

The number

4

appears three times.

The mode is the most frequent value in a data set.

Anahtar Kavram

Measures of Central Tendency

Soru 134Soru →

Match each circuit protective device on the left with its primary operating characteristic or application on the right.

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Cevap

Fast-acting fuse pairs with opening rapidly to protect sensitive semiconductor electronics; Slow-blow fuse pairs with tolerating brief inrush currents from inductive motors; Magnetic circuit breaker pairs with using an electromagnetic coil to trip during heavy short circuits; Metal-oxide varistor pairs with clamping transient high-voltage surges.

Each protective device is engineered for a specific fault type or application: fast-acting fuses react immediately to protect delicate electronics; slow-blow fuses accommodate brief inductive surges; magnetic breakers use electromagnetism for instant short-circuit tripping; and metal-oxide varistors suppress high-voltage spikes.

Adım Adım Çözüm

1

Identify the characteristic of a fast-acting fuse

Matches with immediate element melting to protect delicate solid-state electronics from sudden overcurrent.

Semiconductors cannot withstand overcurrent for even brief durations.

2

Identify the characteristic of a slow-blow fuse

Matches with tolerating brief inrush currents during electric motor startup.

Inductive loads draw high starting current that would blow standard fuses prematurely.

3

Identify the characteristic of a magnetic circuit breaker

Matches with utilizing an electromagnetic coil to trip instantaneously during high-current short circuits.

Electromagnetic pull is proportional to current and trips the contact latch mechanism without relying on heat.

4

Identify the characteristic of a metal-oxide varistor (MOV)

Matches with clamping high-voltage transient spikes.

MOVs are voltage-dependent resistors designed specifically for surge suppression rather than direct overcurrent interruption.

Anahtar Kavram

Operating principles and applications of circuit protection devices including thermal, magnetic, time-delay, and voltage suppression elements

Tahmini Süre:45s

Soru 135Soru →

Match each resistor configuration or color-coded component on the left with its corresponding electrical characteristic and operating principle on the right.

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Cevap

The three-terminal potentiometer matches the voltage divider function; the rheostat matches the series current limiter with wiper-to-end protection; the Yellow-Violet-Orange-Gold resistor matches

47\text{ k}\Omega \pm 5\%

; and the Brown-Gray-Green-Silver resistor matches

1.8\text{ M}\Omega \pm 10\%

.

Each item correctly links the component physical description or color code to its precise electrical definition: potentiometers provide variable potential division, rheostats adjust circuit current, Yellow-Violet-Orange-Gold evaluates to

47\text{ k}\Omega \pm 5\%

, and Brown-Gray-Green-Silver evaluates to

1.8\text{ M}\Omega \pm 10\%

.

Adım Adım Çözüm

1

Analyze the three-terminal potentiometer and rheostat wiring configurations

A potentiometer connected across a power source acts as a continuous voltage divider (

0\text{ V}

to

V_{\text{in}}

) at the wiper terminal. A rheostat uses a variable two-terminal configuration in series with the load to regulate current.

Variable resistors differ in circuit function based on whether they are wired as three-terminal potential dividers or two-terminal current adjusters.

2

Decode the four-band color code for Yellow-Violet-Orange-Gold

Yellow = 4, Violet = 7, Orange = multiplier

10^3 = 1,000

, Gold =

\pm 5\%

. Value

= 47 \times 1,000\ \Omega = 47\text{ k}\Omega \pm 5\%

.

Standard EIA 4-band color coding assigns significant digits to the first two bands, a decimal multiplier to the third band, and tolerance percentage to the fourth band.

3

Decode the four-band color code for Brown-Gray-Green-Silver

Brown = 1, Gray = 8, Green = multiplier

10^5 = 100,000

, Silver =

\pm 10\%

. Value

= 18 \times 100,000\ \Omega = 1.8\text{ M}\Omega \pm 10\%

.

Standard EIA 4-band color coding converts

1,800,000\ \Omega

using standard metric prefixes to

1.8\text{ M}\Omega

with a silver tolerance of

\pm 10\%

.

Anahtar Kavram

Operating principles and terminal configurations of fixed and variable resistors (potentiometers, rheostats, and standard color codes)

Alternatif Yöntem

To quickly decode 4-band resistors, write down the two digits (e.g., 47 for Yellow-Violet or 18 for Brown-Gray), append the number of zeros indicated by the multiplier color (3 zeros for Orange = 47,000, 5 zeros for Green = 1,800,000), and simplify to metric units (kilo or mega).

Tahmini Süre:1m 0s

Soru 136Soru →

A direct current (DC) circuit consists of a $48\text{ V}$ power supply connected in series with three resistors: $R_1 = 12\ \Omega$ , $R_2 = 24\ \Omega$ , and $R_3 = 24\ \Omega$ . In its baseline operating state, the total circuit resistance is $R_T = 60\ \Omega$ and the circuit loop current is $I = 0.8\text{ A}$ .

Match each circuit alteration on the left to its corresponding electrical outcome on the right.

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Cevap

The correct matches pair: (1) shorting resistor

R_3

with total resistance dropping to

36\ \Omega

, current rising to

1.33\text{ A}

, and

0\text{ V}

across

R_3

; (2) an open at

R_2

with loop current dropping to

0\text{ A}

and

48\text{ V}

appearing across

R_2

; (3) adding a

20\ \Omega

series resistor with total resistance rising to

80\ \Omega

, current dropping to

0.6\text{ A}

, and

7.2\text{ V}

across

R_1

; and (4) raising the source to

72\text{ V}

with total resistance remaining

60\ \Omega

, current rising to

1.2\text{ A}

, and

28.8\text{ V}

across

R_2

.

Each modification directly follows the governing principles of series DC circuits. In series circuits, total resistance equals the direct sum of all individual resistances (

R_T = R_1 + R_2 + \dots + R_n

), and current is constant throughout the single loop (

I_T = \frac{V_T}{R_T}

). Short circuits eliminate individual component resistance and drop component voltage to zero while raising loop current. Open circuits eliminate current entirely and place full source voltage across the open terminals. Adding series resistance reduces current throughout the loop, and increasing source voltage increases current and all individual voltage drops proportionally.

Adım Adım Çözüm

1

Analyze the short circuit condition across

R_3

R_T = 12 + 24 = 36\ \Omega

;

I = \frac{48}{36} \approx 1.33\text{ A}

;

V_3 = 0\text{ V}

A short circuit bypasses the component with zero resistance, eliminating its resistance from the total series sum and producing zero potential difference across itself.

2

Analyze the open circuit condition at

R_2

I = 0\text{ A}

;

V_1 = 0\text{ V}

;

V_3 = 0\text{ V}

;

V_2 = 48\text{ V}

An open in a series circuit interrupts the sole conductive loop, causing current to cease everywhere; infinite resistance across the open component causes the full source potential to appear across the gap.

3

Analyze the addition of a fourth series resistor (

R_4 = 20\ \Omega

)

R_T = 60 + 20 = 80\ \Omega

;

I = \frac{48}{80} = 0.6\text{ A}

;

V_1 = 0.6 \times 12 = 7.2\text{ V}

In series circuits, equivalent resistance is additive (

R_T = \sum R

). Increasing total resistance reduces total current according to Ohm's Law (

I = \frac{V}{R_T}

), which proportionally reduces individual component voltage drops.

4

Analyze the voltage source increase to

72\text{ V}

R_T = 60\ \Omega

;

I = \frac{72}{60} = 1.2\text{ A}

;

V_2 = 1.2 \times 24 = 28.8\text{ V}

Resistor values are independent of source voltage. Applying Ohm's Law with higher voltage across constant resistance yields directly proportional increases in loop current and individual voltage drops.

Anahtar Kavram

Series Circuit Governing Rules: Additive Resistance, Current Continuity, Ohm's Law, and Fault Dynamics

Tahmini Süre:2m 0s

Soru 137Soru →

In basic electronics, distinguishing between charge behavior, measurement units, and current flow conventions is essential. Match each electrical concept on the left with its correct definition or governing rule on the right.

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Cevap

Electron Flow Theory matches the movement of negative charge carriers from negative to positive; Conventional Current Theory matches the historical assumption of flow from positive to negative; Electric Current matches the rate of charge flow over time; One Ampere matches one coulomb of charge per second.

Each electrical term accurately maps to its standard scientific definition: Electron Flow describes negative electrons drifting toward the positive terminal; Conventional Current describes the standard positive-to-negative circuit model; Electric Current represents the rate of charge flow (

I = Q/t

); and One Ampere specifically equals one coulomb passing a given point in one second (

1\text{ C/s}

).

Adım Adım Çözüm

1

Identify the physical reality of electron drift versus historical convention.

Electrons are negatively charged, so they drift from negative to positive (Electron Flow). Conventional current historically assumes flow from positive to negative.

Clear differentiation between historical convention and physical subatomic movement is foundational in electrical fundamentals.

2

Define the quantity of electric current.

Current (

I

) represents the rate of charge (

Q

) flow per unit time (

t

), yielding

I = \frac{Q}{t}

.

Current measures the flow rate of charge through a conductor, not electrical pressure or potential difference.

3

Relate the ampere to fundamental SI electrical units.

1\text{ ampere} = 1\text{ coulomb per second}

(

1\text{ A} = 1\text{ C/s}

).

The ampere quantifies current flow as a unit of coulombs transferred over time in seconds.

Anahtar Kavram

Fundamental definitions of electric current, charge rate, ampere units, and directional flow models.

Alternatif Yöntem

Recall the fundamental dimensional relationships: Current is

I = \frac{\Delta Q}{\Delta t}

, so its unit (

1\text{ A}

) must be equal to

\frac{1\text{ C}}{1\text{ s}}

. Then remember that because electrons possess a negative charge, like charges repel and opposite charges attract, forcing them to move away from the negative terminal toward the positive terminal.

Tahmini Süre:45s

Soru 138Soru →

In electrical and electronic systems, understanding the fundamental physical properties governing current flow is essential. Match each resistance-related concept on the left with its correct physical description on the right.

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Cevap

Electrical Resistance matches the total opposition of a specific component in ohms; Material Resistivity matches the intrinsic geometry-independent material property; American Wire Gauge matches the inverse sizing scale where smaller numbers mean thicker wire; and Positive Temperature Coefficient matches the increase in resistance as temperature rises.

Each electrical concept matches its core definition: Electrical Resistance (

R

) is the total opposition to current flow in ohms; Material Resistivity (

\rho

) is the intrinsic material property; American Wire Gauge (AWG) is the inverse sizing standard where smaller numbers indicate thicker conductors; and a Positive Temperature Coefficient defines the increase of resistance with rising temperature.

Adım Adım Çözüm

1

Distinguish between total electrical resistance and intrinsic material resistivity.

Electrical resistance (

R

) is the overall opposition in a specific conductor measured in ohms (

\Omega

), while resistivity (

\rho

) is the inherent property of the material itself.

Total resistance depends on both the material's resistivity and its physical dimensions according to

R = \rho \frac{L}{A}

.

2

Analyze standard conductor sizing and thermal behavior principles.

AWG numbers inversely scale with conductor diameter (smaller number = thicker wire), and a positive temperature coefficient means resistance rises with heat.

Wire gauge dictates cross-sectional area, and thermal excitation in metals increases electron collisions, raising resistance.

Anahtar Kavram

Core physical factors and definitions governing electrical resistance and resistivity in conductors

Tahmini Süre:45s

Soru 139Soru →

In direct-current (DC) circuit analysis, different forms of Watt's Law are used depending on which electrical quantities are known. Match each set of known circuit parameters on the left with the correct formula on the right used to calculate the target value directly.

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Cevabı ve açıklamayı göster

Cevap

Each given set of circuit parameters matches the direct algebraic form of Watt's Law designed for those specific variables: Voltage and Current to

P = V \times I

; Current and Resistance to

P = I^2 \times R

; Voltage and Resistance to

P = \frac{V^2}{R}

; and Power and Voltage to

I = \frac{P}{V}

.

Each match correctly pairs the given known variables with the exact Watt's Law equation variant required to solve directly for the unknown quantity without needing extraneous calculation steps.

Adım Adım Çözüm

1

Identify the base definition of electrical power in terms of voltage and current.

P = V \times I

Power in watts equals electromotive force in volts multiplied by electron current flow in amperes.

2

Derive the power formula when only current and resistance are given using Ohm's Law (

V = I \times R

).

P = (I \times R) \times I = I^2 \times R

Replacing voltage with the product of current and resistance calculates power without needing voltage explicitly.

3

Derive the power formula when only voltage and resistance are given using Ohm's Law (

I = \frac{V}{R}

).

P = V \times \left(\frac{V}{R}\right) = \frac{V^2}{R}

Replacing current with voltage divided by resistance calculates power without needing current explicitly.

4

Rearrange the primary power formula to solve for current when power and voltage are known.

I = \frac{P}{V}

Dividing both sides of

P = V \times I

by voltage isolates the current parameter.

Anahtar Kavram

Watt's Law and its derived variations relate electrical power (

P

), voltage (

V

), current (

I

), and resistance (

R

).

Tahmini Süre:45s

Soru 140Soru →

Match each specialized switching or relay device to its corresponding operational characteristic and actuation method.

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Cevap

Reed switch matches ferromagnetic flexible metal reeds sealed in glass; Rotary switch matches rotating shaft and wiper contact selecting between three or more positions; Contactor matches heavy-duty electromechanical device for high-current power loads; Thermal overload relay matches monitoring sustained overcurrent using a bimetallic strip.

Each switching component is matched according to its fundamental physics of operation: the reed switch relies on magnetic field induction on ferrous contacts; the rotary switch provides multi-position manual circuit routing; the contactor uses an electromagnetic solenoid for high-amperage switching; and the thermal overload relay uses thermal deflection of a bimetallic strip for motor overload protection.

Adım Adım Çözüm

1

Identify the actuation mechanism of a reed switch.

Recognize that reed switches operate magnetically via enclosed flexible ferrous blades.

Reed switches rely on external magnetic flux rather than manual toggling or internal thermal deflection.

2

Analyze the mechanical multi-position selection function of a rotary switch.

Associate the rotary switch with angular shaft rotation routing a signal to multiple switch poles/throws.

Rotary switches provide multi-throw circuit selection through rotational movement.

3

Distinguish between standard low-power control relays and contactors.

Connect contactors to high-current power switching controlled via electromagnetic coils.

Contactors feature heavy-duty contacts built specifically to handle high current without contact welding.

4

Determine the protective operation of a thermal overload relay.

Pair the thermal overload relay with bimetallic thermal expansion sensing excessive motor current.

Thermal overload relays protect motor windings by converting persistent current into heat that mechanically triggers auxiliary contacts.

Anahtar Kavram

Specialized switch and relay actuation mechanisms and circuit roles

Tahmini Süre:1m 0s

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